Title: Covalent Bonding Orbitals Adapted from bobcatchemistry
1Covalent Bonding OrbitalsAdapted from
bobcatchemistry
2Hybridization and the Localized Electron Model
3Localized Electron Model
- The arrangement of valence electrons is
represented by the Lewis structure or structures,
and the molecular geometry can be predicted from
the VSEPR model. - Atomic orbitals are used to share electrons and
form bonds
4Hybridization
- In general we assume that bonding involves only
the valence orbitals. - The mixing of atomic orbitals to form special
bonding orbitals is called hybridization. - Carbon is said to undergo sp3 hybridization or is
sp3 hybridized because is uses one s orbital and
three p orbitals to form four identical bonding
orbitals. - The four sp3 orbitals are identical in shape each
one having a large lobe and a small lobe. The
four orbitals are oriented in space so that the
large lobes form a tetrahedral arrangement.
5Hybridization
6Hybridization
7sp3 example Methane
8sp3 example Ammonia
9sp2 Hybridization
10sp2 Hybridization
11sp2 Hybridization
- Ethylene (C2H4) is commonly used in plastics and
has a CC double bond. Each carbon uses sp2
hybridization in this molecule because a double
bond acts as one effective pair. - In forming the sp2 orbitals, one 2p orbital on
carbon has not been used. This remaining p
orbital is oriented perpendicular to the plane of
the sp2 orbitals. - The double bond utilizes one sigma bond that is
hybridized and one pi bond with the unhybridized
p orbital.
12sp2 Hybridization
13sp2 Hybridization Ethylene
14Multiple Bonds
- Single bonds are sigma bonds (s) and the electron
pair is shared in an area centered on a line
running between the atoms. These are hybridized
bonding orbitals. - With multiple bonds, a sigma bond is formed and
then one or two pi bond (p) form. These
electrons occupy the space above and below the
sigma bond and use unhybridized orbitals.
15sp2 Hybridization Ethylene
16sp Hybridization
- sp hybridization involves one s orbital and one p
orbital. Two effective pairs will always require
sp hybridization. - CO2 is sp hybridized
17sp Hybridization
18sp Hybridization CO2
19sp Hybridization CO2
20sp Hybridization CO2
21sp Hybridization N2
22sp3d Hybridization
- When a molecule exceeds the octet rule,
hybridization occurs using d orbitals. Also
called dsp3. - PCl5 has sp3d hybridization and is trigonal
bipyramidal.
23sp3d Hybridization PCl5
- Each chlorine atom displays a tetrahedral
arrangement around the atom.
24sp3d2 Hybridization
- An octahedral arrangement requires six effective
pairs around the central atom. - SF6 has sp3d2 hybridization.
25Example Problem
- How is the xenon atom in XeF4 hybridized?
sp3d2
26Localized Electron Summary
- Draw the Lewis Structure
- Determine the arrangement of electron pairs using
the VSEPR model. - Specify the hybrid orbitals needed to accommodate
the electron pairs. - Do not overemphasize the characteristics of the
separate atoms. It is not where the valence
electrons originate that is important it is
where they are needed in the molecule to achieve
stability.
27Effective Pairs and Their Spatial Arrangement
28The Molecular Orbital Model
29Molecular Orbital Model
- The localized electron model works very well with
the prediction of structure and bonding of
molecules, but the electron correlation problem
still exists. - Since we do not know the details of the electron
movements, we cannot deal with the
electron-electron interactions in a specific way - The Molecular Orbital model helps us to deal with
the molecular problem.
30Molecular Orbitals
- Molecular orbitals (MOs) have many of the same
characteristics as atomic orbitals. Two of the
most important are - MOs can hold two electrons with opposite spins.
- The square of the MOs wave function indicates
electron probability.
31MOs
- For simplicity we will first look at the H2
molecule. - The combination of hydrogen 1s atomic orbitals
results in 2 molecular orbitals. - The wave phases of the atomic orbitals
combine/overlap. Since electrons move in wave
functions, this causes constructive and
destructive interference in the wave pattern. - When the orbitals are added, the matching phases
produce constructive interference and the
opposite phases produce destructive interference.
32MOs
- A constructive combination gives a bonding MO.
This gives an enhanced electron probability
between the nuclei. - The destructive combination gives an antibonding
MO. This interference produces a node between
the nuclei.
