6'7 Areas of Triangles and Quadrilaterals - PowerPoint PPT Presentation

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6'7 Areas of Triangles and Quadrilaterals

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Find the area of trapezoid WXYZ. Solution: The height of WXYZ is h=5 1 = 4 ... area of trapezoid WXYZ is 20 square units. Justification of Kite/Rhombuses formulas ... – PowerPoint PPT presentation

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Title: 6'7 Areas of Triangles and Quadrilaterals


1
6.7 Areas of Triangles and Quadrilaterals
  • Geometry
  • Mrs. Spitz
  • Spring 2005

2
Objectives
  • Find the areas of squares, rectangles,
    parallelograms and triangles.
  • Find the areas of trapezoids, kites and rhombuses.

3
Assignment
  • pp. 376-378 3-43. Skip 39 and 40.

4
Using Area Formulas
  • Postulate 22 Area of a Square PostulateThe
    area of a square is the square of the length of
    its side, or A s2.
  • Postulate 23 Area Congruence PostulateIf two
    polygons are congruent, then they have the same
    area.
  • Postulate 24 Area Addition PostulateThe area
    of a region is the sum of the areas of its
    nonoverlapping parts.

5
Area Theorems
  • Theorem 6.20Area of a RectangleThe area of a
    rectangle is the product of its base and height.
  • You know this one and you have since
    kindergarten. Since you do the others should be
    a breeze.

h
b
A bh
6
Area Theorems
  • Theorem 6.21Area of a ParallelogramThe area of
    a parallelogram is the product of a base and
    height.

h
b
A bh
7
Area Theorems
  • Theorem 6.22Area of a TriangleThe area of a
    triangle is one half the product of a base and
    height.

h
b
A ½ bh
8
Justification
  • You can justify the area formulas for
    parallelograms as follows.
  • The area of a parallelogram is the area of a
    rectangle with the same base and height.

9
Justification
  • You can justify the area formulas for triangles
    follows.
  • The area of a triangle is half the area of a
    parallelogram with the same base and height.

10
Ex. 1 Using the Area Theorems
  • Find the area of ?ABCD.
  • Solution
  • Method 1 Use AB as the base. So, b16 and h9
  • Areabh16(9) 144 square units.
  • Method 2 Use AD as the base. So, b12 and h12
  • Areabh12(12) 144 square units.
  • Notice that you get the same area with either
    base.

9
11
Ex. 2 Finding the height of a Triangle
  • Rewrite the formula for the area of a triangle in
    terms of h. Then use your formula to find the
    height of a triangle that has an area of 12 and a
    base length of 6.
  • Solution
  • Rewrite the area formula so h is alone on one
    side of the equation.
  • A ½ bh Formula for the area of a triangle
  • 2Abh Multiply both sides by 2.
  • 2Ah Divide both sides by b.
  • b
  • Substitute 12 for A and 6 for b to find the
    height of the triangle.
  • h2A 2(12) 24 4
  • b 6 6
  • ?The height of the triangle is 4.

12
Ex. 3 Finding the Height of a Triangle
  • A triangle has an area of 52 square feet and a
    base of 13 feet. Are all triangles with these
    dimensions congruent?
  • Solution Using the formula from Ex. 2, the
    height is
  • h 2(52) 104 8
  • 13 13
  • Here are a few triangles with these dimensions

8
8
8
8
13
13
13
13
13
Areas of Trapezoids
  • Theorem 6.23Area of a TrapezoidThe area of a
    trapezoid is one half the product of the height
    and the sum of the bases.
  • A ½ h(b1 b2)

b1
h
b2
14
Areas of Kites
d1
  • Theorem 6.24Area of a KiteThe area of a kite is
    one half the product of the lengths of its
    diagonals.
  • A ½ d1d2

d2
15
Areas of Rhombuses
  • Theorem 6.24Area of a RhombusThe area of a
    rhombus is one half the product of the lengths of
    the diagonals.
  • A ½ d1 d2

d2
d1
16
Areas of Trapezoids, Kites and Rhombuses
  • You will have to justify theorem 6.23 in
    Exercises 58 and 59. You may find it easier to
    remember the theorem this way.

b1
h
b2
Height
Area
Length of Midsegment
x

17
Ex. 4 Finding the Area of a Trapezoid
  • Find the area of trapezoid WXYZ.
  • Solution The height of WXYZ is h5 1 4
  • Find the lengths of the bases.
  • b1 YZ 5 2 3
  • b2 XW 8 1 7

18
Ex. 4 Finding the Area of a Trapezoid
Substitute 4 for h, 3 for b1, and 7 for b2 to
find the area of the trapezoid. A ½ h(b1 b2)
Formula for area of a trapezoid. A ½ (4)(3 7
) Substitute A ½ (40) Simplify A 20 Simplify
?The area of trapezoid WXYZ is 20 square units
19
Justification of Kite/Rhombuses formulas
  • The diagram at the right justifies the formulas
    for the areas of kites and rhombuses. The
    diagram show that the area of a kite is half the
    area of a rectangle whose length and width are
    the lengths of the diagonals of the kite. The
    same is true for a rhombus.

20
Ex. 5 Finding the area of a rhombus
B
  • Use the information given in the diagram to find
    the area of rhombus ABCD.
  • Solution
  • Method 1 Use the formula for the area of a
    rhombus d1 BD 30 and d2 AC 40

15
20
20
A
C
24
15
D
E
21
Ex. 5 Finding the area of a rhombus
B
  • A ½ d1 d2
  • A ½ (30)(40)
  • A ½ (120)
  • A 60 square units
  • Method 2 Use the formula for the area of a
    parallelogram, b25 and h 24.
  • A bh 25(24) 600 square units

15
20
20
A
C
24
15
D
E
22
  • ROOF Find the area of the roof. G, H, and K are
    trapezoids and J is a triangle. The hidden back
    and left sides of the roof are the same as the
    front and right sides.

23
SOLUTION
  • Area of J ½ (20)(9) 90 ft2.
  • Area of G ½ (15)(2030) 375 ft2.
  • Area of J ½ (15)(4250) 690 ft2.
  • Area of J ½ (12)(3042) 432 ft2.
  • The roof has two congruent faces of each type.
  • Total area2(90375690432)3174
  • ?The total area of the roof is 3174 square feet.
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