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Title: Exam II Lectures and Text Pages


1
Exam II Lectures and Text Pages
  • I. Cell Cycles
  • Mitosis (218 228)
  • Meiosis (238 249)
  • II. Mendelian Genetics (251 270)
  • III. Chromosomal Genetics
  • IV. Molecular Genetics
  • Replication
  • Transcription and Translation
  • V. Microbial Models
  • VI. DNA Technology

2
Monohybrid Crosses
  • When Mendel crossed contrasting, true-breeding
    white-flowered and purple-flowered pea plants
  • All of the F1 offspring were purple-flowered
  • When Mendel crossed the F1 plants
  • Many of the F2 plants had purple flowers, but
    some had white flowers
  • The traits did NOT blend

3
Large Samples and Accurate Quantitative Records
  • Mendel hypothesized that if the inherited factor
    for white flowers had been lost, then a cross
    between F1 plants should produce only
    purple-flowered plants in the F2.

Figure 14.3
4
Genes
  • Mendel reasoned that since the inheritable factor
    for white flowers was not lost in the F1
    generation, it must be masked by the presence of
    the purple-flower factor.
  • Mendel's factors are now called genes and in
    Mendel's terms, purple flowers is the dominant
    trait and white flowers is the recessive trait.

5
Repeated Experiments
  • Mendel observed the same pattern in many other
    pea plant characters

6
Mendels Model
  • Mendel developed a hypothesis
  • To explain the 31 inheritance pattern that he
    observed among the F2 offspring
  • Four related concepts make up this model

7
Alleles
  • First, alternative versions of genes
  • Account for variations in inherited characters,
    which are now called alleles

8
Alleles Occur in Pairs in Diploid Organisms
  • Second, for each character
  • An organism inherits two alleles, one from each
    parent
  • A genetic locus is actually represented twice
  • Homologous loci may have identical alleles as in
    Mendel's true-breeding organisms, or the two
    alleles may differ, as in F1 hybrids.

9
Dominance vs. Recessiveness
  • Third, if the two alleles at a locus differ
  • Then one, the dominant allele, is completely
    expressed (designated by a capital letter)
  • The other allele, the recessive allele, is
    completely masked (designated by a lowercase
    letter)

10
Law of Segregation
  • Fourth, the law of segregation
  • The two alleles for a heritable character
    separate (segregate) during gamete formation and
    end up in different gametes
  • Without any knowledge of meiosis, Mendel deduced
    that a gamete carries only one allele for each
    inherited characteristic, because the alleles of
    a pair separate (segregate) from each other
    during gamete production.
  • Gametes of true-breeding plants will all carry
    the same allele.
  • If different alleles are present in the parent,
    there is a 50 chance that a gamete will receive
    the dominant allele, and a 50 chance that it
    will receive the recessive allele.

11
Law of Segregation, Probability and the Punnett
Square
  • Does Mendels segregation model account for the
    31 ratio he observed in the F2 generation of his
    numerous crosses?

12
Genetic Vocabulary
  • An organism that is homozygous for a gene
  • Has a pair of identical alleles (PP or pp)
  • All gametes carry that one type of allele
  • Exhibits true-breeding
  • An organism that is heterozygous for a gene
  • Has a pair of alleles that are different (Pp)
  • Half the gametes carry one allele and half carry
    the other
  • Is not true-breeding

13
Phenotype versus genotype
The phenotype is expressed traits - In the
flower color experiment, the F2 generation had a
31 phenotypic ratio of purple-flowered to
white-flowered plants. The genotype is genetic
makeup - The genotypic ratio of the F2
generation was 121
14
The Testcross
  • In pea plants with purple flowers
  • The genotype is not immediately obvious
  • It may be homozygous dominant (PP) or
    heterozygous (Pp).
  • To determine whether such an organism is
    homozygous dominant or heterozygous, we use a
    testcross.

15
The Testcross
  • Crossing an individual of unknown genotype with a
    homozygous recessive


Example If a cross between a purple-flowered
plant of unknown genotype (P_) produced only
purple-flowered plants, the parent was probably
homozygous dominant since a PP x pp cross
produces all purple-flowered progeny that are
heterozygous (Pp). If the progeny of the
testcross contains both purple and white
phenotypes, then the purple-flowered parent was
heterozygous since a Pp X pp cross produces Pp
and pp progeny in a 11 ratio.
?
Dominant phenotype, unknown genotype PP or Pp?
Recessive phenotype, known genotype pp
If PP, then all offspring purple
If Pp, then 1/2 offspring purple and 1/2
offspring white
p
p
p
p
P
P
Pp
Pp
Pp
Pp
P
p
Pp
Pp
pp
pp
Figure 14.7
16
The Law of Independent Assortment
  • The law of segregation was derived
  • From monohybrid crosses using F1 monohybrids
    heterozygous for one character
  • The Law of Independent Assortment requires
  • Using dihybrid crosses between F1 dihybrids
  • Crossing two, true-breeding parents differing in
    two characters
  • Produces F1 dihybrids, heterozygous for both
    characters

17
The Dihybrid Cross
  • Illustrates the inheritance of two characters
  • Produces four phenotypes in the F2 generation
  • When the F1 dihybrid progeny self-pollinate.
  • If the two characters segregate together, the F1
    hybrids can only produce the same two classes of
    gametes (RY and ry) that they received from the
    parents, and the F2 progeny will show a 31
    phenotypic ratio.
  • If the two characters segregate independently,
    the F1 hybrids will produce four classes of
    gametes (RY, Ry, rY, ry), and the F2 progeny will
    show a 9331 phenotypic ratio.

