Title: Sets and Probability
1Sets and Probability
2Ch. 7 Sets and Probabilities
- 7.1 Sets
- 7.2 Applications of Venn Diagrams
- 7.3 Introduction to Probability
- 7.4 Basic Concepts of Probability
- 7.5 Conditional Probability Independent Events
- 7.6 Bayes Theorem
37.1 Sets
- Set A well defined collection of objects.
- The set consisting of all students in the class.
- The set consisting of all the coins produced by
the U.S. government. - The set consisting of the numbers 3, 4, and 5
- 3, 4, 5
- 4 is an element of the set 3, 4, 5
- 4?3, 4, 5
- 8?3, 4, 5
- n(A) the number of elements in finite set A
- A 3, 4, 5, n(A) 3
47.1 Sets
- Two sets are equal if they contain the same
elements - 3, 4, 5 5, 4, 3 4, 3, 5 3, 3, 4, 5,
5 - Subsets
- Set A is a subset of set B (A ? B) if every
element of A is also an element of B. - Set A is a proper subset (A ? B) if A ? B and A ?
B. - A (3, 4, 5, 6, B 2, 3, 4, 5, 6, 7, 8)
- A ? B
- The Universal Set (U)
- The set that contains all objects under
consideration.
5Relationships Among Sets Venn Diagrams
U
B
A
6Relationships Among Sets Venn Diagrams
- Complement of a set
- Set A contains the elements of U that are not in
A
U
A'
A
7Relationships Among Sets Venn Diagrams
- Intersection of Two Sets
- A ? B
U
B
A
8Relationships Among Sets Venn Diagrams
U
B
A
9Relationships Among Sets Venn Diagrams
U
B
A
107.2 Applications of Venn Diagrams
- One set leads to 2 regions
U
2
A
1
117.2 Applications of Venn Diagrams
- One set leads to 2 regions
- Region 1 A
- Region 2 A
U
2
A
1
12Applications of Venn Diagrams
- Two sets leads to 3 regions
U
A
B
2
3
1
13Applications of Venn Diagrams
- Two sets leads to 3 regions
- Or...
U
A
B
2
3
1
14Applications of Venn Diagrams
- Two sets leads to 3 regions
- Or...
U
A
3
3
2
B
1
15Applications of Venn Diagrams
- Two sets leads to 4 regions
U
A
B
3
4
2
1
16Applications of Venn Diagrams
U
A
3
B
2
8
4
5
7
1
6
C
17Example
- 140 people in a suburban shopping center were
interviewed to discover some of their cooking
habbits. - 58 use microwave ovens
- 63 use electric ranges
- 58 use gas ranges
- 19 use microwave ovens and electric ranges
- 17 use microwave ovens gas ranges
- 4 use both gas and electric ranges
- 1 uses all three
- 2 use none of the three
18Example
U
M
18
E
23
41
1
16
3
2
38
G
197.3 Introduction to Probability
- Probability is a numerical measure of the
likelihood that an event will occur. - Probability values are always assigned on a scale
from 0 to 1. - A probability near 0 indicates an event is very
unlikely to occur. - A probability near 1 indicates an event is almost
certain to occur. - A probability of 0.5 indicates the occurrence of
the event is just as likely as it is unlikely.
20An Experiment and Its Sample Space
- An experiment is an activity or occurrence with
an observable result. - Each repetition of an experiment is called a
trial. - The sample space for an experiment is the set of
all experimental outcomes. - An event is a subset of the sample space.
21An Experiment and Its Sample Space
- An experiment consists of studying the number of
boys and girls in families with exactly 3
children. - Let b represent boy and g represent girl.
- Event B the family has only boys. B b, b, b
- Event H the family has exactly two girls
Sample Space
22Set Operations for Events
- Let E and F be events for a sample space S.
- E ? F occurs when both E and F occur
- E ? F occurs when E or F or both occur
- E occurs when E does not occur.
