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TROY

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A measure of the time elapsed between the occurrence of unit rainfall and unit runoff ... unit hydrograph for a 75 acre drainage basin with tc = 37.5 minutes ... – PowerPoint PPT presentation

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Title: TROY


1
GEM 4409HydrologyFall 2005
  • TROY
  • UNIVERSITY

2
Hydrographs
  • Graphs flow vs. time
  • Shape depends on rainfall basin characteristics
  • Provides time distribution of runoff peak
    flow
  • Important where storage is significant
  • Can estimate time that roads/bridges are flooded

3
Hydrographs
  • USGS Synthetic Hydrographs
  • Rural urban streams in Alabama
  • Drainage areas lt 500 square miles
  • Based on a statewide dimensionless hydrograph
  • Applied to individual sites by using lag time
    peak flow

4
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6
Fall Line
Birmingham
Fall Line
Montgomery
7
Seven Major Soil Areas in Alabama
8
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9
Hydrographs
  • Unit Hydrographs
  • Produced by a unit depth of runoff uniformly
    distributed over a basin for a specific excess
    rainfall duration
  • Example
  • The 5-minute unit hydrograph for a basin is a
    graph of the direct runoff resulting from 1 of
    excess rain occurring at a constant rate over
    5-minutes

10
Hydrographs
  • Unit Hydrographs
  • A basin will have many different unit hydrographs
  • For each duration of runoff
  • 5-minute, 10-minute,24 hour, etc.

11
Hydrographs
  • Unit Hydrographs
  • Excess rainfall
  • The rainfall that contributes to the runoff
  • i.e. (Total Rainfall Hydrologic Losses)

12
Hydrographs
  • Unit Hydrographs
  • Excess rainfall volume runoff volume
  • Runoff volume area under hydrograph
  • Rainfall volume depth x area

13
Hydrographs
  • Unit Hydrographs
  • Applicable basin size
  • No well defined upper limit
  • Midsize basins (1 mi2 100 mi2)
  • Has been used with basins up to 3,000 mi2
  • Accuracy decreases with area

14
Hydrographs
  • Unit Hydrographs
  • Lag Time (LT)
  • Central concept to the development of the unit
    hydrograph
  • A measure of the time elapsed between the
    occurrence of unit rainfall and unit runoff
  • i.e. basin response time
  • Involves flow path, land use, slope, etc.

15
Hydrographs
  • Defining
  • Lag Time (LT)
  • T1
  • T2
  • T3
  • T4
  • T5
  • T6
  • T7

16
Hydrographs
  • Defining
  • Lag Time (LT)
  • Most Common
  • T2 Time from
  • centroid of
  • excess rainfall
  • to peak runoff

17
Hydrographs
  • Lag Time (LT)
  • Short lags ? High peak, narrow base
  • Long lags ? Low peak, wide base

18
Hydrographs
  • Unit Hydrographs
  • Calculated
  • Directly By measured data
  • Indirectly By using a synthetic formula

19
Hydrographs
  • Unit Hydrographs
  • Direct Method
  • Gaged basins only
  • Rainfall-runoff data
  • Selected storms should have uniform rainfall
    intensity (in time and space)

20
Hydrographs
  • Unit Hydrographs
  • Indirect Method
  • SCS unit hydrograph

21
Hydrographs
  • Unit Hydrographs
  • SCS Unit Hydrograph
  • Based on the relationship between the lag time of
    a basin and the time of concentration
  • SCS defines lag time as time from center of
    excess rainfall to peak (T2)

22
SCS Unit Hydrograph
tr duration of runoff tbt time base of
DRH tl lag time for the basin
23
SCS Unit Hydrograph
tr duration of runoff tbt time base of
DRH tl lag time for the basin
24
SCS Unit Hydrograph
tr duration of runoff tbt time base of
DRH tl lag time for the basin
25
SCS Unit Hydrograph
mi2, hours, cfs
tr duration of runoff tbt time base of
DRH tl lag time for the basin
26
SCS Unit Hydrograph
  • Shape based on a ratio of 8/3 leading to the
    constant, 484
  • This constant is called a peak factor (PF)

27
SCS Unit Hydrograph
  • The ordinates of the SCS UH can also be
    approximated using the following equation

(For PF484, x 3.79 and for PF 300, x 1.5)
28
SCS Unit Hydrograph
  • The ordinates of the SCS UH can also be
    approximated by combining and solving for flow
    rate

(For PF484, x 3.79 and for PF 300, x 1.5)
29
SCS Unit Hydrograph
30
SCS Unit Hydrograph
31
SCS Unit Hydrograph
  • Calculate tr, tp, qp
  • tc 37.5 / 60 0.627 hours
  • tr 0.133tc 0.133(0.627) 0.0834 hrs 5 min
  • tp 5 tr 5 (5) 25 min 0.417 hrs
  • qp 484 (A)/tp 484(0.117)/0.417 135.8 cfs

32
SCS Unit Hydrograph
2. Determine the coordinates of the dimensionless
unit hydrograph
33
SCS Unit Hydrograph
Q (cfs)
Time (min)
0
25
125
34
SCS Unit Hydrograph
  • 3.Check to see that the depth of runoff is 1
  • Sum the UH flows ? 905.9 cfs
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