Title: For all machines
1For all machines
- Basic concepts of construction and operation
- How to start machine?
- How to calculate the circuit parameters?
- How to achieve voltage (generator) or speed
(motor) control? - The power flow diagram and the power losses
2Review of Motor Concepts
- A motor converts ?
- Electrical Energy ? Mechanical Energy
- Basic Construction of a motor?
ROTOR
AIR GAP
STATOR
3Review of Motor Concepts
- Basic Operation of a motor?
- Produce Stator Magnetic Field, BS
- Produce Rotor Magnetic Field, BR
- ?ind kBR x BS
- In other words, as BS rotates, BR will chase BS
and this induces a torque that causes the rotor
to rotate at speed, ?
Torque Induced
4Chapter 7 Induction Motor
- EEEB 283
- Semester 2 Year 2006 / 2007
- Aishah Mohd Isa
5Induction Motor -concept
- How do we get BS in induction motor?
- Apply 3 phase sinusoidal current to stator
windings - How to get BR in induction motor?
- Current is induced on rotor winding by stator
magnetic field - ? Torque is induced
6Induction Motor- CoNcept
- On stator 3 ? IS ? BS
- On rotor IR ? BR
- ? By definition, an induction motor is an AC
machine where no direct field current is supplied
to its field windings, instead field current is
induced by the stator magnetic field.
?ind
7Induction motor construction
- Stator is the hollow cylindrical core with slots
for windings - Rotor
- revolves inside the stator
- has slots for windings
- has two types of construction
- Squirrel Cage Rotor
- Wound Rotor
8Cage Rotor construction
Casing
Conductor shorting rings
Stator windings
Fins to cool the rotor
Embedded rotor conductors
Iron core
Shaft
- Squirrel Cage Rotor has conducting bars shorted
at the end by shorting (or end) rings
9Wound Rotor Construction
Stator windings
Rotor windings
Slip rings
Shaft
Stator winding connections to power source
Brushes
- Wound rotor has a set of 3-phase windings,
usually Y-connected with the ends tied to slip
rings. Rotor windings are shorted by brushes
riding on the slip rings. - Wound rotor is more expensive and requires more
maintenance
10Principle of operation
- 3 phase winding on stator produces BS and speed
of rotation for BS is - where ?sync synchronous speed of BS
- fe electrical frequency
- Pnumber of poles
- BS induces current and voltage (eind v x B . ?)
on the rotor bars which will then produce BR - Motor action comes from ?ind kBR x BS
11PRINCIPLE OF OPERATION
- BS BR
- ?ind kBR x BS
- Note that if rotor speed is the same as stator
magnetic field speed, - eind 0, IR 0, BR 0 and ?ind 0
- ? Induction motor is operated NEAR synchronous
speed but not at synchronous speed
?
12Rotor Slip
- Stator magnetic field speed is known as
synchronous speed, ?sync - Rotor speed is known as motor speed, ?M
- Rotor bar induced voltage is dependent upon the
relative speed between ?sync and ?M.
13Rotor Slip
- Slip speed, ?slip ?sync - ?M.
- Slip,
- If rotor is stationary, ?M 0, s 1. This
condition is also known as locked rotor
condition. - If rotor is at the same speed as BS,?M ?sync ,
s0. - Note that 0ltslt1 and ?M (1-s) ?sync
14Electrical frequency of rotor
- An induction motor is like a rotating
transformer, i.e. Stator (primary) induces
voltage in the rotor (secondary) - Stator winding electrical frequency comes from
its 3 phase windings, thus stator frequency, fS
fe - For locked rotor condition, ?M 0 and s1,
- When rotor at synchronous speed, ?M ?sync and
s0, - For 0lt ?M lt ?sync ? fR sfe
fR fe
fR0
15Summary
- 3 ? Is ? BS?IR?BR
- kBR x BS? ?ind
-
- ?slip ?sync - ?M.
-
- ?M (1-s) ?sync
- fR sfe
Vaa -
16Example
- A 220 V 15 hp, 8, 50 Hz pole induction motor has
full load slip of 10. (1hp746W) - Find
- ?sync
- ?M.
- fR.
