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Title: Chapter 11 Liquids, Solids, and Intermolecular Forces


1
Chapter 11Liquids, Solids, and Intermolecular
Forces
Chemistry A Molecular Approach, 1st Ed.Nivaldo
Tro
Roy Kennedy Massachusetts Bay Community
College Wellesley Hills, MA
2008, Prentice Hall
2
Comparisons of the States of Matter
  • the solid and liquid states have a much higher
    density than the gas state
  • therefore the molar volume of the solid and
    liquid states is much smaller than the gas state
  • the solid and liquid states have similar
    densities
  • generally the solid state is a little denser
  • notable exception ice is less dense than liquid
    water
  • the molecules in the solid and liquid state are
    in close contact with each other, while the
    molecules in a gas are far apart

3
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4
Freedom of Motion
  • the molecules in a gas have complete freedom of
    motion
  • their kinetic energy overcomes the attractive
    forces between the molecules
  • the molecules in a solid are locked in place,
    they cannot move around
  • though they do vibrate, they dont have enough
    kinetic energy to overcome the attractive forces
  • the molecules in a liquid have limited freedom
    they can move around a little within the
    structure of the liquid
  • they have enough kinetic energy to overcome some
    of the attractive forces, but not enough to
    escape each other

5
Properties of the 3 Phases of Matter
  • Fixed keeps shape when placed in a container
  • Indefinite takes the shape of the container

6
Kinetic - Molecular Theory
  • the properties of solids, liquids, and gases can
    be explained based on the kinetic energy of the
    molecules and the attractive forces between
    molecules
  • kinetic energy tries to give molecules freedom of
    motion
  • degrees of freedom translational, rotational,
    vibrational
  • attractive forces try to keep the molecules
    together
  • kinetic energy depends only on the temperature
  • KE 1.5 kT

7
Gas Structure
Gas molecules are rapidly moving in random
straight lines and free from sticking to each
other.
8
Explaining the Properties of Solids
  • the particles in a solid are packed close
    together and are fixed in position
  • though they may vibrate
  • the close packing of the particles results in
    solids being incompressible
  • the inability of the particles to move around
    results in solids retaining their shape and
    volume when placed in a new container and
    prevents the particles from flowing

9
Solids
  • some solids have their particles arranged in an
    orderly geometric pattern we call these
    crystalline solids
  • salt and diamonds
  • other solids have particles that do not show a
    regular geometric pattern over a long range we
    call these amorphous solids
  • plastic and glass

10
Explaining the Properties of Liquids
  • they have higher densities than gases because the
    molecules are in close contact
  • they have an indefinite shape because the limited
    freedom of the molecules allows them to move
    around enough to get to the container walls
  • but they have a definite volume because the limit
    on their freedom keeps them from escaping the
    rest of the molecules

11
Compressibility
12
Phase Changes
13
Why are molecules attracted to each other?
  • intermolecular attractions are due to attractive
    forces between opposite charges
  • ion to - ion
  • end of polar molecule to - end of polar
    molecule
  • H-bonding especially strong
  • even nonpolar molecules will have temporary
    charges
  • larger the charge stronger attraction
  • longer the distance weaker attraction
  • however, these attractive forces are small
    relative to the bonding forces between atoms
  • generally smaller charges
  • generally over much larger distances

14
Trends in the Strength of Intermolecular
Attraction?
  • the stronger the attractions between the atoms or
    molecules, the more energy it will take to
    separate them
  • boiling a liquid requires we add enough energy to
    overcome the attractions between the molecules or
    atoms
  • the higher the normal boiling point of the
    liquid, the stronger the intermolecular
    attractive forces

15
Attractive Forces
-
-
16
Dispersion Forces
  • fluctuations in the electron distribution in
    atoms and molecules result in a temporary dipole
  • region with excess electron density has partial
    (-) charge
  • region with depleted electron density has partial
    () charge
  • the attractive forces caused by these temporary
    dipoles are called dispersion forces
  • aka London Forces
  • all molecules and atoms will have them
  • as a temporary dipole is established in one
    molecule, it induces a dipole in all the
    surrounding molecules

17
Dispersion Force
18
Size of the Induced Dipole
  • the magnitude of the induced dipole depends on
    several factors
  • polarizability of the electrons
  • volume of the electron cloud
  • larger molar mass more electrons larger
    electron cloud increased polarizability
    stronger attractions
  • shape of the molecule
  • more surface-to-surface contact larger induced
    dipole stronger attraction

19
Effect of Molecular Sizeon Size of Dispersion
Force
Noble Gases are all nonpolar atomic elements.
As the molar mass increases, the number of
electrons increase. Therefore the strength of
the dispersion forces increases.
The stronger the attractive forces between the
molecules, the higher the boiling point will be.
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21
Properties of Straight Chain AlkanesNon-Polar
Molecules
22
Boiling Points of n-Alkanes
23
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24
Effect of Molecular Shapeon Size of Dispersion
Force
25
Alkane Boiling Points
  • branched chains have lower BPs than straight
    chains
  • the straight chain isomers have more
    surface-to-surface contact

