Title: Strain II
1Strain II
2Mohr Circle for Strain
- Recall that for stress, we plotted the normal
stress ?n against the shear stress ?s, and we
used equations which represented a circle - Because geologists deal with deformed rocks, when
using the Mohr circle for strain, we would like
to deal with measures that represent the deformed
state (not the undeformed state!)
3Equations for Mohr circle for strain
- Lets introduce two new parameters
- ? 1/? (to represent the abscissa)
- ? ?/? ?? (to represent the ordinate)
- The two equations for the Mohr circle are in
terms of ? and ? - ? (?1?3)/2(?3-?1)/2 cos2?
- ? (?3-?1)/2 sin2?
4Mohr Circle for Strain
- The coordinates of any point on the circle
satisfy the above two equations - The Mohr circle always plots to the right of the
origin because we plot the reciprocal quadratic
elongation ?1/? (1e)2, i.e., - ? (1e)2 and ?1/? are both
5Mohr Circle for Strain
- In parametric form, the equations of the Mohr
circle are - ? c r cos2?
- ? r sin2?
- Where
- Center, c (?1?3)/2 (mean strain)
- Radius, r (?3-?1)/2
6Sign Conventions
- The 2?? angle is from the c?1 line to the point
on the circle - Points on the circle represent lines in the real
world! - Since we use the reciprocal quadratic elongations
?1 ?3 - clockwise (cw) ?? from c?1 is , and
- Counterclockwise ccw is - (compare it with
stress!) - cw ?? in real world is cw 2?? in the Mohr circle,
and vice versa! - However, ccw ?, from the O? line to any point on
the circle, is , and cw ? is -
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8Deformed Brachiopod
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10Lines of no finite elongation - lnfe
- Draw the vertical line of lnfe 1 ? the ? axis
- The intersection of this magic line with the Mohr
circle defines the lnfe (there are two of them!). - Elongation along the lnfe is zero
- They dont change length during deformation,
i.e., - elnfe0, and ?lnfe1, and therefore ?lnfe1
- Numerical Solution tan2 ? (1-?1)/(?2-1)
11Finding the angular shear
- Because ??/? and ?1/? therefore
- ? ?? which yields ? ?/?
- Since shear strain, ? tan ?, and ? ?/?
- tan ? ?/?
- Note Mohr circle does not directly provide the
shear strain ? or the angular shear ?, it only
provides ? - However, notice that ? ? if ?1!
12Angular Shear
- ? ?/?
- The above equation means that we can get the
angular shear (?) for any line (i.e., any point
on the circle) from the ?/? of the coordinates
of that point - Thus, ? is the angle between the ? axis and a
line connecting the origin to any point on the
circle - ccw ? in the Mohr circle translates into ccw in
the physical world (i.e., same sense)!
13Finding the Shear Strain ?
- The ordinate of the Mohr diagram is ?, not the
shear strain ? - Because ? ?/?, then ? ? only if ?1
- This means that for a given deformed line (e.g.,
a point A on the Mohr circle), the ?
coordinate of the intersection of the magical
?1 line with the OA line (connecting the origin
to A) is actually ? because along the ?1
line, ? and ? are equal! - Procedure
- For any line (which is a point, e.g., A, on the
circle), first connect the point A to the
origin (O), and extend the line OA (if needed),
to intersect the ?1 line - Read ?along the ?1 line this is ? for the
line!
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15Finding lines of maximum shear (lms) strain (?max)
- Draw two tangents () to the Mohr circle from the
origin, and measure the 2? () where the two
lines intersect the circle - Numerical Solution
- Orientation
- tan ?lms ?(?2/?1) (Note these are ?, not ?)
- Amount
- ?max ?(?1-?2 )/2 ??1?2
16Lines of Maximum Shear (lms)
17Another Example
18ExampleA unit sphere is shortened by 50 and
extended by 100
- e11, and e3-0.5
- s1Xl/lo 1e12 s3Zl/lo 1e30.5
- ?1 (1e1)2s12 4 ? 3 (1e3)2 s320.25
- ? 1 1/?1 0.25 ?3 1/?3 4
- Note the area remains constant
- XZ ? ?1 ? ?3 ? 4 ?0.25 1
- c (?1 ?3)/2 (0.254)/22.125
- r (?3 - ?1)/2 (4-0.25)/21.90
- Having c and r, we can plot the circle!
