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RESONANCE STRUCTURES

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Title: RESONANCE STRUCTURES


1
  • RESONANCE STRUCTURES
  • For certain molecules or molecular ions, two or
    more EQUIVALENT Lewis structures can be drawn.
  • The equivalent structures have the same formal
    charge and are equal in energy.

2
Three equivalent structures for the carbonate ion
all have the same formal charge.
These equivalent structures are called RESONANCE
STRUCTURES.
The double bond electron pair is DELOCALIZED over
all three C-O bonds and hence all three C-O bonds
are between pure-single and pure-double bonds.
Note This differs from the two structures for
N3- which had different bonding arrangements for
the atoms, and hence not equivalent.
3
  • The carbonate ion is NOT a mixture of the three
    structures, nor does any one of the three exist
    independently.
  • The real structure is an average of the three
    structures, and properties of these bonds are
    such that they are intermediate between single
    and double bonds.
  • All three C-O bonds identical, the bond lengths
    are between a single bond between C and O and a
    double bond between C and O
  • Other examples of molecules that have more than
    one equivalent resonance structures are NO3-, SO3

4
  • EXCEPTIONS TO THE OCTET RULE
  • Although the octet rule is very useful, it does
    not apply in all cases. There are three classes
    of exceptions
  • 1) Compounds with odd number of electrons
  • 2) Compounds with a shortage of electrons, less
  • than the octet.
  • 3) Compounds with an abundance of electrons,
  • exceeding the octet

5
  • 1) Molecules with ODD number of valence electrons
  • An example is nitrogen monoxide, NO.
  • Molecules with an odd number of electrons cannot
    satisfy the octet rule for all its atoms.
  • In this case the octet rule must be given up for
    one of the atoms by leaving an unpaired lone
    electron.
  • ALL BONDING ELECTRONS MUST BE PAIRED.

6
  • NO is stable molecule with 11 valence electrons

In (i) N has an octet, but not O in (ii) O has
an octet but not N
Calculate the formal charge of each atom for (i)
and (ii) to determine which is the more favored
structure.
Structure (ii) is favored since the formal
charges on both atoms is zero in (i) N is -1 and
O is 1, with the more electronegative atom, O,
possessing a 1 formal charge
7
  • 2) Electron Deficient Molecules
  • Example BF3

Lewis model predicts the following structure for
BF3
However, experimental evidence suggests that the
structure of BF3 is
8
  • (i) assigns a 1 formal charge to a very
    electronegative atom which is undesirable
  • (ii) is the observed structure, even though B
    does not have an octet, the formal charges on all
    atoms are zero.

9
  • 3) Valence-Shell Expansion
  • The elements in Groups IIIA to VII A in the third
    period and beyond show a tendency to surround
    themselves with more than 8 electrons.
  • It is possible for these elements through
    valence shell expansion for the central atom to
    have more than 8 electrons
  • In cases like this, after accounting for bonding
    electrons, assign lone pairs to the outer atoms
    to give them octets.
  • If any electrons still remain, assign them to the
    central atoms as lone pairs.

10
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11
  • Example SF6
  • Number of valence electrons 6 (6x7) 48
  • Total number of electrons needed for each atom to
    satisfy an octet 7x8 56
  • Number of shared electrons 56-48 8
  • 8 electrons, 4 bonds, is not enough bonds for SF6
  • Hence, assign one bond pair to each bond, which
    for SF6 is 6.
  • Then assign lone pairs to the outer atoms to give
    them an octet. If any electrons remain, assign
    them to the central atom.

12
  • Count all electrons
  • (6x6) (6x2) 48 electrons

Formal charge on all atoms 0
13
POCl3 - phosphoryl chloride
(ii)
(i)
i) non zero formal charges ii) valence shell
expansion for P
14
Shapes of Molecules
  • Molecules have definite shape i.e. definite
    geometries.
  • For example, H2O is bent and CO2 is linear.

