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Chapter 3: Sampling Distribution

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Title: Chapter 3: Sampling Distribution


1
Chapter 3 Sampling Distribution
  • 3.1 Population and Sampling Distribution
  • 3.2 Sampling Distribution of
  • 3.3 Sampling Distribution of
  • 3.4 Sampling Distribution of s2

2
3.1 Population and Sampling Distribution
  • 3.1.1 Motivation and Definitions
  • 3.1.2 Population and Sampling Distribution

3
Motivation and Definitions
  • Statistical Inference
  • Arriving at conclusions concerning a population
    parameter.
  • Impossible or impractical to observe the entire
    set of observation that makes up the population,
    therefore we must depend on a subset of
    observations from population (or called the
    sample) that help us make inferences concerning
    that same population.

4
Population Sampling Distribution
  • Population is a collection or set, of all
    individuals, objects, or items of interest.
  • Population Parameters
  • Mean ?,
  • Variance ?2 ,
  • Proportion, p
  • Population Distribution
  • The probability distribution of the population
    data.
  • A sample is a portion, or part, of the population
    of interest.
  • A statistic is any quantity whose value can be
    calculated from a sample data. Sample statistics
    includes
  • Sample mean,
  • Sample variance, s2
  • Sample proportion,

5
Population Sampling Distribution
  • Sampling Distribution
  • The sampling distribution of a sample statistic
    is its probability distribution.
  • E.g. The sampling distribution of the sample
    mean, , is the probability distribution of
    .
  • Standard Error
  • The standard error of a statistic is the standard
    deviation of its sampling distribution.
  • Sampling Error
  • The difference between the value of a sample
    statistics and the value of the corresponding
    population parameter.
  • Nonsampling Error
  • The errors that occur in the collection,
    recording and tabulation of data.

6
3.2 Sampling Distribution of
  • 3.2.1 Shape of the Sampling Distribution of
  • 3.2.2 Central Limit Theorem
  • 3.2.3 Sampling Distribution of the Sample Mean
  • 3.2.4 Sampling Distribution of the Difference
    between Two Mean
  • 3.2.5 Sampling Distribution of Small Sample Mean

7
  • The probability distribution of the mean of all
    the possible random sample of size n that could
    be selected from a given population.
  • It lists the various values that can assume
    and the probability of each value of .
  • The mean and standard deviation of the sampling
    distribution of are called the mean and
    standard deviation of and are denoted by
    and respectively.
  • The mean of the sampling distribution of is
    always equal to the mean of the population.
    (Unbiased estimator)
  • The standard deviation of the sampling
    distribution of is
  • where is the standard deviation of the
    population and n is the sample size. This
    formula is used when n/N 0.05, where N is the
    population size.

8
Steps in tabulating the sampling distribution of
  • Draw many samples of a specified size.
  • Sample size n 2
  • Number of possible samples 10
  • Calculate the value of a statistic for each
    sample.
  • Sample statistic
  • Tabulate the frequency distribution of
  • Tabulate the probability distribution of
  • (probability relative frequency)

9
Example
  • Tabulate the sampling distribution of
  • Population 2 4 6 8 10
  • Population size N 5
  • Population mean
  • Population standard deviation
  • Steps
  • Sample size , n 3
  • No of possible sample 10
  • Value of a statistic for each sample

10
  • Tabulate the frequency distribution and
    probability distribution of
  • (probability relative frequency)

11
  • Mean of the sampling distribution of
  • The standard deviation of the sampling
    distribution of
  • Because n/N is greater than 0.05, we have to use
    the correction
  • factor and get
  • Normally in most practical applications the
    sample size would be smaller than the population
    size, thus we can use the formula below to
    calculate the standard deviation
  • Note
  • As the sample size (n) increases, the value of
    the standard deviation of ( ) decreases.
    (Consistent estimator)
  • Standard deviation

12
Exercise
  • The mean wage per hour for all 5000 employees who
    work at a large company is 13.50 and the
    standard deviation is 2.90. Let be the mean
    wager per hour for a random sample of certain
    employees selected from this company. Find the
    mean and standard deviation of for a sample
    size of
  • 30
  • 75
  • 200

13
  • a) Mean
  • Standard deviation
  • b) Mean
  • Standard Deviation
  • c) Mean
  • Standard Deviation

14
Shape of the Sampling Distribution of
  • The shape of the sampling distribution of
    relates to the two following cases
  • The population from which the sample are drawn
    has a normal distribution
  • The population from which the sample are drawn
    does not have a normal distribution
  • If the population from which the samples are
    drawn is normally distributed ,
    then the sampling distribution of will also
    be normally distributed with mean, , and
    standard deviation,
  • irrespective of the sample size.
  • Note must be 0.05 for to
    be true.

