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Infrared Spectroscopy Part 1

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Absorption of photons causes changes in molecular vibrations. Molecular Vibrations ... Structure versus Photon Quantity. Chance of photon absorption controlled ... – PowerPoint PPT presentation

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Title: Infrared Spectroscopy Part 1


1
Infrared Spectroscopy Part 1
  • Lecture Supplement
  • Take one handout from the stage

2
Midterm Exam 1
  • Date Monday April 30
  • Time 500-650 PM
  • Topics Molecular Structure Introduction and
    Review ? Carbohydrates
  • Location last name A-H in Franz 1178
  • last name I-Sh in Haines 39
  • last name Si-Z in PAB 1425
  • Question and Answer Session
  • Lecture time, Monday April 30
  • Submit questions to harding_at_chem.ucla.edu
  • Label as Question for QA
  • Deadline for possible inclusion noon Sunday
    April 29
  • Extra Office Hours (Steve J) Sunday 2-4 PM,
    Young Hall 3077F

3
Infrared Spectroscopy (IR)Molecular Vibrations
  • Molecular Vibrations
  • Bonded atoms move around in space
  • Very fast one vibration cycle 10-15 seconds
  • Stretching (H-Cl)
  • Atoms move along bond axis

4
Molecular Vibrations
  • Vibration energy
  • ? vibration energy ? average bond length

Excited state higher energy
Ground state lower energy
5
Molecular Vibrations
  • Vibration energy
  • Vibrational energy is quantized (only certain
    energy values are possible)

n stretching frequency
For bond vibrations DE dependent on bond
5 kcal mol-1 lower energy than red
light photons infrared photons
6
The Infrared Spectrum
Spectrum plot of photon energy versus photon
quantity
Typical infrared spectrum
Number of photons absorbed
Stretching frequency Proportional to photon energy
7
Molecular Structure from IR Spectrum
  • How does spectrum give information about
    molecular structure?
  • Structure controls number of photons absorbed
  • Structure controls stretching frequency

8
Structure versus Photon Quantity
From quantum mechanics
Chance of photon absorption controlled by change
in dipole moment (m)
Useful approximation Consider only one bond
9
Absorption Intensity versus Bond Dipoles
  • Bond dipole (magnitude of electronegativity
    difference) x (bond length)
  • ? DEN ? dipole
  • ? bond length ? dipole
  • ? bond dipole ? absorption
  • In practical terms
  • Highly polar bond ? strong peak
  • Symmetrical (nonpolar) or nearly symmetrical bond
    ? peak weak or absent

10
Absorption Intensity versus Bond Dipoles
CO peak strong
Examples
CC peak absent (or maybe weak)
CC peak present but weak
  • Caution!
  • Weak peaks not always discernable
  • Be careful when excluding symmetrical functional
    groups base on absence of peak

11
Structure versus Stretching Frequency
  • Hookes Law (1660)
  • Stretching frequency of two masses on a spring

? bond order
C-C CC C?C
12
Characteristic Stretching FrequenciesThe Five
Zones
IR spectrum divided into five zones (groups) of
important absorptions
13
Characteristic Stretching FrequenciesThe Five
Zones
attached to benzene ring attached to alkene
14
Characteristic Stretching FrequenciesThe Five
Zones
CO frequencies 20-40 cm-1 lower when conjugated
to a pi bond
15
Characteristic Stretching FrequenciesThe Five
Zones
  • Complete table Thinkbook, inside front cover
  • What do I have to know?
  • Functional groups in each zone ? Learn by working
    lots of problems
  • Do not memorize stretching frequencies table
    given on exam

16
Guided Tour of Functional GroupsTerminal Alkyne
17
Guided Tour of Functional GroupsTerminal Alkene
18
Guided Tour of Functional GroupsAlcohol
19
Guided Tour of Functional GroupsKetone
20
Infrared Spectroscopy Part 2
  • Lecture Supplement
  • Take one handout from the stage

21
Infrared Spectroscopy Part 1 Summary
  • Infrared photons cause excitation of molecular
    vibrations
  • Photon absorption probability higher with more
    polar bonds
  • Energy of photons absorbed depends on