26
Practice Choose the Substance in Each Pair with
the Highest Boiling Point
  1. CH4 CH3CH2CH2CH3
  2. CH3CH2CHCHCH2CH3 cyclohexane

27
Practice Choose the Substance in Each Pair with
the Highest Boiling Point
both molecules are nonpolar larger molar mass
  1. CH4 CH3CH2CH2CH3
  2. CH3CH2CHCHCH2CH3 cyclohexane

both molecules are nonpolar flat molecule larger
surface-to-surface contact
28
Dipole-Dipole Attractions
  • polar molecules have a permanent dipole
  • because of bond polarity and shape
  • dipole moment
  • as well as the always present induced dipole
  • the permanent dipole adds to the attractive
    forces between the molecules
  • raising the boiling and melting points relative
    to nonpolar molecules of similar size and shape

29
Effect of Dipole-Dipole Attraction on Boiling and
Melting Points
30
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31
Practice Choose the Substance in Each Pair with
the Highest Boiling Point
  1. CH2FCH2F CH3CHF2

b)
32
Practice Choose the Substance in Each Pair with
the Highest Boiling Point
  1. CH2FCH2F CH3CHF2

more polar
b)
polar
nonpolar
33
Attractive Forces and Solubility
  • Solubility depends on the attractive forces of
    solute and solvent molecules
  • Like dissolves Like
  • miscible liquids will always dissolve in each
    other
  • polar substance dissolve in polar solvents
  • hydrophilic groups OH, CHO, CO, COOH, NH2, Cl
  • nonpolar molecules dissolve in nonpolar solvents
  • hydrophobic groups C-H, C-C
  • Many molecules have both hydrophilic and
    hydrophobic parts - solubility becomes
    competition between parts

34
Immiscible Liquids
35
Polar Solvents
36
Nonpolar Solvents
n-hexane
toluene
carbon tetrachloride
37
Hydrogen Bonding
  • When a very electronegative atom is bonded to
    hydrogen, it strongly pulls the bonding electrons
    toward it
  • O-H, N-H, or F-H
  • Since hydrogen has no other electrons, when it
    loses the electrons, the nucleus becomes
    deshielded
  • exposing the H proton
  • The exposed proton acts as a very strong center
    of positive charge, attracting all the electron
    clouds from neighboring molecules

38
H-Bonding
HF
39
H-Bonding in Water
40
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41
Practice Choose the substance in each pair that
is a liquid at room temperature (the other is a
gas)
  1. CH3OH CH3CHF2
  2. CH3-O-CH2CH3 CH3CH2CH2NH2

42
Practice Choose the substance in each pair that
is a liquid at room temperature (the other is a
gas)
  1. CH3OH CH3CHF2
  2. CH3-O-CH2CH3 CH3CH2CH2NH2

can H-bond
can H-bond
43
Practice Choose the substance in each pair that
is more soluble in water
  1. CH3OH CH3CHF2
  2. CH3CH2CH2CH3 CH3Cl

44
Practice Choose the substance in each pair that
is more soluble in water
  1. CH3OH CH3CHF2
  2. CH3CH2CH2CH3 CH3Cl

can H-bond with H2O
more polar
45
Ion-Dipole Attraction
  • in a mixture, ions from an ionic compound are
    attracted to the dipole of polar molecules
  • the strength of the ion-dipole attraction is one
    of the main factors that determines the
    solubility of ionic compounds in water

46
Summary
  • Dispersion forces are the weakest of the
    intermolecular attractions.
  • Dispersion forces are present in all molecules
    and atoms.
  • The magnitude of the dispersion forces increases
    with molar mass
  • Polar molecules also have dipole-dipole
    attractive forces

47
Summary (contd)
  • Hydrogen bonds are the strongest of the
    intermolecular attractive forces
  • a pure substance can have
  • Hydrogen bonds will be present when a molecule
    has H directly bonded to either O , N, or F atoms
  • only example of H bonded to F is HF
  • Ion-dipole attractions are present in mixtures of
    ionic compounds with polar molecules.
  • Ion-dipole attractions are the strongest
    intermolecular attraction
  • Ion-dipole attractions are especially important
    in aqueous solutions of ionic compounds

48
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49
Liquids
  • properties
  • structure

50
Surface Tension
  • surface tension is a property of liquids that
    results from the tendency of liquids to minimize
    their surface area
  • in order to minimize their surface area, liquids
    form drops that are spherical
  • as long as there is no gravity
  • the layer of molecules on the surface behave
    differently than the interior
  • because the cohesive forces on the surface
    molecules have a net pull into the liquid
    interior
  • the surface layer acts like an elastic skin

51
Surface Tension
  • because they have fewer neighbors to attract
    them, the surface molecules are less stable than
    those in the interior
  • have a higher potential energy
  • the surface tension of a liquid is the energy
    required to increase the surface area a given
    amount
  • at room temp, surface tension of H2O 72.8 mJ/m2

