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Respiratory%20Pharmacology

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Title: Respiratory%20Pharmacology


1
Respiratory Pharmacology
  • RC 195
  • Dan Farrell

2
Goal of Respiratory CareAirway Maintenance
3
Two ways to name a drug Brand (Trade) name and
Generic Name
Always know a drug by both names!
4
Respiratory Pharmacology Calculations
5
Definitions
  • Solute material to be dissolved
  • Usually the actual drug
  • Solvent the dissolving or diluting medium
  • Almost always is water!

6
Handy Conversions
  • 1 ml 1 cc
  • 1 gm 1000mg
  • 1 gm H2O 1 ml H2O
  • 1 lbs 454 gms
  • 1 kg 2.2 lbs

7
3 Ways to Express Drug Strength
8
X mg/ml
  • Tells how many milligrams of drug (solute) are in
    each ml of solution (solvent)
  • 10 mg/ml 10 milligrams of drug in each ml of
    solution
  • Best form to use for most calculations!

9
Solution
  • X grams of solute (drug) in each 100 ml of
    solvent (solution)
  • 1 solution 1 gram of solute (drug) in each 100
    ml of solvent (solution)
  • Is also the same strength as 10 mg/ml since 1
    1gm/100ml 1000mg/100 ml 10 mg/ml

10
Dilution Ratio
  • 1 gram solute (drug) per X grams (or ml) of
    solvent (solution)
  • 1100 1 grams of drug (solute) per 100 grams of
    solvent (or ml of solution)
  • 1100 1000mg/100 ml 10 mg/ml

11
10 mg/ml, 1 and 1100 are all the same strength
just expressed 3 different ways
12
Conversions mg/ml to solution
  • Move decimal point 1 place to the left!
  • 10 mg/ml
  • 1
  • 75 mg/ml
  • 7.5

13
Conversions solution to mg/ml
  • Move decimal point 1 place to the right!
  • 2
  • 20 mg/ml
  • .5
  • 5mg/ml
  • 7.5
  • 75 mg/ml

14
Conversions Dilution Ratio to Solution
  • Convert to mg/ml and then move decimal point 1
    place to the left!
  • 1 1000 1 gram per 1000 grams 1000mg/1000 ml
    (why?)
  • 1 mg/ml .1

15
Conversions mg/ml or solution to a dilution
ratio
  • If in mg/ml, first change to solution, then
    express the solution by its definition and then
    divide it out
  • Crystal clear, isnt it!?!?!?
  • 20 mg/ml 2 solution
  • By definition, a 2 solution is 2 grams of
    solute (drug) in every 100 grams of solvent
    (solution) or 2 100
  • By dividing it out, you get the true dilution
    ratio
  • 2100 is 150 dilution ratio

16
Calculations
  • To determine how many mg of drug are in X ml of
    solution, or to determine how many ml of solution
    contain Xmg of drug, use
  • mg/ml (available) mg/ml (desired)
  • where mg/ml (available) is the strength of the
    drug. Solve for the desired variable on the
    right side (desired) side of the equation

17
Calculation ExampleHow many ml of 1
Isoetharine (Bronkosol) are needed to give the
patient 2.5 mg of drug?
  • Convert 1 to mg/ml and use the equation
  • mg/ml (available) mg/ml (desired)
  • 1 10 mg/ml, so
  • 10 mg/ml 2.5 mg/X ml
  • Using algebra, solve for X
  • X .25 ml

18
Thus, to give a patient 2.5 mg of 1 Isoetharine
(Bronkosol), you would need to administer .25 ml
of 1 Isoetharine (Bronkosol)
19
Calculation Example How much drug does a patient
get if you administer .5 ml of .5 Albuterol
(Proventil)?
  • Convert .5 to mg/ml and use the equation
  • mg/ml (available) mg/ml (desired)
  • .5 5 mg/ml, so
  • 5 mg/ml X mg/.5 ml
  • Use algebra and solve for X
  • X 2.5 mg

20
Thus, if a patient receives .5 ml of .5
Albuterol (Proventil), he receives 2.5 mg of
Albuterol (Proventil)!
21
Calculations Diluting a Solution
  • Use formula, V¹C¹ V²C², where
  • V¹ Volume of desired solution
  • C¹ Concentration (strength) of desired
  • solution
  • V² Volume of available solution to be
  • drawn up and diluted
  • C² Concentration (strength) of
    available
  • solution

22
Calculation Example
  • Give 15 ml of 2.5 Sodium Bicarb. You have 20 ml
    of 7.5 available.
  • Dont be misled by the amount of solution
    available! Its not part of the equation!
  • V¹ 15 ml
  • C¹ 2.5
  • V² X (what you are solving for how much of
    the available solution you are going to use)
  • C² 7.5

23
V¹C¹ V²C²
  • 15 ml (2.5) X ml (7.5)
  • 15ml (2.5)/7.5 X ml
  • Xml 5 ml V²
  • Take 5 ml of the 7.5 solution and add enough
    water to end up with 15 ml of solution
  • Adding 10 ml of water to 5 ml of 7.5 solution
    will yield 15 ml of 2.5 solution!

24
Calculation Example
  • Give 8 ml of 50 ETOH. You have 12 ml of 80
    ETOH available.
  • V¹ 8 ml
  • C¹ 50
  • V² X (the amount of 80 ETOH to be used for
    dilution)
  • C² 80

25
V¹C¹ V²C²
  • 8 ml (50) X ml (80)
  • 8 ml (50)/80 X ml
  • X ml 5 ml V²
  • Take 5 ml of 80 ETOH and add enough water to end
    up with 8 ml of solution
  • Adding 3 ml of water to 5 ml of 80 ETOH will
    yield 8 ml of 50 ETOH!

26
Lets get the hell out of here and take a break!!
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