15
  • Lewis stuctures do not provide information on a
    molecules geometry, i.e. shape.
  • VALENCE SHELL ELECTRON-PAIR REPULSION (VSEPR)
    THEORY predicts molecular shapes based on Lewis
    stuctures
  • VSEPR derives from the realization that bonding
    and non-bonding electron pairs will locate
    themselves in space so as to minimize repulsive
    interactions.
  • The geometry of the electron pairs, and the
    covalent bonds that form, can be predicted using
    VSEPR

16
  • Molecular geometry depends on the total number of
    electron pairs
  • To use the VSEPR theory to predict molecular
    geometry, need to know how electron pairs can be
    arranged around a central atom so as to minimize
    electron-electron repulsion.
  • An electron pairs arranges itself in
    three-dimensional space such that it is equally
    far apart from all the other electron pairs.
  • The resulting arrangement of the electron pairs
    in a molecule depends on the NUMBER of electron
    pairs.
  • Note For VSEPR, the electron pairs we refer to
    are the valence electrons

17
For a central atom surrounded by TWO electron
pairs, the optimum geometry which minimizes
repulsion between the electrons pairs is LINEAR
For a central atom surrounded by THREE electron
pairs, the optimum geometry which minimizes
repulsion between the electrons pairs is TRIGONAL
PLANAR
18
For a central atom surrounded by FOUR electron
pairs, the optimum geometry which minimizes
repulsion between the electrons pairs is
TETRAHEDRAL
For a central atom surrounded by FIVE electron
pairs, the optimum geometry which minimizes
repulsion between the electrons pairs TRIGONAL
BIPYRAMIDAL
19
For a central atom surrounded by SIX electron
pairs, the optimum geometry which minimizes
repulsion between the electrons pairs OCTAHEDRAL
We have been talking about the location of the
electron pairs about the central atom. This
maybe different from molecular geometries i.e.
the structure or shape of a molecule
20
  • Water has a BENT structure with the H-O-H angle
    measured to be 104.5o.

If O is bonded to 2 H atoms, why is the structure
of water not linear?
21
MOLECULAR GEOMETRY Molecular geometry is the
arrangement of ATOMS about the central atom. If
there are no non-bonding electrons, then the
electron geometry and the molecular geometry is
the same.
  • If there are non-bonding electrons on the central
    atom then the molecular geometry differs from the
    electron geometry but is obtained from knowledge
    of the electron geometry about the central atom.

22
  • To determine the molecular geometry about the
    central atom of a molecule
  • 1) Write the best Lewis structure for the
    molecule or ion
  • 2) Count the total number of ATOMS attached to
    the central atom plus the number of NONBONDING
    ELECTRON PAIRS on the central atom .
  • 3) Using the VSEPR geometries establish the
    ELECTRON geometry about the central atom.
  • 4) Finally examine the placement of atoms and
    identify the molecular geometry.

23
  • Step 1 Write the best Lewis structure for the
    molecule
  • Total number of valence electrons 116 8
  • Number of electrons needed for each to complete
    an octet (remember for H need two electrons) 2
    2 8 12
  • Shared electrons 12- 84 gt two bonds
  • Number of unpaired electrons 4 gt 2 lone pairs
    on O
  • Lewis structure of H2O is

24
  • 2) Count the total number of atoms attached to
    the central atom plus the number of non-bonding
    electron pairs on the central atom

For water, Total number of electron pairs
2
pairs of bonding electrons (bp) 2 pairs of
non-bonding electrons (np) 4 pairs
25
3) Then using the VSEPR geometries establish the
electron geometry about the central atom.
According to VSEPR theory For a central atom
surrounded by four electron pairs, the optimum
geometry which minimizes repulsion between the
electrons pairs is tetrahedral
Arrange the two nonbonding electron pairs and the
two H atoms at the apices of the tetrahedron,
with O at the center
26
4) Finally examine the placement of atoms and
identify the molecular geometry.
To determine the molecular geometry of water,
look at the arrangement of just the atoms (in
this case, H,O,H)
Looking at the arrangement of the atoms in H2O,
we see that the molecule is bent.
27
  • For a tetrahedral geometry, expect that the H-O-H
    angle is 109.5o
  • The measured H-O-H angle is 104.5o, slightly
    smaller than predicted.
  • Non-bonding electron pairs are more diffuse than
    bonding electron pairs, taking up more space.

Model
28
  • Draw the Lewis structure to determine the number
    of bonding electron pairs and number of
    nonbonding pairs on the central atom (a double or
    triple bond counts as a single electron pair when
    using VSEPR theory).
  • Arrange the bonding and nonbonding electron pairs
    around the central atom in a geometry predicted
    by VSEPR.
  • Position the atoms bonded to the central atom
    where the bonding electrons are positioned.
  • Determine the molecular geometry based on the
    arrangement of the atoms

29
  • Two electron pairs
  • Example CO2

Number of electron pairs around C 2 (count the
double bond as a single electron pair). Both
are bonding pairs VSEPR predicts a linear
molecular geometry for CO2
Model
30
  • Three electron pairs

The three electron pairs around the central B
atom are all bonding pairs. According to VSEPR
the three electron pairs around the central atom
are positioned at the vertices of an equilateral
triangle In the case of BF3, since the three
electron pairs are bonding pairs, the three F
atoms are positioned at the vertices of the
equilateral triangle.
Model
31
  • For VSEPR count two bonding electron pairs and
    one nonbonding electron pair.
  • Hence the three electron pairs are situated at
    the vertices of an equilateral triangle.