52
Factors Affecting Surface Tension
  • the stronger the intermolecular attractive
    forces, the higher the surface tension will be
  • raising the temperature of a liquid reduces its
    surface tension
  • raising the temperature of the liquid increases
    the average kinetic energy of the molecules
  • the increased molecular motion makes it easier to
    stretch the surface

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54
Viscosity
  • viscosity is the resistance of a liquid to flow
  • 1 poise 1 P 1 g/cms
  • often given in centipoise, cP
  • larger intermolecular attractions larger
    viscosity
  • higher temperature lower viscosity

55
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56
Capillary Action
  • capillary action is the ability of a liquid to
    flow up a thin tube against the influence of
    gravity
  • the narrower the tube, the higher the liquid
    rises
  • capillary action is the result of the two forces
    working in conjunction, the cohesive and adhesive
    forces
  • cohesive forces attract the molecules together
  • adhesive forces attract the molecules on the edge
    to the tubes surface

57
Capillary Action
  • the adhesive forces pull the surface liquid up
    the side of the tube, while the cohesive forces
    pull the interior liquid with it
  • the liquid rises up the tube until the force of
    gravity counteracts the capillary action forces

58
Meniscus
  • the curving of the liquid surface in a thin tube
    is due to the competition between adhesive and
    cohesive forces
  • the meniscus of water is concave in a glass tube
    because its adhesion to the glass is stronger
    than its cohesion for itself
  • the meniscus of mercury is convex in a glass tube
    because its cohesion for itself is stronger than
    its adhesion for the glass
  • metallic bonds stronger than intermolecular
    attractions

59
Vaporization
  • molecules in the liquid are constantly in motion
  • the average kinetic energy is proportional to the
    temperature
  • however, some molecules have more kinetic energy
    than the average
  • if these molecules are at the surface, they may
    have enough energy to overcome the attractive
    forces
  • therefore the larger the surface area, the
    faster the rate of evaporation
  • this will allow them to escape the liquid and
    become a vapor

60
Distribution of Thermal Energy
  • only a small fraction of the molecules in a
    liquid have enough energy to escape
  • but, as the temperature increases, the fraction
    of the molecules with escape energy increases
  • the higher the temperature, the faster the rate
    of evaporation

61
Condensation
  • some molecules of the vapor will lose energy
    through molecular collisions
  • the result will be that some of the molecules
    will get captured back into the liquid when they
    collide with it
  • also some may stick and gather together to form
    droplets of liquid
  • particularly on surrounding surfaces
  • we call this process condensation

62
Evaporation vs. Condensation
  • vaporization and condensation are opposite
    processes
  • in an open container, the vapor molecules
    generally spread out faster than they can
    condense
  • the net result is that the rate of vaporization
    is greater than the rate of condensation, and
    there is a net loss of liquid
  • however, in a closed container, the vapor is not
    allowed to spread out indefinitely
  • the net result in a closed container is that at
    some time the rates of vaporization and
    condensation will be equal

63
Effect of Intermolecular Attraction on
Evaporation and Condensation
  • the weaker the attractive forces between
    molecules, the less energy they will need to
    vaporize
  • also, weaker attractive forces means that more
    energy will need to be removed from the vapor
    molecules before they can condense
  • the net result will be more molecules in the
    vapor phase, and a liquid that evaporates faster
    the weaker the attractive forces, the faster
    the rate of evaporation
  • liquids that evaporate easily are said to be
    volatile
  • e.g., gasoline, fingernail polish remover
  • liquids that do not evaporate easily are called
    nonvolatile
  • e.g., motor oil

64
Energetics of Vaporization
  • when the high energy molecules are lost from the
    liquid, it lowers the average kinetic energy
  • if energy is not drawn back into the liquid, its
    temperature will decrease therefore,
    vaporization is an endothermic process
  • and condensation is an exothermic process
  • vaporization requires input of energy to overcome
    the attractions between molecules

65
Heat of Vaporization
  • the amount of heat energy required to vaporize
    one mole of the liquid is called the Heat of
    Vaporization, DHvap
  • sometimes called the enthalpy of vaporization
  • always endothermic, therefore DHvap is
  • somewhat temperature dependent
  • DHcondensation -DHvaporization

66
Example 11.3 Calculate the mass of water that
can be vaporized with 155 kJ of heat at 100C
155 kJ g H2O
Given Find
1 mol H2O 40.7 kJ, 1 mol 18.02 g
Concept Plan Relationships
Solution
since the given amount of heat is almost 4x the
DHvap, the amount of water makes sense
Check
67
Dynamic Equilibrium
  • in a closed container, once the rates of
    vaporization and condensation are equal, the
    total amount of vapor and liquid will not change
  • evaporation and condensation are still occurring,
    but because they are opposite processes, there is
    no net gain or loss or either vapor or liquid
  • when two opposite processes reach the same rate
    so that there is no gain or loss of material, we
    call it a dynamic equilibrium
  • this does not mean there are equal amounts of
    vapor and liquid it means that they are
    changing by equal amounts

