Title: Milster, Socha, Brooker
1Basics of Optical Imaging in Microlithography A
"Hands-on" Approach
- Tom D. Milster (University of Arizona)
- Robert Socha (ASML)
- Peter Brooker (SYNOPSYS)
- Thanks to
- Del Hansen
- Phat Lu
- Warren Bletscher
2What we want to do with this course
From This
To This
- Take a complicated optical system, like a
lithographic projection camera used to make
computer chips, and simplify it to a working
model that demonstrates basic principles. - Use a simple optical system for the student to
work with hands on and observe the results. - Demonstrate the relationship of the simple system
to a real lithographic system through a
commercial simulator. - Have fun and demonstrate our unparalled acting
abilities
3OUTLINE
- Intro
- Basic Imaging What we do in lithography
- The goal of making a small image
- What limits the size of the image?
- Basic Illumination and Imaging
- Koehler Illumination
- Definition of coherence factor sigma
- Binary Mask
- Contrast versus pitch for sigma 0
- Contrast versus pitch for sigma gt 0
- 2-Beam and 3-Beam Imaging
- Focus behavior
- Phase Mask
- Contrast versus pitch
- Focus behavior
- Off-Axis Illumination
- Contrast versus pitch
- Focus behavior
- Summary
4Introduction
- What is photo lithography ?
- Optical image is recorded in the resist via
changes in concentrations of species. - Concentration level controls development
Object reticle or mask
Optics
Aerial Image
Photoresist
Wafer films
Latent Image
Photoresist Development
Resist Cross sections
Negative Photoresist
Positive Photoresist
Etymology Photolithography Light Stone
Writing
5Introduction
- 1st approximation is that Aerial image propagates
into photoresist normal to the wafer plane,
creating a latent image - Reality is more complicated you need to
calculate E fields in photoresist at many
propagation angles
0.25mm 5-BAR Structures Focus0.0mm, NA0.57
NA0.6, 248nm
Z
Image Cross Section
Z
Resist Cross Section (not top down!)
6Introduction
- The goal of making a small image
- Transfer image into a photosensitive material,
i.e., photoresist, for subsequent processing that
results in a desired pattern to be used as a
stencil
photoresist
7Introduction
- Imaging Resolution and Lord Rayleigh
- Q When can you resolve the image of 2 distance
stars? - A When the 1st Intensity min of one lines up
with peak of other
Large l
Small NA
Decrease l
Increase NA
Large NA
From the math of the Airy function
Web Top Optics, 1999
8- Oh Master-Litho
- ..what limits the size of the photoresist
pattern? - Grasshopper, there are three paths to improve
resolution - Reduce Wavelength (Lambda)
- Increase numerical aperture (NA)
- Decrease k1 Process knob
- Includes off-axis illumination, complex masks,
high contrast photoresist, acid diffusion, etc - .now go away Grasshopper I am busy.
9- What is it now Grasshopper
- Master, what affects the contrast of the image?
- The answer is found in the values of
- NA
- CD and Pitch
- Partial Coherence or illumination (s)
- s0 Coherent Limit
- s1 Incoherent Limit
10- You again grasshopper
- Master
- look at the following data
11Effect of Varying s
l193nm, NA0.75 Dense Lines vs. s (circular)
150nm L/S
100nm L/S
- Master, how come in one case increasing sigma is
good (100nm L/S) and in the other case,
increasing sigma is bad (200nm L/S)? - It depends on the amount of diffraction orders
that are being collected by the lensnow go away!
12- Master, I am sure that your answers are correct
but - yes Grasshopper
- But I find these facts confusing. What is sigma?
How can in some cases a larger sigma be good and
in other cases a larger sigma be bad? And what
the heck is k1? - MasterI do not want only the answersI want to
understandplease help me understand master - Grasshopper you are finally asking the right
question - Go to the optical bench now
- It holds the answer to your questions!!
13Basics of Imaging in Lithography Experimental
Layout
14First Light Get An Image
- Lets do an experiment
- Set up the bench with
- Pinhole Source
- Aperture Stop of 6.35 mm (1/4 in) diameter.
- Put in the L (25.2µm) pitch mask and observe the
aerial image. - The grating simulates a mask.
- The aerial image simulates what is used to expose
the resist. - In our system, the aerial image is reimaged onto
a CCD camera, which is like an Aerial Image
Measurement System (AIMS). - Draw picture of the light pattern at the stop.