32
  • The two O atoms are situated at two of the
    vertices and the nonbonding electron pair at the
    third.

The molecular geometry if NO2- is not trigonal
planar, but bent. The O-N-O angle is less than
120o due to the presence of the nonbonding pair
on N
33
  • Four electron pairs
  • For molecules with four electron pairs, the
    electron pairs surround the central atom in a
    TETRAHEDRAL geometry.
  • The molecular geometry depends on the number of
    bonding and nonbonding electron pairs on the
    central atom.
  • Examples

Model
34
  • Five Electron Pairs
  • Electronic geometry is trigonal bipyramidal.
  • However, unlike the 2, 3 and 4 electron
    geometries all vertices of a trigonal bipyramid
    are NOT equivalent.
  • There are two AXIAL positions and three
    EQUATORIAL positions.

35
  • Angle between
  • axial-central atom-axial 180o
  • axial-central atom-equatorial 90o
  • equatorial -central atom- equatorial 120o

The positions of the nonbonding electron pairs
relative to each other and the bonding pairs have
to account for the non-equivalence of the axial
and equatorial positions. To position the
nonbonding and bonding electrons nb-nb
repulsion gt nb-b gt b-b
36
  • Hence, position nonbonding pairs first, then
    bonding pairs accounting for the repulsion
    between the electron pairs.

PCl5
Model
37
  • SF4

Position the nonbonding electron pair on S at the
equatorial position since this minimizes nb-b
repulsions
F
F
S
F
see-saw
F
38
Other examples ClF3 - distorted T XeF2 - linear
Model
39
  • Six electron pairs
  • Octahedral geometry
  • All vertices are the equivalent, hence bonding
    and nonbonding electron pairs can be positioned
    at any vertex

Molecular geometry determined by number and
position at atoms and nonbonding electron pairs
Model
40
  • Examples

41
  • Molecular Properties
  • Bond Lengths
  • The bond distance is the distance between the two
    nuclei of the two atoms bonded together.
  • Bond lengths depend on the elements and whether
    the bond between the two elements is single,
    double or triple
  • Typically
  • single bond length gt double bond length gt triple
    bond length

42
  • Bond Energies
  • If two atoms in a diatomic molecule are pulled
    far enough apart the bond between the atoms
    breaks.
  • The energy needed to break the bond is called the
    bond energy or bond dissociation energy.
  • Bond energies depend on the nature of the atoms
    bonded together and whether the bond is single,
    double or triple.
  • Typically single bond energies lt double bond
    energy lt triple bond energy

43
  • Dipole Moments
  • The bonding electron pair in HCl is not shared
    equally between the H and Cl atoms.
  • This is because Cl is more electronegative than
    H, and tends to attract the electron pair closer
    towards it.
  • Hence the electron distribution for the bonding
    pair of electrons is not evenly distributed over
    both the H and Cl atoms, but is more concentrated
    over the Cl atom.
  • The more electronegative atom develops a slight
    negative charge and the more electropositive atom
    a slight positive charge

44
  • This charge separation results in a DIPOLE
    MOMENT, and a POLAR HCl bond.
  • The dipole moment is defined as the product of
    the magnitude of the separated charges and the
    distance between the centers of the charges.
  • The dipole moment is a vector

45
  • The larger the electronegative difference between
    the bonded atoms, larger is the magnitude of the
    dipole moment and hence more polar is the bond.
  • All heteronuclear diatomic molecules (A-B. where
    A?B) are polar molecules with the degree of
    polarity depending on the electronegativity
    differences between the two atoms.
  • Heteronuclear diatomics have non-zero dipole
    moments
  • All homonuclear diatomic molecules (A2) are
    non-polar, with zero dipole moments

46
  • Polyatomic molecules
  • Bonds between atoms of different elements will
    each have a dipole moment associated with them.
  • The magnitude of the dipole moment of a bond
    depends on the electronegativity differences
    between the bonded atoms.
  • However, whether the molecule as a whole has a
    dipole moment depends on the geometry of the
    molecule.
  • The dipole moment is a vector and hence the
    dipole moment of the molecule is the vector sum
    of the dipole moments of each bond in the
    molecule.

47
  • Methane, CH4

The net dipole moment for CH4 is zero
48
  • Water, H2O

Model
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