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The Molecular Basis of Inheritance

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... and her X-ray diffraction photo of DNA RACE FOR STRUCTURE OF DNA Figure 5.x3 James Watson and Francis Crick Meselson-Stahl Experiment Practice Questions ... – PowerPoint PPT presentation

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Title: The Molecular Basis of Inheritance


1
The Molecular Basis of Inheritance
  • Chapter 16

2
HISTORY OF DNA STRUCTURE
  • How did we learn that DNA is the key to coding
    for all characteristics of living things?
  • Once Morgans group showed that genes are located
    on chromosomes, the two chemical components of
    chromosomes DNA PROTEIN, became the
    candidates for the genetic material.

3
TIMELINE
  • 1928
  • British scientist -- Frederick Griffith studies
    bacteria looking for cause of pneumonia
  • found two specific strains or cultures of
    bacteria that looked different when growing on
    petri dishes
  • one grew in smooth-edged groups
  • other one produced colonies that were rough and
    ragged around the edges
  • IMPORTANCE
  • Visual differences made it easy to recognize and
    distinguish between the strains of bacteria
  • Also, Griffith found that
  • smooth-edged colonies of bacteria caused disease
  • rough-edged colonies were harmless

4
Griffiths Experimenthttp//nortonbooks.com/colle
ge/biology/animations/ch12a01.htm
5
RESULTS OF GRIFFITHS 1928 EXPERIMENT
  • Discovery of process of transformation
  • Somehow the heat-killed bacteria had passed their
    disease-causing ability to the harmless strain
  • The harmless strain had been transformed into a
    disease-causing strain
  • Hypothesized that some factor was responsible
    for this change

6
TIMELINE CONTINUED
  • 1944
  • American, Oswald Avery, continued bacteria
    research of Griffith
  • Knew were 4 types of organic compounds that make
    up all life
  • used enzymes to destroy lipids, carbohydrates,
    proteins, and RNA in an extract from the disease
    causing bacteria.
  • IMPORTANCE
  • Transformation still occurred, so obviously the
    molecules they had destroyed were not responsible
    for transformation.
  • Only organic molecule left that had not been
    destroyed was DNA
  • When repeated experiment with DNA-destroying
    enzymes, no transformation occurred.DNA was the
    key to heredity

7
TIMELINE CONTINUED
  • 1952
  • Americans Alfred Hershey and Martha Chase
  • worked with viruses called bacteriophages
  • viruses are simple DNA or RNA core and a
    protein coat around them
  • when they infect, bacteriophages inject DNA or
    RNA into cell and protein coat is left outside
  • used radioactive markers to trace
  • phosphorus-32 (32P) for DNA
  • sulfur-35 (35S) for protein coat

8
Figure 16.2a The Hershey-Chase Experiment Phages
9
Hershey-Chase Experimenthttp//nortonbooks.com/co
llege/biology/animations/ch12a02.htm
Bacteriophage with phosphorus-32 in DNA
Phage infectsbacterium
Radioactivity inside bacterium
Bacteriophage with sulfur-35 in protein coat
Phage infectsbacterium
No radioactivity inside bacterium
Go to Section
10
RESULTS OF HERSHEY-CHASE
  • When viruses were separated from the bacteria and
    tested for radioactivity, all of the
    radioactivity from the bacteria was found to be
    32P
  • Conclusion
  • genetic material of the bacteriophage that was
    transferred was DNA NOT PROTEIN!

11
RACE FOR STRUCTURE OF DNA
  • 1940
  • Erwin Chargaff discovers that percentages of A
    and T are equal in any sample of DNA same is
    true for C and G
  • 1944
  • Linus Pauling discovers that proteins can have a
    helical shape
  • 1952
  • Rosalind Franklin takes pictures of DNA molecule
    using technique called X-ray diffraction, shows
    that DNA has helical shape

12
Figure 16.4 Rosalind Franklin and her X-ray
diffraction photo of DNA
13
RACE FOR STRUCTURE OF DNA
  • 1951-1952
  • Maurice Wilkins works with X- ray diffraction and
    sees same pattern as Franklin, shares info with
    James Watson
  • April, 1953
  • James Watson and Francis Crick build first model
    of DNA (are awarded Nobel Prize in 1960s)

14
Figure 5.x3 James Watson and Francis Crick
15
Meselson-Stahl Experiment
  • Late 1950s experiments by Meselson Stahl
    support the semi-conservative replication of DNA
  • Data reject conservative and dispersal hypotheses!