15Basic Illumination and Imaging
Image of source
Stop
Mask Plane
Source Aperture
Aerial Image
Lens 1
Lens 2
Condenser
Imaging Lens
- Field Stop of Imaging Lens is Aperture stop
condenser and vice versa - Lithographic systems use Koehler illumination
where the illumination source aperture is imaged
into the stop of the imaging lens.
16Basic Illumination and Imaging
- Definition of Coherence Factor Sigma
Stop Diameter
Source Image Diameter
Mask Plane
Pupil Edge (the NA)
Source
Source Image
Imaging Lens
View of Entrance Pupil with blank mask
Condenser
17Simple Binary Mask
- Model a Cr on quartz grating mask as an
infinitely thin grating
Note For 11 lines and spaces, P 2 LW LW
Line Width
P
SiO2
Cr
E-Field
Position
3
-3
Grating Equation
q
Diffraction Orders
2
-2
1
-1
0
Lens/Pupil
18Effect of Varying Pitch
- Lets do an experiment
- Set up the bench with
- Pinhole Source
- Aperture Stop of 6.35 mm (1/4 in) diameter.
- Use the S(8.4µm), M(12.6µm) and L(25.2µm) pitches
of the mask and observe the effects in the image
plane and at the stop. - Draw the light pattern at the stop on the next
page. - What is the relationship between the light
pattern at the stop and the image? - What is the smallest pitch for which we can
obtain an image? - This system is very similar to what would be
observed if an on-axis laser beam was used to
illuminate the mask. Therefore, we call this
case coherent imaging. - Notice that the lines in the image are either
completely resolved, or they are not. There is
no partially resolved case.
19Effect of Varying Pitch
20Binary Mask and Diffraction Orders
- Must have more than 1 order in pupil to have
image modulation
3
Pupil (stop)
1
o
Strong Image Modulation
-1
We see diffraction orders emanating from the mask
that are necessary for imaging.
-3
For 11 grating
Coherent limit
pupil
1
qMax
o
Pmin is the minimum pitch that is at the limit of
resolution.
-1
NAsin(qMax)
k11/2
1
pupil
qMax
No Image just constant Irradiance
o
-1
21Coffee Break
22- Time for the Late Shows new and exciting quiz
game sensation. - Do you want to play
- Know your Current events?
- Know your Cuts of Beef?
- Know your Optics Bench Basics?
- Know your Bench Basics! Excellent choice!!!
23Bench basics
- Where is the Source Aperture relative to the
condenser lens? - Is it
- A at minus infinity
- B it refuses to reveal its location
- C The source aperture is located at the front
focus of the condenser lens - Answer is C The source aperture (effective
source for the system) is located at the focus of
the condenser lens. Collimated light from the LED
illuminates the grating. Light from every part of
the source aperture illuminates each point on the
grating.
24Bench basics
fc
f1
f2
fc
f1
f2
2fcam
2fcam
- Q Where does the image of the Source Aperture
appear? - Does it appear
- A only in the Borg space time continuum
- B at the grating
- C in the plane of the Stop.
- Correct answer is C The image of the Source
Aperture appears in the plane of the stop.
25Bench basics
- Q Collimated light from the Source Aperture
illuminates the Grating. This is because. - A The grating is not worthy of the sources
focused attention - B The source is the gratingquestion is
irrelevant - C Kohler Illumination of the grating averages
out non uniformities in the source. - Answer is C
26- Comedy writers strike
- No more multiple choice answers
- Lets continue to cement the concepts associated
with the bench
27Bench Basics
- Q Where is the grating located with respect to
Lens1? - A The grating is located at the focus of lens 1.
- Q Where does the image of the grating appear?
- A The image of the grating appears at the Image
plane
28Bench Basics
- Q If the Image occurs at the image plane, why is
the microscope needed? - A The image of the source at the image plane
cannot be seen with the eye. The microscope is
needed to magnify the image so it can be seen by
your eye.
29Bench Basics Grating off axis point
- Q Look at the above picture. Estimate the
vertical magnification? - 3.7
- How can the vertical magnification be decreased?
- Decrease f2 but keep Stop at focus of Lens2.
30Connection back to real Scanner Optics
- Q Where is the mask plane and image of the mask?
