Title: Solving Systems of Equations in Three Variables
1Solving Systems of Equations in Three Variables
2Objective
- Solve a system of equations in three variables.
3Application
- Courtney has a total of 256 points on three
Algebra tests. His score on the first test
exceeds his score on the second by 6 points. His
total score before taking the third test was 164
points. What were Courtneys test scores on the
three tests?
4Explore
- Problems like this one can be solved using a
system of equations in three variables. Solving
these systems is very similar to solving systems
of equations in two variables. Try solving the
problem - Let f Courtneys score on the first test
- Let s Courtneys score on the second test
- Let t Courtneys score on the third test.
5Plan
- Write the system of equations from the
information given. - f s t 256
- f s 6
- f s 164
The total of the scores is 256.
The difference between the 1st and 2nd is 6
points.
The total before taking the third test is the sum
of the first and second tests..
6Solve
- Now solve. First use elimination on the last two
equations to solve for f. - f s 6
- f s 164
- 2f 170
- f 85
The first test score is 85.
7Solve
- Then substitute 85 for f in one of the original
equations to solve for s. - f s 164
- 85 s 164
- s 79
The second test score is 79.
8Solve
- Next substitute 85 for f and 79 for s in f s
t 256. - f s t 256
- 85 79 t 256
- 164 t 256
- t 92
The third test score is 92.
Courtneys test scores were 85, 79, and 92.
9Examine
- Now check your results against the original
problem. - Is the total number of points on the three tests
256 points? - 85 79 92 256 ?
- Is one test score 6 more than another test score?
- 79 6 85 ?
- Do two of the tests total 164 points?
- 85 79 164 ?
- Our answers are correct.
10Solutions?
- You know that a system of two linear equations
doesnt necessarily have a solution that is a
unique ordered pair. Similarly, a system of
three linear equations in three variables doesnt
always have a solution that is a unique ordered
triple.
11Graphs
- The graph of each equation in a system of three
linear equations in three variables is a plane.
Depending on the constraints involved, one of the
following possibilities occurs.
12Graphs
- The three planes intersect at one point. So the
system has a unique solution.
- 2. The three planes intersect in a line. There
are an infinite number of solutions to the
system.
13Graphs
- 3. Each of the diagrams below shows three planes
that have no points in common. These systems of
equations have no solutions.
14Ex. 1 Solve this system of equations
- Substitute 4 for z and 1 for y in the first
equation, x 2y z 9 to find x. - x 2y z 9
- x 2(1) 4 9
- x 6 9
- x 3 Solution is (3, 1, 4)
- Check
- 1st 3 2(1) 4 9 ?
- 2nd 3(1) -4 1 ?
- 3rd 3(4) 12 ?
- Solve the third equation, 3z 12
- 3z 12
- z 4
- Substitute 4 for z in the second equation 3y z
-1 to find y. - 3y (4) -1
- 3y 3
- y 1
15Ex. 2 Solve this system of equations
- Set the next two equations together and multiply
the first times 2. - 2(x 3y 2z 11)
- 2x 6y 4z 22
- 3x - 2y 4z 1
- 5x 4y 23
- Next take the two equations that only have x and
y in them and put them together. Multiply the
first times -1 to change the signs.
- Set the first two equations together and multiply
the first times 2. - 2(2x y z 3)
- 4x 2y 2z 6
- x 3y -2z 11
- 5x y 17
-
16Ex. 2 Solve this system of equations
- Now you have y 2. Substitute y into one of the
equations that only has an x and y in it. - 5x y 17
- 5x 2 17
- 5x 15
- x 3
- Now you have x and y. Substitute values back
into one of the equations that you started with. - 2x y z 3
- 2(3) - 2 z 3
- 6 2 z 3
- 4 z 3
- z -1
- Next take the two equations that only have x and
y in them and put them together. Multiply the
first times -1 to change the signs. - -1(5x y 17)
- -5x - y -17
- 5x 4y 23
- 3y 6
- y 2
17Ex. 2 Check your work!!!
- Solution is (3, 2, -1)
- Check
- 1st 2x y z
- 2(3) 2 1 3 ?
- 2nd x 3y 2z 11
- 3 3(2) -2(-1) 11 ?
- 3rd 3x 2y 4z
- 3(3) 2(2) 4(-1) 1 ?
18Ex. 2 Solve this system of equations
- Now you have y 2. Substitute y into one of the
equations that only has an x and y in it. - 5x y 17
- 5x 2 17
- 5x 15
- x 3
- Now you have x and y. Substitute values back
into one of the equations that you started with. - 2x y z 3
- 2(3) - 2 z 3
- 6 2 z 3
- 4 z 3
- z -1
- Next take the two equations that only have x and
y in them and put them together. Multiply the
first times -1 to change the signs. - -1(5x y 17)
- -5x - y -17
- 5x 4y 23
- 3y 6
- y 2