Title: ECE 8830 Electric Drives
1 ECE 8830 - Electric Drives
Topic 3 Induction Motor Modeling -
Steady State Spring 2004
2 Introduction
- Induction machines are the most widely used of
all electric motors. They offer the following
attractive features - Generally easy to build and cheaper than
corresponding dc or synchronous motors - Rugged and require little maintenance
- Offer reasonable asynchronous performance
- A manageable torque-speed curve
- Stable operation under load
- Generally satisfactory efficiency
- Range in size from few Watts to several MW
3 Introduction (contd)
- Some disadvantages of induction motors are
- Speeds not as easily controlled as dc motors
- Draw large starting currents, typically 6-8 x
their full load values - Operate with a poor lagging power factor when
lightly loaded
4 Introduction (contd)
- New designs for high performance induction
machines, such as in high speed motors for gas
compressors, will be required to have new
characteristics from existing machines, it is
important to have a good fundamental
understanding of these types of machines. - Goal To develop a simple model for the
induction machine that is useful for control and
simulation.
5Structure of an Induction Machine
- Two types of induction machine
- Wound rotor or squirrel cage rotor
-
6Rotating Magnetic Field and Slip
- We previously showed that a balanced set of
three-phase currents flowing in a set of
symmetrically placed, three-phase stator windings
produces a rotating mmf given by -
- eq. (6.1) Ong, eq. (2.9) Bose
- where ?ae is the electrical angle measured
from the a-phase axis and ?e is the angular speed
of the stator mmf in electrical radians/second.
7Rotating Magnetic Field and Slip (contd)
8Rotating Magnetic Field and Slip (contd)
- In mechanical radians/sec. the synchronous
speed is related to the electrical speed by - If the rotor is rotating at an angular speed
?rm the slip speed is simply equal to ?sm - ?rm.
The slip,s, is the normalized slip speed and is
given by
9 Torque Production
- The torque produced by an induction motor may
be derived and expressed by the following
equation (see ref. 1 in Bose) - where P of poles
- l axial length of motor
- r radius of motor
- Bp peak air-gap flux density
- Fp peak value of rotor mmf
- and
10Per-Phase Equivalent Circuit Model
- A per-phase transformer-like equivalent
circuit is shown below -
11Per-Phase Equivalent Circuit Model (contd)
- Synchronously rotating air gap flux wave
generates a counter emf Vm. This in turn is
converted to a slip voltage in the rotor phase,
Vr nsVm, where nrotorstator turns ratio, and
snormalized slip. - Stator terminal voltage, Vs Vm VRs VLls
- where VRsvoltage drop across stator
resistance (Rs) and VLlsvoltage drop across
stator leakage inductance (Lls).
12Per-Phase Equivalent Circuit Model (contd)
- Excitation current, I0 Ic Im
- where Ic is core loss current (Vm/Rm)
- and Im is magnetizing current (Vm/ )
- Rotor-induced voltage, Vr VRr VLl
- where VRr voltage drop across rotor resistance
- and VLl voltage drop across rotor leakage
- inductance
- The induced voltage in the rotor leads to a rotor
- current Ir at slip frequency ?sl.
13Per-Phase Equivalent Circuit Model (contd)
- The stator current, IS I0 Ir
- where Ir is the rotor-reflected current
induced in the stator. -
I0
14Per-Phase Equivalent Circuit Model (contd)
15Per-Phase Equivalent Circuit Model (contd)
16Per-Phase Equivalent Circuit Model (contd)
- Torque expression can be written as
- where peak value of air gap flux
- linkage/pole
- and peak value of rotor current
17Per-Phase Equivalent Circuit Model Power
Expressions
- Input Power where cos? is input PF
- Stator copper loss
- Rotor copper loss
- Core loss
- Power across air gap
- Output power
- Shaft Power where PFw is friction and
windage power loss
18Per-Phase Equivalent Circuit Model Torque
Expression
- The torque can be expressed as
- where is the rotor
- mechanical speed (radians/sec.)
19Per-Phase Equivalent Circuit Model Torque
Expression (contd)
- Using a little algebra (see Bose) it can
- be shown that the torque may be further
- expressed as
- where .