16
Practice Questions
  • Which of the following is LEAST related to the
    others?
  • Transformation
  • Phage
  • DNA
  • Griffeth
  • Avery
  • Answer phage

17
Practice Questions
  • What was the contribution of the following
    scientists regarding the discovery of our present
    knowledge of the nature of genes and/or the shape
    of the DNA?
  • Griffith
  • Hershey Chase
  • Avery, MacLeod, and McCarty
  • Chargaff
  • Meselson Stahl

18
BASIC DNA STRUCTURE
  • Exists as a double helix
  • Backbone of DNA structure made up of alternating
    sugar (deoxyribose) and phosphate groups
  • Bases are attached to the sugars
  • Bases in DNA are adenine, thymine, cytosine, and
    guanine
  • A pairs with T, C pairs with G and vice-versa
  • A and G are purines larger, double rings
  • T and C are pyrimidines smaller, single rings

19
Figure 16.6 Base pairing in DNA
20
Why does A always pair with T (or U), and G with
C?
Distance between uprights is 2 nm (nanometers)
21
Chromosome Structure of Eukaryotes
Eukaryotic chromosomes contain DNA wrapped around
proteins called histones. The strands of
nucleosomes are tightly coiled and supercoiled to
form chromosomes.
Go to Section
22
3 Important Chromosome Functions
  • Carry information from one generation to the
    next.
  • Put that information to work by determining the
    heritable characteristics of organisms.
  • Have to be easily copied each time a cell
    divides.

23
Practice Question
  • All of the following elements are present in DNA
    except
  • Oxygen
  • Nitrogen
  • Carbon
  • Sulfur
  • Phosphorus
  • Answer sulfur

24
Practice Questions
  • Cytosine makes up 38 of the nucleotides in a
    sample of DNA from an organism. What percent of
    the nucleotides in this sample will be thymine?
  • 12
  • 24
  • 31
  • 38
  • Cannot be determined with information provided
  • Answer 12

25
Practice Questions
  • In an analysis of the nucleotide composition of
    DNA, which of the following is TRUE?
  • A C
  • A G and C T
  • A C G T
  • A T G C
  • Both B and C are true
  • Answer A C G T

26
Practice Question
  • All of the following were determined directly
    from X-ray diffraction photographs of
    crystallized DNA except
  • The diameter of the double helix
  • The helical shape of DNA
  • The sequence of nucleotides
  • The linear distance required for one full turn of
    the double helix
  • The width of the double helix
  • Answer the sequence of nucleotides

27
DNA REPLICATION
  • Open up the helix to promote easier copying
    HELICASE is the enzyme that facilitates this
  • There are MANY helicases that work together to
    unwind the double helix efficiently.
  • WATCH THIS ANIMATION SEVERAL TIMES
  • http//www.wiley.com/college/pratt/0471393878/stud
    ent/animations/dna_replication/index.html

28
Figure 16.7 A model for DNA replication the
basic concept (Layer 1)
REMEMBER this all occurs during the S phase of
interphase in mitosis or- during MEIOSIS I ONLY!
http//bcs.whfreeman.com/thelifewire/content/chp11
/1102002.html http//bcs.whfreeman.com/thelifewir
e/content/chp11/1102002.html http//bcs.whfreeman
.com/thelifewire/content/chp11/1102003.html
29
Figure 16.7 A model for DNA replication the
basic concept (Layer 2)
Hydrogen bonds are broken here!!!
30
Figure 16.7 A model for DNA replication the
basic concept (Layer 3)
31
Figure 16.7 A model for DNA replication the
basic concept (Layer 4)
SEMI-CONSERVATIVE PROCESSwhat does this mean?
32
Semi-Conservative Replicationhttp//www.sumanasin
c.com/webcontent/animations/content/meselson.html
The 2 strands of the parental molecule separate,
and each functions as a template for synthesis of
a new complimentary strand. SEE TEXT PAGE 294.
33
Replication
  • The replication of a DNA molecule begins at an
    origin of replication.
  • Bacterial chromosomes are circular and have a
    SINGLE origin of replication.
  • Eukaryotic chromosomes are linear and may have
    hundreds of origins of replication.
  • Proteins that initiate DNA replication recognize
    these sequences and attach to the DNA, separating
    the two strands and opening up a replication
    bubble.
  • DNA replication occurs in a Replication Bubble
    and each end is called a Replication fork
  • Replication is catalyzed by the enzyme DNA
    polymerase makes sure that correct bases pair.
  • Llike a spell check for the process of
    replication.
  • DNA Ligase is the enzyme that forms the new
    covalent bonds between the DNA nucleotides.

