Dilutions

1
Dilutions
2
Concentration and volume are inversely
proportional

• As the concentration of a solution increases the
  decreases and vice versa
• Concentration of the original solution times the
  volume of the original solution is equal to the
  concentration of the new solution times the
  volume of the new solution

3
C1V1 C2V2

• Example How much of a 5 molar stock solution
  would it take to make 200ml of a 2 molar
  solution?
• (5M)(V1) (2M)(200ml)
• 5M V1 200Mml
• V1 40ml

4
If it takes 250ml of a stock solution to prepare
400ml of a 3.6 m solution, what was the
concentration of the original solution?

• (C1)(250ml) (3.5m)(400ml)
• 250mlC1 1400mlm
• C1 5.6m

5
How would you prepare 200ml of a 2.5M solution of
hydrochloric acid from a 12M stock solution?

• (12M)(V1) (2.5M)(200ml)
• 12MV1 500Mml
• V1 41.7ml
• Thus you would mix 41.7ml of 12M HCl with 158.3ml
  of water

6
What would be the concentration of a solution of
sulfuric acid if it took 50ml of it to prepare
150ml of a 6N solution?

• C1 (50ml) (6N)(150ml)
• 50mlC1 900Nml
• C1 18N