Title: Part 3 Additional Topics
1Part 3Additional Topics
- PHYS 4315
- R. S. Rubins, Fall 2009
2Kinetic Theory
- PHYS 4315
- R. S. Rubins, Fall 2009
3Kinetic Theory Introduction
- Features of kinetic theory
- Kinetic theory goes beyond the limitations of
classical thermodynamics by taking into account
the structures of materials. - However, there is a price to be paid in
complexity, since general relationships may be
obscured. - Unlike both classical thermo and statistical
mechanics, kinetic theory may be used to describe
non-equilibrium situations. - Kinetic theory has been particularly useful in
describing the properties of dilute gases. - It gives a deeper insight into concepts such as
pressure, internal energy and specific heat, and
explains transport processes, such as viscosity,
heat conduction and diffusion.
4Classical Dilute Gas Assumptions 1
- Molecules are classical particles with
well-defined positions and momenta. - A macroscopic volume contains an enormous number
of molecules. - At STP (0oC and 1 atm), 1 kmole of a gas occupies
22.4 m3, which is a density of 3 x 1025
molecules/m3. - Molecular separations are much larger than both
their dimensions and the range of intermolecular
forces. - At STP, the molecular separation is roughly 3 x
10 9 m. - The Lennard-Jones or 6-12 potential
- V K (d/r)12 (d/r)6,
- where K and d are empirical constants is
negligible for molecular separations of 3 x 10 9
m.
5Classical Dilute Gas Assumptions 2
- The mean free path the average distance a
molecule moves between collisions is of the order
10 7 m. - The only interaction between particles occur
during collisions so brief that their durations
may be neglected. - The container is assumed to have an idealized
surface. - The collisions are elastic, so that momentum and
KE are conserved. - The molecules are assumed to be distributed
uniformly in both position and velocity
direction. - Molecular chaos exists that is, the velocity of
a molecule is uncorrelated with its position.
6Kinetic Theory Pressure
- Macroscopic pressure (classical thermo)
- Balancing force F PA.
- Microscopic pressure (kinetic theory)
- Impulse ?F??t ?ptot,
- where, for a single particle,
- ?p 2mv cos?.
- The piston makes an irregular (Brownian)
motion about its equilibrium position, because of
the random collisions of molecules with the
piston.
Macroscopic pressure
?
?
Microscopic pressure
7Molecular Flux
A
x
vave?t
- Simplified calculation
- Assume that the molecules move equally in the x,
y, and z directions i.e. n/6 move in the x
direction, where n is the number of molecules per
unit volume. - In time ?t, a total of Anvave?t/6 molecules will
strike the wall. - Thus, the molecular flux F, the number of
molecules striking unit area of the wall in unit
time, is F nvave/6. - An exact calculations, including integrations
over all directions and speeds gives F nvave/4.
8Molecular Effusion
- F nvave/4, where (from stat. mech.) vave
v(8kT/mp). - For an ideal gas, PV NkT, so that n N/V
P/kT. - Thus, F P/v(2pmkT).
- Imagine two containers containing the same ideal
gas at (P1,T1) and (P2,T2), connected by a
microscopic hole of diameter D ltlt L, where L is
the mean free path, which is of the order 107 m
at STP. - The number of molecules passing through the hole
is so small that the pressure and the temperature
on each side of the hole is unchanged over the
time of the experiment. - The condition for equilibrium is the absence of a
net flux i.e. - F1 F2 or P1/vT1 P2/vT2.
9Experimental Problem
Macroscopic hole (D gtgt L) At equilibrium, P1
P2, T1 T2. Microscopic hole (D ltlt L) At
equilibrium, P1/vT1 P2/vT2.
T2 300 K
- Under effusion conditions,
- P1/vT1 P2/vT2 ,
- so that
- P1 P2/ v(T1/T2) ,
- or
- P1 0.07 P2.
vacuum
P2
?P
Hg
Liquid He
He vapor at pressure P1
Liquid He at T1 1.3 K
10Boltzmanns Transport Equation
- Boltzmanns H theorem
- dH/dt 0, where H(t) ?d3v f(p,t) log
f(p,t) . - Since H ? Hmin, the entropy has the form S
const. H. - The equilibrium (Maxwell) distribution is given
by
11Superfluidity in Liquid Helium
- PHYS 4315
- R. S. Rubins, Fall 2009
12Boiling Points
- The two helium isotopes have the lowest boiling
points of all known substances, 3.2 K for 3He and
4.2 K for 4He. - Both isotopes would apparently remain liquid down
to absolute zero to solidify helium would
require a pressure of about 25 atmospheres. - Two factors produce the reluctance of helium to
condense - i. the low mass of the atoms
- ii. The extremely weak forces between atoms.