- A First plane on the left and last plane on
right. - Q Can you find the stop in the lens column?
- A On the right side of center.
- Q What is the magnification?
- A 4x demagnification.
31Effect of Varying Sigma
- Lets do an experiment
- Set up the bench with
- Pinhole Source
- Aperture Stop of 6.35 mm diameter.
- S(8.4µm) grating
- Use the PH, 3.18mm (1/8 in) and 6.35mm (1/4in)
diameter sources and observe the effect at the
stop and at the image plane. Estimate ? for each
source. - Draw the light pattern at the stop on the next
page. - Is there a point where we can resolve the lines
in the image? - By changing ?, we are allowing more light through
the stop that can interfere to form an image. - Not all of the light that is passed through the
stop can interfere, thus giving us background
light that reduces our contrast. The amount of
background light is a function of the pitch,
therefore the contrast is a function of the
pitch. - This case is called partially coherent imaging,
because of the dependence of the contrast on
pitch.
32Effect of Varying Sigma
33Contrast Curves versus Pitch Sigma
- Sigma0.05 ---Coherent
- Sigma0.5 -----Partially Coherent
- Sigma1 ---Incoherent limit
34Modulation Transfer Function (MTF)
- Optics types love this plot!!!!
- Can you find the Coherent frequency cut off?
35Binary Mask Influence of Sigma
- Pupil diagrams with Partial Coherence
We must have at least 2 conjugate sources points
in the pupil to form an image.
NA
s
Imaging!!
- Each source point is projected by the diffraction
orders from the mask - These will interfere with each other for a given
source point - need more than 1 for interference and hence image
modulation
36Binary Mask Sigma lt 1
Resolution limit with 0ltslt1 for a circular source
- No grating - just blank mask
- Grating period at cut-off frequency
- Grating period resolution limit at given ?
1st
-1st
0th order
37Binary Mask Sigma 1
Resolution limit with s1 for a circular source
- No grating - just blank mask
- Grating period at cut-off frequency
- Grating period corresponds to incoherent cut-off
38Binary Mask, l248nm, NA0.63
39s0.05 s 0.7 for k10.5
40Different cases for on axis, k10.5
- Assume circular, on axis illumination
- Assume dense L/S
- k10.5
- ? Center of n1 diffraction orders are at edge of
lens - ? CD LW 0.5Lambda/NA
- For 248nm illumination, NA0.63
- CD 0.5248nm/0.63 197nm ? 200nm L/S give
k10.5 - For 193nm illumination, NA0.93
- CD 0.5193nm/0.93 104nm ? 104nm L/S give
k10.5 - For 193nm illumination, NA 1.2
- CD 0.5193/1.2 80.4nm ? 80nm L/S gives k1
0.5 - Results above are only good for on axis
illumination. - The usual off-axis case is different.
41Binary Mask Round and Annular Illumination
Small s and k1gt0.5
Larger s and k1lt0.5
- All power is inside pupil (for 0th and ?1st
orders) - Coherent source points have 3-beam interaction
- Some power is inside pupil (center of ?1st
orders is outside) - Coherent source points have 2-beam interaction
Conventional or Circular Source
Annular Source
42Binary Mask 3-Beam Imaging
- Lets do an experiment
- Set up the bench with
- L(25µm) Pitch grating
- PH Source
- Observe the behavior (position and contrast) of
the image as the observation plane is moved from
the perfect focus. Write down your observations. - What happens as the observation plane is moved
beyond the point of zero contrast?
43Binary Mask 3-Beam Imaging
- Do you see reversed-contrast lines?
- This type of focus behavior is indicative of
three-beam imaging, where all of the power from
the 0 and /- 1st diffraction orders passes the
stop. - Every point in the image is derived from three
conjugate source points in the pupil. - Three-beam imaging has the characteristic that
reversed-contrast planes can occur if the focus
is too far or the resist is too thick.
44Binary Mask, l248nm, NA0.63, 300nm L/S
3-Beam Imaging
45Missing Orders
- Lets do an experiment
- Set the bench with
- L(25 µm) pitch
- PH source
- Draw a sketch of the image on the next page.
- Block the zero diffraction order at the stop.
- Draw a sketch of the image on the next page.
- Does the pitch of the image change?
