Title: Schedule
1Schedule
2Introduction
Load Estimation
Terminology
Basic Equipment
Codes and Standards
Power Distribution Final Circuit
Standby Generator and Power Supplies
Protection Cable Wiring
Earthing
Design of Electricity Distribution
3Earthing and Design of Electricity Distribution
- Date 20 November 2008
- Ir. KF Cheung
4Earthed Equipotential Bonding and Automatic
Disconnection - 1
- A) Principle
- To bond all the exposed and extraneous conductive
parts to earth in order to create a zone at
earthed potential so that the potential
difference (touch voltage) between those parts
are minimized in the event of an earth fault
inside the zone (touch voltage would be reduced
by bonding), and then to cut the supply within
the maximum safe time duration.
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6What will happen if electrical appliances are not
earthed?
7Can earthing help?
8What will happen if extraneous conductive parts
are not bonded?
9Earthed Equipotential Bonding and Automatic
Disconnection
- B) Disconnection of Supply under Earth Fault
- A protection device shall disconnect the supply
during an earth fault so as not to cause danger. - Maximum disconnection times are shown as follows
10Earthed Equipotential Bonding and Automatic
Disconnection
- B) Disconnection of Supply under Earth Fault
- Maximum value of earth loop impedance achieving
the above disconnection time for various
protective devices are shown in Table 41B1, Table
41B2 and Table 41D of IEE Regulations (for 240V).
The values shall be multiplied by 0.916 (220V/
240V) for nominal supply voltage of 220V.
11Earthed Equipotential Bonding and Automatic
Disconnection
12Earthed Equipotential Bonding and Automatic
Disconnection
- B) Disconnection of Supply under Earth Fault
- The breaking capacity of the protective device
shall be capable to withstand the prospective
earth fault current. - Local supplementary bonding shall be required
where the disconnection time cannot be achieved
13Earthed Equipotential Bonding and Automatic
Disconnection
- B) Disconnection of Supply under Earth Fault
- The principle is to limit the resistance of the
protective conductor so that the voltage
appearing on exposed conductor parts under fault
conditions is limited to 50 volts or if the
voltage is a higher value the circuit would
disconnect faster. - For ring circuits the impedance of the protective
conductor is calculated between its two ends
before final connection is made and shall not
exceed four times the value given in table 41C.
14Earthed Equipotential Bonding and Automatic
Disconnectio
15Earthed Equipotential Bonding and Automatic
Disconnection
C) Determination of Disconnection Time 1) Maximum
values of earth loop impedance for various
overcurrent protective devices are shown in table
41B1, Table 41B2 Table 41D 2) Actual earth loop
impedance can be calculated as follows Zs Ze
Z1 Z2 Ze Earth loop impedance at the
source Z1 Impedance of phase conductor Z2
Impedance of circuit protective conductor (cpc)
16Earthed Equipotential Bonding and Automatic
Disconnection
- C) Determination of Disconnection Time
- 3) Compare the actual Zs with the tabulated
Zs(max) - The actual Zs value measured from the
installation should be smaller than the Zs(max)
value from IEE Tables in order to achieve safe
disconnection time. Attention is drawn on that
the Zs (max) form IEE Tables shall be converted
to nominal supply voltage system in Hong Kong
before comparison. - Zs (max 220) Zs (max 240) in IEE Tables X
220/240
17Earthed Equipotential Bonding and Automatic
Disconnection
C) Determination of Disconnection Time 4) The
earth fault current can be calculated using the
following formula If Uo /Zs Uo Phase to
earth voltage If earth fault current 5) By
putting the calculated fault current against the
characteristic curves of the protective device
given in IEE, the actual disconnection time can
be found.
18Example
- A 220V circuit is protected by a 30A Type 2 MCB,
the cable used is 2.5/1.5 twin with cpc PVC
copper conductor, if the circuit length is 15m
and Ze up to the MCB board is 0.5O, what is the
actual disconnection time? - From table 17, R1R2 /m 19.51mO x 1.38
- 0.269
O/m
19Time (s)
Current (A)
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22A) Cable Selection
- Factors to be considered in sizing of cable
conductors - Conductor material
- Insulating material
- Method of installation
- Installed environment
- Ambient temperature
- Thermal insulating enclosure
- Adjacent cables
- Type of protective device
- Voltage drop
- Minimum cross-sectional area
23Comparison between Copper Conductor and Aluminum
Conductor
- A) Copper Conductor
- High degree of electrical conductivity
- Tough, slow to tarnish
- Can be jointed without any special provision to
prevent electrolytic action - B) Aluminum Conductor
- Lower price light in weight
- Pliable, it can be used in solid-core cables
- Excellent resistance to corrosion
24Insulating Materials
25Bends of Non-flexible Cable
- The minimum internal radius bend in cables for
fixing wiring are shown in the following table
26Correction Factor for Conductors
- Factors which affect the ability of a cable to
lose heat are - Grouping (Cg or C1)
- Ambient temperature (Ca or C2)
- Thermal insulation (Ci or C3)
- Semi-enclosed fuse to BS 3036 (0.725 or C4)
- Type of installation (Table 4A)
27Correction Factor for Conductors
- A) Grouping factor (Cg) - 1
- IEE Table 4B1 gives correction factors to be
applied to te tabulated current-carrying
capacities where cables or circuits are grouped. - Where the horizontal clearance s between adjacent
cables exceed two cable diameter (2D2), no
correction factor need be applied.
28Correction Factor for Conductors
- A) Grouping factor (Cg) - 2
- If a cable is expected to carry not more than 30
of its grouped rating, it may be ignored from the
rest of the group.