- The low atomic mass ensures a high zero-point
energy, a result that may be deduced from the
uncertainty principle. -
13Zero-point Energy 1
- The uncertainty in momentum of a particle in a
cavity is - ?p ? h/R.
- Its zero-point energy is thus
- E0 ? (?p)2/2m
- or
- E0 ? h2/2mR2.
- The large zero-point energy must be added to the
potential energy of the liquid to give the
liquids total energy.
14Zero-point Energy 2
- Because He atoms are
- so light, the zero-point
- Energy is comparable to
- the PE, the minimum of
- the total energy occurs
- at a relativity high atomic
- volume.
- For other inert gases, the
- zero-point energy is of
- negligible magnitude.
15Phase Diagrams
- The large zero-point energy of liquid eliminates
the solid-vapor curve present for a normal
material. - The ? line occurs only for 4He, and is associated
with the ?-point transition to superfluid
behavior near 2 K.
16The ? Specific Heat Transition in Liquid 4He
- If liquid helium, which
- liquifies below 4.2 K, is
- cooled by lowering the
- pressure above it,
- bubbles of vapor form
- within the liquid, which
- boils vigorously.
-
- However, below 2.17 K,
- the ? point, the liquid
- becomes very still, as
- the transition from a
- Normal fluid (He I) to a
- superfluid (He II) occurs.
- In 3He, a transition to a
- superfluid occurs near
- 3 mK.
17Macroscopic Properties of Superfluid He II 1
- Zero viscosity
- Measurements showing the zero resistance to flow
of He II were made in 1964. - This was done by showing that the flow velocity
through channels of widths between 0.1 µm and 4
µm were independent of the pressure gradient
along the channel.
18Two-fluid Model of He II
- Zero viscosity 2
- Experiments showed an apparent contradiction,
that He II was both viscous and non-viscous at
the same time. - This result was the source of the two-fluid model
of He II, introduced by Tisza in 1938. - This is a quantum effect the liquid does not
consist of two distinct fluids, one normal and
the other superconducting. - In Andronikashvilis 1946 experiment, a series of
equally spaced metal disks, suspended by a
torsion fibre, were made to oscillate in liquid
He. - The results confirmed that He II consists of a
normal viscous fluid of density ?n and a
superfluid of density ?s, and allowed the ratios
?s/? and ?n/? to be measured as functions of
temperature, where ? ?n ?s.
19Andronikashvilis Experiment
20Macroscopic Properties of Superfluid He II 2
- Infinite thermal conductivity
- This makes it impossible to establish a
temperature gradient in a bulk liquid. - In a normal liquid, bubbles are formed when the
local temperature in a small region in the body
of the liquid is higher than the surface
temperature. - Unusually thick adsorption film
- The unusual flow properties of He II result in
the covering of the exposed surface of a
partially immersed object being covered with a
film about 30 nm (or 100 atomic layers) thick,
near the surface, and decreasing with height.
21Flow of He II over Beaker Walls
- The temperature is the same throughout the
system, and the superfluid acts as a siphon,
flowing through the film to equalize the levels
in the two bulk liquids. - By observing the rate at which the beaker level
changes, the superfluid velocity has been found
to be about 20 cm/s.
22Thermomechanical Effect 1
- If a temperature gradient is set up between two
bulk volumes connected by a superleak, through
which only the superfluid can flow, the
superfluid flows to the higher temperature side,
in order to reduce the temperature gradient. - This example of the thermomechanical effect,
shows that heat transfer and mass transfer cannot
be separated in He II.
23Thermomechanical Effect 2
- At equilibrium, GA GB i.e. ?G 0.
- Now, dG S dT V dP 0
- ? ?P (S/V) ?T (s/v) ?T,
- where s and v are the values per kg.
- Now ? 1/v, so that,
- ?P s ? ?T.
24The Fountain Effect
- In this celebrated experiment of Allen and Jones
(1938), the superleak is heated by a flashlight.
