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Gauss's Law Applications. PHYS 2326-7 ... Applying Gauss's Law ... 4. Apply Gauss's Law = total flux through G surface equals charge enclosed divided by eo ...
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E is larger where field lines are closer together ... Gaussian cube of face area A is immersed in a uniform electric field E that ...
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... field on the axis of an annulus of radius R and infinitesimal thickness dR is. dEz = 2pske z RdR [z2 R2 ] 3/2 where s is the surface charge density, show ...
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The amount of field, material or other physical entity passing through a surface. ... A shell of uniform charge attracts or repels a charge particle that is outside ...
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It is a physical quantity that determines the degree of electrification of a body. ... VQ q = 4pe0 BQ. 1. VQ = VP q VP q- VQ q- = 4pe0 AQ. 1 - q. VQ = 4pe0 ...
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Physics 212 lecture 4: Electric Flux and Gauss's Law ... Example: Electric flux through two connected half-spheres of radii r and R ... Solve for electric field ...
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Changement de la Q de M = flux de la Q de M forces agissant ... 2. Toutes les forces agissant l'int rieur de Q. est la composante suivant Oy de la force ...
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