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Hidden Markov Models

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Title: Hidden Markov Models


1
Hidden Markov Models
1
2
K

2
Outline
  • Hidden Markov Models Formalism
  • The Three Basic Problems of HMMs
  • Solutions
  • Applications of HMMs for Automatic Speech
    Recognition (ASR)

3
Example The Dishonest Casino
  • A casino has two dice
  • Fair die
  • P(1) P(2) P(3) P(5) P(6) 1/6
  • Loaded die
  • P(1) P(2) P(3) P(4) P(5) 1/10
  • P(6) 1/2
  • Casino player switches back--forth between fair
    and loaded die once in a while
  • Game
  • You bet 1
  • You roll (always with a fair die)
  • Casino player rolls (maybe with fair die, maybe
    with loaded die)
  • Highest number wins 2

4
Question 1 Evaluation
  • GIVEN
  • A sequence of rolls by the casino player
  • 12455264621461461361366616646616366163661636165
  • QUESTION
  • How likely is this sequence, given our model of
    how the casino works?
  • This is the EVALUATION problem in HMMs

5
Question 2 Decoding
  • GIVEN
  • A sequence of rolls by the casino player
  • 12455264621461461361366616646616366163661636165
  • QUESTION
  • What portion of the sequence was generated with
    the fair die, and what portion with the loaded
    die?
  • This is the DECODING question in HMMs

6
Question 3 Learning
  • GIVEN
  • A sequence of rolls by the casino player
  • 12455264621461461361366616646616366163661636165
  • QUESTION
  • How loaded is the loaded die? How fair is the
    fair die? How often does the casino player change
    from fair to loaded, and back?
  • This is the LEARNING question in HMMs

7
The dishonest casino model
0.05
0.95
0.95
FAIR
LOADED
P(1F) 1/6 P(2F) 1/6 P(3F) 1/6 P(4F)
1/6 P(5F) 1/6 P(6F) 1/6
P(1L) 1/10 P(2L) 1/10 P(3L) 1/10 P(4L)
1/10 P(5L) 1/10 P(6L) 1/2
0.05
8
Example the dishonest casino
  • Let the sequence of rolls be
  • O 1, 2, 1, 5, 6, 2, 1, 6, 2, 4
  • Then, what is the likelihood of
  • X Fair, Fair, Fair, Fair, Fair, Fair, Fair,
    Fair, Fair, Fair?
  • (say initial probs P(t0,Fair) ½,
    P(t0,Loaded) ½)
  • ½ ? P(1 Fair) P(Fair Fair) P(2 Fair) P(Fair
    Fair) P(4 Fair)
  • ½ ? (1/6)10 ? (0.95)9 .00000000521158647211
    0.5 ? 10-9

9
Example the dishonest casino
  • So, the likelihood the die is fair in all this
    run
  • is just 0.521 ? 10-9
  • OK, but what is the likelihood of
  • X Loaded, Loaded, Loaded, Loaded, Loaded,
    Loaded, Loaded, Loaded, Loaded, Loaded?
  • ½ ? P(1 Loaded) P(Loaded, Loaded) P(4
    Loaded)
  • ½ ? (1/10)8 ? (1/2)2 (0.95)9 .000000000787811762
    15 7.9 ? 10-10
  • Therefore, it is after all 6.59 times more likely
    that the die is fair all the way, than that it is
    loaded all the way.

10
Example the dishonest casino
  • Let the sequence of rolls be
  • O 1, 6, 6, 5, 6, 2, 6, 6, 3, 6
  • Now, what is the likelihood X F, F, , F?
  • ½ ? (1/6)10 ? (0.95)9 0.5 ? 10-9, same as
    before
  • What is the likelihood
  • X L, L, , L?
  • ½ ? (1/10)4 ? (1/2)6 (0.95)9 .000000492382351347
    35 0.5 ? 10-7
  • So, it is 100 times more likely the die is loaded

11
HMM Timeline
time ?
  • Arrows indicate probabilistic dependencies.
  • xs are hidden states, each dependent only on the
    previous state.
  • The Markov assumption holds for the state
    sequence.
  • os are observations, dependent only on their
    corresponding hidden state.

12
HMM Formalism
  • An HMM ? can be specified by 3 matrices P, A,
    B
  • P pi are the initial state probabilities
  • A aij are the state transition probabilities
    Pr(xjxi)
  • B bik are the observation probabilities
    Pr(okxi)

13
Generating a sequence by the model
  • Given a HMM, we can generate a sequence of length
    n as follows
  • Start at state xi according to prob ?i
  • Emit letter o1 according to prob bi(o1)
  • Go to state xj according to prob aij
  • until emitting oT

1
?2
2
2
0
N
b2o1
o1
o2
o3
oT
14
The three main questions on HMMs
  • Evaluation
  • GIVEN a HMM ?, and a sequence O,
  • FIND Prob O ?
  • Decoding
  • GIVEN a HMM ?, and a sequence O,
  • FIND the sequence X of states that maximizes
    PX O, ?
  • Learning
  • GIVEN a sequence O,
  • FIND a model ? with parameters ?, A and B
    that
  • maximize P O ?

