Title: Physics 123
1 Physics 123
223. Light Geometric Optics
23.1 The Ray Model of Light 23.2 Reflection -
Plane Mirror 23.3 Spherical Mirrors 23.5
Refraction - Snells law 23.7 Converging and
Diverging Lenses
3Reflection
Angle of incidence equals the angle of reflection
4Image in a Plane Mirror
5Image in a Plane Mirror
6Image in a Plane Mirror
7Image in a Plane Mirror
8Image in a Plane Mirror
9Image in a Plane Mirror
do di
10Spherical Mirrors
Concave mirror
Convex mirror
11Concave Mirror
r f
focus f
radius r
f r /2
12Concave Mirror
A parallel ray reflects through the focus
13Concave Mirror
Solar Cooker!
14Concave Mirror
A ray through the focus reflects parallel
15Concave Mirror
Image is inverted, real, reduced
16Concave Mirror Equation
1 / d o 1 / d i 1 / f
17Concave Mirror Problem
A 3 cm high candle is located 5 cm from a concave
mirror whose radius of curvature is 20 cm. What
are the characteristics of the image?
18Concave Mirror Problem
f 10 cm 1/do 1/ di 1/f 1/5 1/ di
1/10 1/ di - 1/10 di - 10 cm The image is 10
cm behind the mirror, virtual, upright, and
magnified 2X m - di / do
19Concave Mirror Problem
Makeup mirror! If the object is within the focus
of the concave mirror the image is enlarged
(magnified), upright but virtual its all in
your head!!!
20Convex Mirror
21Convex Mirror
Image will ALWAYS be reduced, virtual, upright
22Jurassic Park!
Rear View Mirror Objects in the mirror are closer
than they appear!
23Convex Mirror Equation
1 / d o 1 / d i 1 / f Note f is negative d
i is negative
24Convex Mirror Problem
A 3 cm high candle is located 5 cm from a convex
mirror whose radius of curvature is 20 cm. What
are the characteristics of the image?
25Convex Mirror Problem
f - 10 cm 1/do 1/ di 1/f 1/5 1/ di -
1/10 1/ di - 3/10 di - 3.3 cm The image is
3.3 cm behind the mirror, virtual, upright, and
reduced in size m - di / do m 1 / 3
26Refraction
?i
?r
27Index of Refraction
n sin ?i / sin ?r
28Refraction Problem
The index of refraction of glass is 1.5. A ray
of light is incident on a glass pane at an angle
of 600. Calculate the angle of refraction.
29Refraction Problem
n sin ?i / sin ?r 1.5 sin 600 / sin ?r 1.5
0.866 / sin ?r sin ?r 0.866 / 1.5 sin ?r
0.58 ?r 350
30Converging (convex) Lens
31Converging Lens
When the object is outside the focus, the image
is real and inverted
32Converging Lens
When the object is inside the focus, the image is
virtual, upright, and enlarged.
33Diverging (concave) Lens
34Diverging (concave) Lens
35Diverging (concave) Lens
The image is ALWAYS reduced, upright, virtual
36Lens Problem
A 35 mm slide projector uses a converging lens
with f 20 cm. The screen is 3 m away. How far
is the slide from the lens?
37Lens Problem
1/do 1/ di 1/f 1/do 1/ 300 1/20 1/do
1/20 - 1/ 300 do 21. 4 cm m - di / do m -
300 / 21.4 m -14 Image is real, inverted,
magnified
38Thats all folks!