More Equilibria in Aqueous Solutions: Slightly Soluble Salts and Complex Ions - PowerPoint PPT Presentation

1 / 40
About This Presentation
Title:

More Equilibria in Aqueous Solutions: Slightly Soluble Salts and Complex Ions

Description:

Chapter Sixteen More Equilibria in Aqueous Solutions: Slightly Soluble Salts and Complex Ions The Solubility Product Constant, Ksp Solubility product constant, Ksp ... – PowerPoint PPT presentation

Number of Views:248
Avg rating:3.0/5.0
Slides: 41
Provided by: TerryM166
Category:

less

Transcript and Presenter's Notes

Title: More Equilibria in Aqueous Solutions: Slightly Soluble Salts and Complex Ions


1
More Equilibria in Aqueous SolutionsSlightly
Soluble Salts and Complex Ions
Chapter Sixteen
2
The Solubility Product Constant, Ksp
  • Many important ionic compounds are only slightly
    soluble in water (we used to call them
    insoluble Chapter 4).
  • An equation can represent the equilibrium between
    the compound and the ions present in a saturated
    aqueous solution
  • Solubility product constant, Ksp the equilibrium
    constant expression for the dissolving of a
    slightly soluble solid.

Ksp Ba2 SO42
3
(No Transcript)
4
  • Example 16.1
  • Write a solubility product constant expression
    for equilibrium in a saturated aqueous solution
    of the slightly soluble salts (a) iron(III)
    phosphate, FePO4, and (b) chromium(III)
    hydroxide, Cr(OH)3.

5
Ksp and Molar Solubility
  • Ksp is an equilibrium constant
  • Molar solubility is the number of moles of
    compound that will dissolve per liter of
    solution.
  • Molar solubility is related to the value of Ksp,
    but molar solubility and Ksp are not the same
    thing.
  • In fact, smaller Ksp doesnt always mean lower
    molar solubility.
  • Solubility depends on both Ksp and the form of
    the equilibrium constant expression.

6
  • Example 16.2
  • At 20 C, a saturated aqueous solution of silver
    carbonate contains 32 mg of Ag2CO3 per liter of
    solution. Calculate Ksp for Ag2CO3 at 20 C. The
    balanced equation is
  • Ag2CO3(s) 2 Ag(aq) CO32(aq)
    Ksp ?
  • Example 16.3
  • From the Ksp value for silver sulfate, calculate
    its molar solubility at 25 C.
  • Ag2SO4(s) 2 Ag(aq) SO42(aq)
  • Ksp 1.4 x 105 at 25 C

7
  • Example 16.4 A Conceptual Example
  • Without doing detailed calculations, but using
    data from Table 16.1, establish the order of
    increasing solubility of these silver halides in
    water AgCl, AgBr, AgI.

8
The Common Ion Effectin Solubility Equilibria
  • The common ion effect affects solubility
    equilibria as it does other aqueous equilibria.
  • The solubility of a slightly soluble ionic
    compound is lowered when a second solute that
    furnishes a common ion is added to the solution.

9
Common Ion Effect Illustrated
The added sulfate ion reduces the solubility of
Ag2SO4.
Na2SO4(aq)
Saturated Ag2SO4(aq)
Ag2SO4 precipitates
10
Common Ion Effect Illustrated
When Na2SO4(aq) is added to the saturated
solution of Ag2SO4
Ag attains a new, lower equilibrium
concentration as Ag reacts with SO42 to produce
Ag2SO4.
11
  • Example 16.5
  • Calculate the molar solubility of Ag2SO4 in 1.00
    M Na2SO4(aq).

12
Solubility and Activities
  • Ions that are not common to the precipitate can
    also affect solubility.
  • CaF2 is more soluble in 0.010 M Na2SO4 than it is
    in water.
  • Increased solubility occurs because of interionic
    attractions.
  • Each Ca2 and F is surrounded by ions of
    opposite charge, which impede the reaction of
    Ca2 with F.
  • The effective concentrations, or activities, of
    Ca2 and F are lower than their actual
    concentrations.

13
Will Precipitation Occur? Is It Complete?
  • Qip is the ion product reaction quotient and is
    based on initial conditions of the reaction.

Qip and Qc new look, same great taste!
  • Qip can then be compared to Ksp.
  • Precipitation should occur if Qip gt Ksp.
  • Precipitation cannot occur if Qip lt Ksp.
  • A solution is just saturated if Qip Ksp.
  • In applying the precipitation criteria, the
    effect of dilution when solutions are mixed must
    be considered.

14
  • Example 16.6
  • If 1.00 mg of Na2CrO4 is added to 225 mL of
    0.00015 M AgNO3, will a precipitate form?
  • Ag2CrO4(s) 2 Ag(aq) CrO42(aq)
    Ksp 1.1 x 1012

15
  • Example 16.7 A Conceptual Example
  • Pictured here is the result of adding a few drops
    of concentrated KI(aq) to a dilute solution of
    Pb(NO3)2. What is the solid that first appears?
    Explain why it then disappears.

