Title: Solution Stoichiometry
1Solution Stoichiometry
- Edward A. Mottel
- Department of Chemistry
- Rose-Hulman Institute of Technology
2Concentration Units
- Reading Assignment
- Zumdahl Chapter 4.1-4.3, 5
- Solutions can be described by several different
concentration units. - Density ( r )
- Mole Fraction (c)
- Molality (m)
- Molarity (M)
- Parts per Million (ppm)
3Applications
- Density (mass per volume)
- rough measure of concentration
- battery acid
- anti-freeze
- Mole Fraction (moles / total moles)
- colligative property measurements
- gas mixtures, vapor pressure, distillation
4Applications
- Molality (moles of solute / kilogram of solvent)
- colligative property measurements
- change in freezing point, boiling point
- vapor pressure, osmotic pressure
- Molarity (moles of solute / liter of solution)
- bench top laboratory applications
- titration
5Applications
- Analytical applications
- Parts per Million (ppm)
- trace analysis, impurities
- Parts per Billion (ppb)
- environmental
- Parts per Trillion (ppt)
6Preparation of Solutions
- From pure compounds
- By the mixture of a solid and a solution
- By the mixture of two solutions
- Note
- masses are always additive
- volumes involving concentrated solutions may not
be additive
7Solution Preparation
- Prepare 500. mL of 3.0 M sulfuric acid from
sulfur trioxide gas and water. - Outline the process
- Solve the problem
8Prepare 500. mL of 3.0 M sulfuric acid from
sulfur trioxide gas and water.
9Prepare 500. mL of 3.0 M sulfuric acid from
sulfur trioxide gas and water.
- Dissolve 120. grams of sulfur trioxide in enough
water to give 500. mL of solution.
10Solution Preparation
- Prepare 275 mL of 0.450 M aqueous sulfuric acid
solution from 18.0 M sulfuric acid and water. - Outline the process
- Solve the problem
11Prepare 275 mL of 0.450 M aqueous sulfuric acid
solution from 18.0 M sulfuric acid and water.
Write a balanced equation
Define terms
12Prepare 275 mL of 0.450 M aqueous sulfuric acid
solution from 18.0 M sulfuric acid and water.
Dissolve 6.87 mL of 18.0 M sulfuric acid in some
water and then dilute to 275 mL of total
solution volume.
13Solution Preparation
- Prepare 400. mL of 2.50 M sulfuric acid from 1.00
M sulfuric acid and 6.00 M sulfuric acid. Assume
volumes are additive. - Outline the process
- Solve the problem
14Prepare 400. mL of 2.50 M sulfuric acid from
1.00Â M sulfuric acid and 6.00 M sulfuric acid.
Write a balanced equation
Define terms
15Prepare 400. mL of 2.50 M sulfuric acid from
1.00Â M sulfuric acid and 6.00 M sulfuric acid.
Volumes of reactants needed
Write a balanced equation
What information would be needed if this
isnt assumed?
Define terms
16Prepare 400. mL of 2.50 M sulfuric acid from
1.00Â M sulfuric acid and 6.00 M sulfuric acid.
x mL of 1.00 M H2SO4
y mL of 6.00 M H2SO4
x y 400 mL
(x 1.00 M) (y 6.00 M) 400 mL 2.50 M
y 120. mL
17Neutralization
- Balanced Equation
- Moles react with moles
moles of acid moles of base
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