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Title: Covalent Bonding Orbitals Adapted from bobcatchemistry


1
Covalent Bonding OrbitalsAdapted from
bobcatchemistry
2
Hybridization and the Localized Electron Model
3
Localized Electron Model
  • The arrangement of valence electrons is
    represented by the Lewis structure or structures,
    and the molecular geometry can be predicted from
    the VSEPR model.
  • Atomic orbitals are used to share electrons and
    form bonds

4
Hybridization
  • In general we assume that bonding involves only
    the valence orbitals.
  • The mixing of atomic orbitals to form special
    bonding orbitals is called hybridization.
  • Carbon is said to undergo sp3 hybridization or is
    sp3 hybridized because is uses one s orbital and
    three p orbitals to form four identical bonding
    orbitals.
  • The four sp3 orbitals are identical in shape each
    one having a large lobe and a small lobe. The
    four orbitals are oriented in space so that the
    large lobes form a tetrahedral arrangement.

5
Hybridization
6
Hybridization
7
sp3 example Methane
8
sp3 example Ammonia
9
sp2 Hybridization
10
sp2 Hybridization
11
sp2 Hybridization
  • Ethylene (C2H4) is commonly used in plastics and
    has a CC double bond. Each carbon uses sp2
    hybridization in this molecule because a double
    bond acts as one effective pair.
  • In forming the sp2 orbitals, one 2p orbital on
    carbon has not been used. This remaining p
    orbital is oriented perpendicular to the plane of
    the sp2 orbitals.
  • The double bond utilizes one sigma bond that is
    hybridized and one pi bond with the unhybridized
    p orbital.

12
sp2 Hybridization
13
sp2 Hybridization Ethylene
14
Multiple Bonds
  • Single bonds are sigma bonds (s) and the electron
    pair is shared in an area centered on a line
    running between the atoms. These are hybridized
    bonding orbitals.
  • With multiple bonds, a sigma bond is formed and
    then one or two pi bond (p) form. These
    electrons occupy the space above and below the
    sigma bond and use unhybridized orbitals.

15
sp2 Hybridization Ethylene
16
sp Hybridization
  • sp hybridization involves one s orbital and one p
    orbital. Two effective pairs will always require
    sp hybridization.
  • CO2 is sp hybridized

17
sp Hybridization
18
sp Hybridization CO2
19
sp Hybridization CO2
20
sp Hybridization CO2
21
sp Hybridization N2
22
sp3d Hybridization
  • When a molecule exceeds the octet rule,
    hybridization occurs using d orbitals. Also
    called dsp3.
  • PCl5 has sp3d hybridization and is trigonal
    bipyramidal.

23
sp3d Hybridization PCl5
  • Each chlorine atom displays a tetrahedral
    arrangement around the atom.

24
sp3d2 Hybridization
  • An octahedral arrangement requires six effective
    pairs around the central atom.
  • SF6 has sp3d2 hybridization.

25
Example Problem
  • How is the xenon atom in XeF4 hybridized?

sp3d2
26
Localized Electron Summary
  • Draw the Lewis Structure
  • Determine the arrangement of electron pairs using
    the VSEPR model.
  • Specify the hybrid orbitals needed to accommodate
    the electron pairs.
  • Do not overemphasize the characteristics of the
    separate atoms. It is not where the valence
    electrons originate that is important it is
    where they are needed in the molecule to achieve
    stability.

27
Effective Pairs and Their Spatial Arrangement
28
The Molecular Orbital Model
29
Molecular Orbital Model
  • The localized electron model works very well with
    the prediction of structure and bonding of
    molecules, but the electron correlation problem
    still exists.
  • Since we do not know the details of the electron
    movements, we cannot deal with the
    electron-electron interactions in a specific way
  • The Molecular Orbital model helps us to deal with
    the molecular problem.

30
Molecular Orbitals
  • Molecular orbitals (MOs) have many of the same
    characteristics as atomic orbitals. Two of the
    most important are
  • MOs can hold two electrons with opposite spins.
  • The square of the MOs wave function indicates
    electron probability.

31
MOs
  • For simplicity we will first look at the H2
    molecule.
  • The combination of hydrogen 1s atomic orbitals
    results in 2 molecular orbitals.
  • The wave phases of the atomic orbitals
    combine/overlap. Since electrons move in wave
    functions, this causes constructive and
    destructive interference in the wave pattern.
  • When the orbitals are added, the matching phases
    produce constructive interference and the
    opposite phases produce destructive interference.

32
MOs
  • A constructive combination gives a bonding MO.
    This gives an enhanced electron probability
    between the nuclei.
  • The destructive combination gives an antibonding
    MO. This interference produces a node between
    the nuclei.