15
Example
  • The speeds of all cars traveling on a stretch of
    Interstate Highway are normally distributed with
    a mean of 68 miles per hour and a standard
    deviation of 3 miles per hour. Let be the
    mean speed of a random sample of 20 cars
    traveling on this highway.
  • Calculate the mean and standard deviation of
    and describe the shape of its sampling
    distribution.
  • Answer
  • miles per hour
  • Normal distribution

16
Central Limit Theorem
  • Most of the time the population from which the
    samples are selected is not normally distributed.
  • In such case, the shape of the sampling
    distribution of is inferred from a very
    important theorem called the central limit
    theorem.
  • If a random sample of n observations is drawn
    from a population with unknown distribution,
    either finite or infinite, then when n is
    sufficiently large (n 30) , the sampling
    distribution of the sample mean can be
    approximated by a normal density function.
    Irrespective of the shape of the population
    distribution.

17
Central Limit Theorem
18
Example
  • The GPAs of all 5540 students enrolled at a
    university have an approximate normal
    distribution with a mean of 3.02 and a standard
    deviation of 0.29. Let be the mean GPA of a
    random sample of 48 student selected from this
    university.
  • Find the mean and standard deviation of and
    comment on the shape of its sampling
    distribution.
  • Answer
  • Approximately normal distribution

19
Sampling Distribution of the Sample Mean
  • If we take all possible samples of the same
    (large) size from a population parameter and
    calculate the mean for each of these samples,
    then about
  • 68.26 of the sample means will be within one
    standard deviation of the population mean.
  • 95.44 of the sample means will be within two
    standard deviation of the population mean.
  • 99.74 of the sample means will be within three
    standard deviation of the population mean.

20
  • Sampling distribution of is its probability
    distribution. The area under the distribution
    curve represent this probability.
  • In order to find the probability, you have to
    compute the z-value for the respective value.
  • Then, find the value of z under the standard
    normal curve.

21
Example
  • The insider diameter of a randomly selected
    piston ring is a random variable with mean value
    12 cm and standard deviation 0.04 cm. Supposed
    the distribution of diameter is normal.
  • If is the sample mean diameter for a random
    sample of n 16 rings, find the mean and the
    standard deviation of the
  • distribution?
  • Answer the question posed in part (a) for a
    sample size of
  • n 64 rings.
  • Calculate when n
    16.
  • How likely is that the sample mean diameter
    exceeds 12.01 when n 25?

22
Example
  • Sam and Janet Evening wants to estimate the
    average dollar amount of the orders filled by
    their South Pacific Catering Company. They obtain
    their estimate by selecting a simple random
    sample of 49 orders. Their order are normally
    distributed with and .
  • Whats the value of the standard error?
  • Whats the chance that the sample mean will fall
    within one standard deviation of the population
    mean?
  • Whats the probability the sample mean will lie
    between 116.50 and 124.00?
  • Within what range of values does the have a
    94.5 chance of falling?

23
  • Standard error standard deviation
  • Probability falls within one standard deviation
    of the
  • 120 3, or between 117.00 and 123.00.
  • Find the corresponding z-value
  • for 117.00,
  • for 123.00,
  • P (117 123) P (z 1) 1 - P( z
    1 )
  • 0.8413 1 0.8413
  • 0.6826

24
  • Probability the sample mean will lie between
    116.50 and 124.00
  • for 116.50,
  • for 124.00,
  • P ( lt 116.5) P (z -1.17 )
  • 0.1210
  • P ( lt 124) P (z 1.33)
  • 0.9082
  • P (116.5 lt lt 124) P (-1.17 z 1.33)
  • 0.9082 0.1210
    0.7872

25
  • Range of values does the have a 94.5 chance
    of falling
  • 94.5 of the falls within two standard
    deviation of the population mean
  • Thus, the range of values must be within two
    standard deviation of the mean.
  • 120 2(3) 120 2(3)
  • 114 126

26
Sampling Distribution of the Difference between
Two Means
27
Example
  • The television picture tubes of manufacturer A is
    normally distributed with a mean lifetime of 6.5
    years and a standard deviation of 0.9 year, while
    those of manufacturer B is normally distributed
    with a mean lifetime of 6.0 years and a standard
    deviation of 0.8 year. What is the probability
    that a random sample of 36 tubes from
    manufacturer A will have a mean lifetime that is
    at least 1 year more than the mean lifetime of a
    sample of 49 tubes from manufacturer B?