68
Dynamic Equilibrium
69
Vapor Pressure
  • the pressure exerted by the vapor when it is in
    dynamic equilibrium with its liquid is called the
    vapor pressure
  • remember using Daltons Law of Partial Pressures
    to account for the pressure of the water vapor
    when collecting gases by water displacement?
  • the weaker the attractive forces between the
    molecules, the more molecules will be in the
    vapor
  • therefore, the weaker the attractive forces, the
    higher the vapor pressure
  • the higher the vapor pressure, the more volatile
    the liquid

70
Vapor-Liquid Dynamic Equilibrium
  • if the volume of the chamber is increased, that
    will decrease the pressure of the vapor inside
  • at that point, there are fewer vapor molecules in
    a given volume, causing the rate of condensation
    to slow
  • eventually enough liquid evaporates so that the
    rates of the condensation increases to the point
    where it is once again as fast as evaporation
  • equilibrium is reestablished
  • at this point, the vapor pressure will be the
    same as it was before

71
Dynamic Equilibrium
  • a system in dynamic equilibrium can respond to
    changes in the conditions
  • when conditions change, the system shifts its
    position to relieve or reduce the effects of the
    change

72
Vapor Pressure vs. Temperature
  • increasing the temperature increases the number
    of molecules able to escape the liquid
  • the net result is that as the temperature
    increases, the vapor pressure increases
  • small changes in temperature can make big changes
    in vapor pressure
  • the rate of growth depends on strength of the
    intermolecular forces

73
Vapor Pressure Curves
74
Boiling Point
  • when the temperature of a liquid reaches a point
    where its vapor pressure is the same as the
    external pressure, vapor bubbles can form
    anywhere in the liquid
  • not just on the surface
  • this phenomenon is what is called boiling and the
    temperature required to have the vapor pressure
    external pressure is the boiling point

75
Boiling Point
  • the normal boiling point is the temperature at
    which the vapor pressure of the liquid 1 atm
  • the lower the external pressure, the lower the
    boiling point of the liquid

76
Heating Curve of a Liquid
  • as you heat a liquid, its temperature increases
    linearly until it reaches the boiling point
  • q mass x Cs x DT
  • once the temperature reaches the boiling point,
    all the added heat goes into boiling the liquid
    the temperature stays constant
  • once all the liquid has been turned into gas, the
    temperature can again start to rise

77
Clausius-Clapeyron Equation
  • the graph of vapor pressure vs. temperature is an
    exponential growth curve
  • the logarithm of the vapor pressure vs.
  • inverse absolute temperature is a linear
    function
  • the slope of the line x 8.314 J/molK DHvap
  • in J/mol

78
Example 11.4 Determine the DHvap of
dichloromethane given the vapor pressure vs.
temperature data
  • enter the data into a spreadsheet and calculate
    the inverse of the absolute temperature and
    natural log of the vapor pressure

Temperature, K Vapor Pressure, torr Inverse Temperature, K-1 ln(Vapor Pressure)
200 0.8 0.00500 -0.2
220 4.5 0.00455 1.5
240 21 0.00417 3.0
260 71 0.00385 4.3
280 197 0.00357 5.3
300 391 0.00333 6.0
79
Example 11.4 Determine the DHvap of
dichloromethane given the vapor pressure vs.
temperature data
  • graph the inverse of the absolute temperature vs.
    the natural log of the vapor pressure

80
Example 11.4 Determine the DHvap of
dichloromethane given the vapor pressure vs.
temperature data
  • add a trendline, making sure the display equation
    on chart option is checked off

81
Example 11.4 Determine the DHvap of
dichloromethane given the vapor pressure vs.
temperature data
  • determine the slope of the line
  • -3776.7 3800 K

82
Example 11.4 Determine the DHvap of
dichloromethane given the vapor pressure vs.
temperature data
  • use the slope of the line to determine the heat
    of vaporization
  • -3776.7 3800 K

83
Clausius-Clapeyron Equation2-Point Form
  • the equation below can be used with just two
    measurements of vapor pressure and temperature
  • however, it generally gives less accurate results
  • fewer data points will not give as accurate an
    average because there is less averaging out of
    the errors
  • as with any other sets of measurements
  • can also be used to predict the vapor pressure if
    you know the heat of vaporization and the normal
    boiling point
  • remember the vapor pressure at the normal
    boiling point is 760 torr

