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Limiting Reactants

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Limiting Reactants & Percent Yield. Continuation from Stoichiometry. A. Types of Reactants ... B. Reactants Stoichiometry Problems. 4 NH3 5 O2 4 NO 6 H2O ... – PowerPoint PPT presentation

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Title: Limiting Reactants


1
Limiting Reactants Percent Yield
  • Continuation from Stoichiometry

2
A. Types of Reactants
  • 1. Limiting Reactant
  • Limits the amounts in a chemical reaction (the
    other reactant all products)

2. Excess Reactant The substance not used up
in the reaction (more than enough)
3
B. Reactants Stoichiometry Problems 4 NH3 5 O2
? 4 NO 6 H2O
  • 1. Which is the limiting reactant when 7.50 mol
    NH3 is mixed with 11.0 mol O2?

7.50 mol NH3
5 mol O2

X
4 mol NH3
9.38 mol O2
NH3 is the limiting reactant.
4
2. What is the excess reactant? How much of
the excess reactant is left over in moles?
  • Oxygen is the excess reactant
  • 11.0 mol 9.38 mol 1.62 mol

5
3. How much of each product is formed in
moles?
7.50 mol NH3
4 mol NO

X
4 mol NH3
7.50 mol NO
7.50 mol NH3
6 mol H2O

X
4 mol NH3
11.3 mol H2O
6
If 20.5 g NH3 react with 20.5 g O2, which is the
limiting reactant? How do you know?
20.5 g NH3
160.0 g O2

X
68.16 g NH3
48.1 g O2
O2 is the limiting reactant because 48.1 g are
needed but there are only 20.5 g available.
7
C. Types of Yields of Products
  • Theoretical Yieldthe calculated amount that
    should be produced
  • Actual Yieldthe measured amount of a product
  • Percent Yieldthe efficiency of the reaction
    found from the ratio of the actual yield to the
    theoretical yield x 100 ( A/T x 100)

8
D. Yield Stoichiometry Problems 4 NH3 5 O2 ?
4 NO 6 H2O
  • When the proper amount of NH3 reacts with enough
    O2, 120.0 g of NO was produced. Tom performed the
    experiment, but actually produced 98.0 g NO. What
    is the yield of NO?

98.0 g NO
X 100

81.7
120.0 g NO
9
  • 2. When 36.8 g of NH3 react with excess of
    oxygen, the actual yield of water is 56.2 g. What
    is the yield of water?

36.8 g NH3
X
108.1 g H2O

68.16 g NH3
58.4 g H2O
56.2 g H2O
X 100

96.2
58.4 g H2O
10
  • 3. When 204.8 g of O2 react with excess of NH3,
    the actual yield of water is 75.83 g. What is the
    yield of water?

204.8 g O2
X
108.1 g H2O

160.0 g O2
138.4 g H2O
75.83 g H2O
X 100

54.79
138.4 g H2O
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