- ?ind
17answer
- a)
-
- b) ?M (1-s) ?sync
- (1-0.10) 750
- 675 rpm c) fR s
fe - 0.10 x 50 5 Hz
18Induction motor Equivalent Circuit
- Induction motor operation relies on rotor
voltages and currents induced by the stator
circuit - This is similar to transformer action.
- ? Induction motor equivalent circuit is similar
to transformer equivalent circuit
19Induction Motor Equivalent Circuit
Stator
Excitation Branch
Rotor
20Induction Motor Equivalent Circuit
- For Primary Side
- Essentially the same as the transformer
- R1 Stator winding resistance
- jX1 Stator winding leakage reactance
21Induction Motor Equivalent Circuit
- The flux in the induction motor depends on the
integral of the applied voltage, E1 . - The magnetization curve for the induction motor
is as shown. - Notice that the slope for induction motor is
shallower than the one for transformer. - This is due to the air gap reluctance which
requires more magnetomotive force to obtain a
certain flux level
22Induction Motor Equivalent Circuit
- The excitation current is modeled by RC and XM
23Induction Motor Equivalent Circuit
- The primary stator voltage E1 is coupled to
secondary rotor voltage ER by effective turns
ration, aeff - Voltage ER produces current flow in the rotor
circuit
24Induction Motor Equivalent Circuit
- The primary impedances and magnetising current in
the induction motor is very similar to
corresponding components in a transformer
equivalent circuit. - Difference comes from the effect varying rotor
frequency on rotor voltage and rotor impedances.
25Induction Motor Equivalent Circuit
- The Rotor Circuit Model
- When voltage is applied to the stator windings,
voltage will be induced in the rotor circuit. - The amount of induced rotor voltage is dependent
upon slip. - In general, as the relative motion between the
rotor and the stator magnetic fields increases,
the resulting rotor voltage and rotor frequency
increases. (s?, ER?, FR?)
26Induction Motor Equivalent Circuit
- Components in the rotor circuit model that
depends on slip are - Rotor induced voltage, ER sER0
- Rotor frequency, frsfe
- Rotor windings leakage reactance, XRsXR0 where
XR 2?fLR - Rotor windings resistance, RR is the only
constant component
27Induction Motor Equivalent Circuit
- At locked rotor conditions (?M 0, s1)
- ER0 sER ER ? maximum voltage induced
- fr sfe fe
- XRsXR0 XR0 2?fLR 2?feLR
- At synchronous conditions (?M ?Sync, s0)
- ER 0? no voltage induced
- fr sfe 0
- XRsXR0 2?fLR 0
28Induction Motor Equivalent Circuit
- As before
- ER sER0
- frsfe
- XRsXR0
-
29Induction Motor Equivalent Circuit
- Referring to primary side
- E1 aeff ER0
- R2 aeff2 RR
- X2 aeff2 XR0
30Final Equivalent circuit model
I? I1
jX2
j
V?
R2/S
-
31Power and Torque
- What is the input and output of an ideal
induction motor?
Input Power (electrical)
Output Power (mechanical)
32Power and Torque
- Power losses on the stator side
- Stator Copper Loss, PSCL 3 I12R1 at the stator
windings - Core Losses, PCORE, consists of Hysterisis and
eddy current losses. - As power is transferred through the air gap to
the rotor, power loss as air gap power PAG 3
I22R2/s ?ind ?sync
33Power and Torque
- Power losses on rotor side
- Rotor copper loss PRCL I22R2 at the rotor
windings - As power converts from electrical to mechanical
power, power loss as - For electrical
- For mechanical
34Power and Torque
- Miscellaneous losses
- Friction and windage losses, PFW
- Stray losses, Pstray
35Power Flow Diagram
PSTRAY
PFW
36Power and torque
- Please note that at higher speeds (?M?sync),
core losses are lumped with the miscellaneous
losses as rotational losses, - ProtationalPcorePstrayPFW
37Power Flow Diagram
P rotational
38Losses at the Circuit
PSCL
PAG
PCORE
39Losses at The Circuit
40Losses at the Circuit
PSCL
PRCL
PCORE
PCONV
41Induction Motor TorQue Speed Characteristics
- How does speed vary when shaft load increases?
- Case I No Load
- ?M?sync ? s 0
- Since s is very small, relative motion small
- fr?, Er ?, iR ? , BR ?