84
Example 11.5 Calculate the vapor pressure of
methanol at 12.0C
T1 BP 64.6C, P1 760 torr, DHvap 35.2
kJ/mol, T2 12.0C P2, torr
Given Find
T1 BP 337.8 K, P1 760 torr, DHvap 35.2
kJ/mol, T2 285.2 K P2, torr
Concept Plan Relationships
T(K) T(C) 273.15
Solution
Check
the units are correct, the size makes sense since
the vapor pressure is lower at lower temperatures
85
Supercritical Fluid
  • as a liquid is heated in a sealed container, more
    vapor collects causing the pressure inside the
    container to rise
  • and the density of the vapor to increase
  • and the density of the liquid to decrease
  • at some temperature, the meniscus between the
    liquid and vapor disappears and the states
    commingle to form a supercritical fluid
  • supercritical fluid have properties of both gas
    and liquid states

86
The Critical Point
  • the temperature required to produce a
    supercritical fluid is called the critical
    temperature
  • the pressure at the critical temperature is
    called the critical pressure
  • at the critical temperature or higher
    temperatures, the gas cannot be condensed to a
    liquid, no matter how high the pressure gets

87
Sublimation and Deposition
  • molecules in the solid have thermal energy that
    allows them to vibrate
  • surface molecules with sufficient energy may
    break free from the surface and become a gas
    this process is called sublimation
  • the capturing of vapor molecules into a solid is
    called deposition
  • the solid and vapor phases exist in dynamic
    equilibrium in a closed container
  • at temperatures below the melting point
  • therefore, molecular solids have a vapor pressure

sublimation
solid gas
88
Sublimation
89
Melting Fusion
  • as a solid is heated, its temperature rises and
    the molecules vibrate more vigorously
  • once the temperature reaches the melting point,
    the molecules have sufficient energy to overcome
    some of the attractions that hold them in
    position and the solid melts (or fuses)
  • the opposite of melting is freezing

90
Heating Curve of a Solid
  • as you heat a solid, its temperature increases
    linearly until it reaches the melting point
  • q mass x Cs x DT
  • once the temperature reaches the melting point,
    all the added heat goes into melting the solid
    the temperature stays constant
  • once all the solid has been turned into liquid,
    the temperature can again start to rise
  • ice/water will always have a temperature of 0C
  • at 1 atm

91
Energetics of Melting
  • when the high energy molecules are lost from the
    solid, it lowers the average kinetic energy
  • if energy is not drawn back into the solid its
    temperature will decrease therefore, melting is
    an endothermic process
  • and freezing is an exothermic process
  • melting requires input of energy to overcome the
    attractions between molecules

92
Heat of Fusion
  • the amount of heat energy required to melt one
    mole of the solid is called the Heat of Fusion,
    DHfus
  • sometimes called the enthalpy of fusion
  • always endothermic, therefore DHfus is
  • somewhat temperature dependent
  • DHcrystallization -DHfusion
  • generally much less than DHvap
  • DHsublimation DHfusion DHvaporization

93
Heats of Fusion and Vaporization
94
Heating Curve of Water
95
Segment 1
  • heating 1.00 mole of ice at -25.0C up to the
    melting point, 0.0C
  • q mass x Cs x DT
  • mass of 1.00 mole of ice 18.0 g
  • Cs 2.09 J/molC

96
Segment 2
  • melting 1.00 mole of ice at the melting point,
    0.0C
  • q nDHfus
  • n 1.00 mole of ice
  • DHfus 6.02 kJ/mol

97
Segment 3
  • heating 1.00 mole of water at 0.0C up to the
    boiling point, 100.0C
  • q mass x Cs x DT
  • mass of 1.00 mole of water 18.0 g
  • Cs 2.09 J/molC

98
Segment 4
  • boiling 1.00 mole of water at the boiling point,
    100.0C
  • q nDHvap
  • n 1.00 mole of ice
  • DHfus 40.7 kJ/mol

99
Segment 5
  • heating 1.00 mole of steam at 100.0C up to
    125.0C
  • q mass x Cs x DT
  • mass of 1.00 mole of water 18.0 g
  • Cs 2.01 J/molC

100
Phase Diagrams
  • describe the different states and state changes
    that occur at various temperature - pressure
    conditions
  • areas represent states
  • lines represent state changes
  • liquid/gas line is vapor pressure curve
  • both states exist simultaneously
  • critical point is the furthest point on the vapor
    pressure curve
  • triple point is the temperature/pressure
    condition where all three states exist
    simultaneously
  • for most substances, freezing point increases as
    pressure increases

101
Phase Diagrams
Liquid
Solid
Pressure
normal boiling pt.
normal melting pt.
Gas
Temperature
102
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103
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104
Phase Diagram of Water
105
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106
Morphic Forms of Ice
107
Phase Diagram of CO2
108
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109
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110
Water An Extraordinary Substance
  • water is a liquid at room temperature
  • most molecular substances with small molar masses
    are gases at room temperature
  • due to H-bonding between molecules
  • water is an excellent solvent dissolving many
    ionic and polar molecular substances
  • because of its large dipole moment
  • even many small nonpolar molecules have
    solubility in water
  • e.g., O2, CO2
  • water has a very high specific heat for a
    molecular substance
  • moderating effect on coastal climates
  • water expands when it freezes
  • at a pressure of 1 atm
  • about 9
  • making ice less dense than liquid water