- This type of focus behavior is indicative of
two-beam imaging. - Every point in the image is derived from two
conjugate source points in the pupil, which are
widely separated and lead to a double-frequency
image. - Now change the system to block either the 1 or
-1 order, but let the zero order pass the stop. - Draw a sketch of the image on the next page.
- Observe the image pitch and defocus behavior.
Write down your observations.
46Missing Orders
47Binary Mask, l248nm, NA0.63, 250nm L/S
48Phase Mask
P
E
E-Field
-5
Diffraction Orders
Grating Equation
5
-3
3
q
1
-1
Lens/Pupil
1st
-1st
49Pure Phase Chromeless
E
1
P
E-Field
-1
Position
Diffraction Orders
-5
Grating Equation
5
-3
3
q
1
-1
Lens/Pupil
1st
-1st
50Phase Mask
- The phase mask produces no zero order
3
Pupil (stop)
1
Strong Image Modulation
-1
No zero order is emitted from the phase mask.
-3
For alternating phase shift grating
Coherent limit
pupil
1
qMax
pmin is the minimum Cr pitch that is at the limit
of resolution.
-1
NAsin(qMax)
k11/4
1
pupil
qMax
No Image just constant Irradiance
-1
51Phase Mask
- Lets do an experiment
- Set the bench with ?.
- 12.5µm Pitch Phase Mask
- 14.25mm Diameter stop (No Magnet)
- 3mm Diameter Source (? 0.3)
- Observe the light pattern at the stop. How many
diffraction orders do you see? - Draw a sketch of image and the light pattern at
the stop on the next page. - Note the relative brightness of the zero order
and the /-1st orders. If needed, remove the
grating to identify where the zero order occurs. - Observe the line pattern at the observation
plane. (Block the zero order if present) - How does the image pitch compare to using a
simple grating mask?
52Phase Mask
- Change the observation plane location. How
sensitive is the observationplane location to
focus changes? - The phase mask has no zero order, and it produces
a double-frequency pitch in the aerial image
compared to a binary mask. - The minimum pitch in the image is half the
minimum pitch of a simple grating mask. - The phase-mask image is relatively insensitive to
focus changes, due to the missing zero order.
53l248nm, NA0.63, sigma 0.3
54Off-Axis Illumination
- Illumination source shapes that do not have axial
intensity as usually known as off-axis sources - Examples are annular, quadrupole, and dipole
- Off-axis illumination helps to enable k1lt0.5 with
binary masks - Reduction of on axis source reduces DC terms
and enhances contrast - A conventional on axis small source
- Some Off-axis sources
55Coherent Off-Axis Illumination and a Binary Mask
- Orders shift relative to pupil
Image Modulation
For 11 grating
Incoherent limit
qMax
Pmin is the minimum pitch that is at the limit of
resolution.
NAsin(qMax)
k11/4
pupil
0
qMax
No Image just constant Irradiance
-1
56Binary Mask with Annular Illumination
Resolution limit with 0ltslt1 for a circular source
?outer
- No grating - just blank mask
?center
?inner
0th order
- Grating period at cut-off frequency
-1st
1st
0th order
- Grating period resolution limit at given ?
-1st
1st
0th order
57Off-Axis Illumination with a Binary Mask
- Lets do an experiment
- Set up the bench with system for minimum ?.
- S(8.2µm) pitch mask
- PH Source centered on axis
- Observe the pattern at the stop. Draw the light
pattern at the stop on the next page. - Do you see an image? Sketch the camera output on
the next page. - Move the source until at least two orders pass
through the stop. Draw the pattern at the stop
and the image on the next page.
58Off-Axis Illumination with a Binary Mask
59l248nm, NA0.63, sigma 0.3
60Different cases for off axis, k10.25
- Assume off axis illumination
- Assume dense L/S
- k10.25
- ? Center of n0 and n1 diff. orders are at edge
of lens - ? CD LW 0.25Lambda/NA
- For 248nm illumination, NA0.63
- CD 0.5248nm/0.63 98nm ? 100nm L/S give
k10.25 - For 193nm illumination, NA0.93
- CD 0.25193nm/0.93 52nm ? 50nm L/S give
k10.25 - For 193nm illumination, NA 1.2
- CD 0.25193/1.2 40.2nm ? 40nm L/S gives k1
0.25 - Current off-axis results.
- Actually might want whole orders inside with
sigma0.3
61Summary
- What have we learned?