29Correction Factor for Conductors
- B) Correction Factor for Ambient Temperature (Ca)
- Correction factor for ambient temperature is
shown in IEE Table 4C1. Where for semi-enclosed
fuses are being used, see IEE Table 4C2. -
- It In / Ca
- Typical data are shown in the following table for
quick reference.
30Correction Factor for Conductors
- C) Correction Factor for thermal Insulation (Ci)
- The value of current-carrying-capacity for
various sizes of conductors shown in Tables of
Appendix 4 have been taken into account of cables
installed in a thermally insulated wall or
ceiling where one side of the cable is in contact
with a thermally conductive surface. - Where the cable is totally enclosed in thermal
insulation, Ci0.5 shall be used in absence of
more precise information. -
- It In / Ci
- Ci shall only be applied to the open and clipped
direct column of respective IEE Tables.
31Correction Factor for Conductors
- D) factor for Semi-enlosed fuse to BS3036 (C4)
- When semi-enclosed fuse is used for protecting
the conductor, a derating factor of 0.726 shall
be applied.
32Correction Factor for Conductors
- E) General Formula for Correction Factors Applied
to Cable Sizing - It In / Cg x Ca x Ci x C4
33Example
34Example
- Protective device BS 3036 fuses
- Ambient temperature 30oC
- Cable use PVC twin with cpc cable
- Cabling conditions at
- 1) Bunched and clipped direct
- 2) Passed through totally enclosed thermal
insulation area - 3) One side in contact with thermally insulated
ceiling - 4) Passed through a boiler house where ambient
temperature of 45oC - 5) Clipped direct
- Ignore voltage drop
- Select the appropriate size of cables?
35Voltage Drop
- The overall voltage drop shall not exceed the
value appropriate to the safe functioning of the
equipment in normal service. - The voltage drop in any circuit from the origin
of installation to the current-using equipment
should not exceed 4 of the nominal voltage. - Volt drop pre unit value in from of mv/A/m are
shown on IEE tables of Appendix 4. The values are
based on the circuit conductor working at the
maximum permitted operating temperature and at
unity power factor.
36Voltage Drop
37Voltage Drop
38Voltage Drop
39Voltage Drop
- Voltage drop (V.D.) can be calculated as follows
- V.D. design current (Ib) x circuit length (L)
x volt drop per unit (mv/A/m)
40Example
- A PVC/SWA/PVC armoured cable is to be installed
from an HRC 100A fuse in a distribution board to
a 3-phase 380V motor, along with 5 other cables
fixed to a perforated metal cable tray where the
cable sheaths will be touching, if the cable
length is 125 meters and the power factor of the
load is 0.89, what size of cable would be
required to satisfy voltage drop if the ambient
temperature is 30oC and the voltage drop in the 3
phase feeder cable up to the distribution board
is 3.7V and the total voltage drop allowed is 4?
41- Cg 0.74 (from the Table)
- It 100/0.74 135.14A
From the Table - Iz 163 A (for 50mm2 cable)
- V.D. allowances for the circuit
- (380V x 4) 3.7V 11.5V
- From the Table, z 0.81 mV/A/m
Actual
V.D. circuit 125m x 100A x 0.81 x 10-3 - 10.125V
- V.D. from Table for 50mm2 r 0.8, x 0.14
Consider the power
factor - cos Power factor is 0.89
- sin power factor is 0.46
- V.D. ((0.89 x 0.8 0.14 x 0.46) x 125m x 100A)
/ 1000 - 9.705V lt 11.5V
42Sizing Circuit Protective Conductors
- If the conductor 35mm2 Zs Ze R1 R2
- gt35mm2 Zs Ze
Z1 Z2 - Use the formula S v(I2t) / K
- Value of K from IEE Tables 54B to 54F
- If Uo / Zs
- Value of t from IEE Fig. 1 to 8 of Appendix 3
- Use Table 54G to size the minimum size of
protective conductors.
43Thermal Constraint
- To protect conductor insulation against thermal
damage during short circuit conditions. - I2 t K2 S2
- t K2 S2/ I2
- t duration in second
- S cross-sectional area in mm2
- I effective short-circuit current in A
- K 115 for copper conductor insulated with PVC
44Thermal Constraint
- Procedure
- To check the prospective short-circuit current at
the farthest point of the circuit from the point
where the device is installed - To check the operation time of the device
according to the short-circuit current from the
time/ current characteristic of the device - To check the adiabatic line of the conductor by
superimposing onto the characteristics of
protective devices.
45Cable Selection Procedure
- Select wiring system to be installed and type of
cable - Calculate the equipment current demand using
Table 4A - Calculate the circuit design current (Ib) and
using diversity allowance. - Determine the overcueent protective device (In)
type rating - Check Ib In
- Determine correction factors for installation
- Grouping (Cg)
- Ambient temperature (Ca)
- Thermal insulation (Ci)
- Semi-enclosed fuse (C4)
46Cable Selection Procedure
- Calculate the tabulated current carrying capacity
of conductor - It (min) In x (1/ Cg) x (1/ Ca) x (1/ Ci) x
(1/ C4) - Select cable size from Appendix 4
- Check Ib In Iz
- Calculate volt drop at the farthest point of
circuit
47Cable Selection Procedure
- Does it offer shock protection in accordance with
table 41B1, 41B2 41D for Zs (max)? - Check Zs Zs (max) from the tables
- If No
- Re-select device or re-select phase conductor
size - Re-select cpc size
- Use alternative method as stated in Reg.
413-02-12 - Checked by calculation
- Obtain Ze form supply authority
- Calculate R1 R2 using Table 17A B
- Determine actual Zs Ze (R1 R2)
48Cable Selection Procedure
- Does the type and size of cpc offer protection?
- Check S v(I2t) / K
- If No re-select type and/ or size of cpc
- Check the adiabatic line of conductor against the
characteristic of overcurrent protective device.
49Q A
50The End