Title: Review on the Properties of Gases
1Review on the Properties of Gases
- Kinetic Theory- particles are in constant motion
- Increase in temperature increase movement of
particles (increase kinetic energy) - Collisions cause pressure (collisions with walls
of container and collisions with other molecules)
2Review on Gases cont
- Gases have no definite shape (they take the shape
of their container) - Gas molecules are spread apart (not fixed in
position) - Changing the kinetic energy of the particles will
cause a significant change in volume (as
discussed earlier)
3Factors Affecting Gas Pressure
- Number of Particles
- What happens when you put air in your tire?
- Pressure increases because you are increasing the
number of gas particles which increases
collisions. - If you double the number of gas particles then
you will double the gas pressure - Volume of Gas/Container
- What happens if you decrease the volume of a
container of gas?increase the volume of the
container? - Decreasing volume causes more collisions thus
increasing pressureIncreasing volume decreases
collision thus decreasing pressure. - Temperature
- What happens if you increase the temperature of a
gas?decrease it? - Increasing temperature will increase pressure due
to the increase in kinetic energy. The particles
are moving faster and hit the walls with more
force and more frequently. Opposite is true for
a decrease in temp
4The Pressure-Volume Relationship Boyles Law
- For a given mass of gas at a constant
temperature, the volume of the gas varies
inversely with pressure. - If you increase volume you decrease pressure.
- If you decrease volume you increase pressure.
5Boyles Law cont
- The mathematical equation for Boyles Law is P1
X V1 P2 X V2 - P1 and V1 are the initial pressure and volume
given - P2 and V2 are the final pressure and volume given
- REMINDER!! Standard pressure is 1.0 atm or 760
mmHg or 101 kPa or 76 cmHg
6- A high-altitude balloon contains 30.0 L of helium
at standard temperature and pressure. What is
the volume when the balloon rises to an altitude
where the pressure is only 25.0 kPa? (assume
temperature remains constant) - P1 101 kPa
- V1 30.0 L
- P2 25 kPa
- V2 ?
- 101 X 30 25 X V2 124 L
- 25 25
7The Temperature Volume Relationship Charles
Law
- The volume of a fixed mass of gas is directly
proportional to its Kelvin temperature if the
pressure is kept constant. - As temperature increases volume increases
- As temperature decreases volume decreases
8Charles Law cont
- The mathematical equation for Charles Law is
V1/T1 V2/T2 - Remember V1 and T1 are the initial and V2 and T2
are the final - Temperature MUST be measured in Kelvin
- To convert from C to K you add 273 to the Celsius
temp - To convert from K to C you subtract 273 from
Kelvin temp -
9The Temperature-Pressure Relationship
Gay-Lussacs Law
- The pressure of a gas is directly proportional to
the Kelvin temperature if the volume remains
constant - The mathematical equation is represented by
P1/T1 P2/T2
10- The gas left in a used aerosol can is at standard
pressure and a temperature of 298 K. If this can
is thrown into a fire, what is the pressure of
the gas in kPa if the temperature of the aerosol
can reaches 1201 K? - P1 101 kPa
- T1 298 K
- P2 ? kPa
- T2 1201 K
- 101 P2 101 X 1201 415 kPa
- 298 1201 298
11The Combined Gas Law
- Boyles, Charles, and Gay-Lussacs Laws can be
used together to form the Combined Gas Law - P1V1 P2V2
- T1 T2
12- The Volume of a gas-filled balloon is 30.0 L at
313 K and 153 kPa pressure. What volume will the
balloon have at standard temperature and
pressure? - V1 30L
- T1 313K
- P1 153 kPa
- V2 ? L
- T2 273 K (standard temperature)
- P2 101 kPa
- V2 30L X 153 kPa X 273K 39.5
- 101.3 kPa X 313 K
13Daltons Law of Partial Pressure
- At constant volume and temperature, the total
pressure exerted by a mixture of gases is equal
to the sum of the partial pressures of the
component gases. - This is represented by the equation
- Ptotal P1 P2 P3
14- Air contains oxygen, nitrogen, carbon dioxide,
and trace amounts of other gases. What is the
partial pressure of oxygen if the total pressure
is 101.3 kPa and the partial pressures of
nitrogen, carbon dioxide, and other gases are
79.10 kPa, 0.040 kPa, and 0.94 kPa respectively. - PN2 79.10 kPa
- PCO2 0.040 kPa
- Pothers 0.94 kPa
- Ptotal 101.30 kPa
- PO2 ? kPa
- PO2 Ptotal (PN2 PCO2 Pothers)
- 101.3 (79.1 .04 .94) 21.22 kPa
-
15Ideal Gas Law
- Based on Avogadros principl
- -At equal pressures and temperature, equal
volumes of gases contain the same number of
molecules
16- One mole of any gas at STP will occupy the same
volume as one mole of any other gas at STP - One mole of any gas at STP has a volume of 22.4
liters - The molar volume of a gas at STP
17Ideal Gas Equation
- Uses the 3 variables of the combined gas law plus
the molar volume
18PV nRT
- P pressure
- V volume
- n number of moles
- R molar gas constant
- T temperature
19Molar Gas Constants
- Derived from the molar volume of
- a gas at STP
- P standard pressure
- 1 atm 760 mmHg 101.3 kPa
- V 22.4 L
- n one mole
- T 273 K
- R
20Calculation of the Constant
- When pressure is in atm
- (1 atm)(22.4 L) (1 mole) R (273 K)
- 22.4 atmL 273 mol K (R )
- 0.0821 atm L/mol K R
- When pressure is in kPa
- (101.3 kPa)(22.4 L) (1 mole) R (273 K)
- 2269 kPa L 273 mol K (R )
- 8.31 kPa L/ mol K R
21When pressure is in mmHG (Torr) (760
mmHg)(22.4 L) (1 mole) R (273 K) 17024
mmHg L 273 mol K (R ) 62.4 mmHg L/ mol K
R
22What pressure is exerted by .306 moles of gas in
a 25.9 L container at 282 K ?-
P(25.9)(0.306mol)(0.0821atmL/mol K) (282 K)-
P (25.9L) 7.085 atm L- P 0.274 atm
23 What volume is occupied by 0.684
mol of a gas at 743 mmHg and 282 K? (743
mmHg)V 0.684 mol (62.4) (282K )