111
Solids
  • properties
  • structure

112
Determining Crystal Structure
  • crystalline solids have a very regular geometric
    arrangement of their particles
  • the arrangement of the particles and distances
    between them is determined by x-ray diffraction
  • in this technique, a crystal is struck by beams
    of x-rays, which then are reflected
  • the wavelength is adjusted to result in an
    interference pattern at which point the
    wavelength is an integral multiple of the
    distances between the particles

113
X-ray Crystallography
114
Braggs Law
  • when the interference between x-rays is
    constructive, the distance between the two paths
    (a) is an integral multiple of the wavelength
  • nl2a
  • the angle of reflection is therefore related to
    the distance (d) between two layers of particles
  • sinq a/d
  • combining equations and rearranging we get an
    equation called Braggs Law

115
Example 11.6 An x-ray beam at l154 pm striking
an iron crystal results in the angle of
reflection q 32.6. Assuming n 1, calculate
the distance between layers
n 1, q 32.6, l 154 pm d, pm
Given Find
Concept Plan Relationships
Solution
Check
the units are correct, the size makes sense since
the iron atom has an atomic radius of 140 pm
116
Crystal Lattice
  • when allowed to cool slowly, the particles in a
    liquid will arrange themselves to give the
    maximum attractive forces
  • therefore minimize the energy
  • the result will generally be a crystalline solid
  • the arrangement of the particles in a crystalline
    solid is called the crystal lattice
  • the smallest unit that shows the pattern of
    arrangement for all the particles is called the
    unit cell

117
Unit Cells
  • unit cells are 3-dimensional,
  • usually containing 2 or 3 layers of particles
  • unit cells are repeated over and over to give the
    macroscopic crystal structure of the solid
  • starting anywhere within the crystal results in
    the same unit cell
  • each particle in the unit cell is called a
    lattice point
  • lattice planes are planes connecting equivalent
    points in unit cells throughout the lattice

118
7 Unit Cells
c
b
a
Rhombohedral a b c no 90
119
Unit Cells
  • the number of other particles each particle is in
    contact with is called its coordination number
  • for ions, it is the number of oppositely charged
    ions an ion is in contact with
  • higher coordination number means more
    interaction, therefore stronger attractive forces
    holding the crystal together
  • the packing efficiency is the percentage of
    volume in the unit cell occupied by particles
  • the higher the coordination number, the more
    efficiently the particles are packing together

120
Cubic Unit Cells
  • all 90 angles between corners of the unit cell
  • the length of all the edges are equal
  • if the unit cell is made of spherical particles
  • ? of each corner particle is within the cube
  • ½ of each particle on a face is within the cube
  • ¼ of each particle on an edge is within the cube

121
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122
Simple Cubic
123
Cubic Unit Cells - Simple Cubic
  • 8 particles, one at each corner of a cube
  • 1/8th of each particle lies in the unit cell
  • each particle part of 8 cells
  • 1 particle in each unit cell
  • 8 corners x 1/8
  • edge of unit cell twice the radius
  • coordination number of 6

2r
124
Body-Centered Cubic
125
Cubic Unit Cells - Body-Centered Cubic
  • 9 particles, one at each corner of a cube one
    in center
  • 1/8th of each corner particle lies in the unit
    cell
  • 2 particles in each unit cell
  • 8 corners x 1/8 1 center
  • edge of unit cell (4/Ö 3) times the radius of
    the particle
  • coordination number of 8

126
Face-Centered Cubic
127
Cubic Unit Cells - Face-Centered Cubic
  • 14 particles, one at each corner of a cube one
    in center of each face
  • 1/8th of each corner particle 1/2 of face
    particle lies in the unit cell
  • 4 particles in each unit cell
  • 8 corners x 1/8 6 faces x 1/2
  • edge of unit cell 2Ö 2 times the radius of the
    particle
  • coordination number of 12

128
Example 11.7 Calculate the density of Al if it
crystallizes in a fcc and has a radius of 143 pm
face-centered cubic, r 143 pm density, g/cm3
Given Find
face-centered cubic, r 1.43 x 10-8 cm, m
1.792 x 10-22 g density, g/cm3
Concept Plan Relation-ships
atoms x mass 1 atom
l 2rv2
V l3
d m/V
1 cm 102 m, 1 pm 10-12 m
V l3, l 2rv2, d m/V
fcc 4 atoms/uc, Al 26.982 g/mol, 1 mol
6.022 x 1023 atoms
Solution
the accepted density of Al at 20C is 2.71 g/cm3,
so the answer makes sense
Check
129
Closest-Packed StructuresFirst Layer
  • with spheres, it is more efficient to offset each
    row in the gaps of the previous row than to
    line-up rows and columns

