Learn to find permutations and combinations' - PowerPoint PPT Presentation

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Learn to find permutations and combinations'

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... ADB AEB ADC AEC AED BDC BEC BED CED. BAC BAD BAE CAD CAE DAE CBD ... B. If Mary wants to buy 7 books, find the number of different sets of 7 books she can buy. ... – PowerPoint PPT presentation

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Title: Learn to find permutations and combinations'


1
Learn to find permutations and combinations.
2
Vocabulary
factorial permutation combination
3
The factorial of a number is the product of all
the whole numbers from the number down to 1. The
factorial of 0 is defined to be 1.
5! 5 4 3 2 1
4
Additional Example 1A 1B Evaluating
Expressions Containing Factorials
Evaluate each expression.
A. 8!
8 7 6 5 4 3 2 1 40,320
8!
B.
6!
Write out each factorial and simplify.
Multiply remaining factors.
8 7 56
5
Additional Example 1C Evaluating Expressions
Containing Factorials
C.
Subtract within parentheses.
10 9 8 720
6
Try This Example 1A 1B
Evaluate each expression.
A. 10!
10 9 8 7 6 5 4 3 2 1 3,628,800
7!
B.
5!
Write out each factorial and simplify.
Multiply remaining factors.
7 6 42
7
Try This Example 1C
C.
Subtract within parentheses.
9 8 7 504
8
A permutation is an arrangement of things in a
certain order.
If no letter can be used more than once, there
are 6 permutations of the first 3 letters of the
alphabet ABC, ACB, BAC, BCA, CAB, and CBA.
3 choices
2 choices
1 choice


The product can be written as a factorial.
3 2 1 3! 6
9
If no letter can be used more than once, there
are 60 permutations of the first 5 letters of the
alphabet, when taken 3 at a time ABE, ACD, ACE,
ADB, ADC, ADE, and so on.
5 choices
4 choices
3 choices
?
?
60 permutations
Notice that the product can be written as a
quotient of factorials.
60 5 4 3
10
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11
Additional Example 2A Finding Permutations
Jim has 6 different books.
A. Find the number of orders in which the 6 books
can be arranged on a shelf.
6P6
720
There are 720 permutations. This means there are
720 orders in which the 6 books can be arranged
on the shelf.
12
Additional Example 2B Finding Permutations
B. If the shelf has room for only 3 of the books,
find the number of ways 3 of the 6 books can be
arranged.
6 5 4
6P3
120
There are 120 permutations. This means that 3 of
the 6 books can be arranged in 120 ways.
13
Try This Example 2A
There are 7 soup cans in the pantry.
A. Find the number of orders in which all 7 soup
cans can be arranged on a shelf.
7P7
5040
There are 5040 orders in which to arrange 7 soup
cans.
14
Try This Example 2B
There are 7 soup cans in the pantry.
B. If the shelf has only enough room for 4 cans,
find the number of ways 4 of the 7 cans can be
arranged.
7P4
7 6 5 4
840
There are 840 permutations. This means that the 7
cans can be arranged in the 4 spaces in 840 ways.
15
A combination is a selection of things in any
order.
16
If no letter is used more than once, there is
only 1 combination of the first 3 letters of the
alphabet. ABC, ACB, BAC, BCA, CAB, and CBA are
considered to be the same combination of A, B,
and C because the order does not matter.
If no letter is used more than once, there are 10
combinations of the first 5 letters of the
alphabet, when taken 3 at a time. To see this,
look at the list of permutations on the next
slide.
17
ABC ABD ABE ACD ACE ADE BCD BCE BDE CDE ACB ADB AE
B ADC AEC AED BDC BEC BED CED BAC BAD BAE CAD CAE
DAE CBD CBE DBE DCE BCA BDA BEA CDA CEA DEA DBC CE
B DEB DEC CAB DAB EAB DAC EAC EAD DCB EBC EBD ECD
CBA DBA EBA DCA ECA EDA DBC ECB EDB EDC
These 6 permutations are all the same combination.
18
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19
Additional Example 3A Finding Combinations
Mary wants to join a book club that offers a
choice of 10 new books each month. A. If Mary
wants to buy 2 books, find the number of
different pairs she can buy.
10C2

45
There are 45 combinations. This means that Mary
can buy 45 different pairs of books.
20
Additional Example 3B Finding Combinations
B. If Mary wants to buy 7 books, find the number
of different sets of 7 books she can buy.
10C7
120
There are 120 combinations. This means that Mary
can buy 120 different sets of 7 books.
21
Try This Example 3A
Harry wants to join a DVD club that offers a
choice of 12 new DVDs each month. A. If Harry
wants to buy 4 DVDs, find the number of different
sets he can buy.
12C4
495
22
Try This Example 3A Continued
There are 495 combinations. This means that Harry
can buy 495 different sets of 4 DVDs.
23
Try This Example 3B
B. If Harry wants to buy 11 DVDs, find the number
of different sets of 11 DVDs he can buy.
12C11
12
24
Try This Example 3B Continued
There are 12 combinations. This means that Harry
can buy 12 different sets of 11 DVDs.
25
Lesson Quiz
Evaluate each expression. 1. 9! 2. 3. There
are 8 hot air balloons in a race. In how many
possible orders can all 8 hot air balloons finish
the race? 4. A group of 12 people are forming a
committee. How many different 4-person committees
can be formed?
362,880
3024
40,320
495
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