Title: Systems of Linear Equations, Direct Methods
1Lecture 8
- Systems of Linear Equations, Direct Methods
2Lecture 8 Objectives
- Geometrically solve linear systems of eqns in 2
vars - Get the augmented matrix of a linear system of
eqns - Decide if a matrix is in (reduced) row echelon
form - Use elementary operations to reduce a matrix to
(reduced) row echelon form - Algebraically solve linear systems of equations
using - Gaussian elimination
- Gauss-Jordan elimination
- Find the value(s) of parameter(s) that make a
linear system have - a unique solution
- infinitely many solutions
- no solution
3Example
- Solve the following equations
- x 3y ?1
- 3x 2y 4
- Note 1 Geometrically you are looking for the
intersection of the two lines in the x-y plane.
Here we get a unique solution.
4Example
- Solve the following equations
- x 3y ?1
- 3x 2y 4
- Note 2 These two equations can be written as
5Example
- Solve the following equations
- x 3y ?1
- 3x 9y 4
- Note These are two different parallel lines.
Thus, we get no solution (the solution set is
empty). We call this system inconsistent.
6Example
- Solve the following equations
- x 3y 1
- 3x 9y 3
- Note These are two identical lines. Thus, we get
infinitely many solutions, namely y t (any
arbitrary value), and x 1 ? 3t. Thus, the
solutions can be written as (x, y) (1 ? 3t,
t), where t?R.
7Example
- Solve the matrix equation
8Example
- I.e., solve the following equations
- x 2y ? 3z ?4
- 2x ? y 2z 10
- 3x y ? 4z 3
- Note Geometrically you are looking for the
intersection of three planes in space.
9Solution Step 1 Elimination
- x 2y ? 3z ?4 (1)
- 2x ? y 2z 10 (2)
- 3x y ? 4z 3 (3)
- We use Eq. 1 to eliminate x from Eqs. 2, 3
- x 2y ? 3z ?4 (1)
- ?5y 8z 18 (2)
- ?5y 5z 15 (3)
- Note Those 3 equations are equivalent to the
original set of equations, i.e. they have the
same set of solutions.
10Solution Step 2 Elimination
- x 2y ? 3z ?4 (1)
- ?5y 8z 18 (2)
- ?5y 5z 15 (3)
- We now use Eq. 2 to eliminate y from Eq. 3
- x 2y ? 3z ?4 (1)
- ?5y 8z 18 (2)
- ?3z ?3 (3)
- Note Again, we get 3 equivalent equations, which
can now be easily solved.
11Solution Step 3 Back Substitution
- x 2y ? 3z ?4 (1)
- ?5y 8z 18 (2)
- ?3z ?3 (3)
- We first get z, then y, then x
- z 1
- ?5y 8(1) 18, so y ?2
- x 2(?2) ? 3(1) ?4, so x 3
- Note Thus, we finally get the unique solution
(point, or vector) (x, y, z) (3, ?2, 1).
12Example (revisited)
- Solve the following equations
- x 2y ? 3z ?4
- 2x ? y 2z 10
- 3x y ? 4z 3
- A Simplified Method We only keep track of the
coefficients of x, y, and z, as well as the right
hand sides.
13Solution Step 1 Form the Augmented Matrix
(Table)
- x 2y ? 3z ?4 (1)
- 2x ? y 2z 10 (2)
- 3x y ? 4z 3 (3)
- The equations are summarized in the augmented
matrix
Notes Each row represents an equation. Also
Ab is the augmented matrix for the system Ax
b.
14The Elementary Row Operations
- Those are operations performed on the augmented
matrix Ab, maintaining the equivalence between
the old and the new set of equations. - They are
- 1) Add a multiple of a row to another
- 2) Multiply a row by a nonzero constant
- 3) Interchange two rows
- Note These operations change the augmented
matrix, but do NOT change the set of solutions.
15Solution Step 2 Perform the legal Elementary Row
Operations
16Solution Step 3 We can stop and solve, or
continue to simplify
Thus, x 3 y ?2 z 1
17In general We can solve any system (set) of m
linear equations in n unknowns
- a11x1 a12x2 ? a1nxn b1
- a21x1 a22x2 ? a2nxn b2
- ?
- am1x1 am2x2 ? amnxn bm
- i.e. Ax b, by first getting the augmented
matrix
18Example
- Find the solution of the system, whose augmented
matrix is
19Solution
- We perform row operations to get the reduced row
echelon form
Thus x4 ?5 x3 2 x2 t x1 ?11 ? 2t
20Gaussian Elimination
- Here we perform the elementary row operations
- to find an equivalent matrix in row echelon form,
i.e. with the following properties - 1) All zero rows are at the bottom.
- 2) The first nonzero entry of a nonzero row is
called a pivot. Each pivot lies to the left of
any pivot below it. - E.g.
21Gauss-Jordan Elimination
- Here we go further to get an equivalent matrix in
reduced row echelon form, i.e. with the following
properties - 1) All zero rows are at the bottom.
- 2) Each pivot lies to the left of pivots below
it. - 3) Each pivot must 1, and is the only nonzero
entry in its column. - E.g.
22The Rank of a Matrix A
- rank(A) is defined as the number of pivots (or
nonzero rows) in the (reduced) row echelon form
of A. - E.g.
has rank 3, since it is row-equivalent to
23The Rank Theorem
- Let Ab be the augmented matrix of a linear
system of m equations in n variables. Then - 1) The system is inconsistent iff rank(A) lt
rank(Ab) - 2) The system has a unique solution
iff rank(A) rank(Ab) n - 3) The system has infinitely many solutions iff
rank(A) rank(Ab) lt n, and - Number of free variables n ? rank(A)
24Example
- For what values of k does the system
- x ? 2y 3z 2
- x y z k
- 2x ? y 4z k2 have
- a) No Solution
- b) A unique solution
- c) Infinitely many solutions
25- Thank you for listening.
- Wafik