- In order to equalize temperatures, the superfluid
flows through the superleak with sufficient speed
to produce a fountain rising 30 cm or more. - According to Landaus theory (1941), the normal
fluid consists of the excited quantum states.
The fine channels in the superleak filter out the
excited states
25Bose-Einstein Condensation
- PHYS 4315
- R. S. Rubins, Fall 2009
26About BEC
- In 1924, Einstein applied Satyendra Boses
explanation of blackbody radiation to matter,
predicting the phenomenon known as Bose-Einstein
condensation (BEC). - BEC is a quantum mechanical phase-transition,
thought to be responsible for superfluidity in
liquid helium. - Not until 1995 was it observed in isolated atoms,
in 87Rb (NIST), 23Na (MIT) and 7Li (Rice U.).
Since then, BEC has been observed around the
world, and 1H (MIT) and 4He France. - Samples typically contain of the order of 105 -
106 atoms, in which several thousand form the
condensate, with transition temperatures in the
range 300 600 nK.
27BEC Scientific Entanglements
- BEC belongs to atomic
- physics, condensed matter
- physics and stat. mech.
- It could not have been
- produced without the tools
- of optics and laser physics,
- the manipulation of
- magnetism and fluid
- dynamics, and the use of
- new techniques in low
- temperature physics.
- BEC is a deep entanglement
- of fields, giving rise to a
- totally new field of physics.
- See Physics Today, December 2006
28Bosons and Fermions
- Identical particles follow either Bose-Einstein
or Fermi-Dirac statistics. - Bosons have integer angular momentum quantum
numbers (e.g. photons, atoms with an even no. of
neutrons.). - They have symmetrical wavefunctions
- i.e. if two particles (1 and 2) are in the
states a and b, then - ?sym ?a(1) ?b(2) ?a(2) ?b(1) ? ?a(1)
?a(2) if a b. - Fermions have half-integer angular momentum
quantum nos. (e.g. electrons, nucleons, atoms
with an odd no. of neutrons.). - They have antisymmetrical wavefunctions
- i.e. if two particles (1 and 2) are in the
states a and b, then - ?anti ?a(1) ?b(2) ?a(2) ?b(1) ? 0 if
a b.
29Boson and Fermion Gases Below 1 mK
- In these Rice University
- images of atomic clouds,
- those of 7Li (a boson with
- 4 neutrons) continue to
- collapse as the
- temperature is lowered.
- Since identical fermions
- cannot occupy the
- same space (the Pauli
- exclusion principle), the
- atomic cloud of 6Li (a
- fermion with 3 neutrons)
- shows a smaller collapse.
30BEC Photo from Rice University
- Cloud of about 70,000 7Li atoms, with about 1200
in the BEC peak at the center, at about 600 nK.
31BEC a Phase Transition in an Ideal Gas
- Like the ferromagnetic transition at the Curie
point of iron (1043 K), BEC is a phase
transition, but unlike the ferromagnetic
transition, which occurs because of the strong
interaction between iron atoms, BEC occurs in an
ideal gas, for which interatomic forces are
negligible.
32BEC Atoms Each in the Same Wave Function
- The de Broglie
- wavelength ?dB h/mv,
- becomes for a quantum
- gas
- ?dB h/(2pmkT)1/2.
- Thus ?dB increases as
- T is lowered, and a
- phase transition to
- a BEC state occurs
- when ?dB reaches the
- atomic separation.
33Interference Between BEC Waves
- Like the interference patterns that may be
produced by the coherent light from lasers, BEC
waves show interference phenomena. - However, unlike laser beams, which are in
non-equilibrium states, a BEC wave is an
equilibrium state.
34Loading a Magnet Trap for Li7 (Rice U.)
- The apparatus is contained in an ultra-high
vacuum at room temperature. - Hot Li7 atoms, emitted from an oven at 800 K,
form an atomic beam. - The atomic beam is slowed by an oppositely
directed laser beam, and deflected by a second
laser beam towards a magnetic and optical trap. - Another laser beam collimates the deflected
atomic beam, and optically pumps it, so that each
atom is in the same magnetic state. - Once in the trap, the atomic beam is contained by
a set of six laser beams.
35Magnetic Trap (Rice U.)
