Title: Burton W. Jones
1Burton W. Jones
- Distinguished
- Teacher
- and
- MAA Member
2 3These famous names
- Newton Legendre
- Euler Gauss Lagrange
- Laplace Bessel
- might all be found on a list of
4Great Astronomers!!!
5Why Astronomy?
- Celestial (orbital) mechanics the mathematics
of things in orbit
6My introduction to orbital mechanics
- From the good Dr. Gauss himself, in a most
unexpected way - The Method of Least Squares
7From Edwards and Penneys Calculus
- The great German mathematician Carl Friedrich
Gauss (1777-1855) invented the method of least
squares when he was 18 years old. A short time
later, he used it to determine the orbit of the
first-discovered asteroid Ceres, initially
observed on the first day of the nineteenth
century, but lost from sight a few weeks later.
8From Larson and Hostetlers Calculus
- The method of least squares was introduced by
the French mathematician Adrien-Marie Legendre
(1752-1833).
9Whats a curious fellow to do?
- Summarische Übersicht der zur Bestimmung der
Bahnen der beiden neuen Hauptplaneten angewandten
Methoden - Summary Survey of the Methods for Determining the
Orbits of the Two New Major Planets -
10What its like to read Gauss(Quotes from
Summarische Übersicht)
11What its like to read Gauss(Quotes from
Summarische Übersicht)
- One can easily convince oneself
- From this it is easy to conclude
- From this the following three equations follow
easily - It is clear
- Further, one easily recognizes
- I allow myself this easily understood expression
for the sake of brevity
12Learning orbital mechanics from Gausss
Summarische Übersicht
13Learning orbital mechanics from Gausss
Summarische Übersicht
- Method of successive humiliations
- What I didnt learn (least squares)
- What I later learned (least squares)
- Where it led me (a whole new direction in my
research, with some interesting impacts on my
teaching!)
14Todays TalkOrbital mechanics applications in
the standard undergraduate mathematics curriculum
15Orbit basics
E (central angle)
satellite
?
t t0
f (polar angle)
16I. Calculus I
Analysis of Keplers Equation
17Analysis of Keplers Equation
- Problem 1. Given e0.5, M2.5, solve k(E)0.
-
- (I say, Blah blah blah Newtons method.
Students reach for their calculators. ) -
18Analysis of Keplers Equation
- Problem 2. Are there other solutions?
-
- (Three really clever students put their
calculators in graphing mode.) -
19Analysis of Keplers Equation
- Problem 3. Same questions
- for e 1.5, M 0.2.
20Keplers Equation E-0.5 sin(E)-2.50
E-1.5 sin(E)-0.20
k(E)
k(E)
E
E
21Consider Keplers Equation E - e sin(E)
M 0, 0
Must there be a solution? If so, must the solution be unique? Why NASA cares about these questions (Students look in vain for the right button on
their calculator.) 22k(E) E - e sin(E) M 0
Observe k is continuous k(0) 0, k(M1)0 (there is a root) k '(E) 1 - e cos(E) 0 (root is unique) Calculus books are jammed with functions, but
rarely look at families of functions A valuable point of view in real world
applications 23II. Linear Algebra
- Textbook problem
- Consider the bases
- B(2,1,1), (2,-1,1), (1,2,1) and
- B(3,1,-5), (1,1,-3), (-1, 0,2).
- Find the transition matrix from B to B.
- My students always ask
24- Why in the world would I ever want to express
vectors in any basis other than - B(1,0,0), (0,1,0), (0,0,1)?
25- Why in the world would I ever want to express
vectors in any basis other than - B(1,0,0), (0,1,0), (0,0,1)?
- Answer Things that are very complicated in one
coordinate system may be simple in another!
26- We can choose our basis to make the Earths
rotation simple to describe
27- or we can choose our basis to make the
satellites motion easy to describe
z'
y'
x'
28- Or we could choose the basis so that the
elliptical orbit has an easy polar
representation -
-
29- But we really need all three! So
- Express vectors in the most convenient basis,
then use transition matrices to convert as
necessary between the various bases!
z
z'
y'
y''
z''
?
x''
y
x'
x
30- First transition matrix
- basis to
- basis
z'
y'
y''
z''
x''
Wp
x'
31z
z'
y'
i
y
x'
x
32z
y
RA
x
33This completes the conversion from
coordinates to coordinates!
z
y
x
34Now we can easily work with satellite positions
in one coordinate system, then change them to
another!