33
MOs
  • Two MOs exist for H2
  • MO1 1sH1 1sH2
  • MO1 is constructive and therefore a bonding MO
  • MO1 is lower energy
  • MO2 1sH1 1sH2
  • MO2 is destructive and therefore an antibonding
    MO
  • MO2 is higher energy

34
MOs
  • The type of electron distribution described in
    these MOs is called sigma as in the localized
    electron model. MO1 and MO2 are sigma (s)
    molecular orbitals.
  • In this molecule only the molecular orbitals are
    available for occupation by electrons. The 1s
    atomic orbitals of the hydrogen atoms no longer
    exist, because the H2 molecule a new entity
    has its own set of new orbitals.

35
MOs
  • The energy level of the bonding MO is lower and
    more stable than that of the antibonding MO.
    Since molecule formation favors the lowest energy
    state, this provides the driving force for
    molecule formation of H2. This is called
    probonding.
  • If two electrons were forced to occupy the
    higher-energy MO2 this would be anti-bonding and
    the lower energy of the separated atoms would be
    favored.

36
Bonding and Antibonding
37
MOs
  • Labels are given to MOs indicate their symmetry
    (shape), the parent atomic orbitals, and whether
    they are bonding or antibonding.
  • Antibonding character is indicated by an
    asterisk.
  • Subscripts indicate parent orbitals
  • s and p indicate shape.
  • H2 has the following MOs
  • MO1 s1s
  • MO2 s1s

38
MOs
  • Molecular electron configurations can be written
    in much the same way as atomic (electron)
    configurations. Since the H2 molecule has two
    electrons in the s1s molecular orbital, the
    electron configuration is s1s2
  • Each molecular orbital can hold two electrons,
    but the spins must be opposite.
  • Orbitals are conserved. The number of molecular
    orbitals will always be the same as the number of
    atomic orbitals used to construct them.

39
MOs
  • From this molecular electron configuration, we
    can determine a molecules stability.
  • Would H2- be stable?
  • (s1s )2 ( s1s) 1
  • The key idea is that H2- would exist if it were
    a lower energy than its separated parts. Two
    electrons are in bonding and one is in
    antibonding. Since more electrons favor bonding
    H2- is formed.
  • This also is a good indicator of bond strength.
    H2 has a stronger bond than H2-. The net
    lowering of the bonding electrons by one is a
    direct relationship to bond strength. H2 is
    twice as strong.

40
Bond Order
  • To indicate bond strength, we use the concept of
    bond order.
  • Example H2 has a bond order of 1
  • H2- has a bond order of ½

41
Bond Order
  • Bond order is an indication of bond strength
    because it reflects the difference between the
    number of bonding electrons and the number of
    antibonding electrons.
  • Larger bond order means greater bond strength.
  • Bond order of 0 gives us a molecule that doesnt
    exist.

42
Bonding in Homonuclear Diatomic Molecules
43
Homonuclear Bonding
  • When looking at bonding beyond energy level 1, we
    need to consider what orbitals are overlapping
    and therefore bonding.
  • Li2 has electrons in the 1s and 2s orbitals the
    2s orbitals are much larger and overlap, but the
    1s orbitals are smaller and do not overlap.
  • To participate in molecular orbitals, atomic
    orbitals must overlap in space. This means that
    only the valence orbitals of the atoms contribute
    significantly to the molecular orbitals of a
    particular molecule.

44
Li2 MO
  • What is the molecular electron configuration and
    bond order of Li2?
  • s2s2 with a bond order of 1
  • Li2 is a stable molecule because the overall
    energy of the molecule is lower than the separate
    atoms.

45
Be2 MO
  • What is the molecular electron configuration and
    bond order of Be2?
  • (s2s)2 (s2s)2 with a bond order of 0
  • Be2 has 2 bonding and 2 antibonding electrons and
    is not more stable than the individual atoms.
    Be2 does not form.

46
MOs from p orbitals
  • p orbitals must overlap in such a way that the
    wave patterns produce constructive interference.
    As with the s orbitals, the destructive
    interference produces a node in the wave pattern
    and decreases the probability of bonding.

47
MOs from p orbitals
  • When the parallel p orbitals are combined with
    the positive and negative phases matched,
    constructive interference occurs, giving a
    bonding p orbital. When orbitals have opposite
    phases, destructive interference results in an
    antibonding p orbital.

48
MOs from p orbitals
  • Since the electron probability lies above and
    below the line between the nuclei (with parallel
    p orbitals), the stability of a p molecular
    bonding orbital is less than that of a s bonding
    orbital. Also, the antibonding p MO is not as
    unstable as the antibonding s MO. The energies
    associated with the orbitals reflect this
    stability.

