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MAE 5310: COMBUSTION FUNDAMENTALS

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NO Dissociation: Complete Combustion. Equivalence ratio less than ... WITH Dissociation. Products formed include: CO2, CO H2O, H2, H, OH, O2, O, NO, N2, and N ... – PowerPoint PPT presentation

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Title: MAE 5310: COMBUSTION FUNDAMENTALS


1
MAE 5310 COMBUSTION FUNDAMENTALS
  • Lecture 5 Chemical Equilibrium
  • September 1, 2008
  • Mechanical and Aerospace Engineering Department
  • Florida Institute of Technology
  • D. R. Kirk

2
CHEMICAL EQUILIBRIUM
  • So far we have calculated adiabatic flame
    temperature assuming complete combustion
  • All fuel is completely oxidized to form CO2, H2O
    and excess O2 and N2 are carried through
    unaffected
  • This assumption is fine for T lt 1250 K, but most
    combustion systems operate at higher T
  • Species that are normally stable at ambient
    conditions dissociate
  • Concentration is determined by a balance between
    oxidation and formation
  • Balance is a function of T, P and concentration
  • Note The chemical equilibrium relations we will
    use still only approximate the species
    concentrations in a combustion process. That is,
    they rest on the assumption that the conditions
    are constant for a sufficiently long time for all
    the reactions to reach equilibrium

3
ADDITIONAL PRODUCT FORMATION
  • NO Dissociation Complete Combustion
  • Equivalence ratio less than or equal unity, f 1
  • The products formed are CO2, H2O, O2, and N2
  • Equivalence ratio greater than unity, f gt 1
  • The products formed are CO2, CO, H2O, H2, and N2
  • WITH Dissociation
  • Products formed include CO2, CO H2O, H2, H, OH,
    O2, O, NO, N2, and N
  • Concentration is dependent on T, P and f

4
CHEMICAL EQUILIBRIUM FOR A FIXED-MASS SYSTEM
  • If final temperature of combustion reaction is
    high enough, CO2 will dissociate
  • Can calculate adiabatic flame temperature as
    function of a (a fraction of CO2 dissociated)
  • Must consider second law dS 0
  • Composition of system will shift toward point of
    maximum entropy when approaching from either
    side, since dS is positive
  • Once maximum entropy is reached no further
    changes since would violate second law
  • (dS)U,V,m 0

5
PROPANE-AIR COMBUSTION AT 1 ATMAdopted From
Turns, S.R., Introduction to Combustion
6
2nd LAW OF THERMODYNAMICS GIBBS FREE ENERGY
  • To arrive at equilibrium relations, employ 2nd
    Law of Thermodynamics
  • State 2nd Law in terms of the Gibbs Free Energy,
    GH-TS
  • For a closed system at constant T and P, the
    Gibbs free energy is minimum at thermodynamic
    equilibrium

Basic Thermodynamic Relations
Criteria for Equilibrium
7
MORE USEFUL FORMS
  • GiHi-TSi
  • Separate Gi into a pressure dependent and term
    and pressure independent term
  • Recall that Cpi is not a function of pressure
  • The more negative DGº is, the larger Kp is and
    the more spontaneous the reaction is

Another useful form
Equation 40
8
COMMENTS ON KP
  • The Kp of a reaction depends on temperature only
  • Independent of pressure of the equilibrium
    mixture
  • Not affected by presence of inert gases
  • The Kp of the reverse reaction is 1/ Kp
  • The larger the Kp, the more complete the reaction
  • If Kp gt 1,000 (or ln Kp gt 7) reaction assumed
    complete
  • If Kp lt 0.001 (or ln Kp lt -7) reaction assumed
    not to occur
  • Mixture pressure affects the equilibrium
    composition (but not Kp)
  • Presence of inert gases affects the equilibrium
    composition
  • When stoichiometric coefficients are doubled, the
    value of Kp is squared
  • Free electronic in the equilbrium composition can
    be treated as an ideal gas
  • Equilibrium calculations provide information on
    the equilibrium composition of a reaction, not on
    the reaction rate.
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