Title: Chapter 1: Basic Concepts in Probability
1Chapter 1 Basic Concepts in Probability
- It will include the following topics/sections
- 1.1 Sample Spaces, Events, and Probabilities
- 1.2 Simulations
- 1.3 Complementary Events and Mutually Exclusive
Events - 1.4 Some Probability Rules
-
21.1 Sample Spaces, Events, and Probabilities
- A sample space, S, is defined as the set of all
possible outcomes of an experiment. If the
outcomes in S are equally likely, we call S an
equally probable sample space. Any subset of S is
called an event. -
31.1 Sample Spaces, Events, and Probabilities
- Example 1If a box contains three balls numbered
1, 2, 3 and we draw one ball from the box in such
a way that each of the three balls are equally
likely to be selected, then 1, 2, 3 is an
equally probable sample space and -
- For this experiment odd, even is also a
sample space but not an equally probable sample
space since an odd outcome is twice as likely as
an even outcome.
41.1 Sample Spaces, Events, and Probabilities
51.1 Sample Spaces, Events, and Probabilities
- Example 2 Box I contains balls numbered 1, 2, 3
and box II contains 2, 3 and 4. One ball is
selected at random from each box. Then, the
sample space is S(1, 2), (1, 3), (1, 4), (2,
2), (2, 3), (2, 4), (3, 2), (3, 3), (3, 4),
where the first number in each order pair denotes
the number on the ball drawn from box I and the
second number in each ordered pair denotes the
number on the ball drawn from box II. This is the
set of all possible outcomes of this experiment,
and S is an equally probable sample space.
Consider the event A where Asum of digits on
the selected balls is an even number. Then
A(1, 3),(2, 2),(2, 4),(3, 3). Hence P(A)4/9.
(Why?)
61.1 Sample Spaces, Events, and Probabilities
- Example 3 Two red blocks and two green blocks
are arranged at (all the possible arrangements
are equally likely) in a row. Let Athere is
exactly one green block between two red blocks.
Find P(A). - Hint S(RRGG),(RGRG),(RGGR),(GGRR),(GRGR),(GRRG
), and S is equally probable sample space.
Why?
71.1 Sample Spaces, Events, and Probabilities
- Example 4 A box contains four balls numbered 1,
2, 3, 4. Two chips are drawn, at random, without
replacement, from the box. Let Alargest number
selected is 3. Find P(A).
81.1 Sample Spaces, Events, and Probabilities
- Homework / Class Exercises (Section 1.6, page 19)
- Do problems 2, 3, 6
-
- Enjoy your homework, and have a
wonderful day!
91.2 Simulations
- There are situations where either there is
no an analytic solution or we dont know to find
the analytic solution to a probability problem.
In these cases we can estimate P(A) by long-run
proportion of the times that A occurs. In other
words, we simulate the experiment. For this
course, we will use a random number target (see
page 6) to carry out these simulations. -
101.2 Simulations
- Example 1 Box I contains balls numbered 1,
2, 3 and box II contains balls numbered 2, 3, 4.
One ball is selected at random from each box.
Consider the event Athe sum of the digits on
the selected balls is an even number. To
demonstrate the simulation procedure we will
estimate P(A) in this example. -
111.2 Simulations
- Let us simulate this experiment 20 times
(why?). For the drawing from box I, we select
a number from the random number target until we
get either a 1, 2, or 3. So for this drawing,
4s, 5s, and 6s will be ignored. For the
drawing from box II, we select a number from the
random number target until we get either a 2, 3,
or 4. In this case 1, 5, and 6 are ignored.
-
121.2 Simulations
131.2 Simulations
141.2 Simulations
- The estimate of P(A) is the proportion of
times which A occurs which is 8/20 or 0.4. This
is not P(A). We have already evaluated P(A) to be
4/9. The value of 0.4 is an estimate of P(A)
based on the simulations.
151.2 Simulations
- Example 2 Problem 9, section 1.6
- Describe how to estimate P(A) for the above
example without ignoring any numbers from the
random number target.
161.2 Simulations
- Homework / Class Exercises (Section 1.6, page
18-20) - Do problems 1, 8
-
- Enjoy your homework, and have a
wonderful day!
171.3 Complementary Events and Mutually Exclusive
Events
- Definition
- Events A, B are said to be mutually exclusive if
they cannot occur together. - Example 1 Toss a die once. Then the events A1
and 5 are mutually exclusive. Why?
181.3 Complementary Events and Mutually Exclusive
Events
- Definition
- Events A, B are said to be complementary if both
of the following conditions are satisfied - Events A, B are mutually exclusive.
- Events A, B exhaust the sample space in the sense
that every outcome in S is ether in A or in B. - Example 2 Toss a die once. Then the events
Aodd number and Beven number are complementary.
Why?
191.3 Complementary Events and Mutually Exclusive
Events
- Example 3 Suppose that student Meat Loaf takes 5
courses for each of the 8 semester that he is
working on his college degree. Describe the
complementary event to each of the following - Gat least one semester Meat Loaf gets all As,
- HMeat Loaf makes at least one A every
semester,
201.3 Complementary Events and Mutually Exclusive
Events
- Solution (i) This means that Meat Loaf gets 5
As in either 1, 2, 3, 4, 5, 6, 7, or 8
semesters. The complementary event is that he
makes 5 As zero times. So, not Ghe makes less
than 5 As every semester. - (ii) This means that Meat Loaf makes either 1, 2,
3, 4, or 5 As for all eight semesters. The
complementary event is that he makes zero As in
at least one semester. So, not Hhe makes zero
As in at least one semester.
211.3 Complementary Events and Mutually Exclusive
Events
- Exercise Suppose that student Meat Loaf takes 2
courses for each of the 2 semester that he is
working on his college degree. - (a) Describe the sample space.
- (b) Describe the complementary event to each of
the following both in terms of English statement,
and mathematical notation. - Gat least one semester Meat Loaf gets all As,
- HMeat Loaf makes at least one A every
semester,
221.3 Complementary Events and Mutually Exclusive
Events
- Homework / Class Exercises (Section 1.6, page
18-20) - Do problems 10
-
- Enjoy your homework, and have a
wonderful day!
231.4 Some Probability Rules
- Probabilities satisfy the following rules
- Rule 1 P(A)0 if A is impossible event (Athe
empty set) - Rule 2 P(A)1 of A is certain event (AS)
- Rule 3 P(A)1-P(not A)
- Rule 4 If A and B are mutually exclusive events,
P(A or B)P(A)P(B)
241.4 Some Probability Rules
- Example 1Look Example 1.8 on page 10.
- Choose one letter from English language text.
- Find
- P(vowel is chosen)
- P(consonant is chosen)
251.4 Some Probability Rules
- Homework / Class Exercises (Section 1.6, page
18-20) - Do problems 11, 15
-
- Enjoy your homework, and have a
wonderful day!