- The basic optical components of a lithography
system are the source, condenser and imaging
lens. - The size and shape of the source influence
properties of the aerial image. - The stop of the system determines the maximum
angle of diffraction orders that can pass to the
image. - It takes at least two diffraction orders passing
the stop to form a line-space image. - By increasing ?, we can change from coherent-like
illumination to partially-coherent illumination. - Partially coherent illumination can allow higher
pitch in the image at the expense of reduced
contrast. - 2-Beam and 3-Beam geometries have different focus
characteristics. - By using a phase-shift mask, the zero order is
eliminated and the first diffraction orders move
closer to the center. - Off-axis illumination can produce a half-pitch
image, but the contrast is lower than with a
phase-shift mask.
62References
- Introductory Articles
- SPIE Proceedings for Microlithography
- Journal of Microlithography, Microfabrication,
and Microsystems (JM3) SPIE Press - Industry Magazines
- Microlithography World
- www.pennwell.com
- Books
- Intro to Fourier Optics and Statistical Optics
- by J. Goodman
- Resolution Enhancement Techniques and Optical
Imaging in Projection Microlithography - Alfred Wong, SPIE Press
- Microlithography Science and Technology
- Ed James Sheats and Bruce Smith
- Pub Marcel Dekker
63References
- Intro Papers
- Using location of diffraction orders to predict
performance of future scanners, - Peter Brooker Publication Proc. SPIE Vol.
5256, p. 973-984, 23rd BACUS (2003) - Roles of NA, sigma, and lambda in low-k1 aerial
image formation, - Peter D. Brooker Publication Proc. SPIE Vol.
4346, p. 1575-1586, (2001) - Advanced Papers
- U of A Dissertation by Doug Goodman (1979),
Stationary Optical Projectors - Papers by H.H. Hopkins for partial coherent
imaging, Richards and Wolf for high NA
64Thank You for Taking This Course!
65Backup Slides
66Basic Illumination and Imaging
- Pupil or the aperture stop Physical Limiting
aperture of system - Location and size defined by Chief Ray and
Marginal Ray - Chief Ray Starts at edge of object (field) goes
through center of pupil - Marginal Ray Starts at axial object and goes
through edge of pupil
Pupil
Object
n image side refractive index
Chief ray
Aerial Image
h
Marginal ray
h
n object side refractive index
- NA numerical aperture
- defined by marginal ray
- maximum angle accepted by system
67Basic Illumination and Imaging
Imaging Lens
- Lets do an experiment
- Calculate NA at the image plane for rs _______
. -
- Calculate the coherent resolution limit in terms
of pitch in the aerial image.
rs
?m
68Optimum DOF and Modulation for Annular (and
dipole)
0
1
-1
- Optimum when phase differences between 0th and
1st orders are minimum
69Optimum DOF and Modulation for Quadrupole
0
1
-1
NA scenter
l/Pitch
- Optimum when phase differences between 0th and
1st orders are minimum
70Off-axis Illumination PrinciplesEffects of
different illumination modes
- Periodic features benefit most from QUASAR
illumination - Optimum illumination is specific to reticle
features
71More Facts Aerial Image Cross Section
l193nm, NA0.75 Dense Lines vs. s (circular)
Varying s
100nm L/S
150nm L/S
- Increase sigma and contrast goes up (100nm L/S)
- Increase sigma and contrast goes down (200 nm
L/S) - Very confusing!!! What is going on??
72Lithography Imaging Laws
- What limits the size of the photoresist pattern ?
- Three paths to improve resolution
- Wavelength (l)
- Numerical Aperture (NA)
- k1 Process knob
- Includes off-axis illumination, complex masks,
high contrast photoresist, acid diffusion, etc - What limits the size of the optical (and/or
aerial) image? (Assuming circular illumination
source and binary reticle) - NA
- l
- Partial Coherence or illumination (s)
- s0 Coherent Limit
- s1 Incoherent Limit
- Finebut where do these come from??
- Note resolution is often written as Linewidth
(LW) or critical dimension (CD) in the context
with photoresist
73Basic Illumination and Imaging
- Definition of Coherence Factor Sigma
Stop Diameter
Source Image Diameter
Mask Plane
Pupil Edge (the NA)
Source
Source Image
Imaging Lens
View of Entrance Pupil with blank mask
Condenser
If pupil diameter NA, then source size NA
s (pupil or NA units)