- Mutually Exclusive Events
- E and F are mutually exclusive if E ? F Ø.
23Basic Probability Principle
- For sample spaces with equally likely outcomes,
the probability of an event is defined as follows.
BASIC PROBABILITY PRINCIPLE Let S be a sample
space of equally likely outcomes, and let Event E
be a subset of S. Then the probability that E
occurs is
24Basic Probability Principle
If a single playing card is drawn at random from
a standard 52-card deck, find the probability of
each event
25Basic Probability Principle
If a single playing card is drawn at random from
a standard 52-card deck, find the probability of
each event
- Drawing a spade
- Drawing a spade or a heart
267.4 Basic Concepts of Probability
- Union (Addition) Rule for Probability
- Union Rule for Mutually Exclusive Events
- Complement Rule
- Odds
27Union of Two Events
- The union of events A and B is the event
containing all sample points that are in A or B
or both. - The union is denoted by A ??B?
- The union of A and B is illustrated below.
- P(A ??B) The probability of the occurrence of
Event A or Event B.
Sample Space S
28Addition Rule
- The addition rule provides a way to compute the
probability of event A, or B, or both A and B
occurring. - The rule is written as
- P(A ??B) P(A) P(B) - P(A ? B?
Event A
29Addition Rule
- The addition rule provides a way to compute the
probability of event A, or B, or both A and B
occurring. - The rule is written as
- P(A ??B) P(A) P(B) - P(A ? B?
Event B
30Addition Rule
- The addition rule provides a way to compute the
probability of event A, or B, or both A and B
occurring. - The rule is written as
- P(A ??B) P(A) P(B) - P(A ? B?
Event A
Event B
31Union of Two Events
- ADDITION RULE FOR PROBABILITY
- For any events E and F from sample space S
Consider an assembly plant with 50 employees.
Each worker is expected to complete work
assignments on time and in such a way that the
assembled product will pass a final inspection.
On occasion, some of the workers fail to meet the
performance standards by completing work late
and/or assembling a defective product. Recently,
the manager found that 5 workers had completed
work late, 6 had assembled a defective product,
and 2 had both completed work late and assembled
a defective product.
32Union of Two Events
- Let
- L the event that the work is completed late
- D the event that the assembled product is
defective
The manager decided to assign a poor performance
rating to any employee whose work was either late
or defective. What is the probability an employee
was given a poor performance rating?
33Addition Rule forMutually Exclusive Events
- Two events are said to be mutually exclusive if
the events have no sample points in common. That
is, two events are mutually exclusive if, when
one event occurs, the other cannot occur. - Addition Rule for Mutually Exclusive Events
- P(A ??B) P(A) P(B)
Event A
Event B
34Roll the Dice
- If you roll 2 dice, whats the probability of
rolling a 7 or 11?
35Die 1
Die 2
P(7) 6/36 .167
P(11) 2/36 .056
36Roll the Dice
- If you roll 2 dice, whats the probability of
rolling a 7 or 11?
37Complement of an Event
- The complement of event A is defined to be the
event consisting of all sample points that are
not in A. - The complement of A is denoted by A.
Event A
A
COMPLEMENT RULE P(E) 1 P(E) and
P(E) 1 P(E)
387.5 Conditional Probability
- The probability of an event given that another
event has occurred is called a conditional
probability. - The conditional probability of A given B is
denoted by P(AB).
39Conditional Probability
40Joint Probability Table
P(A ??M)
P(M)
41Joint Probability Table
Joint probabilities
42Joint Probability Table
Marginal probabilities
43Joint Probability Table
44Conditional Probability
- The probability of an event given that another
event has occurred is called a conditional
probability. - The conditional probability of A given B is
denoted by P(AB). - A conditional probability is computed as follows
- If P(AB) 0, then event A and event B are
mutually exclusive.