Example 16.8 If 0.100 L of 0.0015 M MgCl2 and
0.200 L of 0.025 M NaF are mixed, should a
precipitate of MgF2 form? MgF2(s)
Mg2(aq) 2 F(aq) Ksp 3.7 x 108
16
To Determine Whether Precipitation Is Complete
  • A slightly soluble solid does not precipitate
    totally from solution
  • but we generally consider precipitation to be
    complete if about 99.9 of the target ion is
    precipitated (0.1 or less left in solution).
  • Three conditions generally favor completeness of
    precipitation
  1. A very small value of Ksp.
  2. A high initial concentration of the target ion.
  3. A concentration of common ion that greatly
    exceeds that of the target ion.

17
  • Example 16.9
  • To a solution with Ca2 0.0050 M, we add
    sufficient solid ammonium oxalate, (NH4)2C2O4(s),
    to make the initial C2O42 0.0051 M. Will
    precipitation of Ca2 as CaC2O4(s) be complete?

CaC2O4(s) Ca2(aq) C2O42(aq)
Ksp 2.7 x 109
18
Selective Precipitation
AgNO3 added to a mixture containing Cl and I
19
  • Example 16.10
  • An aqueous solution that is 2.00 M in AgNO3 is
    slowly added from a buret to an aqueous solution
    that is 0.0100 M in Cl and also 0.0100 M in I.
  • Which ion, Cl or I, is the first to precipitate
    from solution?
  • When the second ion begins to precipitate, what
    is the remaining concentration of the first ion?
  • Is separation of the two ions by selective
    precipitation feasible?

AgCl(s) Ag(aq) Cl(aq)
Ksp 1.8 x 1010
AgI(s) Ag(aq) I(aq)
Ksp 8.5 x 1017
20
Effect of pH on Solubility
  • If the anion of a precipitate is that of a weak
    acid, the precipitate will dissolve somewhat when
    the pH is lowered

Added H reacts with, and removes, F
LeChâteliers principle says more F forms.
  • If, however, the anion of the precipitate is that
    of a strong acid, lowering the pH will have no
    effect on the precipitate.

H does not consume Cl acid does not affect
the equilibrium.
21
  • Example 16.11
  • What is the molar solubility of Mg(OH)2(s) in a
    buffer solution having OH 1.0 x 105 M, that
    is, pH 9.00?

Mg(OH)2(s) Mg2(aq) 2 OH(aq)
Ksp 1.8 x 1011
Example 16.12 A Conceptual Example Without
doing detailed calculations, determine in which
of the following solutions Mg(OH)2(s) is most
soluble (a) 1.00 M NH3 (b) 1.00 M NH3 /1.00 M
NH4 (c) 1.00 M NH4Cl.
22
Equilibria Involving Complex Ions
Silver chloride becomes more soluble, not less
soluble, in high concentrations of chloride ion.
23
Complex Ion Formation
  • A complex ion consists of a central metal atom or
    ion, with other groups called ligands bonded to
    it.
  • The metal ion acts as a Lewis acid (accepts
    electron pairs).
  • Ligands act as Lewis bases (donate electron
    pairs).
  • The equilibrium involving a complex ion, the
    metal ion, and the ligands may be described
    through a formation constant, Kf

AgCl2 Kf 1.2 x 108
AgCl2
24
Complex Ion Formation
Concentrated NH3 added to a solution of pale-blue
Cu2
forms deep-blue Cu(NH3)42.
25
(No Transcript)
26
Complex Ion Formationand Solubilities
But if the concentration of NH3 is made high
enough
the AgCl forms the soluble Ag(NH3)2 ion.
AgCl is insoluble in water.
27
  • Example 16.13
  • Calculate the concentration of free silver ion,
    Ag, in an aqueous solution prepared as 0.10 M
    AgNO3 and 3.0 M NH3.

Example 16.14 If 1.00 g KBr is added to 1.00 L of
the solution described in Example 16.13, should
any AgBr(s) precipitate from the solution?
Ksp 5.0 x 1013
28
Example 16.15 What is the molar solubility of
AgBr(s) in 3.0 M NH3?
AgBr(s) 2 NH3(aq) Ag(NH3)2(aq)
Br(aq)
Kc 8.0 x 106
Example 16.16 A Conceptual Example Figure
16.10 shows that a precipitate forms when
HNO3(aq) is added to the solution in the beaker
on the right in Figure 16.9. Write the
equation(s) to show what happens.
29
Complex Ions in AcidBase Reactions
  • Water molecules are commonly found as ligands in
    complex ions (H2O is a Lewis base).