33MOs
- Two MOs exist for H2
- MO1 1sH1 1sH2
- MO1 is constructive and therefore a bonding MO
- MO1 is lower energy
- MO2 1sH1 1sH2
- MO2 is destructive and therefore an antibonding
MO - MO2 is higher energy
34MOs
- The type of electron distribution described in
these MOs is called sigma as in the localized
electron model. MO1 and MO2 are sigma (s)
molecular orbitals. - In this molecule only the molecular orbitals are
available for occupation by electrons. The 1s
atomic orbitals of the hydrogen atoms no longer
exist, because the H2 molecule a new entity
has its own set of new orbitals.
35MOs
- The energy level of the bonding MO is lower and
more stable than that of the antibonding MO.
Since molecule formation favors the lowest energy
state, this provides the driving force for
molecule formation of H2. This is called
probonding. - If two electrons were forced to occupy the
higher-energy MO2 this would be anti-bonding and
the lower energy of the separated atoms would be
favored.
36Bonding and Antibonding
37MOs
- Labels are given to MOs indicate their symmetry
(shape), the parent atomic orbitals, and whether
they are bonding or antibonding. - Antibonding character is indicated by an
asterisk. - Subscripts indicate parent orbitals
- s and p indicate shape.
- H2 has the following MOs
- MO1 s1s
- MO2 s1s
38MOs
- Molecular electron configurations can be written
in much the same way as atomic (electron)
configurations. Since the H2 molecule has two
electrons in the s1s molecular orbital, the
electron configuration is s1s2 - Each molecular orbital can hold two electrons,
but the spins must be opposite. - Orbitals are conserved. The number of molecular
orbitals will always be the same as the number of
atomic orbitals used to construct them.
39MOs
- From this molecular electron configuration, we
can determine a molecules stability. - Would H2- be stable?
- (s1s )2 ( s1s) 1
- The key idea is that H2- would exist if it were
a lower energy than its separated parts. Two
electrons are in bonding and one is in
antibonding. Since more electrons favor bonding
H2- is formed. - This also is a good indicator of bond strength.
H2 has a stronger bond than H2-. The net
lowering of the bonding electrons by one is a
direct relationship to bond strength. H2 is
twice as strong.
40Bond Order
- To indicate bond strength, we use the concept of
bond order. - Example H2 has a bond order of 1
- H2- has a bond order of ½
41Bond Order
- Bond order is an indication of bond strength
because it reflects the difference between the
number of bonding electrons and the number of
antibonding electrons. - Larger bond order means greater bond strength.
- Bond order of 0 gives us a molecule that doesnt
exist.
42Bonding in Homonuclear Diatomic Molecules
43Homonuclear Bonding
- When looking at bonding beyond energy level 1, we
need to consider what orbitals are overlapping
and therefore bonding. - Li2 has electrons in the 1s and 2s orbitals the
2s orbitals are much larger and overlap, but the
1s orbitals are smaller and do not overlap. - To participate in molecular orbitals, atomic
orbitals must overlap in space. This means that
only the valence orbitals of the atoms contribute
significantly to the molecular orbitals of a
particular molecule.
44Li2 MO
- What is the molecular electron configuration and
bond order of Li2? - s2s2 with a bond order of 1
- Li2 is a stable molecule because the overall
energy of the molecule is lower than the separate
atoms.
45Be2 MO
- What is the molecular electron configuration and
bond order of Be2? - (s2s)2 (s2s)2 with a bond order of 0
- Be2 has 2 bonding and 2 antibonding electrons and
is not more stable than the individual atoms.
Be2 does not form.
46MOs from p orbitals
- p orbitals must overlap in such a way that the
wave patterns produce constructive interference.
As with the s orbitals, the destructive
interference produces a node in the wave pattern
and decreases the probability of bonding.
47MOs from p orbitals
- When the parallel p orbitals are combined with
the positive and negative phases matched,
constructive interference occurs, giving a
bonding p orbital. When orbitals have opposite
phases, destructive interference results in an
antibonding p orbital.
48MOs from p orbitals
- Since the electron probability lies above and
below the line between the nuclei (with parallel
p orbitals), the stability of a p molecular
bonding orbital is less than that of a s bonding
orbital. Also, the antibonding p MO is not as
unstable as the antibonding s MO. The energies
associated with the orbitals reflect this
stability.