- This torque expression is similar to that for
- a dc motor, where Im magnetizing
- component of stator current and Ia
- armature component of stator current.
20Simplified Per-Phase Equivalent Circuit
- A simplified circuit dropping Rm and shifting
Lm to the input is applicable to integral
horsepower machines. -
-
- Performance of this equivalent circuit is
typically within 5.
21Simplified Per-Phase Equivalent Circuit Model
(contd)
- The current Ir in this circuit is given by
- The torque of the motor using this circuit
- is given by
22Example of Calculating Efficiency of an Induction
Motor
23Flowchart for Computing Steady State Performance
of Induction Motor
Ref R. Krishnan, Electric Motor Drives
24Torque-Speed Curve of Induction Motor
- The torque-speed curve as a function of slip
can be calculated from the equation two slides
back. -
25Torque-Speed Curve of Induction Motor (contd)
- Three regions in torque-speed curve
- 1) Plugging (braking) region (1
- Rotor rotates opposite to direction of air
gap flux. Can happen, for example, if stator
supply phase sequence reversed while rotor is
moving. - 2) Motoring region (0
- Te0 at s0. As s increases (speed decreases),
Te increases until max. torque (breakdown torque)
is reached. Beyond this point, Te decreases with
increasing s.
26Torque-Speed Curve of Induction Motor (contd)
- 3) Regenerating Region (s
- Here the induction machine acts as a
generator. Rotor moves faster than air gap flux
resulting in negative slip. -
27Torque-Speed Curve of Induction Motor (contd)
Ref R. Krishnan, Electric Motor Drives
28Performance Characteristics of Induction Motor
Ref R. Krishnan, Electric Motor Drives
29Starting Torque of Induction Motor
- The starting torque of an induction motor is
given by substituting for s1 and is given by
30Starting Torque of Induction Motor (contd)
- This torque can be enhanced for line start
motors (ones started directly with full line
voltage) by increasing the rotor resistance. This
can be achieved by connecting external resistors
in the case of slip ring rotors. However, with
squirrel cage rotors where the rotor is shorted,
deep bar or double-cage rotors can be used to
increase starting torque.
31Characterizing Induction Motors
- One way to characterize an induction motor is
with the No-load/blocked rotor tests which yield
the per-phase equivalent circuit model shown
earlier (see figure below). -
-
iar
ias
vas
M
32Characterizing Induction Motors (contd)
- We can characterize an induction motor with
the variables Rs, Lls, M, Llr, Rr determined
through lab tests using balanced 3? excitation.
This circuit described the impedance perceived
per phase on a line-neutral connected machine.
Everything in the dashed box is a rotor quantity
that has been referred to the stator by the
ideal transformer in the machine model. From now
on, assume that Llr, Rr and iar are referred to
the stator.
33Characterizing Induction Motors (contd)
- No-Load Test (s0)
- Equivalent circuit
-
Ref R. Krishnan, Electric Motor Drives
34Characterizing Induction Motors (contd)
- No-Load Test (s0) yields
- In sinusoidal steady state, ignoring
resistances - But -ias (ibsics)
- ?
- From transformer model
Las
35Characterizing Induction Motors (contd)
- Blocked rotor test (s1) yields estimates of Lls
and Llr. Equivalent circuit at standstill is
shown below -
Ref R. Krishnan, Electric Motor Drives
36Characterizing Induction Motors (contd)
- Ohmmeter/Power loss tests give Rs
- and Rr.
-
- So, with Llr, Rr and all irs understood as
- referred rotor quantities, the stator-side
- tests identify all the model parameters for
- the induction motor.
37Example of Determining Induction Motor Model
Parameters
38NEMA Classification of Induction Motors
- The National Electrical Manufacturers
Association (NEMA) has classified induction
motors based on their torque-slip
characteristics. (see text for details) -
39Circuit Model of a Three-Phase Induction Machine
(State-Space Approach)
40Voltage Equations
41Voltage Equations (contd)
42 Flux Linkage Equations
43 Model of Induction Motor
- To build up our simulation equation, we could
just differentiate each expression for ?, e.g. - But since Lsr depends on position,
- which will generally be a function of time,
the trig. terms will lead to a mess! -
- Parks transform to the rescue!
-
first row of matrix