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Kinetic Theory 2

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The internal energy is represented by the potential energy and kinetic energy in ... the molecules are so far apart that there are no intermolecular interactions. ... – PowerPoint PPT presentation

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Title: Kinetic Theory 2


1
Kinetic Theory 2
  • Linking Kinetic Theory and Temperature

2
Key Ideas
  • We are going to relate the rms speed of gas
    molecules to the temperature of the gas.
  • Temperature is a measure of the internal energy
    of a material.
  • The higher the temperature in a gas, the faster
    the molecules will travel.

3
Some Assumptions
  • The internal energy is represented by the
    potential energy and kinetic energy in the bonds
    of any material.
  • In a gas, the molecules are so far apart that
    there are no intermolecular interactions. So
    there is no potential energy.
  • Therefore the energy is entirely kinetic.

4
Kinetic Energy in a Gas
  • Kinetic energy is shared randomly throughout the
    gas.
  • This means that any given molecule can be moving
    at any velocity.
  • Because there are lots of molecules, there is a
    random distribution of speeds. A few molecules
    will travel slowly, a few very fast, while most
    will be somewhere in between.

5
We can show this on a graph
100 K
1000 K
6
Thermal Equilibrium
  • If no energy is being transferred as heat between
    an object and its surroundings, we say that it is
    in thermal equilibrium.
  • If a gas is in thermal equilibrium and it is not
    being compressed or expanded, the average kinetic
    energy will remain constant, so will the
    temperature.

7
Two Relationships from Before
pV nRT and pV 1/3 Nmc2
It does not take a genius to see that nRT 1/3
Nmc2
8
Lets look at this relationship further
nRT 1/3 Nmc2
Mean square speed
Mass of each molecule
No of molecules
Total mass of the molecules
It reminds us of the relationship that describes
kinetic energy Ek 1/2 mv2
9
So we can write
nRT 2/3 N1/2mc2 since 2/3 1/2 1/3.
Rearranging gives us 1/2mc2 3/2nRT 3/2RT
N N/n
10
Since N is the total number of molecules and n is
the number of moles, N/n will always be NA, which
is Avagadros number, 6.02 x 1023. So we can
write 1/2mc2 3/2RT NA
11
Boltzmanns Constant
R/NA is called Boltzmanns constant and is given
the code k. We can easily work out the value for
k. k 8.31 1.38 x 10-23 J K-1
6.02 x 1023
And this gives us our final relationship 1/2mc2
3/2kT
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