Solubility

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Solubility Lesson 3 Calculating Ksp
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The Molar Solubility is the molarity required to
saturate or fill the solution at any given
temperature.
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The Molar Solubility is the molarity required to
saturate of fill the solution at any given
temperature. 1. The solubility (s) of BaCO3 is
5.1 x 10-5 M _at_ 250 C. Calculate the
solubility product or Ksp.
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The Molar Solubility is the molarity required to
saturate of fill the solution at any given
temperature. 1. The solubility (s) of BaCO3 is
5.1 x 10-5 M _at_ 250 C. Calculate the
solubility product or Ksp.
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The Molar Solubility is the molarity required to
saturate of fill the solution at any given
temperature. 1. The solubility (s) of BaCO3 is
5.1 x 10-5 M _at_ 250 C. Calculate the
solubility product or Ksp. BaCO3(s)
? Ba2 CO32-
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The Molar Solubility is the molarity required to
saturate of fill the solution at any given
temperature. 1. The solubility (s) of BaCO3 is
5.1 x 10-5 M _at_ 250 C. Calculate the
solubility product or Ksp. BaCO3(s)
? Ba2 CO32- s s
s
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The Molar Solubility is the molarity required to
saturate of fill the solution at any given
temperature. 1. The solubility (s) of BaCO3 is
5.1 x 10-5 M _at_ 250 C. Calculate the
solubility product or Ksp. BaCO3(s)
? Ba2 CO32- s s
s Ksp
Ba2CO32-
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The Molar Solubility is the molarity required to
saturate of fill the solution at any given
temperature. 1. The solubility (s) of BaCO3 is
5.1 x 10-5 M _at_ 250 C. Calculate the
solubility product or Ksp. BaCO3(s)
? Ba2 CO32- s s
s Ksp
Ba2CO32- Ksp ss

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The Molar Solubility is the molarity required to
saturate of fill the solution at any given
temperature. 1. The solubility (s) of BaCO3 is
5.1 x 10-5 M _at_ 250 C. Calculate the
solubility product or Ksp. BaCO3(s)
? Ba2 CO32- s s
s Ksp
Ba2CO32- Ksp ss
Ksp s2
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The Molar Solubility is the molarity required to
saturate of fill the solution at any given
temperature. 1. The solubility (s) of BaCO3 is
5.1 x 10-5 M _at_ 250 C. Calculate the
solubility product or Ksp. BaCO3(s)
? Ba2 CO32- s s
s Ksp
Ba2CO32- Ksp ss
Ksp s2 Ksp
(5.1 x 10-5)2
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The Molar Solubility is the molarity required to
saturate of fill the solution at any given
temperature. 1. The solubility (s) of BaCO3 is
5.1 x 10-5 M _at_ 250 C. Calculate the
solubility product or Ksp. BaCO3(s)
? Ba2 CO32- s s
s Ksp
Ba2CO32- Ksp ss
Ksp s2 Ksp
(5.1 x 10-5)2 Ksp 2.6 x
10-9
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Ksp Solubility Product Special Keq Saturated
solutions No Units Only Changes with Temperature
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2. The solubility of PbBr2 is 0.012 M _at_ 25 0C.
Calculate the Ksp. dissociation equation
PbBr2(s) ? Pb2 2Br- solubility
s s 2s equilibrium expression Ksp
Pb2Br-2 substitute solve Ksp
s2s2 Ksp 4s3 Ksp
4(0.012)3 Ksp 6.9 x 10-6 Note that
the Br- is doubled and then squared!
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3. If 0.00243 g of Fe2(CO3)3 is required to
saturate 100.0 mL of solution. What is the
solubility product? Fe2(CO3)3 ? 2Fe3
3CO32- s 2s 3s s 0.00243 g x 1
mole 291.6 g 0.100
L 8.333 x 10-5 M Ksp
Fe32CO32-3 Ksp 2s23s3 Ksp
108s5 Ksp 108(8.333 x 10-5)5 Ksp
4.34 x 10-19
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4. A 200.0 mL sample of a saturated solution of
Mg(OH)2 weighs 222.1210 g. When the beaker
containing the solution is evaporated to dryness
it weighs 22.1213 g. The mass of the empty
beaker is 22.1200 g. Calculate the Ksp. Mass of
Beaker Mg(OH)2 22.1213 g - Mass of
Beaker - 22.1200 g Mass of Mg(OH)2 0.0013
g note sig figs s 0.0013 g x 1
mole 58.3 g 0.2000 L 1.1149 x
10-4 M Mg(OH)2 ? Mg2 2OH- s s 2s
Ksp Mg2OH-2 s2s2
4s3 4(1.1149 x 10-4)3 5.5 x 10-12