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Solving Systems of Equations Using Substitution

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When and where will the office catch up to the motorist? ... At t=0.02 hours both the police and motorist will be 1.2 miles from the intersection. ... – PowerPoint PPT presentation

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Title: Solving Systems of Equations Using Substitution


1
Lesson 5.2
  • Solving Systems of Equations Using Substitution

2
  • Graphing systems and comparing table values are
    good ways to see solutions.
  • It is not always easy to find a good graphing
    window or the right settings for the table to
    view the solution.
  • Often these solutions are only approximations.
  • To find the exact solutions, youll need to work
    algebraically with the equations.
  • Lets look at the substitution method.

3
  • On a rural highway a police officer sees a
    motorist run a red light at 50 mph and begins
    pursuit. At the instant the police officer
    passes through the intersection at 60 mph, the
    motorist is 0.2 mi down the road. When and where
    will the office catch up to the motorist?
  • Write an equation in two variables to model this
    situation.

d the distance from the intersection t time
traveled
4
  • On a rural highway a police officer sees a
    motorist run a red light at 50 mph and begins
    pursuit. At the instant the police officer
    passes through the intersection at 60 mph, the
    motorist is 0.2 mi down the road. When and where
    will the office catch up to the motorist?
  • Solve this system by the substitution method and
    check the solution.

5
  • When the officer catches up to the motorist they
    will the same distance from the intersection (so
    both equations will have the same d value.
  • Replace the d value in one equation with the d
    value from the other equation.
  • Solve this new equation for t.

6
So at t0.02 hours the police and motorist will
be the same distance from the intersection.
At t0.02 hours both the police and motorist will
be 1.2 miles from the intersection. This is the
only ordered pair that works in both equations.
7
All Tied Up
  • Materials needed
  • Two ropes of different thickness about 1 m long
  • Measuring tape
  • One 9 meter long thin rope (optional)
  • One 10 meter long thick rope (optional)

8
Collecting Data and Writing Equations
  • Measure the thinner rope without any knots.
  • Tie a knot in the rope and measure the length
    again.
  • Continue to tie knots and measure the length of
    the rope.
  • Record the number of knots and the length of the
    rope in a table.
  • Define the variables and write equations in
    intercept form to model the data.
  • Repeat for both ropes.

9
  • Suppose that you had 9 meters of the thinner rope
    and 10 meters of the thicker rope.
  • Write a system of equations that gives the length
    of each rope depending on the number of knots
    tied on the rope.

10
Analyzing the Data and Solution
  • Solve the system of equations using the
    substitution method.
  • Select an appropriate window setting and graph
    this system of equations.
  • Estimate the coordinates for the point of
    intersection to check your solution.
  • Explain the real-world meaning of the solution of
    the system of equations.
  • What happens to the graph of the system of the
    two ropes
  • Have the same thickness?
  • Have the same length?

11
  • So far you have seen equations written in
    intercept form.
  • These equations make it easy to use the
    substitution method since they are already both
    solved for y.
  • y900 -6x
  • y1000-10.3x
  • Sometimes it is necessary to place equations in
    intercept form before using substitution.

12
A Mixture Problem
  • A pharmacist has 5 saline (salt) solution and
    20 saline solution. How much of each solution
    should be combined to create a bottle of 90 ml of
    10 solution.
  • Write a system of equations that models this
    situation.

13
  • A pharmacist has 5 saline (salt) solution and
    20 saline solution. How much of each solution
    should be combined to create a bottle of 90 ml of
    10 solution.
  • Solve the one equation for x or y and substitute
    it into the other equation. Find a solution.

14
In this Section
  • Saw limitations to solving a problem graphically
  • Learned how to solve a system of equations using
    substitution.
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