35 Vector Time (GMT) 2005/024/133200.000
Vector Time (MET) N/A Weight (LBS)
404236.9 M50 Cartesian
M50 Keplerian
-----------------------------------
-------------------------------- X
4205964.20 a
6731367.37 meter Y -1135248.32 meter
e .0009492 Z
5124138.27 i
51.32425 XDOT 448.028837
Wp 48.90129 YDOT 7575.227356 meter/sec
RA 274.58915 deg ZDOT 1315.109936
f 28.49040
M 28.43854
36III. Differential Equations
- Space Shuttle Mission to Hubble Telescope March
1, 2002
Initial Space Shuttle Orbit
Transfer Orbit
Hubble Orbit
?v
37- Vector Time (GMT) 2002/060/113232.000
- Vector Time (MET) 000/001030.000
- Weight (LBS) 254068.0
-
- M50 Cartesian
M50 Keplerian - -----------------------------------
-------------------------------- - X 429037.29 a
6700526.03 meter - Y -5724011.02 meter e
.0395379 - Z 3066426.36 i
28.47537 - XDOT 7923.139316 Wp
53.88105 - YDOT 93.941694 meter/sec RA
174.32026 deg - ZDOT -476.018849 f
44.89957
38- SHUTTLE TRAJECTORY DATA
- Lift off time (UTC) 2002/060/112202.000
- Maneuvers contained within the current ephemeris
are as follows - IMPULSIVE TIG (GMT) M50 DVx(FPS) LVLH
DVx(FPS) - IMPULSIVE TIG (MET) M50 DVy(FPS) LVLH
DVy(FPS) - DT M50
DVz(FPS) LVLH DVz(FPS) - -----------------------------------------------
------------------------- - 060/120713.533 -99.2
133.3 - 000/004511.533 80.6
-0.1 - 000/000128.577 -38.0
-0.0
39- Vector Time (GMT) 2002/060/121157.821
- Vector Time (MET) 000/004955.821
- Weight (LBS) 250747.5
-
- M50 Cartesian M50
Keplerian - -----------------------------
-------------------------------- - X 2861810.80 a
6769217.50 meter - Y 5503917.12 meter e
.0277775 - Z -3128507.70 i
28.48130 - XDOT -6827.375539 Wp
52.94227 - YDOT 817.354008 meter/sec RA
174.16154 deg - ZDOT -1143.785242 f
197.83838
40Apply Eulers Method to a System of Differential
Equations
41IV. Calculus III The Mother Lode
42Derivation of Keplers Laws
43 Vector Time (GMT) 2005/024/133200.000
Vector Time (MET) N/A Weight (LBS)
404236.9 M50 Cartesian
M50 Keplerian
-----------------------------------
-------------------------------- X
4205964.20 a
6731367.37 meter Y -1135248.32 meter
e .0009492 Z
5124138.27 i
51.32425 XDOT 448.028837
Wp 48.90129 YDOT 7575.227356 meter/sec
RA 274.58915 deg ZDOT 1315.109936
f 28.49040
44z
h
v
i
r
y
x
45 Vector Time (GMT) 2005/024/133200.000
Vector Time (MET) N/A Weight (LBS)
404236.9 M50 Cartesian
M50 Keplerian
-----------------------------------
-------------------------------- X
4205964.20 a
6731367.37 meter Y -1135248.32 meter
e .0009492 Z
5124138.27 i
51.32425 XDOT 448.028837
Wp 48.90129 YDOT 7575.227356 meter/sec
RA 274.58915 deg ZDOT 1315.109936
f 28.49040
46V. My all time favorite student project
- Given the position and velocity YDOT, ZDOT of the International Space Station at
time t0 -
- Determine where (azimuth and altitude) and when
to look for the space station as it flies over
your location.
47 - Solution uses trigonometry, vector calculus,
linear algebra, and just a dash of computer
programming. - Students see the results of the project in an
extraordinary way they go outside and look in
the calculated direction at the calculated time,
and watch the space station fly by!
48(No Transcript)
49Related Project Real-time International Space
Station Tracker
50Research Opportunities Outside the Classroom
Context
History
Astronomy
Mathematics
51Which brings us toGauss Again!(A Current
Project)
- Problem Calculate the date of Easter in a given
year. - Certainly of mathematical interest (number
theory?) - Certainly of historical interest
- Has its roots in astronomy (full moon, vernal
equinox, etc.)
52But what does it have to do with Gauss?
- Berechnung des Osterfestes
- Calculation of the Easter Date
- published August 1800
-
53Gausss Easter Algorithm
- then Easter falls on the 22 d eth of March or
the d e 9th of April. (For 2000-2099, M24,
N5)
54Example
- a 2005 mod 19 10
- b 2005 mod 4 1
- c 2005 mod 7 3
- d 19aM mod 30 4
- e 2b4c6dN mod 7 1
- Then Easter falls on the 22 d eth of March,
or March 27th.
55Gausss explanation of the various steps of the
algorithm
56Gausss explanation of the various steps of the
algorithm
- The analysisdoes not allow itself to be shown
here in its complete simplicity - A further development of this circumstance would
be too long and drawn out here. - which one can easily convince oneself
- From this it is clear
57A parting gem from Dr. Gauss
- Handschriftliche Bemerkung at the end of his
article - From Christmas to Easter is on average,
- however, weekdays.
- (Absolutely no explanation whatever!)
58 773 ???? 950
- My own observations
- A complete (Gregorian) calendar cycle consists of
400 years, or 146,097 days
59 773 ???? 950
- My own observations
- A complete (Gregorian) calendar cycle consists of
400 years, or 146,097 days - Prime factorization of 146,097 337773
- Coincidence? Seems unlikely, but
60I have no idea!