Title: Finding Square Roots
1Finding Square Roots
2Warm Up
Find the two square roots of each number.
Evaluate each expression.
12
16
20
119
3Finding Square Roots
Learn to estimate square roots to a given number
of decimal places and solve problems using square
roots.
4A museum director wants to install a skylight to
illuminate an unusual piece of art. It must be
square and have an area of 300 square inches,
with wood trim around it. Can you calculate the
trim that you need? You can do this by using your
knowledge of squares and square roots.
5Example Estimating Square Roots of Numbers
Each square root is between two integers. Name
the integers.
Think What are perfect squares close to 55?
55
A.
49 lt 55
72 49
64 gt 55
82 64
6Example Estimating Square Roots of Numbers
Continued
Each square root is between two integers. Name
the integers.
Think What are perfect squares close to 90?
90
B.
81 lt 90
92 81
100 gt 90
102 100
7Try This
Each square root is between two integers. Name
the integers.
Think What are perfect squares close to 80?
80
A.
64 lt 80
82 64
81 gt 80
92 81
8Try This
Each square root is between two integers. Name
the integers.
Think What are perfect squares close to 45?
45
B.
36 lt 45
62 36
49 gt 45
72 49
9Example 2 Problem Solving Application
You want to sew a fringe on a square tablecloth
with an area of 500 square inches. Calculate the
length of each side of the tablecloth and the
length of fringe you will need to the nearest
tenth of an inch.
First find the length of a side. Then you can use
the length of a side to find the perimeter, the
length of fringe around the tablecloth.
10Example 2 Continued
11Example 2 Continued
Because 500 is between 222 and 232, the square
root of 500 is between 22 and 23.
The square root is between 22.3 and 22.4.
12Example 2 Continued
The square root is between 22.3 and 22.4. To
round to the nearest tenth, look at the next
decimal place.
Consider 22.35.
Too low
22.352 499.5225
The square root must be greater than 22.35, so
round up.
The length of each side of the table is about
22.4 in.
13Example 2 Continued
Solve
The length of a side of the tablecloth is 22.4
inches, to the nearest tenth of an inch. Now
estimate the length around the tablecloth.
4 22.4 89.6
Perimeter 4 side
You will need about 89.6 inches of fringe.
14Example 2 Continued
The length 90 inches divided by 4 is 22.5 inches.
A 22.5-inch square has an area of 506.25 square
inches, which is close to 500, so the answers are
reasonable.
15Try This
You want to build a fence around a square garden
that is 250 square feet. Calculate the length of
one side of the garden and the total length of
the fence, to the nearest tenth.
First find the length of a side. Then you can use
the length of a side to find the perimeter, the
length of the fence.
16Try This
17Try This
Because 250 is between 152 and 162, the square
root of 250 is between 15 and 16.
2
4
1
3
The square root is between 15.8 and 15.9.
18Try This
To round to the nearest tenth, look at the next
decimal place.
15.852 251.2225
Consider 15.85.
The square root is lower than 15.85, so round
down.
The length of each side of the garden is about
15.8 ft.
19Try This
Solve
The length of a side of the garden is 15.8 feet,
to the nearest tenth of a foot. Now estimate the
length around the garden.
4 15.8 63.2
Perimeter 4 side
You will need about 63.2 feet of fence.
20Try This
The length 63.2 feet divided by 4 is 15.8 feet. A
15.8 foot square has an area of 249.64 square
feet, which is close to 250, so the answers are
reasonable.
21Examples 3 Using a Calculator to Estimate the
Value of a Square Root
Use a calculator to find 500. Round to the
nearest tenth.
Using a calculator, 500 22.36067977.
Rounded, 500 is 22.4.
22Try This
Use a calculator to find 200. Round to the
nearest tenth.
Rounded, 200 is 14.1.
23Lesson Quiz
Each square root is between two integers. Name
the two integers.
1. 27 2. 456
5 and 6
22 and 21
Use a calculator to find each value. Round to the
nearest tenth.
9.4
35.0
3. 89 4. 1223
5. A square field has an area of 2000 square
feet. To the nearest foot, how much fencing would
be needed to enclose the field?
179 ft