Title: Active Control NonInferiority Trial The Hypothesis
1Active Control Non-Inferiority Trial The
Hypothesis
- George Y.H. Chi, Gang Chen, Kevin Liu
- Clinical Biostatistics
- Global Drug Development, JJ PRD
- Yong-Cheng Wang
- Food and Drug Administration
- November 1, 2004, BASS XI, Savannah, Georgia
2Disclaimer
- This talk is based on research work that was
- initiated while Dr. Gang Chen and I were still
- at FDA. The views expressed here are those
- of the authors and do not represent those of
- the FDA in any way.
3Outline of Presentation
- Reasons for Active Control
- Purposes of Active Control Trials
- Fixed Margin Non-inferiority Hypothesis
- Fraction Retention Non-inferiority Hypothesis
- Critical Assumptions
- Summary
4Reasons for Active Control
- Ethics For trials involving mortality or
serious morbidity outcome, it is unethical to use
placebo when there are available active drugs on
the market - Assay sensitivity In trials involving
psychotropic drugs, placebo often has large
effect. An active control is sometime used to
demonstrate that the trial has assay sensitivity. - Comparative purpose To show how the
experimental drug compares to another known
active drug or a competitor
5Purposes of Active Trials
- The purpose of an active control trial could be
to demonstrate that a new experimental treatment
is either - superior to the control
- equivalent to the control, or
- non-inferior to the control
- superior to a virtual placebo
6Scope of Our Discussion
- Focus on use of active control for ethical reason
- Placebo is not permitted in such trials
- The primary objective is to show that relative to
either an efficacy or safety endpoint, the new
experimental drug is either - superior to the control
- equivalent to the control, or
- non-inferior to the control
- superior to a virtual placebo
7Some Notations
- Let T stand for an experimental drug
- Let C stand for an active control
- Let P stand for a placebo
- Relative to a given time to event endpoint, such
as, mortality, let HR(T/C) stand for the hazard
ratio of T relative to C and similarly for
HR(P/C). Then, - HR(T/C) 1 gt T C
- HR(T/C) gt 1 gt T lt C
- HR(T/C) lt 1 gt T gt C
8HR(T/C) Hazard Ratio of T Relative to CFigure 1
- T C
- T gt C
T lt C - 0.8 1
1.05 HR(T/C)
9Active Control Superiority Trial
- In an active control trial, if we demonstrate
that T gt C, then what can we claim? - T is superior to the control, i.e., T gt C ?
- Not quite. We can only claim that T is effective
in the sense that T is superior to a virtual
placebo, that is, T gt P, if a placebo,
P, were to be present. - The reason being
- The control C may not be effective in the current
trial, and hence we have - T gt C P See Figure 2
10Active Control Superiority TrialFigure 2
- If HR(T/C) lt 1, then T is effective
-
-
-
- 0.8 1
HR(T/C)
11Active Control Superiority Trial
- Therefore, in an active control superiority
trial, if we demonstrate that T gt C, then we can
claim that - T is superior to C, i.e., T
gt C , - only under the following assumption
- That the control C is effective in the current
trial, i.e., if a placebo P were to be present,
then the trial would also have demonstrated that
C gt P - For then, we have T gt C gt P See Figure 3.
12Active Control Superiority TrialFigure 3
- If HR(T/C) lt 1, then T is superior to
C, - provided C is effective.
- T gt C
- HR(T/C)
HR(P/C) - 0.8 1
1.2 HR(T/C)
13Active Control Non-inferiority Trial
- To demonstrate that a new experimental drug T is
superior to an active control, C, is usually
difficult and requires a large sample size,
unless T is really effective. - Furthermore, even if we succeeded in showing
T gt C, we can only claim that T is effective,
because we cannot really prove the assumption
that C is effective in this trial without the
presence of a placebo, P. - Even if C were effective, a regulatory authority
may not be willing to grant a comparative claim.
14Active Control Non-inferiority Trial
- Therefore, it makes sense to show that the new
experimental drug T is non-inferior to the
control, C, i.e., no worse than the control, by a
margin of ?. - We shall denote this by
- T ?? C
- and it is depicted graphically in Figure
4.
15Active Control Non-inferiority TrialFigure 4
- If HR(T/C) lt 1 ?, then T is non-inferior to C
by a margin of ?. - T ?? C
-
-
? -
- 0.8 1
1 ? HR(T/C) -
16Active Control Non-inferiority Trial
- To design an active control non-inferiority
trial, how does one specify the non-inferiority
margin ?? - Can this ? be arbitrarily specified?
