CSCI 4260 MATH 4150 - PowerPoint PPT Presentation

1 / 26
About This Presentation
Title:

CSCI 4260 MATH 4150

Description:

Can we say anything about the connectivity? Let's start with some sufficient conditions ... there must be a third vertex, say vt, which is adjacent to vr but ... – PowerPoint PPT presentation

Number of Views:41
Avg rating:3.0/5.0
Slides: 27
Provided by: csr8
Category:
Tags: csci | math | anything | odd | say

less

Transcript and Presenter's Notes

Title: CSCI 4260 MATH 4150


1
CSCI 4260MATH 4150
  • GRAPH THEORY

2
Last time, I forgot to mention.
  • Email mylastname _at_ cs.rpi.edu
  • Webpagehttp//www.cs.rpi.edu/isler
  • Course webpagehttp//www.cs.rpi.edu/isler/teachi
    ng/spring06/

3
Degree of a vertex
  • Recall the definition of neighborhood from last
    lecture.
  • Definitions
  • degree of a vertex
  • ?(G)
  • ?(G)

4
Theorem
  • Let G (V,E) with E m. We have

5
For bipartite G (U, W, E)
6
Theorem
  • Every graph has an even number of odd vertices
    (vertices with odd degree).

7
Global properties from local investigation
  • Connectivity of a graph. Local or global
    property?
  • Suppose we are allowed to investigate only one
    vertex at a time.
  • Can we say anything about the connectivity?

8
Lets start with some sufficient conditions
  • What is a
  • Necessary condition
  • Sufficient condition
  • If G contains a vertex with degree n-1, then G is
    connected.
  • How about n-2?

9
Theorem
  • If
  • for every u,v ? V then
  • G is connected
  • diam(G) lt 2

10
Corollary
  • If
  • then
  • G is connected

11
Theorem
  • If

FALSE
  • for every u,v ? V then
  • G is connected

This means that our bound of n-1 is sharp (or
tight)
12
Regular graph
  • A graph is k-regular if every vertex has exactly
    k neighbors
  • Remember our theoremno graph contains an odd
    number of odd vertices
  • What does this say about regular graphs?
  • Can you have a k regular graph for arbitrary n?

13
k-regular graph
  • We can not have k and n both odd.
  • Can you think of other constraints?
  • It turns out that this is the only constraint we
    have

14
Theorem
  • There exists a k-regular graph of order n if and
    only if at least one of r and k is even

15
Theorem
  • For every graph G and every integer r ??(G),
    there exists an r-regular graph containing G as
    an induced graph.

16
r 3 G as given below
17
Not so regular graphs
  • Degree sequences
  • graphical sequence
  • How do we know if a given sequence is graphical?

18
Theorem
  • Lets d1, d2, , dn be non-increasing sequence.
  • Constructs1 d2-1,d3-1, , dd11, d12,, dn
  • s is graphical iff s1 is graphical

19
If direction s1 is graphical
  • Lets d1, d2, , dn be non-increasing sequence.
  • Constructs1 d2-1,d3-1, , dd11, dd12,, dn
  • s is graphical iff s1 is graphical

20
Only if direction s is graphical
  • Lets d1, d2, , dn be non-increasing sequence.
  • Constructs1 d2-1,d3-1, , dd11, dd12,, dn
  • s is graphical iff s1 is graphical
  • Claim among all graphs with degree sequence s,
    there is one where the vertex with degree d1is
    adjacent to vertices with degrees d2, , dd11

21
Proof of the claim. Suppose not
We have dr gt ds
vr
Hence there must be a third vertex, say vt, which
is adjacent to vr but not to vs
vs
vt
v1
Among all graphs with degree sequence of s, pick
the one such that the sum of the degrees of the
neighbors of v1 is max.
22
Proof of the claim. Suppose not
Lets reorder the edges
vr
vs
vt
v1
What happened to the sum of the degrees of the
neighbors of v1?
23
Irregular graphs
  • Definition no two vertices have the same degree
  • Can you come up with one?

24
Theorem
  • Irregular graphs dont exist.

25
Quiz
  • Please take out a sheet of paper and put your
    name.

26
Theorem
  • G is a connected graph of order gt 3
  • if and only if
  • it contains two vertices u,v such that G-u and
    G-v are connected.
Write a Comment
User Comments (0)
About PowerShow.com