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Hierarchical Well-Separated Trees (HST)

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Hierarchical Well-Separated Trees (HST) Edges distances are uniform across a level of the tree Stretch s = factor by which distances decrease from root to leaf – PowerPoint PPT presentation

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Title: Hierarchical Well-Separated Trees (HST)


1
Hierarchical Well-Separated Trees (HST)
  • Edges distances are uniform across a level of
    the tree
  • Stretch s factor by which distances decrease
    from root to leaf
  • Distortion factor by which distance between 2
    points increases when HST is used to traverse
    instead of direct distance
  • Upper bound is O(s logs n)

Diagram from Fakcharoenphol, Rao Talwar 2003
2
Pure Randomized vs. Fractional Algorithms
  • Fractional view keep track only of marginal
    distributions of some quantities
  • Lossy compared to pure randomized
  • Which marginals to track?
  • Claim for some algorithms, fractional view can
    be converted back to randomized algorithm with
    little loss

3
Fractional View of K-server Problem
  • For node j, let T(j) leaves of the subtree of T
    rooted in j
  • At time step t, for leaf i, pit probability of
    having a server at i
  • If there is a request at i on time t, pit should
    be 1
  • Expected number of servers across T(j) kt(j)
    Si?T(j) pit
  • Movement cost to get servers at j Sj?T W(j)
    kt(j) kt-1(j)

j
T(j)
i
Parts of diagram from Bansal 2011
4
The Allocation Problem
  • Decide how to (re-)distribute k servers among d
    locations (each location of uniform distance from
    a center and may request arbitrary no. of
    servers)
  • Each location i has a request denoted as ht(0),
    ht(1), ht(k)
  • ht(j) cost of serving request using j servers
  • Ex. request at i0 is 8, 2, 1, 0, 0
    (monotonic decrease)
  • Total cost hit cost movement cost

I can work with 1, but Id like 3!
Parts of diagram from Bansal 2011
5
Fractional View of Allocation Problem
  • Let xi,jt (non-negative) probability of having
    j servers at location i at time t
  • Sum of probabilities Sj xi,jt 1
  • No. of servers used must not exceed no. available
  • Si Sj j xi,jt k
  • Hit cost incurred Sj ht(j) xi,jt
  • Movement cost incurred Si Sj (Sjltj xi,jt
    Sjltj xi,jt-1)
  • Note fractional A.P. too weak to obtain
    randomized A.P. algorithm
  • But we dont really care about A.P., we care
    about K-server problem!

6
From Allocation to K-Server
  • Theorem 2 It suffices to have a (1?,
    ?(?))-competitive fractional AP algorithm on
    uniform metric to get a k-server algorithm that
    is O(ßl)-competitive algorithm (Coté et al. 2008)
  • Theorem 1 Bansal et al.s k-server algorithm has
    a competitive ratio of Õ(log2 k log3 n)

7
The Main Algorithm
  • Embed the n points into a distribution m over
    s-HSTs with stretch s Q(log n log(k log n))
  • (No time to discuss, this step is essentially
    from the paper of Fakcharoenphol, Rao Talwar
    2003)
  • According to distribution m, pick a random HST T
  • Extra step Transform the HST to a weighted HST
    (Well briefly touch on this)

Diagram from Bansal 2011
8
The Main Algorithm
  • Solve the (fractional) allocation problem on Ts
    root node immediate children, then recursively
    solve the same problem on each child
  • Intuitive application of Theorem 2
  • d immediate children of a given node
  • At root node k all k servers
  • At internal node i k resulting (re)allocation
    of servers from is parent

Allocation instances
Diagram from Bansal 2011
9
Detour Weighted HST
  • Degenerate case of normal HST
  • Depth l O(n) (can happen if n points are on a
    line with geometrically increasing distances)

10
Detour Weighted HST
  • Solution allow lengths of edges to be
    non-uniform
  • Allow distortion from leaf-to-leaf to be at most
    2s/(s1)
  • Depth l O(log n)
  • Consequence Uniform A.P. becomes weighted-star
    A.P.

11
Proving the Main Algorithm
  • Theorem 1 Bansal et al.s k-server algorithm has
    a competitive ratio of Õ(log2 k log3 n)
  • Idea of proof How does competitive ratio and
    distortion evolve as we transform
  • Fractional allocation algorithm
  • ?
  • Fractional k-server algorithm on HST
  • ?
  • Randomized k-server algorithm on HST

12
Supplemental Theorems
  • Theorem 3 For e gt 0, there exists a fractional
    A.P. algorithm on a weighted-star metric that is
    (1e, O(log(k/e)))-competitive (Refinement of
    theorem 2, to be discussed by Tanvirul)
  • Theorem 4 If T is a weighted s-HST with depth l,
    if Theorem 3 holds, then there is a fractional
    k-server algorithm that is O(l
    log(kl))-competitive as long as s W(l log(kl))
  • Theorem 5 If T is a s-HST with sgt5, then any
    fractional k-server algorithm on T converts to a
    randomized k-server algorithm on T that is about
    as competitive (only O(1) loss)
  • Theorem 6 If T is a s-HST with n leaves and any
    depth, it can transform to a weighted s-HST with
    identical leaves but with depth O(log n) and
    leaf-to-leaf distance distorted only by at most
    2s/(s1)

13
Proof of Theorem 1
  • Embed the n points into a distribution m over
    s-HSTs with stretch s Q(log n log(k log n))
  • Distortion at O(s logs n)
  • Resulting HSTs may have depth l up to O(n)
  • According to distribution m, pick a random HST T
    and transform to a weighted HST
  • From Theorem 6, depth l reduced to O(log n)
  • Stretch s is now Q(l log (kl)))

14
Proof of Theorem 1
  • Solve the (fractional) allocation problem on Ts
    root node immediate children, then recursively
    solve the allocation problem on children
  • This is explicitly Theorem 2 refined by Theorem 3
    ?
  • Stretch s Q(l log (kl))), so Theorem 4 is
    applicable!
  • Transform to a fractional k-server algorithm with
    competitiveness
  • O(l log (kl))) O(log n log (k log n))
  • Applying Theorem 5, we get similar
    competitiveness for the randomized k-server
    algorithm

15
Proof of Theorem 1
  • Expected distortion to optimal solution OptM,
    given the cost of the solution on T, cT
  • EmcT O(s logs n) OptM
  • AlgM AlgT
  • O(log n log (k log n)) cT
  • EmAlgM O(log n log (k log n)) EmcT
  • O(log n log (k log n)) O(s
    logs n) OptM

16
Proof of Theorem 1
  • EmAlgM O(log n log (k log n)) O(s logs n)
    OptM
  • This implies a competitive ratio of
  • O(log n log (k log n)) O(s logs n)
  • O(log n log (k log n)) O(s (log n / log s))
  • Olog3 n (log (k log n))2 / log log n
  • O(log2 k log3 n log log n)
  • Õ(log2 k log3 n)
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