- - fr small, X2 2? fr L small, R2 /s big, current
in phase with ER - since IR induces torque, torque induced is very
small and just enough to overcome rotational
losses
42Induction Motor TorQue Speed Characteristics
- Case II With Load
- ?Mgt?sync ? slip increases
- As slip inceases, ? fr?, Er ? iR ? BR ?
- fr large, X2 2? fr L large, R2 /s small, current
lags ER - since IR induces torque, torque increases too ?
ir?, ?ind ? - Pullout Torque
- - If load too high, there comes a point where iR
lags Er too much that the torque starts to
decrease. This is the pullout or maximum torque. - - After that point, torque will decrease
43Induction Motor Torque Speed Characteristics
Torque Induced
Synchronous Speed
44Torque Speed Characteristic
- Low Slip Region
- As load increases, slip increases almost linearly
(speed reduces) - Power factor nearly unity (XR0)
- Torque increases as load increases
- Linear region is normal steady state operating
range
45Torque Speed Characteristic
- Moderate Slip Region
- Relative motion is higher, fR higher
- XR RR
- Pullout torque occurs in this region
- High Slip Region
- If load increased in this region, torque
decreases and stops
46(No Transcript)
47Induction Motor Torque Speed Curve
- At synchronous speed, ?ind 0.
- The curve is linear between no load and full
load. - The maximum torque is known as pullout torque or
breakdown torque. It is approximately 2 to 3
times the rated full-load torque of the motor. - The starting torque is slightly larger than its
full-load torque. So, IM will start carrying any
load it can supply at full power - Torque for a given slip varies as square of the
applied voltage. This is useful as one form of IM
speed control. - If rotor is driven faster than synchronous speed,
machine becomes a generator - If motor is turning backward relative to the
direction of magnetic fields (achieved by
reversing the magnetic field rotation
direction)?ind will stop the machine very rapidly
(braking) and try to rotate in the other
direction.
48Induced Torque Equation
-
- How to find PAG?
- PAG 3 I22R2/s, so need to find I2
- To find I2 simplify the stator circuit to get the
Thevenin Equivalent
49Thevenin Values
50Pullout torque
- Occurs when PAG maximum
- PAG incurred from R2/s
- For maximum power transfer
Magnitude of impedance
Magnitude of source impedance
51Pullout Torque
- At maximum power transfer, slip max
- Substitute into induced torque equation
52Variations in Induction Motor Torque Speed
Characteristic
- High R2
- High starting torque
- High slip
- But Pconv (1-s) PAG
- Efficiency low at normal operation
- Low R2
- Low starting torque (high starting current)
- Low slip
- Efficiency high at normal operation
- What do we need to do to get desired curve?
- High R2 at start but low R2 at normal operation
53Rotor designs
- For wound rotor?
- For cage rotor?
- Design A - Large bars near surface
- Design D - Small bars near surface
- Design B - Variable rotor resistance
- Design C - Variable rotor resistance
54Starting induction Motor
- -can connect straight to power line but this will
cause voltage dip in power system due to high
starting current required - For wound rotor?
- Insert extra resistance during startup
- For cage rotor?
- Determine current required from code letter
factor - Either
- insert extra inductors or resistors into power
line during startup - Reduce VT using transformers
55(No Transcript)
56Autotransformer
3 phase power system
1. Close 1 and 3
2. Open 1 and 3
3. Close 2
1
1
2
2
1
2
3
3
Induction Motor
57Induction Motor Protective Circuits
58Induction Motor Protective Circuits
- Start Protection Circuit
- When igtirated, fuses F1,F2 and F3 will melt
- Overload Protection
- OL heater elements and OL contacts will react
when temperature is too high - Undervoltage Protection
- When line voltage lt rated motor terminal voltage
59Speed Control of Induction Motors
- Vary synchronous speed, ?sync
- Change electrical frequency,fe
- Change number of poles, P
- Vary slip,s
- Change terminal voltage, VT
- Change rotor resistance, R2
60Determining Circuit Model Parameters
- How to find R1, R2, X1, X2 and XM ?
- Use three tests No Load Test, DC Test, Locked
Rotor Test
61No load Test
62DC Test
63Locked Rotor Test