34
Replication begins at specific sites where the
two parental strands separate to form replication
bubbles. The bubbles expand laterally, as DNA
replication proceeds in both directions. Eventual
ly, the replication bubbles fuse, and synthesis
of the daughter strands is complete.
REPLICATION FORK a y-shaped region where new
strands of DNA are elongating.
35
Figure 16.11 Incorporation of a nucleotide into
a DNA strand
Where does the energy for DNA replication come
from?
36
Figure 16.12 The two strands of DNA are
antiparallel
The two DNA strands are ANTIPARALLEL that is,
their sugar-phosphate backbones run in opposite
directions. The 5 ? 3 direction of one strand
runs counter to the 5 ? 3 direction of the
other strand. The numbers assigned to the carbon
atoms of the deoxyribose are shown for two of
them. In the figure, the five carbons of one
deoxyribose sugar of each DNA strand are numbered
from 1 to 5. Notice in the figure that a
nucleotides phosphate group is attached to the
5 carbon of deoxyribose. Notice also that the
phosphate group of one nucleotide is joined to
the 3 carbon of the adjacent nucleotide.
37
Antiparallel Arrangement of DNA
  • Replicating the LEADING STRAND
  • Antiparallel sugar-phosphate backbones run in
    opposite directions
  • See page 296 in text
  • DNA polymerases add nucleotides ONLY to the free
    3 end of a growing DNA strand, never to the 5
    end
  • SO, a new DNA strand can only elongate in the 5?
    3 direction!
  • Polymerase nestles in the replication fork on the
    template strand that is read 5 ? 3 (leading
    strand)
  • This strand is replicated continuously in the 5
    to 3 direction.

38
Antiparallel Arrangement of DNA
  • Replicating the LAGGING STRAND
  • To elongate the other new DNA strand, polymerase
    must work along the other template strand in the
    direction AWAY FROM the replication fork.
  • As a replication bubble opens, a polymerase
    molecule can work its way away from a replication
    fork and synthesize a short segment of DNA.
  • As the bubble grows, another short segment of the
    lagging strand can be made in a similar way.
  • This is known as DISCONTINUOUS replication
    because the DNA is synthesized in short fragments
    called OKAZAKI fragments.

39
Practice Question
  • The strands that make up DNA are antiparallel.
    What does this mean?
  • Answer the 5 to 3 direction of one strand runs
    counter to the 5 to 3 direction of the other
    strand

40
Figure 16.13 Synthesis of leading and lagging
strands during DNA replication
1. DNA polymerase elongates DNA strands only in
the 5 ? 3 direction.
2. One new strand (leading strand) can therefore
elongate continuously 5 ? 3 as the replication
for progresses.
3. The other new strand (lagging strand), must
grow in an overall 3 ? 5 direction by addition
of short segments (Okazaki fragments) that grow
5 ? 3 (numbered here in the order they were
made).
4. Ligase connects the Okazaki fragments.
41
Priming DNA Synthesis
  • DNA polymerases cannot initiate synthesis of a
    polynucleotide it can only add nucleotides to
    already existing chain!
  • The start of a NEW chain is not DNA, but a short
    stretch of RNA called a primer.
  • The enzyme primase joins this RNA to the DNA
    template to make the primer.
  • Primase can start an RNA chain from scratch!

42
Figure 16.14 Priming DNA synthesis with RNA
DNA polymerase cannot initiate a polynucleotide
strand it can only add to the 3 end of an
already-started strand. The primer is a short
segment of RNA synthesized by the enzyme primase.
Each primer is eventually replaced by DNA.
43
Figure 16.15 The main proteins of DNA
replication and their functions
44
Figure 16.16 A summary of DNA replication
http//highered.mcgraw-hill.com/olc/dl/120076/bio2
3.swf
45
Practice Question
  • Which enzymes catalyze the elongation of a DNA
    strand in the 5 to 3 direction?
  • Primase
  • DNA ligase
  • DNA polymerases
  • Topoisomerase
  • Helicase
  • Answer DNA polymerases

46
Practice Question
  • What is the function of the following enzymes in
    DNA replication?
  • Helicase
  • SSBs
  • Nuclease
  • Ligase
  • DNA polymerase
  • primase

47
Practice Question
  • In DNA, the designations 3 and 5 refer to what?
  • Answer carbon atoms of deoxyribose to which
    phosphate groups may bond

48
Practice Question
  • Which of the following is LEAST related to the
    others on the list?
  • Okazaki fragment
  • Primer
  • Telomere
  • Leading strand
  • Lagging strand
  • Answer telomere

49
Practice Question
  • If I am writing an essay about DNA replication
    what pertinent vocabulary terms should I use AND
    define?