49
B2 Example
  • 1s2 2s2 2p1
  • 1s2 does not bond
  • 2s2 and 2p1 bond
  • (s2s)2 (s2s)2 (s2p)2
  • Bond order 1

50
Exceptions
  • B2, C2, and N2 molecules use the same set of
    molecular orbitals that we expect but some mixing
    of orbital energies occurs. The s and p atomic
    orbitals mix or hybridize in a way that changes
    some MO energy states. This affects filling
    order and pairing of electrons.

51
Paramagnetism
  • Most materials have no magnetism until they are
    placed in a magnetic field. However, in the
    presence of such a field, magnetism of two types
    can be induced
  • Paramagnetism causes the substance to be
    attracted into the magnetic field.
  • Diamagnetism causes the substance to be
    repelled from the magnetic field.

52
Paramagnetism
53
Paramagnetism
  • Paramagnetism is associated with unpaired
    electrons and diamagnetism is associated with
    paired electrons.
  • Any substance that has both paired and unpaired
    electrons will exhibit a net paramagnetism since
    the effect of paramagnetism is much stronger than
    that of diamagnetism.
  • Paramagnetism Video

54
Summary
  • There are definite correlations between bond
    order, bond energy, and bond length. As bond
    order increases so does bond energy and bond
    length decreases.
  • Comparison of bond orders between different
    molecules cannot predict bond energies of
    different molecules.
  • B2 and F2 both have bond order of 1 but bond
    energies are very different. B-B is a much
    stronger bond.
  • N2 has a bond order of 3 and has a very large
    bond energy. N2 is a very stable molecule and is
    used to drive powerful reactions.

55
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56
Example Problem
  • For O2, O2, and O2-, give the MO electron
    configuration and the bond order for each. Which
    has the strongest bond?
  • O2 (s2s)2 (s2s)2 (s2p)2 (p2p)4 (p2p)2
    BO2
  • O2 (s2s)2 (s2s)2 (s2p)2 (p2p)4 (p2p)1
    BO2.5
  • O2- (s2s)2 (s2s)2 (s2p)2 (p2p)4 (p2p)3
    BO1.5

B2 C2 N2 B2 C2 N2 B2 C2 N2 O2 F2 O2 F2 O2 F2
s2p   s2p  
p2p   p2p  
s2p   p2p  
p2p   s2p  
s2s   s2s  
s2s   s2s  
s1s   s1s  
s1s     s1s    
57
Example Problem
  • Use the molecular orbital model to predict the
    bond order and magnetism of each of the following
    molecules Ne2 and P2
  • Ne2 bond order is 0 does not exist
  • P2 bond order is 3 and diamagnetic

B2 C2 N2 B2 C2 N2 B2 C2 N2 O2 F2 O2 F2 O2 F2
s2p   s2p  
p2p   p2p  
s2p   p2p  
p2p   s2p  
s2s   s2s  
s2s   s2s  
s1s   s1s  
s1s     s1s    
58
Bonding in Heteronuclear Diatomic Molecules
59
Heteronuclear Molecules
  • When dealing with different atoms within diatomic
    molecules we can still use the MO model to
    determine bond order and magnetism

60
NO example
  • The valence electrons from both atoms fill in the
    order expected by the model.
  • The bond order is 2.5 and is paramagnetic.

61
Example Problem
  • Use the MO model to predict the magnetism and
    bond order of the NO and CN- ions.
  • Both ions are diamagnetic and have the same
    configuration. Their bond order is 3

62
Heteronuclear Diatomics
  • What happens with the diatomic molecules are very
    different?
  • A molecular orbital forms between two different
    atomic orbitals.
  • HF example
  • Note energy level difference vs.
    electronegativity

63
Combining the Localized Electron and MO models
64
Resonance
  • When a molecule has resonance. It is usually a
    double bond that can have different positions
    around the molecule.
  • The single s bonds remain localized and the p
    bonds are said to be delocalized.

65
Resonance
  • Benzene All C-C bonds are known to be
    equivalent and the molecule has resonance

66
Resonance
  • Benzene The s bonds remain centered (on the
    plane) between C atoms.

67
Resonance
  • Benzene The p orbitals are perpendicular to the
    plane and form p bonds above and below the plane.
    The electrons in the p bonds delocalize and give
    six equivalent C-C bonds that give the structure
    true resonance.
  • This is called delocalized p bonding.

68
NO3-
  • NO3- ion also displays delocalized p bonding.

69
The End
70
MO Worksheet

B2 C2 N2 B2 C2 N2 B2 C2 N2 O2 F2 O2 F2 O2 F2
s2p   s2p  
p2p   p2p  
s2p   p2p  
p2p   s2p  
s2s   s2s  
s2s   s2s  
s1s   s1s  
s1s     s1s    
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