- If the magnetic moment of an atom is parallel to
the magnetic field, it will be attracted to a
local minimum of the field, which occurs at the
center of the magnet distribution. - If the direction of the magnetic moment is
reversed, the center of the distribution becomes
a local maximum, which causes that atom to leave. - The magnetic field at the minimum must not be
zero, otherwise the atomic moments may
spontaneously reverse their directions. - In practice, the field at the minimum was 0.1 T.
- Atoms in the trap may be lost by collisions in
which the moment direction is reversed.
36Laser Cooling 1
- Laser cooling is achieved by using the Doppler
effect to reduce vrms. - Two opposing laser beams of equal intensity are
each tuned to the low frequency side of an
optical transition. - The beam opposing the atoms motion is
blue-shifted to higher frequencies, so that the
force on it is increased. - The beam in the same direction as the atoms
motion is red-shifted to lower frequencies, so
that the force on it is decreased.
37Laser Cooling 2
- The net effect of the two opposing laser beams is
to reduce the magnitude of the velocity component
of each atom along the axis of the two beams. - Three orthogonal pairs of lasers are used to slow
the motions of atoms moving in all directions. - Using laser cooling for Rb87, the NIST group in
Boulder, achieved temperatures of 10 µK, which
are still ten to a hundred times too high for
observing BEC. - The effect of reducing vrms on the temperature of
the sample may be calculated using the
equipartition theorem i.e. - ½ mvrms2 (3/2)kT.
38Evaporative Cooling 1
- This method is analogous to the cooling of a hot
liquid by evaporation. - The fastest moving atoms move furthest from the
minimum, to a position of highest energy (see the
upper atom shown in the figure). - Magnetic resonance is used to reverse the moments
of the most energetic atoms, causing them to
leave the trap, which is now an energy maximum. - Slowly reducing the radio frequency removes
progressively cooler atoms. - At the end, only about 1 of the atoms remain in
the trap, and the temperature is reduced by a
factor of about 100, giving a temperature of the
order of 100 nK.
39Photographing the Condensate (NIST) 1
- False color images show the velocity distribution
just before the appearance of - BEC (right), just after it (center), and for a
nearly pure condensate (right). - To increase the sample size, the magnetic trap is
turned off. - The excited- state (thermal) atoms move out
faster, leaving the condensate - near the center of the trap.
- These photographs were taken after the atoms had
moved for about 0.05 s. - The thermal cloud is almost circular, while the
condensate cloud is elliptical.
40Photographing the Condensate (NIST) 2
- The right frame has a horizontal dimension of 40
50 µm, equivalent to about 1500 atoms forming a
single wave. - The shape of the peak is related to the
elliptical shape of the trap, giving a vivid
demonstration of the uncertainty principle ?px?x
? h. - The temperature within the condensate may be of
the order of 1 nK.
41Information Theory
- PHYS 4315
- R. S. Rubins, Fall 2009
42Lack of Information
- Entropy S is a measure of the randomness (or
disorder) of a system. - A quantum system in its single lowest state is in
a state of perfect order S0 (3rd law). - A system at higher temperatures may be in one of
many quantum states, so that there is a lack of
information about the exact state of the system. - The greater the lack of information, the greater
is the disorder. - Thus, a disordered system is one about which we
lack complete information. - Information theory (Shannon, 1948) provides a
mathematical measure of the lack of information,
which may be linked to the entropy.
43Missing Information H
- For an experiment with n possible outcomes p1,
p2, pn, Shannon introduced a function H(p1, p2,
pn), which quantitatively measures the missing
information associated with the set of
probabilities. - Three conditions are needed to specify H to
within a constant factor. - 1. H is a continuous function of pi.
- 2. If all the pi are equal, then pi 1/n, and H
is a monotonically increasing function of n,
since the number of possibilities increases with
n. - 3. If the possible outcomes of an experiment
depend on the outcomes of n subsidiary
experiments, then H is the sum of the
uncertainties of the subsidiary experiments. - With these assumptions, H was found to be
proportional to the entropy S k ?r pr ln pr.
44Example of Sum of Uncertainties
- Single experiment, using H K(pr lnpr).
- H(1/2,1/3,1/6) K(1/2) ln(1/2) (1/3)
ln(1/3) (1/6) ln(1/6) - K(1/2)ln2 (1/3)ln3 (1/6)ln6
K(2/3)ln2 (1/2)ln3 1.01 K.
