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Hard Instances of the Constrained Discrete Logarithm Problem

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Title: Hard Instances of the Constrained Discrete Logarithm Problem


1
Hard Instances of the Constrained
DiscreteLogarithm Problem
  • Ilya Mironov Microsoft Research
  • Anton Mityagin UCSD
  • Kobbi Nissim Ben Gurion University
  • Speaker Ramarathnam Venkatesan
  • (Microsoft Research)

2
DLP
  • Discrete Logarithm Problem
  • Given gx find x
  • Believed to be hard in some groups
  • - Zp
  • - elliptic curves

3
Hardness of DLP
  • Hardness of the DLP
  • specialized algorithms (index-calculus)
  • complexity depends on the algorithm
  • generic algorithms (rho, lambda, baby-step
    giant-step)
  • complexity vp if group has order p

4
Constrained DLP
  • Constrained Discrete Logarithm Problem
  • Given gx find x, when x ? S
  • Example S consists of exponents with short
    addition chains.

5
Hardness of the Constrained DLP
  • Bad sets (DLP is relatively easy)
  • x with low Hamming weight
  • x ? a, b
  • x2 x lt vp
  • Good sets (DLP is hard) - ?

6
Generic Group Model Nec94,Sho97
  • Group G, random encoding sG?S
  • Group operations oracle
  • s(g),s(h),a,b ?s(gahb)
  • Formally, DLP
  • given s(g) and s(gx), find x
  • Assume order of g p is prime

7
DLP is hard Nec94,Sho97
  • Suppose there is an algorithm that solves the DLP
    in the generic group model
  • The algorithm makes n queries s(g), s(gx),
    s(ga1xb1), s(ga2xb2),, s(ganxbn)
  • The simulator answers randomly but
    consistently, treating x as a formal variable.
  • The algorithm outputs its guess y
  • The simulator chooses x at random.
  • The simulator loses if there is
  • inconsistency gaixbi gajxbj for some i, j
  • x y.

Pr lt n2/p
Pr 1/p
8
DLP is hard Nec94,Sho97
  • Probability of success of any algorithm for the
    DLP in the generic group model is at most
  • n2/p 1/p,
  • where n is the number of group operations.

9
Graphical representation
  • Queries s(g),s(gx),s(ga1xb1),s(ga2xb2),,
    s(ganxbn)

x
Zp
a1xb1
a3xb3
success
a2xb2
1
Zp
x
y
0
10
Graphical representation
  • Queries s(g),s(gx),s(ga1xb1),s(ga2xb2),,
    s(ganxbn)

x
Zp
a1xb1
a3xb3
failure
a2xb2
1
Zp
x
y
0
11
Attack
  • The argument is tight
  • if for some s(gaixbi) s(gajxbj),
    computing x is easy

12
Constrained DLP
given s(g) and s(gx), find x?S
x
Zp
a1xb1
a3xb3
a2xb2
1
Zp
0
S
13
Generic complexity of S
  • Ca(S) generic a-complexity of S ? Zp is the
    smallest such that their
    covers an a-fraction of S.

number of lines
intersection set
Zp
0
S
14
Bound
  • Adversary who is making at most n queries
    succeeds in solving
  • DLP with probability at most
  • n2/p 1/p
  • DLP constrained to set S If n lt Ca(S),
    probability is at most
  • a 1/S

15
Whats known about Ca(S)?
  • Obvious Ca(S) lt v a p (omitting constants)
  • Ca(S) lt aS
  • Ca(S) gt v aS

Zp
Zp
0
S
16
Simple bounds
Ca(S)
ap
sweet spot small set, high complexity
vap
S
log scale
p
vp
17
Random subsets Sch01
Ca(S)
ap
random subsets
vap
S
log scale
p
vp
18
Problem
Ca(S)
ap
random subsets
short description???
vap
S
log scale
p
vp
19
Relaxing the problem Cbsgs1
  • Cbsgs1(S) baby-step-giant-step-1-complexity
  • Two lists ga1, ga2,, gan and gx-b1, gx-b2,,
    gx-bn