19Graphic representation of strain ellipse
- Point A (1,1) represents an undeformed circle (?1
?2 1) - Because by definition, ?1?2 , all strain
ellipses fall below or on a line of unit slope
drawn through the origin - All dilations fall on the ?1 ?2 line through
the origin - All other strain ellipses fall into one of three
fields - Above the ?21 line where both principal
extensions are - To the left of the ?11 where both principal
extensions are - Between two fields where one is () and the other
(-)
20Shapes of the Strain Ellipse
21Graphic representation of strain ellipse
- Along AB, the original circle does not change
shape but only change radius - From A to origin the radius gets smaller (?l ?2
- Along AC elongation along ?1, and no change
along ?2 - Along AD shortening along ?2 no change along
?1 - Only along the hyperbola through field 3, where
?1 1/?2, is the area of the ellipse equal to the
area of the undeformed circle (i.e., constant
area) - Zone 3 is the only field in which there are two
lnfes
22Flinn Diagram
23Volume change on Flinn Diagram
- Recall S1e l'/lo and ev ?v/vo ?v
(v-vo)/vo - An original cube of sides 1 (i.e., lo1), gives
vo1 - Since Sl'/lo, and lo1, then Sl
- The deformed volume is therefore v'l'.l'.l
- Orienting the cube along the principal axes
- VS1.S2.S3 (1e1)(1e2)(1e3)Since ?v
(v-vo), for vo1 we get - ?v (1e1)(1e2)(1e3)-1
- Given vo1, since ev ?v/vo, ev ?v
(1e1)(1e2)(1e3)-1 - 1ev (1e1)(1e2)(1e3)
- If volumetric strain, ?v ev 0, then
- (1e1)(1e2)(1e3) 1 i.e., XYZ1
- Express 1ev (1e1)(1e2)(1e3) in e take log
- ln(1ev) e1e2e3
- Rearrange (e1-e2)(e2-e3)-3e2ln(1ev)
- Plane strain (e20) leads to
- (e1-e2)(e2-e3)ln(1ev)straight line ymxb
m1
24Ramsay Diagram
25Ramsay Diagram
- Small strains are near the origin
- Equal increments of progressive strain (i.e.,
strain path) plot along straight lines - Unequal increments plot as curved plots
- If ?vev is the volumetric strain, then
- 1?v (1e1)(1e2)(1e3) ? lnSln(1e)
- It is easier to examine ?v on this plot Take log
from both sides and substitute ? for ln(1e) - ln(?v 1) ?1 ?2 ?3
- If ?v0, the lines intersect the ordinate
- If ?v
26Measurement of Strain
- Originally circular objects
- When markers are available that are assumed to
have been perfectly circular and to have deformed
homogeneously, the measurement of a single marker
defines the strain ellipse
27Direct Measurement of Stretches
- Sometimes objects give us the opportunity to
directly measure extension - Examples
- Boudinaged burrow
- Boudinaged tourmaline
- Boudinaged belemnites
- Under these circumstances, we can fit an ellipse
graphically through lines, or we can analytically
find the strain tensor from three stretches
28Direct Measurement of Shear Strain
- Bilaterally symmetrical fossils are an example of
a marker that readily gives shear strain - Since shear strain is zero along strain axes,
inspection of enough distorted fossils (e.g.
brachiopods, trilobites) can allow us to find the
direction
29Wellman's Method
- Relies on a theorem in geometry that says that if
two chords together cover 180 of a circle, the
angle between them is 90 - In Wellmans method, we draw an arbitrary diameter
of the strain ellipse - Then we take pairs of lines that were originally
at 90 and draw them through the two ends of the
diameter - The pairs of lines intersect on the edge of the
strain ellipse
30Frys Method
- Depends on objects that originally were clustered
with a relatively uniform inter-object distance - We repeatedly trace the pattern of objects,
shifting the pattern so a different object is
over the origin - Shape of the strain ellipse shows up in an
anticluster at the center
31Rf/? Method
- In many cases originally, roughly circular
markers have variations in shape that are random - In this case the final shape Rf of any one marker
is a function of the original shape Ro and the
strain ratio Rs Rf,max Rs.Ro Rf,min Ro/Rs - The Fry method is a graphical technique for
determining the strain ratio Rs(Rf,max/Rf,min)1
/2 - Assume an initial uniform point distribution
(isotopic) - After deformation, the point distribution is
non-uniform - Where extension has occurred, distances between
points increase where contraction has occurred,
distances decrease - The maximum distance between points occurs to
principal stretch direction, S1, while minimum
distance occurs to S2
32Rf/? Method - Procedure
- Mark the center of each object on a tracing paper
overlay (Centers Sheet) - Copy the dots onto a second overlay and choose a
central reference point ("Reference Sheet"). You
should now have two identical pieces of tracing
paper with a bunch of dots - Place the Reference Sheet on top of the Centers
sheet - Line up the reference point with another point on
the Centers Sheet - Trace all the dots from the Centers Sheet onto
the Reference Sheet. They should show up in
different locations because youve moved the
Reference Sheet - Repeat the process with the Reference point
lining up with every other point. Your final
product will have a lot of points ( n2-n points)
- If all goes as planned you should clearly see the
strain ellipse around the reference point, which
shows up as either an elliptical area devoid of
points or an elliptical area of concentrated
points - Draw in your interpretation of the strain ellipse
size and orientation
33How good is it?
- Strengths
- Quick and easy
- Can be used on rocks that have pressure solution
along grain boundaries, i.e. rocks in which some
original material may have been lost - Applies to sand grains in sandstone, ooids in
limestone, and pebbles in a conglomerate - Weaknesses
- Requires lots of points (at least 25 for more
precise answers) - Estimates of ellipticity can be extremely
subjective and, hence, inaccurate - Cannot be used if particles being analyzed had
some preferred axial direction prior to
deformation