28
  • Solution
  • Given
  • ?A 6.5 ?A0.9 nA 36,
  • ?B 6.0 ?B 0.8 nB 49
  • In order to determine
    , write
  • Thus

29
Example
  • The elasticity of a polymer is affected by the
    concentration of a reactant. When low
    concentration is used, the true mean elasticity
    is 55, and when high concentration is used the
    mean elasticity is 60. The standard deviation of
    elasticity is 4, regardless of concentration. If
    two random samples of size 16 are taken, find the
    probability that mean elasticity of high
    concentration is at least 2 more than the mean
    elasticity of low concentration.

30
  • Solution
  • Given
  • ?high 60, ?high 4 nhigh 16 and
  • ?low 55, ?low 4 nlow 16
  • In order to determine
    , write
  • Thus

31
Sampling Distribution of Small Sample Mean
  • Students t-distribution is used in the inference
    of population mean or comparative samples when
    the population standard deviation ? is unknown.
  • In practice, when is the mean, s2 is
    variance of a random sample of size n obtained
    from population satisfying a normal distribution
    with mean ? , then the sample statistic
  • follows the t-distribution with (n ?1) degree of
    freedom.

32
  • If the sample size is large (n ? 30),
    distribution of T does not differ considerably
    from the standard normal.
  • When the sample size is small (n lt 30), the
    values of s2 fluctuate considerably from sample
    to sample and the distribution of T deviates
    appreciably from that of standard normal
    distribution (see figure below).
  • The probability distribution of T is described by
    the Student's t-distribution.
  • Let random variables Z N(0,1) and
    , and if Z and V are independent, then the
    distribution of
  • is referred to as students t-distribution with
    (? n ? 1) degree of freedom (df).

33
  • A typical way to refer to the t-distribution
    table is by the Critical Values, ? for
    t-distribution,
  • P(T gt t?,? ) ?

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35
Example
  • For a random sample of size 24 selected from a
    normal distribution,
  • Find k such that .
  • Find k such that .

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38
Example
  • A random sample of size 9 is drawn from a normal
    population with unknown variance and a mean of
    20. Find the probability that the sample mean is
    greater than 24 if the sample standard deviation
    is 4.1436.

39
  • Solution

40
Example
  • Supposing you know that average Malaysian man
    exercises for 60 minutes a week and a random
    sample of 25 means you have drawn from the
    population has a mean of 65 minutes per week with
    a standard deviation of 10 minutes.
  • What is the probability of getting a random
    sample of this size with a mean less than or
    equals 65 if the actual population mean is 60?

41
  • Solution

42
3.3 Sampling Distribution of
  • 3.3.1 Central Limit Theorem
  • 3.3.2 Sampling Distribution of the Sample
    Proportion
  • 3.3.3 Sampling Distribution of the Difference
    between Two Proportions

43
  • The concept of proportion is the same as the
    concept of relative frequency.
  • The population proportion is obtained by taking
    the ratio of the number of elements in a
    population with a specific characteristic to the
    total number of elements in the population.
  • The sample proportion gives a similar ratio for a
    sample.

44
Example
  • Suppose a total of 789,654 families live in a
    city and 563,282 of them own homes. Then
  • Take a sample of 240 families from this city and
    158 of them are homeowners. Then

45
  • Similar to sample mean, the sample proportion is
    a random variable. Hence, it possesses a
    probability distribution, which is called its
    sampling distribution.
  • This distribution gives the various values that
    can assume and their probability.
  • The mean of the sample proportion is denoted by
    and is equal to the population proportion, p.
    Thus,
  • The standard deviation of the sample proportion
    is denoted by and is given by the
    formula
  • p population proportion
  • q 1 p
  • This formula is used when n/N 0.05.