x-b1
x-b2
a1
a2
a3
Zp
a2b2
0
a1b2
a3b1
20
Modular weak Sidon set EN77
  • S is such that for any distinct s1,s2,s3,s4?S
  • s1 s2 ? s3 s4 (mod p)

x-b1
all four cannot belong to S
x-b2
a1
a2
Zp
a2b2
a2b1
0
a1b2
a1b1
21
Zarankiewicz bound
  • S is such that for any distinct s1,s2,s3,s4?S
  • s1 s2 ? s3 s4 (mod p)

a1
a2
How many elements of S can be in the table?
b1
a1b1
a2b1
Zarankiewicz bound at most n3/2 Cbsgs1(S)
gtS2/3
b2
a1b2
a2b2
22
Weak modular Sidon sets
  • S is such that for any distinct s1,s2,s3,s4?S
  • s1 s2 ? s3 s4 (mod p)
  • Explicit constructions for such sets exist of
    size O(p1/2).
  • Higher order Sidon sets
  • s1 s2 s3 ? s4 s5 s6 (mod p)
  • Turan-type bound
  • Cbsgs1(S) lt S3/4

23
A harder problem Cbsgs
  • Cbsgs(S) baby-step-giant-step-complexity
  • Two lists ga1, ga2,, gan and g?1x-b1,gc2x-b2,,g
    cnx-bn

c1x-b1
c2x-b2
a1
a2
a3
Zp
x3
0
x2
x1
y1
y2
y3
24
Harder the problem Cbsgs
  • S for any six distinct x1,x2,x3,y1,y2,y3?S
  • (x1-x2)/(x2-x3) ? (y1-y2)/(y2-y3) (mod p)

c1x-b1
c2x-b2
a1
all six cannot belong to S
a2
a3
Zp
x3
0
x2
x1
y1
y2
y3
25
Zarankiewicz bound
  • S for any six distinct x1,x2,x3,y1,y2,y3?S
  • (x1-x2)/(x2-x3) ? (y1-y2)/(y2-y3) (mod p)

(b2,c2)
How many elements of S can be in the table?
(b1,c1)
(b3,c3)
Zarankiewicz bound still at most n3/2 Cbsgs(S)
gt S2/3
x1
x2
x3
a1
a2
y1
y2
y3
26
How to construct?
  • S for any six distinct x1,x2,x3,y1,y2,y3?S
  • (x1-x2)/(x2-x3) ? (y1-y2)/(y2-y3) (mod p)

Six-wise independent set of size p1/6
27
Generic complexity
Smallest possible theorem involves 7 lines
l1
lz
l2
ly
lx
l3
l4
Zp
x1
y1
z1
x4
z2
y4
z3
z4
y3
x2
x3
y2
28
Bipartite Menelaus theorem
  • S for any twelve distinct x1,x2,x3,x4,
    y1,y2,y3,y4,z1,z2,z3,z4 ? S
  • x1-y1 x1-z1 z1(x1-y1) y1(x1-z1)
  • x2-y2 x2-z2 z2(x2-y2) y2(x2-z2)
  • x3-y3 x3-z3 z3(x3-y3) y3(x3-z3)
  • x4-y4 x4-z4 z4(x4-y4) y4(x4-z4)

?0
det
degree 6 polynomial
29
How to construct?
  • 12-wise independent set of size p1/12
  • C(S) gt S3/5

30
Conclusion
random subsets
Ca(S)
ap
vap
Cbsgs1
(ap)1/4
Cbsgs
C
(ap)1/9
(ap)1/20
S
p1/12
p1/6
p1/3
p
vp
log scale
31
Open problems
  • Better constructions - stronger bounds
  • - explicit
  • Constrained DLP for natural sets
  • - short addition chains
  • - compressible binary representation
  • - three-way products xyz
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