Figure 14.8
18
The Law of Independent Assortment
  • Using the information from a dihybrid cross,
    Mendel developed the law of independent
    assortment
  • Each pair of alleles segregates independently
    from every other pair during gamete formation

19
Probability
  • Segregation, independent assortment and
    fertilization are random events and
  • Reflect the rules of probability
  • From the genotypes of parents, we can predict the
    most likely genotypes of their offspring using
    simple laws of probability.

20
Probability Scale
  • The probability scale ranges from 0 to 1 an
    event that is certain to occur has a probability
    of 1, and an event that is certain not to occur
    has a probability of 0.
  • The probabilities of all possible outcomes for an
    event must add up to 1.
  • Random events are independent of one another.
  • The outcome of a random event is unaffected by
    the outcome of previous such events.
  • Example it is possible that five successive
    tosses of a normal coin will produce five heads
    however, the probability of heads on the sixth
    toss is still 1/2.

21
Two basic rules of probability
1. Rule of multiplication states that the
probability that independent events will occur
simultaneously is the product of their individual
probabilities.
  • Question In a monohybrid cross between pea
    plants (Rr), what is the probability that the
    offspring will be homozygous recessive?
  • Answer
  • Probability that an egg from the F1 (Rr) will
    receive an r allele 1/2.
  • Probability that a sperm from the F1 will receive
    an r allele 1/2.
  • The overall probability that two recessive
    alleles will unite at fertilization 1/2 x 1/2
    1/4.

22
Multiplication also applies to dihybrid crosses
  • Question For a dihybrid cross, YyRr x YyRr, what
    is the probability of an F2 plant having the
    genotype YYRR?
  • Answer
  • Probability that an egg from a YyRr parent will
    receive the Y and R alleles 1/2 x 1/2 1/4.
  • Probability that a sperm from a YyRr parent will
    receive the Y and R alleles 1/2 x 1/2 1/4.
  • The overall probability of an F2 plant with the
    genotype YYRR 1/4 x 1/4 1/16.

23
Two Rules of Probability
  • 2. Rule of addition states that the probability
    of an event that can occur in two or more
    independent ways sum of the separate
    probabilities of the different ways.
  • Question In this cross between pea plants, Pp x
    Pp, what is the probability of the offspring
    being heterozygous?
  • Answer There are two ways a heterozygote may be
    produced the dominant allele (P) may be in the
    egg and the recessive allele (p) in the sperm, or
    vice versa.
  • So, the probability that the offspring will be
    heterozygous is the sum of the probabilities of
    those two possible ways
  • Probability that the dominant allele will be in
    the egg with the recessive in the sperm is 1/2 x
    1/2 1/4.
  • Probability that the dominant allele will be in
    the sperm and the recessive in the egg is 1/2 x
    1/2 1/4.
  • So, the probability that a heterozygous offspring
    will be produced is 1/4 1/4 1/2.

24
Complex Genetics Problems
  • A dihybrid or other multicharacter cross
  • Is equivalent to two or more independent
    monohybrid crosses occurring simultaneously
  • In calculating the chances for various genotypes
    from such crosses
  • Each character first is considered separately and
    then the individual probabilities are multiplied
    together

25
Multiple Locus Problem
  • Question What is the probability that a
    trihybrid cross between organisms with genotypes
    AaBbCc and AaBbCc will produce an offspring with
    genotype aabbcc?
  • Answer Segregation of each allele pair is an
    independent event, we can treat this as three
    separate monohybrid crosses
  • Aa x Aa probability for aa offspring 1/4
  • Bb x Bb probability for bb offspring 1/4
  • Cc x Cc probability for cc offspring 1/4
  • The probability that these independent events
    will occur simultaneously is the product of their
    independent probabilities (rule of
    multiplication).
  • The probability that the offspring will be aabbcc
    is 1/4 aa x 1/4 bb x 1/4 cc 1/64

26
Problem 2
  • Question Using garden peas, where and assuming
    the cross is PpYyRr x Ppyyrr what is the
    probability of obtaining offspring with
    homozygous recessive genotypes for at least two
    of the three traits?
  • Answer Write the genotypes that are homozygous
    recessive for at least two characters, (note that
    this includes the homozygous recessive for all
    three). Use the rule of multiplication to
    calculate the probability that offspring would be
    one of these genotypes. Then use the rule of
    addition to calculate the probability of
    offspring in which at least two of the three
    traits would be homozygous recessive.
  • Genotypes with at least two homozygous recessives
  • ppyyRr - 1/4 x 1/2 x 1/2 1/16
  • ppYyrr - 1/4 x 1/2 x 1/2 1/16
  • Ppyyrr - 1/2 x 1/2 x 1/2 2/16
  • PPyyrr - 1/4 x 1/2 x 1/2 1/16
  • ppyyrr - 1/4 x 1/2 x 1/2 1/16
  • 6/16 or 3/8 chance of two recessive traits

27
Particulate Behavior of Genes
  • Reviewing Mendels discoveries
  • If a seed is planted from the F2 generation of a
    monohybrid cross, we cannot predict with absolute
    certainty that the plant will grow to produce
    white flowers (pp). We can say that there is a
    1/4 chance that the plant will have white
    flowers. Alternatively, we can say that if
    there are several offspring, it is likely that
    1/4 of them will have white flowers.
  • Alleles are discrete units that segregate into
    separate gametes at meiosis. Each gene pair
    separates independently of all the other pairs.
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