130
Closest-Packed StructuresSecond Layer
  • the second layer atoms can sit directly over the
    atoms in the first called an AA pattern

or the second layer can sit over the holes in
the first called an AB pattern
131
Closest-Packed StructuresThird Layer with
Offset 2nd Layer
  • the third layer atoms can align directly over the
    atoms in the first called an ABA pattern

or the third layer can sit over the uncovered
holes in the first called an ABC pattern
Cubic Closest-Packed Face-Centered Cubic
Hexagonal Closest-Packed
132
Hexagonal Closest-Packed Structures
133
Cubic Closest-Packed Structures
134
Classifying Crystalline Solids
  • classified by the kinds of units found
  • sub-classified by the kinds of attractive forces
    holding the units together
  • molecular solids are solids whose composite units
    are molecules
  • ionic solids are solids whose composite units are
    ions
  • atomic solids are solids whose composite units
    are atoms
  • nonbonding atomic solids are held together by
    dispersion forces
  • metallic atomic solids are held together by
    metallic bonds
  • network covalent atomic solids are held together
    by covalent bonds

135
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136
Molecular Solids
  • the lattice site are occupied by molecules
  • the molecules are held together by intermolecular
    attractive forces
  • dispersion forces, dipole attractions, and
    H-bonds
  • because the attractive forces are weak, they tend
    to have low melting point
  • generally lt 300C

137
Ionic SolidsAttractive Forces
  • held together by attractions between opposite
    charges
  • nondirectional
  • therefore every cation attracts all anions around
    it, and vice versa
  • the coordination number represents the number of
    close cation-anion interactions in the crystal
  • the higher the coordination number, the more
    stable the solid
  • lowers the potential energy of the solid
  • the coordination number depends on the relative
    sizes of the cations and anions
  • generally, anions are larger than cations
  • the number of anions that can surround the cation
    limited by the size of the cation
  • the closer in size the ions are, the higher the
    coordination number is

138
Ionic Crystals
CsCl coordination number 8 Cs 167 pm Cl-
181 pm
NaCl coordination number 6 Na 97 pm Cl-
181 pm
139
Lattice Holes
Tetrahedral Hole
Octahedral Hole
Simple Cubic Hole
140
Lattice Holes
  • in hexagonal closest packed or cubic closest
    packed lattices there are 8 tetrahedral holes and
    4 octahedral holes per unit cell
  • in simple cubic there is 1 hole per unit cell
  • number and type of holes occupied determines
    formula (empirical) of salt

Octahedral
Tetrahedral
141
Cesium Chloride Structures
  • coordination number 8
  • ? of each Cl- (184 pm) inside the unit cell
  • whole Cs (167 pm) inside the unit cell
  • cubic hole hole in simple cubic arrangement of
    Cl- ions
  • CsCl 1 (8 x ?), therefore the formula is CsCl

142
Rock Salt Structures
  • coordination number 6
  • Cl- ions (181 pm) in a face-centered cubic
    arrangement
  • ? of each corner Cl- inside the unit cell
  • ½ of each face Cl- inside the unit cell
  • each Na (97 pm) in holes between Cl-
  • octahedral holes
  • 1 in center of unit cell
  • ¼ of each edge Na inside the unit cell
  • NaCl (¼ x 12) 1 (? x 8) (½ x 6) 44
    11,
  • therefore the formula is NaCl

143
Zinc Blende Structures
  • coordination number 4
  • S2- ions (184 pm) in a face-centered cubic
    arrangement
  • ? of each corner S2- inside the unit cell
  • ½ of each face S2- inside the unit cell
  • each Zn2 (74 pm) in holes between S2-
  • tetrahedral holes
  • 1 whole in ½ the holes
  • ZnS (4 x 1) (? x 8) (½ x 6) 44 11,
  • therefore the formula is ZnS

144
Fluorite Structures
  • coordination number 4
  • Ca2 ions (99 pm) in a face-centered cubic
    arrangement
  • ? of each corner Ca2 inside the unit cell
  • ½ of each face Ca2 inside the unit cell
  • each F- (133 pm) in holes between Ca2
  • tetrahedral holes
  • 1 whole in all the holes
  • CaF (? x 8) (½ x 6) (8 x 1) 48 12,
  • therefore the formula is CaF2
  • fluorite structure common for 12 ratio
  • usually get the antifluorite structure when the
    cationanion ratio is 21
  • the anions occupy the lattice sites and the
    cations occupy the tetrahedral holes

145
Nonbonding Atomic Solids
  • noble gases in solid form
  • solid held together by weak dispersion forces
  • very low melting
  • tend to arrange atoms in closest-packed structure
  • either hexagonal cp or cubic cp
  • maximizes attractive forces and minimizes energy

146
Metallic Atomic Solids
  • solid held together by metallic bonds
  • strength varies with sizes and charges of cations
  • coulombic attractions
  • melting point varies
  • mostly closest packed arrangements of the lattice
    points
  • cations