Antiparallel arrangement Helicase Hydrogen bonds SSBs
Base pairing Semi-conservative Replication bubble Replication fork
DNA polymerase Primase RNase H Ligase
RNA primer 5 to 3 Leading strand (continuous) Lagging strand (discontinuous)
Okazaki fragments complementary S phase of mitosis Meiosis I
nuclease Telomeres telomerase
50
PROOFREADING DNA FOR ERRORS
  • Enzymes proofread DNA during its replication and
    repair damage in existing DNA
  • See page 299
  • errors in completed DNA molecule amount to only
    one in a billion nucleotides
  • Initial pairing errors error rate of 1 per
    10000 base pairs
  • exposure damage reactive chemicals, radiation,
    X-rays, ultraviolet light (unpredictable, but
    common)
  • Ex. Skin cells and UV damage
  • Mismatch repair cells use special enzymes to
    fix incorrectly paired nucleotide
  • Nucleotide excision repair uses nuclease (DNA
    cutting enzyme that excises damaged area)

51
Figure 16.17 Nucleotide excision repair of DNA
damage
A team of enzymes detects and repairs damaged
DNA. Repair enzymes can excise damaged DNA
regions from the DNA and replace them with a
normal segment. Good Animation http//nortonbook
s.com/college/biology/animations/ch12a05.htm
52
The Dilemma of DNA Ends
  • For linear DNA, like that found in eukaryotes,
    DNA polymerase can only add nucleotides to the 3
    end of a preexisting polynucleotide this is a
    potential problem!
  • The normal replication machinery has no way to
    complete the 5 ends of daughter DNA strands as
    a result repeated rounds of replication produce
    shorter and shorter DNA molecules.
  • Result deletion of essential genes!
  • NOTE prokaryotes avoid this problem by having
    circular DNA!

53
Figure 16.18 The end-replication problem
When a linear DNA molecule replicates, a gap is
left at the 5 end of each new strand (light
blue) because DNA polymerase can only add
nucleotides to a 3 end. As a result, with
each round of replication, the DNA molecules get
slightly shorter. Good Animation http//spine.ru
tgers.edu/cellbio/assets/flash/tel.htm
54
Telomeres and Telomerase
  • Eukaryotic chromosomal DNA molecules have special
    nucleotide sequences called telomeres at their
    ends
  • Telomeres are regions of DNA that do not contain
    genes rather, are multiple repetitions of one
    short nucleotide sequence.
  • Typically, the repeated unit TTAGGG is seen in
    human telomeres.
  • Telomeric DNA protects an organisms genes from
    being eroded through successive rounds of DNA
    replication!
  • These (along with special protein called
    telomerase associated with it) prevent the ends
    from activating the cells systems for monitoring
    DNA damage.
  • Ex. The end of DNA strand seen as double strand
    break might trigger signal transduction
    pathways leading to cell cycle arrest or cell
    death)!

55
Figure 16.19b Telomeres and Telomerase
SOME eukaryotes deal with the end-replication
issues by having expendable, noncoding sequences
called telomeres at the ends of their DNA and the
enzyme telomerase in some of their cells. In the
long term, over the course of generations,
eukaryotic organisms need a way of restoring
their shortened telomeres. This is provided by
telomerase (a special enzyme that catalyzes the
lengthening of telomeres).
56
Telomeres Limiting Life?
  • Telomerase is NOT present in most cells of
    multicellular organisms like ourselves, and the
    DNA of dividing somatic cells does tend to be
    shorter in older individuals and in cultured
    cells that have divided many times.
  • Thus, it is possible that telomeres are a
    limiting factor in the life span of certain
    tissues and even organisms as a whole.
  • Telomerase is however present in germ-line cells
    that give rise to gametes and here the enzyme
    produces long telomeres in these cells and hence
    in the newborn.
  • Intriguingly, telomerase is also found in somatic
    cells that are cancerous these usually have
    unusually short telomeres, which one would expect
    for cells that have undergone many rounds of
    division.
  • Progressive shortening would eventually lead to
    self-destruction of cancer unless telomerase
    became available to stabilize telomere length.
  • This is exactly what seems to happen in cancer
    cells. IF this is an important factor it may
    well provide a useful target for cancer diagnosis
    and chemotherapy!

57
The Essay
  • Scientists seeking to determine which molecule is
    responsible for the transmission of
    characteristics from one generation to the next
    knew that the molecule must
  • (1) copy itself precisely,
  • (2) be stable but able to be changed, and
  • (3) be complex enough to determine the organism's
    phenotype.
  • Explain how DNA meets each of the three criteria
    stated above.
  • Select one of the criteria stated above and
    describe experimental evidence used to determine
    that DNA is the hereditary material.
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