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Strain II

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Points on the circle represent lines in the real world! ... Since shear strain, =tan , and = '/ ': tan ... we take pairs of lines that were originally at 90 ... – PowerPoint PPT presentation

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Title: Strain II


1
Strain II
2
Mohr Circle for Strain
  • Recall that for stress, we plotted the normal
    stress ?n against the shear stress ?s, and we
    used equations which represented a circle
  • Because geologists deal with deformed rocks, when
    using the Mohr circle for strain, we would like
    to deal with measures that represent the deformed
    state (not the undeformed state!)

3
Equations for Mohr circle for strain
  • Lets introduce two new parameters
  • ? 1/? (to represent the abscissa)
  • ? ?/? ?? (to represent the ordinate)
  • The two equations for the Mohr circle are in
    terms of ? and ?
  • ? (?1?3)/2(?3-?1)/2 cos2?
  • ? (?3-?1)/2 sin2?

4
Mohr Circle for Strain
  • The coordinates of any point on the circle
    satisfy the above two equations
  • The Mohr circle always plots to the right of the
    origin because we plot the reciprocal quadratic
    elongation ?1/? (1e)2, i.e.,
  • ? (1e)2 and ?1/? are both

5
Mohr Circle for Strain
  • In parametric form, the equations of the Mohr
    circle are
  • ? c r cos2?
  • ? r sin2?
  • Where
  • Center, c (?1?3)/2 (mean strain)
  • Radius, r (?3-?1)/2

6
Sign Conventions
  • The 2?? angle is from the c?1 line to the point
    on the circle
  • Points on the circle represent lines in the real
    world!
  • Since we use the reciprocal quadratic elongations
    ?1 ?3
  • clockwise (cw) ?? from c?1 is , and
  • Counterclockwise ccw is - (compare it with
    stress!)
  • cw ?? in real world is cw 2?? in the Mohr circle,
    and vice versa!
  • However, ccw ?, from the O? line to any point on
    the circle, is , and cw ? is -

7
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8
Deformed Brachiopod
9
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10
Lines of no finite elongation - lnfe
  • Draw the vertical line of lnfe 1 ? the ? axis
  • The intersection of this magic line with the Mohr
    circle defines the lnfe (there are two of them!).
  • Elongation along the lnfe is zero
  • They dont change length during deformation,
    i.e.,
  • elnfe0, and ?lnfe1, and therefore ?lnfe1
  • Numerical Solution tan2 ? (1-?1)/(?2-1)

11
Finding the angular shear
  • Because ??/? and ?1/? therefore
  • ? ?? which yields ? ?/?
  • Since shear strain, ? tan ?, and ? ?/?
  • tan ? ?/?
  • Note Mohr circle does not directly provide the
    shear strain ? or the angular shear ?, it only
    provides ?
  • However, notice that ? ? if ?1!

12
Angular Shear
  • ? ?/?
  • The above equation means that we can get the
    angular shear (?) for any line (i.e., any point
    on the circle) from the ?/? of the coordinates
    of that point
  • Thus, ? is the angle between the ? axis and a
    line connecting the origin to any point on the
    circle
  • ccw ? in the Mohr circle translates into ccw in
    the physical world (i.e., same sense)!

13
Finding the Shear Strain ?
  • The ordinate of the Mohr diagram is ?, not the
    shear strain ?
  • Because ? ?/?, then ? ? only if ?1
  • This means that for a given deformed line (e.g.,
    a point A on the Mohr circle), the ?
    coordinate of the intersection of the magical
    ?1 line with the OA line (connecting the origin
    to A) is actually ? because along the ?1
    line, ? and ? are equal!
  • Procedure
  • For any line (which is a point, e.g., A, on the
    circle), first connect the point A to the
    origin (O), and extend the line OA (if needed),
    to intersect the ?1 line
  • Read ?along the ?1 line this is ? for the
    line!

14
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15
Finding lines of maximum shear (lms) strain (?max)
  • Draw two tangents () to the Mohr circle from the
    origin, and measure the 2? () where the two
    lines intersect the circle
  • Numerical Solution
  • Orientation
  • tan ?lms ?(?2/?1) (Note these are ?, not ?)
  • Amount
  • ?max ?(?1-?2 )/2 ??1?2

16
Lines of Maximum Shear (lms)
  • .

17
Another Example
18
ExampleA unit sphere is shortened by 50 and
extended by 100
  • e11, and e3-0.5
  • s1Xl/lo 1e12 s3Zl/lo 1e30.5
  • ?1 (1e1)2s12 4 ? 3 (1e3)2 s320.25
  • ? 1 1/?1 0.25 ?3 1/?3 4
  • Note the area remains constant
  • XZ ? ?1 ? ?3 ? 4 ?0.25 1
  • c (?1 ?3)/2 (0.254)/22.125
  • r (?3 - ?1)/2 (4-0.25)/21.90
  • Having c and r, we can plot the circle!

