By: Matthew John Haworth XXXIII - PowerPoint PPT Presentation

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By: Matthew John Haworth XXXIII

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By: Matthew John Haworth XXXIII. The MOLE!!! Moles Volume. To go to moles multiply by 22.4L ... 10molx22.4L=224.0L. To go back to moles divide by 22.4L. 224.0L ... – PowerPoint PPT presentation

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Title: By: Matthew John Haworth XXXIII


1
The MOLE!!!
  • By Matthew John Haworth XXXIII

2
Moles ? Volume
  • To go to moles multiply by 22.4L
  • 10molx22.4L224.0L
  • To go back to moles divide by 22.4L
  • 224.0L / 22.4L 10mol

3
Grams ? Moles
  • 38g of N gas
  • 38g N (1mole) 2.71 moles N gas
  • (14g N)
  • Divide 38g by 14g because that is 1 mole of N gas
  • To go back to moles multiply 2.74 times 14g

4
Mole Map
22.4L1 mole
Gram Formula mass (PT) 1 Mole
5
Sample Problems
  • Volume
  • 55L O2 gas
  • How many moles of O2 gas do you have?
  • Grams
  • 56g N2 gas
  • How many moles of N2 do you have?

6
Sample Problem Answers
  • 55L / 22.4L 2.46 mol
  • 56g n2 ( 1mol)
  • (28g n2)
  • Answer 2 moles

7
Summary
  • To go from Grams to moles you divide what you
    have by what a single mole of that substance is
    from the PT, to go back multiply the moles by the
    mole from PT
  • To go from moles to volume multiply the moles by
    22.4L. To go back divide by 22.4L

8
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