Na(H2O)4
Al(H2O)63
Fe(H2O)63
  • The electron-withdrawing power of a small, highly
    charged metal ion can weaken an OH bond in one
    of the ligand water molecules.
  • The weakened OH bond can then give up its proton
    to another water molecule in the solution.
  • The complex ion acts as an acid.

30
Ionization of a Complex Ion
The highly-charged iron(III) ion withdraws
electron density from the OH bonds.
Fe(H2O)63 H2O Fe(H2O)5OH2
H3O
Ka 1 x 107
31
Amphoteric Species
  • Certain metal hydroxides, insoluble in water, are
    amphoteric they will react with both strong
    acids and strong bases.
  • Al(OH)3, Zn(OH)2, and Cr(OH)3 are amphoteric.

32
Qualitative Inorganic Analysis
  • Acidbase chemistry, precipitation reactions,
    oxidationreduction, and complex ion formation
    all apply to an area of analytical chemistry
    called classical qualitative inorganic analysis.
  • Qualitative signifies that the interest is in
    determining what is present.
  • Quantitative analyses are those that determine
    how much of a particular substance or species is
    present.
  • Although classical qualitative analysis is not
    used as widely today as are instrumental methods,
    it is still a good vehicle for applying all the
    basic concepts of equilibria in aqueous solutions.

33
Qualitative Analysis Outline
In acid, H2S produces very little S2, so only
the most-insoluble sulfides precipitate.
In base, there is more S2, and the
less-insoluble sulfides also precipitate.
Some hydroxides also precipitate here.
34
Cation Group 1
  • If aqueous HCl is added to an unknown solution of
    cations, and a precipitate forms, then the
    unknown contains one or more of these cations
    Pb2, Hg22, or Ag.
  • These are the only ions to form insoluble
    chlorides.
  • Any precipitate is separated from the mixture and
    further tests are performed to determine which of
    the three Group 1 cations are present.
  • The supernatant liquid is also saved for further
    analysis (it contains the rest of the cations).
  • If there is no precipitate, then Group 1 ions
    must be absent from the mixture.

35
Cation Group 1 (contd)Analyzing for Pb2
  • Precipitated PbCl2 is slightly soluble in hot
    water.
  • The precipitate is washed with hot water, then
    aqueous K2CrO4 is added to the washings.
  • If Pb2 is present, a precipitate of yellow lead
    chromate forms, which is less soluble than PbCl2.
  • (If all of the precipitate dissolves in the hot
    water, what does that mean?)

36
Cation Group 1 (contd)Analyzing for Ag and
Hg22
  • Next, any undissolved precipitate is treated with
    aqueous ammonia.
  • If AgCl is present, it will dissolve, forming
    Ag(NH3)2 (the dissolution may not be visually
    apparent).
  • If Hg22 is present, the precipitate will turn
    dark gray/ black, due to a disproportionation
    reaction that forms Hg metal and HgNH2Cl.
  • The supernatant liquid (which contains the Ag,
    if present) is then treated with aqueous nitric
    acid.
  • If a precipitate reforms, then Ag was present in
    the solution.

37
Group 1 Cation Precipitates
PbCl2 precipitates when HCl is added.
The presence of lead is confirmed by adding
chromate ion yellow PbCrO4 precipitates.
Hg2Cl2 reacts with NH3 to form black Hg metal and
HgNH2Cl.
38
Hydrogen Sulfide in theQualitative Analysis
Scheme
  • Once the Group 1 cations have been precipitated,
    hydrogen sulfide is used as the next reagent in
    the qualitative analysis scheme.
  • H2S is a weak diprotic acid there is very little
    ionization of the HS ion and it is the
    precipitating agent.
  • Hydrogen sulfide has the familiar rotten egg odor
    that is very noticeable around volcanic areas.
  • Because of its toxicity, H2S is generally
    produced only in small quantities and directly in
    the solution where it is to be used.

39
Cation Groups 2, 3, 4, and 5
  • The concentration of HS is so low in a strongly
    acidic solution, that only the most insoluble
    sulfides precipitate.
  • These include the eight metal sulfides of Group
    2.
  • Five of the Group 3 cations form sulfides that
    are soluble in acidic solution but insoluble in
    alkaline NH3/NH4.
  • The other three Group 3 cations form insoluble
    hydroxides in the alkaline solution.
  • The cations of Groups 4 and 5 are soluble.
  • Group 4 ions are precipitated as carbonates.
  • Group 5 does not precipitate these must be
    determined by flame test.

40
  • Cumulative Example
  • A solid mixture containing 1.00 g of ammonium
    chloride and 2.00 g of barium hydroxide is heated
    to expel ammonia. The liberated NH3 is then
    dissolved in 0.500 L of water containing 225 ppm
    Ca2 as calcium chloride. Will a precipitate form
    in this water?
Write a Comment
User Comments (0)
About PowerShow.com