45Example Conditional Probability
- Conditional Probability
- Officer promoted given the officer is a man
-
- Officer promoted given the officer is a woman
46Intersection of Two Events
- The intersection of events A and B is the set of
all sample points that are in both A and B. - The intersection is denoted by A ????
- The intersection of A and B is the area of
overlap in the illustration below. - P(A ???) The probability of the occurrence of
Event A and Event B.
Sample Space S
Intersection
Event A
Event B
47Product Rule
- The product rule provides a way to compute the
probability of an intersection of two events. - The law is written as
-
Event A
Event B
48Product Rule for Independent Events
- Events A and B are independent if P(AB) P(A).
- Multiplication Law for Independent Events
- P(A ? B) P(A)P(B)
- The product rule also can be used as a test to
see if two events are independent.
49You are given the following information on Events
A, B,
C, and D.
È
P(A) .4
P(A
D) .6
ô
P(B) .2
P(A
B) .3
Ç
P(C) .1
P(A
C) .04
Ç
P(A
D) .03
b. Compute P(A ? B)
507.5 Bayes Theorem
- The probability of an event A B is generally
different from the probability of B A. - However, there is a definite relationship between
the two. - Bayes' theorem is the statement of that
relationship. - Medical researchers know that the probability of
getting lung cancer if a person smokes is .34. - The probability that a nonsmoker will get lung
cancer is .03. - With Bayes theorem, we can calculate the
probability that a person with lung cancer is (or
was) a smoker.
51Bayes Theorem
S Person is a smoker N Person is a
non-smoker
According to the Center for Disease Control and
Prevention, approximately 22 of the population
18 years or older smokes tobacco products
regularly.
P(S) .22, P(N) .78
52Bayes Theorem
- Conditional Probabilities
- Let
C Person has (or will have) lung cancer H
Person will not have lung cancer
Based upon medical research
P(CS) .34
P(CN) .03
P(HS) .66
P(HN) .97
Hence
53Bayes Theorem
- We can illustrate the different possible outcomes
with a tree diagram (2-step experiment).
Step 2 Health
Step 1 Smoker or non-smoker
Experimental Outcomes
C
(S, C)
S
(S, H)
H
C
(N, C)
N
(N, H)
H
54Bayes Theorem
- Now we can fill in the probabilities
Step 2 Health
Step 1 Smoker or non-smoker
Experimental Outcomes
P(CS) .34
P(S ? C) P(S)P(CS) .07
P(S) .22
P(S ? H) .15
P(HS) .66
P(CN) .03
P(N ? C) .02
P(N) .78
P(N ? H) .76
P(HN) .97
55Bayes Theorem
- Now suppose we want to determine the probability
that a person who has been diagnosed with lung
cancer is a smoker. In other words, - From the law of conditional probabilities, we
know that - From the probability tree, we know that
- Event C can occur in only two ways (S ? C) and
(N ? C)
Posterior probability
Equation 1
Equation 2
56Bayes Theorem
Bayes Theorem (2 events)
57Bayes Theorem
- To find the posterior probability that event
Ai will - occur given that event B has occurred, we
apply - Bayes theorem.
- Bayes theorem is applicable when the events
for - which we want to compute posterior
probabilities - are mutually exclusive and their union is
the entire - sample space.
58Bayes Theorem, example
- A local bank reviewed its credit card policy with
the intention of recalling some of its credit
cards. In the past, approximately 5 of
cardholders defaulted, leaving the bank unable to
collect the outstanding balance. Hence,
management established a prior probability of .05
that any particular cardholder will default. The
bank also found that the probability of missing a
monthly payment is .20 for customers who do not
default. Of course, the probability of missing a
monthly payment for those who default is 1. - Given that a customer missed a monthly payment,
compute the posterior probability that the
customer will default.
59Bayes Theorem
- M missed payment
- D1 customer defaults
- D2 customer does not default
- P(D1) .05 P(D2) .95 P(MD2) .2
P(MD1) 1
60End of Chapter 4