- If ? is arbitrarily set, then
- ? may be too tight and it requires a large
sample size, or - ? may be too liberal and as a consequence, a new
experimental treatment may be shown to be
non-inferior to the control, but in fact, it
could be worse than placebo - We need some reference
17Active Control Non-inferiority Trial
- If C P, then HR(P/C) 1, and if 1 lt HR(T/C) lt
1 ?, then T is inferior to P, since HR(T/C)
HR(T/P). -
-
-
-
-
HR(T/C)
18Active Control Non-inferiority Trial
- If C gt P and 1 lt HR(P/C) lt 1 ?, then if HR(P/C)
lt HR(T/C) lt 1 ?, then T is inferior to P. -
-
-
-
-
HR(T/C)
-
HR(P/C)
19Active Control Non-inferiority Trial
- Thus, we cannot set ? such that HR(P/C)
1 lt ?, i.e., we - cannot allow HR(P/C) lt 1 ?.
- This implies that we must set
- 0 lt ? HR(P/C) - 1.
- This means that ? must be a fraction, ?, of the
control - effect, i.e.,
- ? ? HR(P/C) 1.
20Active Control Non-inferiority Trial
- We can interpret ? as the amount of loss of the
control effect that we are willing to accept See
Figure 5. - Then
-
- HR(P/C) 1 ? HR(P/C) 1 - ?
HR(P/C) 1 - (1 - ?)
HR(P/C) 1 - d
HR(P/C) 1 -
- is the amount of the control effect that
we would like to retain, where d is the retention
fraction.
21Active Control Non-inferiority TrialFigure 5
22Active Control Non-inferiority Trial
- Now from the previous equation, we can obtain the
following expression - d 1 - ? / HR(P/C)
1 - i.e.,
- d HR(P/C) 1 ? /HR(P/C)
-1.
23Active Control Non-inferiority Trial
- If we are interested in
demonstrating that the new - experimental treatment is not worse than the
control C - by an amount ?o, then we are interested in
testing the - following hypothesis
- Ho HR(T/C) 1 ?o vs.
Ha HR(T/C) lt 1 ?o , - i.e.,
- Ho HR(T/C) -1 ? ?o vs. Ha
HR(T/C) -1 ? lt ?o. -
-
24Active Control Non-inferiority Trial
- Now if the true control effect, HR(P/C) 1, is
known, or can - be accurately estimated, and do lt HR(P/C) 1,
then, this - would be equivalent to testing the null
hypothesis - Ho d
do vs. Ha d gt do , - where
-
- do HR(P/C) 1
?o/HR(P/C) -1, - and
? - d HR(P/C) 1 HR(T/C) 1
/HR(P/C) -1, -
25Active Control Non-inferiority Trial
- Now if the true control effect, HR(P/C) 1, is
not known, or - cannot be accurately estimated, then we can no
longer be sure - that a fixed margin ?o lt HR(P/C) -1.
- In this event, the fixed margin hypothesis may
not be - appropriate, if ?o gt HR(P/C) -1.
- Therefore, to avoid this problem, it seems
natural to select a do - such that 0 lt do lt 1, and test the following null
hypothesis - Ho ? (1 - do) HR(P/C) 1
26Active Control Non-inferiority Trial
- Now this hypothesis has two unknown parameters,
and one - can reformulate this hypothesis to the following
hypothesis - Ho d do vs.
Ha d gt do , - where
- HR(P/C) 1 ?
- d
- HR(P/C) 1
27Active Control Non-inferiority Trial
- Note that
- if do 1, then this is the superiority trial.
- If 0 lt do lt 1, then this is the equivalence, or
non-inferiority trial - FDA had used do ½ for non-inferiority
demonstration in Xeloda and in thrombolytic
trials - How should do be set?
- If do 0, then this is a superior to virtual
placebo trial -
28Active Control Non-inferiority Trial
- Summary
- Whether it is fixed margin or not, we need to
have some information on HR(P/C) 1 as a
reference - If HR(P/C) 1 cannot be reliably estimated,
then fixed margin approach may be problematic - If the fraction retention approach is used, we
need to satisfy some assumptions including - HR(P/C) 1 gt 0
- There are relevant historical studies of the
control compared to placebo, or other comparator
such as standard of care for estimating the
control effect - How to set the level of retention fraction, do,
needs to be investigated through some simulation
work. In the end, it will be based on both
clinical and statistical judgment -
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