46
Example
  • BCC Consultant has five employees. The table
    below list their names and information regarding
    their knowledge of statistics.
  • Population proportion,

47
  • Steps
  • Sample size , n 3
  • No of possible sample 10
  • Value of a statistic for each sample

48
  • Frequency, relative frequency and sampling
    distribution
  • Calculate the mean and standard deviation

49
Central Limit Theorem
  • The shape of the sampling distribution of is
    inferred from the central limit theorem.
  • According to the central limit theorem, the
    sampling distribution of is approximately
    normal for a sufficiently large sample size.
  • In this case, the sample size is considered to be
    sufficiently large if np and nq are both greater
    than 5, that is if
  • np gt 5 and nq gt 5

50
Example
  • Suppose that in a local school, 20 of all
    students in grades 7 through 12 are afraid of
    being attacked in their school. Let be the
    proportion of students in a random sample of 50
    seventh-through-twelfth-grade students who fear
    such attacks.
  • Calculate the mean and standard deviation of
    and comment on the shape of its sampling
    distribution.
  • Answer
  • Approximately normal distribution

51
Sampling Distribution of the Sample Proportion
  • We use the concept of mean, standard deviation,
    shape of the sampling distribution of to
    determine the probability that the value of
    computed from one sample falls within a given
    interval.
  • The z-value for a value of
  • with limiting distribution Z N(0,1) as n??.

52
Example
  • A college had a business entering freshman class
    of 528 students last year. Of these, 211 have
    brought their own personal computers to campus. A
    random sample of 120 entering freshman was taken.
  • What is the standard deviation of the sample
    proportion bringing own personal computer to
    campus?
  • What is the probability that the sample
    proportion is less than 0.33?
  • What is the probability that the sample
    proportion is between 0.4 and 0.5?

53
  • Solution

54
Example
  • Maureen Webster, who is contesting for the
    mayors position in a large city, claim that she
    is favored by 53 of all eligible voters of that
    city. Assume that this claim is true.
  • What is the probability that in random sample of
    400 registered voters taken from this city, less
    than 49 will favor Maureen Webster?
  • Answer
  • Calculate p and q
  • p 0.53, q 1 p 1.0 0.53 0.47

55
  • Calculate the mean and standard deviation
  • Calculate the z-value
  • Find the required probability
  • P( lt 0.49) P(z lt -1.60)
  • 0.0548

56
Sampling Distribution of the Difference between
Two Proportions
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Example
  • Election returns showed that a certain candidate
    received 65 of the votes. Find the probability
    that two random samples, sample A consists of 200
    voters and sample B consists of 150 voters,
    indicated more than a 10 difference in the
    proportions who voted for the candidate.

59
  • Solution

60
Example
  • For the freshman class in Example 3.8, 20 of
    female students and 23 of male students have
    brought their own personal computer to campus. A
    random sample of 50 female and 55 male students
    been taken. Find the probability that the
    difference for proportion of female and male
    students who brought their own personal computer
    to campus is less than 0.1

61
  • Solution

62
3.3 Sampling Distribution of s2
63
  • Sample variance s2 and the chi-square
    distribution is often used to determine the
    interval estimate of the actual (population)
    variance sits.
  • Typically one need to find probability such as
    P(X2 gt ?2?) and one can use the table of upper
    critical values of chi-square distribution as
    shown below.

64
Example
  • Find the value of for the following
  • (Refer to the table of Critical Area Chi-Square
    Distribution)
  • a) 0.99 when v 4
  • b) 0.025 when v 19
  • c) 0.045 when v 25

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Example
  • The claim that the variance of a normal
    population is is to be rejected
    if the variance of a random sample of size 16
    exceeds 54.668 or is less than 12.102. What is
    the probability that this claim will be rejected
    even though ?
  • Solution

67
Example
  • A random sample of 10 observations is taken from
    a normal population having the variance 42.5.
    find the approximate probability of obtaining
    sample variance between 9.8596 and 79.9236
  • Solution
  • n 10, s2 42.5, thus v 10 1 9

68
Sampling Distribution of the Ratio of Two
Variances
  • F-Distribution used to compare two or more sample
    variances.
  • The statistics F is defined to be the ratio of
    two independent Chi-squared random variables,
    each divided by its number of degrees of freedom.
  • If and are independent,
    then the random variable
  • defines the F-distribution with ?1 and ?2
    degrees of freedom.
  • Writing fa (v1, v2) for fa with v1 and v2 degrees
    of freedom, we obtain

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Example
  • For a F-distribution find
  • a) f0.01 with v1 24 and v2 20
  • b) f0.01 with v1 20 and v2 24
  • c) f0.95 with v1 15 and v2 20
  • c) f0.99 with v1 30 and v2 12

71
Example
  • ,
  • ,
  • The heat producing capacity of two coal mines,
    Mine A and Mine B, are normally distributed with
    the variances sA2 10920 and sB2 15750. If
    sA2 and sB2 are the variances of independent
    random samples of size nA 5 and nB 6 taken
    from these two mines, find the probability that
    the ratio of the two variances are more than 3.6.
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