147
Metallic Structure
148
Metallic Bonding
  • metal atoms release their valence electrons
  • metal cation islands fixed in a sea of mobile
    electrons

e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
e-
149
Crystal Structure of Metals at Room Temperature
other
body-centered cubic
cubic cp, face-centered
hexagonal closest packed
diamond
150
Network Covalent Solids
  • atoms attached to its nearest neighbors by
    covalent bonds
  • because of the directionality of the covalent
    bonds, these do not tend to form closest-packed
    arrangements in the crystal
  • because of the strength of the covalent bonds,
    these have very high melting points
  • generally gt 1000C
  • dimensionality of the network affects other
    physical properties

151
The Diamond Structurea 3-Dimensional Network
  • the carbon atoms in a diamond each have 4
    covalent bonds to surrounding atoms
  • sp3
  • tetrahedral geometry
  • this effectively makes each crystal one giant
    molecule held together by covalent bonds
  • you can follow a path of covalent bonds from any
    atom to every other atom

152
Properties of Diamond
  • very high melting, 3800C
  • need to overcome some covalent bonds
  • very rigid
  • due to the directionality of the covalent bonds
  • very hard
  • due to the strong covalent bonds holding the
    atoms in position
  • used as abrasives
  • electrical insulator
  • thermal conductor
  • best known
  • chemically very nonreactive

153
The Graphite Structurea 2-Dimensional Network
  • in graphite, the carbon atoms in a sheet are
    covalently bonded together
  • forming 6-member flat rings fused together
  • similar to benzene
  • bond length 142 pm
  • sp2
  • each C has 3 sigma and 1 pi bond
  • trigonal-planar geometry
  • each sheet a giant molecule
  • the sheets are then stacked and held together by
    dispersion forces
  • sheets are 341 pm apart

154
Properties of Graphite
  • hexagonal crystals
  • high melting, 3800C
  • need to overcome some covalent bonding
  • slippery feel
  • because there are only dispersion forces holding
    the sheets together, they can slide past each
    other
  • glide planes
  • lubricants
  • electrical conductor
  • parallel to sheets
  • thermal insulator
  • chemically very nonreactive

155
Silicates
  • 90 of earths crust
  • extended arrays of Si?O
  • sometimes with Al substituted for Si
    aluminosilicates
  • glass is the amorphous form

156
Quartz
  • 3-dimensional array of Si covalently bonded to 4
    O
  • tetrahedral
  • melts at 1600C
  • very hard

157
Micas
  • minerals that are mainly 2-dimensional arrays of
    Si bonded to O
  • hexagonal arrangement of atoms
  • sheets
  • chemically stable
  • thermal and electrical insulator

158
Band Theory
  • the structures of metals and covalent network
    solids result in every atoms orbitals being
    shared by the entire structure
  • for large numbers of atoms, this results in a
    large number of molecular orbitals that have
    approximately the same energy, we call this an
    energy band

159
Band Theory
  • when 2 atomic orbitals combine they produce both
    a bonding and an antibonding molecular orbital
  • when many atomic orbitals combine they produce a
    band of bonding molecular orbitals and a band of
    antibonding molecular orbitals
  • the band of bonding molecular orbitals is called
    the valence band
  • the band of antibonding molecular orbitals is
    called the conduction band

160
Molecular orbitals of polylithium
161
Band Gap
  • at absolute zero, all the electrons will occupy
    the valence band
  • as the temperature rises, some of the electrons
    may acquire enough energy to jump to the
    conduction band
  • the difference in energy between the valence band
    and conduction band is called the band gap
  • the larger the band gap, the fewer electrons
    there are with enough energy to make the jump

162
Types of Band Gaps andConductivity
163
Band Gap and Conductivity
  • the more electrons at any one time that a
    substance has in the conduction band, the better
    conductor of electricity it is
  • if the band gap is 0, then the electrons will be
    almost as likely to be in the conduction band as
    the valence band and the material will be a
    conductor
  • metals
  • the conductivity of a metal decreases with
    temperature
  • if the band gap is small, then a significant
    number of the electrons will be in the conduction
    band at normal temperatures and the material will
    be a semiconductor
  • graphite
  • the conductivity of a semiconductor increases
    with temperature
  • if the band gap is large, then effectively no
    electrons will be in the conduction band at
    normal temperatures and the material will be an
    insulator

164
Doping Semiconductors
  • doping is adding impurities to the
    semiconductors crystal to increase its
    conductivity
  • goal is to increase the number of electrons in
    the conduction band
  • n-type semiconductors do not have enough
    electrons themselves to add to the conduction
    band, so they are doped by adding electron rich
    impurities
  • p-type semiconductors are doped with an electron
    deficient impurity, resulting in electron holes
    in the valence band. Electrons can jump between
    these holes in the valence band, allowing
    conduction of electricity

165
Diodes
  • when a p-type semiconductor adjoins an n-type
    semiconductor, the result is an p-n junction
  • electricity can flow across the p-n junction in
    only one direction this is called a diode
  • this also allows the accumulation of electrical
    energy called an amplifier
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