15
Problem 1 Evaluation
  • Find the likelihood a sequence is generated by
    the model

16
Probability of an Observation
o1
ot
ot-1
ot1
Given an observation sequence and a model,
compute the probability of the observation
sequence
17
Probability of an Observation
Let X x1 xt be the state sequence.
18
Probability of an Observation
19
HMM Evaluation (cont.)
  • Why isnt it efficient?
  • For a given state sequence of length T we have
    about 2T calculations
  • Let N be the number of states in the graph.
  • There are NT possible state sequences.
  • Complexity O(2TNT )
  • Can be done more efficiently by the
    forward-backward (F-B) procedure.

20
The Forward Procedure (Prefix Probs)
The probability of being in state i after
generating the first t observations.
21
Forward Procedure
22
Forward Procedure
23
Forward Procedure
24
Forward Procedure
25
Forward Procedure
26
Forward Procedure
27
Forward Procedure
28
Forward Procedure
29
The Forward Procedure
  • Initialization
  • Iteration
  • Termination
  • Computational Complexity O(N2T)

30
Another Version The Backward Procedure (Suffix
Probs)
x1
xt1
xT
xt
xt-1
oT
o1
ot
ot-1
ot1
Probability of the rest of the states given the
first state
31
Problem 2 Decoding
  • Find the best state sequence

32
Decoding
  • Given an HMM and a new sequence of observations,
    find the most probable sequence of hidden states
    that generated these observations
  • In general, there is an exponential number of
    possible sequences.
  • Use dynamic programming to reduce search space to
    O(n2T).

33
Viterbi Algorithm
x1
xt-1
j
oT
o1
ot
ot-1
ot1
The state sequence which maximizes the
probability of seeing the observations up to time
t-1, landing in state j, and seeing the
observation at time t.
34
Viterbi Algorithm
x1
xt-1
j
oT
o1
ot
ot-1
ot1
Initialization
35
Viterbi Algorithm
x1
xt-1
xt
xt1
Recursion
Prob. of ML state
Name of ML state
36
Viterbi Algorithm
x1
xt-1
xt
xt1
xT
Termination
Read out the most likely state sequence,
working backwards.
37
Problem 3 Learning
  • Re-estimate the parameters of the model based on
    training data

38
Learning by Parameter Estimation
  • Goal Given an observation sequence, find the
    model that is most likely to produce that
    sequence.
  • Problem We dont know the relative frequencies
    of hidden visited states.
  • No analytical solution is known for HMMs.
  • We will approach the solution by successive
    approximations.

39
The Baum-Welch Algorithm
  • Find the expected frequencies of possible values
    of the hidden variables.
  • Compute the maximum likelihood distributions of
    the hidden variables (by normalizing, as usual
    for MLE).
  • Repeat until convergence.
  • This is the Expectation-Maximization (EM)
    algorithm for parameter estimation.
  • Applicable to any stochastic process, in theory.
  • Special case for HMMs is called the Baum-Welch
    algorithm.

40
Arc and State Probabilities
A
A
A
A
B
B
B
B
B
Probability of traversing an arc From state i (at
time t) to state j (at time t1)
Probability of being in state i at time t.
41
Aggregation and Normalization
A
A
A
A
B
B
B
B
B
Now we can compute the new MLEs of the model
parameters.
42
The Baum-Welch Algorithm
  1. Initialize A,B and ? (Pick the best-guess for
    model parameters or arbitrary)
  2. Repeat
  3. Calculate and
  4. Calculate and
  5. Estimate , and
  6. Until the changes are small enough

43
The Baum-Welch Algorithm Comments
  • Time Complexity
  • iterations ? O(N2T)
  • Guaranteed to increase the (log) likelihood of
    the model
  • P(? O) P(O, ?) / P(O) P(O ?) / ( P(O)
    P(?) )
  • Not guaranteed to find globally best parameters
  • Converges to local optimum, depending on initial
    conditions
  • Too many parameters / too large model -
    Overtraining

44
Application Automatic Speech Recognition
45
Examples (1)
46
Examples (2)
47
Examples (3)
48
Examples (4)
49
(No Transcript)
50
Phones
51
Speech Signal
  • Waveform
  • Spectrogram

52
Speech Signal cont.
Articulation
53
Feature Extraction
Frame 1
Frame 2
Feature VectorX1
Feature VectorX2
54
(No Transcript)
55
(No Transcript)
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