- Two successive experiments
- H(1/2,1/2) K(1/2) ln(1/2) (1/2) ln(1/2)
K ln2. - (1/2)H(2/3,1/3) K( (1/3)ln2 (1/3)ln3
(1/6)ln3 - Thus, H(1/2,1/2) (1/2)H(2/3,1/3) K1
(1/3)ln2 (1/3) (1/6)ln3 -
K(2/3)ln2 (1/2)ln3 1.01 K.
45Shannons Calculation 1
The simplest choice of continuous function
(Condition 1)is
For simplicity, consider the case of equal
probabilities i.e. pi 1/n.
Since H is a monotonically increasing function of
n (Condition 2),
For two successive experiments (Condition 3)
46Shannons Calculation 2
Since H(1/n,1/n) n f(1/r),
.
Letting R 1/r and S 1/s,
47Shannons Calculation 3
Since g(R) g(S) g(R,S)
and
,
so that
Thus,
so that
Since R 1/r,
.
48Shannons Calculation 4
For r 1, the result is certain, so that H(r)
f(1/r) 0. Thus, C 0, so that
Now d/dn( A ln n) must be positive (Condition
2), so that A must be negative. Letting K
A, and p pi 1/n,
Thus, the missing information function H is given
by
.
With K replaced by Boltzmanns constant k, H
equals S (entropy).
49Black-Hole Thermodynamics
- PHYS 4315
- R. S. Rubins, Fall 2009
50Quantum Fluctuations of the Vacuum
- The uncertainty principle applied to
electromagnetic fields indicates that it is
impossible to find both E and B fields to be zero
at the same time. - The quantum fluctuations of the vacuum so
produced cannot be detected by normal
instruments, because they carry no energy. - However, they may be detected by an accelerating
detector, which provides a source of energy. - The accelerating observer would measure a
temperature of the vacuum (the Unruh
temperature), given by - TU ah/2pc.
- Notes
- i. For an acceleration of 1019 m/s2, TU 1 K.
- ii. TU 0 if either h 0 or c 8, which is the
classical result.
51Zeroth Law of Black-Hole Mechanics
- Zeroth law
- The horizon of a stationary black hole has a
uniform surface gravity ?. - Thermodynamic analogy
- An object in thermal equilibrium with a heat
reservoir has a uniform temperature T. - Relationship between ? and T
- Analogous to the Unruh effect , Hawking showed
that black holes emit Hawking radiation at a
temperature TH, given by - TH h?/2pc,
- where ? may be thought of as the magnitude of
the acceleration needed by a spaceship to just
counteract the gravitational acceleration just
outside the event horizon.
52Entropy of a Black Hole
- Black holes must carry entropy, because the 2nd
law of thermodynamics requires that the loss of
entropy of an object falling into a black hole
must at least be compensated by the increase of
entropy of the black hole. - The expression for the entropy of a black hole,
obtained by Beckenstein, and later confirmed by
Hawking is - SBH kAc3/4Gh,
- where k is Boltzmanns constant, A is the
area of the black holes horizon, and BH could
stand for black hole or Beckenstein-Hawking. - A system of units with c1 gives SBH kA/4Gh,
while one in which c1, h1, k1 and G1 gives
SBH A/4, showing that a black-holes entropy is
proportional to the area of its horizon.
53First Law of Black-Hole Mechanics
- 1st law
- dM (?/8p) dA O dJ F dQ,
- where M is the mass, O is the angular
velocity, J is the angular momentum,F is the
electric potential, Q is the charge, and the
constants c, h, k, and G are all made equal to
unity. - Thermodynamic analogy
- dU T dS P dV
- Relationship between (?/8p)dA and TdS
- Since TH ?/2p and SBH A/4,
- (?/8p) dA (2pTH)(1/8p)(4dSBH) THdSBH
- i.e. the first term is just the product of
the black-hole temperature and its change of
entropy.
54Second Law of Black-Hole Mechanics
- 2nd law
- The area A of the horizon of a black hole is a
non-decreasing function of time i.e. ?A 0. - Thermodynamic analogy
- The entropy of an isolated system is a
non-decreasing function of time i.e. ?S 0. - Hawking radiation
- If the quantum fluctuations of the vacuum
produces a particle-antiparticle pair near the
horizon of a black hole, and the antiparticle
drops into the hole, the particle will appear to
have come from the black hole, which loses
entropy. - This leads to a generalized 2nd law
- ?Soutside (A/4) 0.