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Systems of Linear Equations with two variables

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A 600-seat movie theater charges $5.50 admission for adults and $2.50 for children. ... Solve the system obtained for the movie theater problem by substitution. ... – PowerPoint PPT presentation

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Title: Systems of Linear Equations with two variables


1
Systems of Linear Equations with two variables
2
An interesting problem
  • A 600-seat movie theater charges 5.50 admission
    for adults and 2.50 for children.
  • If the theater is full, and 1911 is collected,
    how many adults and how many children are in the
    audience?

3
To solve a real-life problem like this, we need
to
  • formulate it as a mathematical problem,
  • solve the math problem, and
  • interpret the solution of the math problem

4
Let
x number of children in attendance
y number of adults in attendance
xy 600 2.50x5.50y 1911
5
Observe that both equations are linear.
  • We call such a set of equations a

System of linear equations with two variables
6
Solving a system of linear equations with two
variables
  • by substitution (Read page 186)
  • by elimination (Read page 187)
  • by graphing (Read page 182)

7
Example Solve the system obtained for the movie
theater problem by substitution.
xy 600 2.50x5.50y 1911
x 463 y 137
We conclude that there are 463 children and 137
adults in attendance.
8
Example Solve the system obtained for the movie
theater problem by elimination.
9
Example Solve the system obtained for the movie
theater problem by graphing.
10
Three possible cases when we solve a system of
linear equations with 2 variables
  • Exactly one solution.
  • Graphically, there is one point of intersection
  • No solution
  • Graphically, the lines never intersect
  • Infinitely many solutions
  • Graphically, the lines are equivalent
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