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CE 201 Statics

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Magnitude of Resultant Force ... Therefore, the magnitude of the resultant force is equal to the entire area ... Using MR = M ... – PowerPoint PPT presentation

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Title: CE 201 Statics


1
CE 201 - Statics
  • Lecture 15

2
Reduction of a Simple Distributed Loading
  • In many cases, bodies or structures are subjected
    to distributed loading. The loading intensity at
    each point is measured in lb/ ft2 or N/m2 which
    are units of pressure. Uniform distributed
    loading will be discussed. If we have the
    distributed loading shown

3
  • The loading is a system of parallel forces. The
    number of forces is infinite and separated by
    differential distances. The loading function is
    a function of x
  • p p (x)
  • If p p (x) was multiplied by the width ( a
    ), the loading along y will be obtained
  • w p (x) N/m2 a m w (x) N/m

4
  • The loading intensity is represented by a
    coplannar system of forces.

5
Magnitude of Resultant Force
  • To find the resultant force ( FR ? F ),
    integration must be followed since infinite
    number of forces (dF) are acting on the body.
  • dF w(x) dx dA
  • (since w(x) is the force per unit length, x)
  • for the entire length,
  • FR ? F
  • ? w (x)
    dx ? dA A
  • Therefore, the magnitude of the resultant force
    is equal to the entire area under the loading
    diagram w w(x) .

6
Location of Resultant Force
  • Using MR ? M
  • The location of FR (D) is found by equating the
    moments of FR and distributed forces about point
    (O)
  • D FR ? x w(x) dx
  • Then, D ? x w(x) dx / FR
  • Substituting for FR
  • D ? x w(x) dx / ? w(x) dx
  • ? x dA / ? dA
  • which is the equation of the geometric center
    (centroid). Therefore, FR acts at the centroid
    of the distributed loading diagram

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