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ME 358 Mechanism Analysis Dr' Naghshineh

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ME 358. Mechanism Analysis. Dr. Naghshineh. Presented By: Ryan Allen. Phuong Tran. Initial Design Requirements ... Output velocity of point on path had to be ... – PowerPoint PPT presentation

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Title: ME 358 Mechanism Analysis Dr' Naghshineh


1
ME 358Mechanism AnalysisDr. Naghshineh
Presented By Ryan Allen Phuong Tran
2
Initial Design Requirements
  • Output velocity of point on path had to be less
    than 10 in/sec.
  • No guides or surfaces could be used to aid in
    motion for any parts.
  • Motor had to be mounted in specified area with
    output vertical path also being in specified
    place.
  • Mechanism had to fit in smallest possible box
    while allowing 6 inch clearance.

3
Specified Requirements
4
Final Mechanism Design
5
Design Specifications
  • Motor is located in center of circle which is
    located on bottom-most right of the possible
    motor mounting location.
  • Circle has a 6 inch radius.
  • Pivoting member connected to the circle is 42
    inches long.
  • Vertical member is 20 inches long.
  • Two identical horizontal members are 10 inches
    long.

6
Total Area of Box
  • Total area of empty box 84 inch x 34 inch
  • 2856 inch2
  • Area of circle p62 113.09 inch2
  • Area of pivoting member 42 inch2
  • Area of vertical member 20 inch2
  • Area of combined horizontal members 40inch2
  • Total Combined Area 2856 113.09 42 40
    3051.09 inch2

7
Calculations
  • Assume Slider Crank Configuration
  • ?AB 0.5 rad./sec.
  • aAB 1 rad./sec2
  • Link 1 6 inch.
  • Link 2 42 inch.
  • Offset -36 inch.

8
Calculation
  • Case 1
  • Position C is at the top of the
    vertical path.
  • T 2 217 from vertical.
  • T 3 arcsin((-6sin(217 )-(-36))/42)p 129.5
  • D 6cos(217 )-42cos(129.5 ) 21.95inch
  • This value represents the height of the position
    from the center of the circle.

9
Calculation
  • Velocity Analysis for case 1
  • ?BC (6cos(217 ))\(42cos(129.5 )) .5 rad/sec
    .089 rad/sec.
  • Vc -6(0.5)sin(217)-42(0.89)sin(129.5)
  • Vc4.7j inch/sec.
  • This represents a velocity moving up.

10
Acceleration Calculation
  • Acceleration Analysis for case 1
  • aBC ( 6(1)cos(217)- 6(0.50)sin(217)
    42(0.892)sin(129.5))\(42cos(
    129.5)
  • aBC0.136 rad/sec2
  • Acceleration _at_ C -1sin(217)-
    6(0.52)cos(217) 420.136sin(129.5)420.89
    2cos(129.5)
  • 8.99j rad/sec2

11
Calculation
  • Case 2
  • Position C is at the center of the
    vertical path.
  • T 2 41 from vertical.
  • T 3 arcsin((-6sin(42)-(-36))/42)p 108.03
  • D 6cos(41 )-42cos(108.03 ) 17.53inch
  • This value represents the vertical distance from
    the center of the path to the center of the
    circle.

12
Calculations
  • Velocity Analysis for case 2
  • ?BC (6cos(41))\(42cos(108.03)) .5 rad/sec
    ?BC -1.74 rad/sec.
  • Vc -6(0.5)sin(41)- 42(-1.74)sin(108.03)
  • Vc-8.92j inch/sec.
  • This represents a velocity moving down.

13
Acceleration Calculation
  • Acceleration Analysis for case 2
  • aBC ( 6(1)cos(41)- 6(0.50)sin(41)
    42(-1.742)sin(108.03))\(42cos(
    108.03))
  • aBC-0.365 rad/sec2
  • Acceleration _at_ C -1sin(41)- 6(0.52)cos(41)
    420.136sin(108.03)420.892cos(108.03)
  • -20.066j rad/sec2

14
Calculations
  • Case 3
  • Position C is at the bottom of the vertical
    path.
  • T 2 59 from vertical.
  • T 3 arcsin((-6sin(59)-(-36))/42)p 101.59
  • D 6cos(59 )-42cos(101.59 ) 11.53inch
  • This value represents the vertical distance from
    the bottom of the path to the center of the
    circle.

15
Calculation
  • Vertical Analysis of case 3
  • ?BC (6cos(59))\(42cos(101.6)) .5 rad/sec
  • ?BC -0.183 rad/sec.
  • Vc -6(0.5)sin(59) - 42(-0.183)sin(101.6)
  • Vc-10.02j inch/sec.
  • This represents a velocity moving down.

16
Acceleration Calculation
  • Acceleration Analysis for case 3
  • aBC ( 6(1)cos(59)- 6(0.50)sin(59)
    42(-0.1832)sin(101.59))\(42cos
    (101.59))
  • aBC-0.377 rad/sec2
  • Acc _at_ C -1sin(59)- 6(0.52)cos(59)
    42(-0.377)sin(101.59)42(-0.1832)cos(101.59
    )
  • -21.712j rad/sec2

17
Results What can we do with this?
  • This mechanism design can be used for machinery
    in certain factory settings.
  • May be used to lift many products, thus saving
    time, labor, and valuable floor space.
  • Materials used to build this mechanism can be
    customized to make lighter or using cheaper
    materials to save money.
  • Also, by adding different lengths to the arms
    the output path can be customized.

18
Conclusion and Recomendations
  • Easier to start design with guidelines or
    requirements that help refine rough ideas.
  • Make mechanism simple compared to complex. The
    more cluttered the mechanism is with useless
    pieces it is harder to predict the behavior. Thus
    saving money and time.
  • Whenever possible, contour a design mechanism
    relating to those that are familiar. Completely
    redefining and designing a mechanism puts much
    more burden on velocity and acceleration
    calculations.
  • Use light materials whenever economical.
  • Build a mechanism that can be easily repaired or
    maintained.

19
Resources
  • Design of Machinery , Third Edition. Norton,
    Robert L.
  • www.howstuffworks.com
  • Working Model, student edition
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