49B2 Example
- 1s2 2s2 2p1
- 1s2 does not bond
- 2s2 and 2p1 bond
- (s2s)2 (s2s)2 (s2p)2
- Bond order 1
50Exceptions
- B2, C2, and N2 molecules use the same set of
molecular orbitals that we expect but some mixing
of orbital energies occurs. The s and p atomic
orbitals mix or hybridize in a way that changes
some MO energy states. This affects filling
order and pairing of electrons.
51Paramagnetism
- Most materials have no magnetism until they are
placed in a magnetic field. However, in the
presence of such a field, magnetism of two types
can be induced - Paramagnetism causes the substance to be
attracted into the magnetic field. - Diamagnetism causes the substance to be
repelled from the magnetic field.
52Paramagnetism
53Paramagnetism
- Paramagnetism is associated with unpaired
electrons and diamagnetism is associated with
paired electrons. - Any substance that has both paired and unpaired
electrons will exhibit a net paramagnetism since
the effect of paramagnetism is much stronger than
that of diamagnetism. - Paramagnetism Video
54Summary
- There are definite correlations between bond
order, bond energy, and bond length. As bond
order increases so does bond energy and bond
length decreases. - Comparison of bond orders between different
molecules cannot predict bond energies of
different molecules. - B2 and F2 both have bond order of 1 but bond
energies are very different. B-B is a much
stronger bond. - N2 has a bond order of 3 and has a very large
bond energy. N2 is a very stable molecule and is
used to drive powerful reactions.
55(No Transcript)
56Example Problem
- For O2, O2, and O2-, give the MO electron
configuration and the bond order for each. Which
has the strongest bond? - O2 (s2s)2 (s2s)2 (s2p)2 (p2p)4 (p2p)2
BO2 - O2 (s2s)2 (s2s)2 (s2p)2 (p2p)4 (p2p)1
BO2.5 - O2- (s2s)2 (s2s)2 (s2p)2 (p2p)4 (p2p)3
BO1.5
B2 C2 N2 B2 C2 N2 B2 C2 N2 O2 F2 O2 F2 O2 F2
s2p s2p
p2p p2p
s2p p2p
p2p s2p
s2s s2s
s2s s2s
s1s s1s
s1s s1s
57Example Problem
- Use the molecular orbital model to predict the
bond order and magnetism of each of the following
molecules Ne2 and P2 - Ne2 bond order is 0 does not exist
- P2 bond order is 3 and diamagnetic
B2 C2 N2 B2 C2 N2 B2 C2 N2 O2 F2 O2 F2 O2 F2
s2p s2p
p2p p2p
s2p p2p
p2p s2p
s2s s2s
s2s s2s
s1s s1s
s1s s1s
58Bonding in Heteronuclear Diatomic Molecules
59Heteronuclear Molecules
- When dealing with different atoms within diatomic
molecules we can still use the MO model to
determine bond order and magnetism
60NO example
- The valence electrons from both atoms fill in the
order expected by the model. - The bond order is 2.5 and is paramagnetic.
61Example Problem
- Use the MO model to predict the magnetism and
bond order of the NO and CN- ions. - Both ions are diamagnetic and have the same
configuration. Their bond order is 3
62Heteronuclear Diatomics
- What happens with the diatomic molecules are very
different? - A molecular orbital forms between two different
atomic orbitals. - HF example
- Note energy level difference vs.
electronegativity
63Combining the Localized Electron and MO models
64Resonance
- When a molecule has resonance. It is usually a
double bond that can have different positions
around the molecule. - The single s bonds remain localized and the p
bonds are said to be delocalized.
65Resonance
- Benzene All C-C bonds are known to be
equivalent and the molecule has resonance
66Resonance
- Benzene The s bonds remain centered (on the
plane) between C atoms.
67Resonance
- Benzene The p orbitals are perpendicular to the
plane and form p bonds above and below the plane.
The electrons in the p bonds delocalize and give
six equivalent C-C bonds that give the structure
true resonance. - This is called delocalized p bonding.
-
68NO3-
- NO3- ion also displays delocalized p bonding.
69The End
70MO Worksheet
B2 C2 N2 B2 C2 N2 B2 C2 N2 O2 F2 O2 F2 O2 F2
s2p s2p
p2p p2p
s2p p2p
p2p s2p
s2s s2s
s2s s2s
s1s s1s
s1s s1s