19
Graphic representation of strain ellipse
  • Point A (1,1) represents an undeformed circle (?1
    ?2 1)
  • Because by definition, ?1?2 , all strain
    ellipses fall below or on a line of unit slope
    drawn through the origin
  • All dilations fall on the ?1 ?2 line through
    the origin
  • All other strain ellipses fall into one of three
    fields
  • Above the ?21 line where both principal
    extensions are
  • To the left of the ?11 where both principal
    extensions are
  • Between two fields where one is () and the other
    (-)

20
Shapes of the Strain Ellipse
21
Graphic representation of strain ellipse
  • Along AB, the original circle does not change
    shape but only change radius
  • From A to origin the radius gets smaller (?l ?2
  • Along AC elongation along ?1, and no change
    along ?2
  • Along AD shortening along ?2 no change along
    ?1
  • Only along the hyperbola through field 3, where
    ?1 1/?2, is the area of the ellipse equal to the
    area of the undeformed circle (i.e., constant
    area)
  • Zone 3 is the only field in which there are two
    lnfes

22
Flinn Diagram
23
Volume change on Flinn Diagram
  • Recall S1e l'/lo and ev ?v/vo ?v
    (v-vo)/vo
  • An original cube of sides 1 (i.e., lo1), gives
    vo1
  • Since Sl'/lo, and lo1, then Sl
  • The deformed volume is therefore v'l'.l'.l
  • Orienting the cube along the principal axes
  • VS1.S2.S3 (1e1)(1e2)(1e3)Since ?v
    (v-vo), for vo1 we get
  • ?v (1e1)(1e2)(1e3)-1
  • Given vo1, since ev ?v/vo, ev ?v
    (1e1)(1e2)(1e3)-1
  • 1ev (1e1)(1e2)(1e3)
  • If volumetric strain, ?v ev 0, then
  • (1e1)(1e2)(1e3) 1 i.e., XYZ1
  • Express 1ev (1e1)(1e2)(1e3) in e take log
  • ln(1ev) e1e2e3
  • Rearrange (e1-e2)(e2-e3)-3e2ln(1ev)
  • Plane strain (e20) leads to
  • (e1-e2)(e2-e3)ln(1ev)straight line ymxb
    m1

24
Ramsay Diagram
25
Ramsay Diagram
  • Small strains are near the origin
  • Equal increments of progressive strain (i.e.,
    strain path) plot along straight lines
  • Unequal increments plot as curved plots
  • If ?vev is the volumetric strain, then
  • 1?v (1e1)(1e2)(1e3) ? lnSln(1e)
  • It is easier to examine ?v on this plot Take log
    from both sides and substitute ? for ln(1e)
  • ln(?v 1) ?1 ?2 ?3
  • If ?v0, the lines intersect the ordinate
  • If ?v

26
Measurement of Strain
  • Originally circular objects
  • When markers are available that are assumed to
    have been perfectly circular and to have deformed
    homogeneously, the measurement of a single marker
    defines the strain ellipse

27
Direct Measurement of Stretches
  • Sometimes objects give us the opportunity to
    directly measure extension
  • Examples
  • Boudinaged burrow
  • Boudinaged tourmaline
  • Boudinaged belemnites
  • Under these circumstances, we can fit an ellipse
    graphically through lines, or we can analytically
    find the strain tensor from three stretches

28
Direct Measurement of Shear Strain
  • Bilaterally symmetrical fossils are an example of
    a marker that readily gives shear strain
  • Since shear strain is zero along strain axes,
    inspection of enough distorted fossils (e.g.
    brachiopods, trilobites) can allow us to find the
    direction

29
Wellman's Method
  • Relies on a theorem in geometry that says that if
    two chords together cover 180 of a circle, the
    angle between them is 90
  • In Wellmans method, we draw an arbitrary diameter
    of the strain ellipse
  • Then we take pairs of lines that were originally
    at 90 and draw them through the two ends of the
    diameter
  • The pairs of lines intersect on the edge of the
    strain ellipse

30
Frys Method
  • Depends on objects that originally were clustered
    with a relatively uniform inter-object distance
  • We repeatedly trace the pattern of objects,
    shifting the pattern so a different object is
    over the origin
  • Shape of the strain ellipse shows up in an
    anticluster at the center

31
Rf/? Method
  • In many cases originally, roughly circular
    markers have variations in shape that are random
  • In this case the final shape Rf of any one marker
    is a function of the original shape Ro and the
    strain ratio Rs Rf,max Rs.Ro Rf,min Ro/Rs
  • The Fry method is a graphical technique for
    determining the strain ratio Rs(Rf,max/Rf,min)1
    /2
  • Assume an initial uniform point distribution
    (isotopic)
  • After deformation, the point distribution is
    non-uniform
  • Where extension has occurred, distances between
    points increase where contraction has occurred,
    distances decrease
  • The maximum distance between points occurs to
    principal stretch direction, S1, while minimum
    distance occurs to S2

32
Rf/? Method - Procedure
  • Mark the center of each object on a tracing paper
    overlay (Centers Sheet)
  • Copy the dots onto a second overlay and choose a
    central reference point ("Reference Sheet"). You
    should now have two identical pieces of tracing
    paper with a bunch of dots
  • Place the Reference Sheet on top of the Centers
    sheet
  • Line up the reference point with another point on
    the Centers Sheet
  • Trace all the dots from the Centers Sheet onto
    the Reference Sheet. They should show up in
    different locations because youve moved the
    Reference Sheet
  • Repeat the process with the Reference point
    lining up with every other point. Your final
    product will have a lot of points ( n2-n points)
  • If all goes as planned you should clearly see the
    strain ellipse around the reference point, which
    shows up as either an elliptical area devoid of
    points or an elliptical area of concentrated
    points
  • Draw in your interpretation of the strain ellipse
    size and orientation

33
How good is it?
  • Strengths
  • Quick and easy
  • Can be used on rocks that have pressure solution
    along grain boundaries, i.e. rocks in which some
    original material may have been lost
  • Applies to sand grains in sandstone, ooids in
    limestone, and pebbles in a conglomerate
  • Weaknesses
  • Requires lots of points (at least 25 for more
    precise answers)
  • Estimates of ellipticity can be extremely
    subjective and, hence, inaccurate
  • Cannot be used if particles being analyzed had
    some preferred axial direction prior to
    deformation
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