Bond order Masses of atoms bonded
  • IR spectrum divided into five zones
  • Each zone analyzed for absence or presence of
    functional groups
  • Stretching frequency, peak shape both important

Alcohol O-H usually gives broad peak CO stretch
gives strong peak
22
Guided Tour of Functional GroupsKetone (again)
23
Guided Tour of Functional GroupsAldehyde
24
Guided Tour of Functional GroupsKetone with
Alkene Conjugation
Conjugation with pi bond lowers CO stretch by
20-40 cm-1
25
Guided Tour of Functional GroupsEster
26
Guided Tour of Functional GroupsCarboxylic Acid
27
Guided Tour of Functional GroupsBenzene Ring
28
Five Zone IR Spectrum AnalysisExample 1 C6H12O2
1700 cm-1
Step 1 Calculate DBE DBE C - (H/2) (N/2)
1 6 - (12/2) (0/2) 1 1
One ring or one pi bond
29
Five Zone IR Spectrum AnalysisExample 1 C6H12O2
1700 cm-1
  • Step 2 Analyze IR Spectrum
  • Zone 1 (3700-3200 cm-1)

Alcohol O-H N-H ?C-H
Absent - no N in formula Absent - not enough DBE
30
Five Zone IR Spectrum AnalysisExample 1 C6H12O2
1700 cm-1
  • Zone 2 (3200-2700 cm-1)

Aryl/vinyl sp2 C-H Alkyl sp3 C-H Aldehyde
C-H Carboxylic acid O-H
Probably not (not enough DBE)
Absent - no 2700 cm-1 Absent - not broad enough
31
Five Zone IR Spectrum AnalysisExample 1 C6H12O2
1700 cm-1
  • Zone 3 (2300-2000 cm-1)

Alkyne C?C Nitrile C?N
Absent - no peaks not enough DBE Absent - no
peaks not enough DBE
32
Five Zone IR Spectrum AnalysisExample 1 C6H12O2
1700 cm-1
  • Zone 4 (1850-1650 cm-1)

CO
Possibilities ketone ester
- not enough oxygens
aldehyde - no 2700 cm-1 peak
carboxylic acid - zone 2 not broad
amide - no nitrogen
33
Five Zone IR Spectrum AnalysisExample 1 C6H12O2
1700 cm-1
  • Zone 5 (1680-1450 cm-1)

Benzene ring Alkene CC
Absent - no peak 1600 cm-1 not enough
DBE Absent - no peak 1600 cm-1 not enough DBE
34
Five Zone IR Spectrum AnalysisExample 2 C8H7N
Step 1 Calculate DBE DBE C - (H/2) (N/2)
1 8 - (7/2) (1/2) 1 6
Six rings and/or pi bonds Possible
benzene ring
35
Five Zone IR Spectrum AnalysisExample 2 C8H7N
  • Step 2 Analyze IR Spectrum
  • Zone 1 (3700-3200 cm-1)

Absent - no oxygen in formula Absent - peaks too
small Absent - peaks too small
Alcohol O-H N-H ?C-H
36
Five Zone IR Spectrum AnalysisExample 2 C8H7N
  • Zone 2 (3200-2700 cm-1)

Aryl/vinyl sp2 C-H Alkyl sp3 C-H Aldehyde
C-H Carboxylic acid O-H
Present - peaks gt 3000 cm-1
Present - peaks lt 3000 cm-1
Absent - no 2700 cm-1 no CO in zone 4 Absent -
not broad enough CO in zone 4
37
Five Zone IR Spectrum AnalysisExample 2 C8H7N
  • Zone 3 (2300-2000 cm-1)

Alkyne C?C Nitrile C?N
Possible Possible
38
Five Zone IR Spectrum AnalysisExample 2 C8H7N
  • Zone 4 (1850-1650 cm-1)

CO Absent - no peak no oxygen in formula
39
Five Zone IR Spectrum AnalysisExample 2 C8H7N
  • Zone 5 (1680-1450 cm-1)

Benzene ring Alkene CC
Present - peaks 1600 cm-1 and 1500 cm-1
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