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Physics 123

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Jurassic Park! Rear View Mirror. Objects in the mirror are closer than they appear! ... do = 21. 4 cm. m = - di / do. m = - 300 / 21.4. m = -14. Image is real, ... – PowerPoint PPT presentation

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Title: Physics 123


1
Physics 123
2
23. Light Geometric Optics
23.1 The Ray Model of Light 23.2 Reflection -
Plane Mirror 23.3 Spherical Mirrors 23.5
Refraction - Snells law 23.7 Converging and
Diverging Lenses
3
Reflection
Angle of incidence equals the angle of reflection
4
Image in a Plane Mirror
5
Image in a Plane Mirror
6
Image in a Plane Mirror
7
Image in a Plane Mirror
8
Image in a Plane Mirror
9
Image in a Plane Mirror
do di
10
Spherical Mirrors
Concave mirror
Convex mirror
11
Concave Mirror
r f
focus f
radius r
f r /2
12
Concave Mirror
A parallel ray reflects through the focus
13
Concave Mirror
Solar Cooker!
14
Concave Mirror
A ray through the focus reflects parallel
15
Concave Mirror
Image is inverted, real, reduced
16
Concave Mirror Equation
1 / d o 1 / d i 1 / f
17
Concave Mirror Problem
A 3 cm high candle is located 5 cm from a concave
mirror whose radius of curvature is 20 cm. What
are the characteristics of the image?
18
Concave Mirror Problem
f 10 cm 1/do 1/ di 1/f 1/5 1/ di
1/10 1/ di - 1/10 di - 10 cm The image is 10
cm behind the mirror, virtual, upright, and
magnified 2X m - di / do
19
Concave Mirror Problem
Makeup mirror! If the object is within the focus
of the concave mirror the image is enlarged
(magnified), upright but virtual its all in
your head!!!
20
Convex Mirror
21
Convex Mirror
Image will ALWAYS be reduced, virtual, upright
22
Jurassic Park!
Rear View Mirror Objects in the mirror are closer
than they appear!
23
Convex Mirror Equation
1 / d o 1 / d i 1 / f Note f is negative d
i is negative
24
Convex Mirror Problem
A 3 cm high candle is located 5 cm from a convex
mirror whose radius of curvature is 20 cm. What
are the characteristics of the image?
25
Convex Mirror Problem
f - 10 cm 1/do 1/ di 1/f 1/5 1/ di -
1/10 1/ di - 3/10 di - 3.3 cm The image is
3.3 cm behind the mirror, virtual, upright, and
reduced in size m - di / do m 1 / 3
26
Refraction
?i
?r
27
Index of Refraction
n sin ?i / sin ?r
28
Refraction Problem
The index of refraction of glass is 1.5. A ray
of light is incident on a glass pane at an angle
of 600. Calculate the angle of refraction.
29
Refraction Problem
n sin ?i / sin ?r 1.5 sin 600 / sin ?r 1.5
0.866 / sin ?r sin ?r 0.866 / 1.5 sin ?r
0.58 ?r 350
30
Converging (convex) Lens
31
Converging Lens
When the object is outside the focus, the image
is real and inverted
32
Converging Lens
When the object is inside the focus, the image is
virtual, upright, and enlarged.
33
Diverging (concave) Lens
34
Diverging (concave) Lens
35
Diverging (concave) Lens
The image is ALWAYS reduced, upright, virtual
36
Lens Problem
A 35 mm slide projector uses a converging lens
with f 20 cm. The screen is 3 m away. How far
is the slide from the lens?
37
Lens Problem
1/do 1/ di 1/f 1/do 1/ 300 1/20 1/do
1/20 - 1/ 300 do 21. 4 cm m - di / do m -
300 / 21.4 m -14 Image is real, inverted,
magnified
38
Thats all folks!
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