Title: ELEG 840
1ELEG 840
- Lecture 8
- Professor Dennis W. Prather
2- Last Time
- Structure of a 2D FDTD program
- Stability in higher dimensions
- Derived the 3D FDTD formulation
- Today
- Equivalent medium parameters
- Ideal conducting sources
- Determination of steady state fields
- Transient sources
3- Equivalent Medium Parameters
- The discretization of Maxwells equations becomes
invalid at the boundary, or interface, between
two media. - In this case, we use special boundary conditions
to deal with this problem. - One simple method is to simply let all of the
cell be homogenous cubes ?ignore the interface. - A better method is to introduce an equivalent
medium parameter at the surface of scattering
object. - Once the medium is discretized, the boundaries,
or surfaces align perfectly with the boundaries
of the FDTD cells.
2
y
1
x
4- The E field components at each node are
tangential to the surface of the cells. - The H-Field components are normal to the surface
- ?Along x constant surface
- ?TE, 2D
- The arrangement of cells and surface is
consistent with the boundary conditions that the
E-field and normal B-field are continuous across
the boundary.
5 6Consider them across an x constant surface
Ey
z
Hz
Ez
Ez
y
Ex
Hx
Ex
Hy
x
Ey
Hy
Ey
Hz
2D Space
Ez
Ez
Hx
Ey
7- At one side of the surface, and at
the other side , so we need to decide
what value of we should use. - Therefore we make a table of modification to
at different constant surfaces
8Draw a two cell interface
z
y
x
x constant surface
9The corresponding form of (5) (1) medium
1 (2) medium 2 If we add these two equations,
we get
10- At the x constant surface, the tangential
Hz-field is continuous - Also, the normal Bx-field is continuous
11Combining, we get
12Substituting in we get This form must be
representative of Maxwells Equations
13Similar to two inductors in series. ?We can
follow a similar procedure to determine the
equivalent permitivity and conductivity
14This then requires that
Series capacitor
So the resulting expression is
This is the same as eqn. 5, but
15- Ideal Conducting Surfaces
- In a highly conducting media, there are two
common methods for dealing with this kind of
boundary. - The first way us to assume the surface to a PEC
- In this case, the tangential electric field
components are set equal to ZERO! - The second approach we use the medium parameters
for a real conductor. - For example, if the medium has mhos/m ?
copper - ? aluminum
- If the frequency is then the corresponding skin
depth
16- If the FDTD cell was
- Then the skin depth is only a small fraction of
the edge of one cell! - Determination of Steady State Fields
- One of the more significant advantages of the
FDTD is its ability to perform both steady state
and transient field analysis. - A steady state condition can be achieved using
the FDTD method by either Fourier transforming
the output response of the EM and the extracting
the frequency of interest. - ? Pulse based incident field
- ? Store 1N,
- As incident source use was a sinwave and let a
steady condition build up.
Frequency domain representations of E-field at
(i, j, k)
17- A key factor in achieving a steady state
condition is to time-step long enough to ensure
that all of the transient fields have decayed
away. - Typically, this requires 2-5 transient periods,
T5, which are defined as the number of time-steps
required for one cycle of the incident field to
transverse the maximum extent of the scattering
object.
T5
2-5 periods of this to reach s.s
x
18- In this case, the incident field is a sinusoidal
wave, having a frequency of the desired response. - Note that the source may also be different from a
plane wave. - In this approach the value of the E and the H
field components are zero at t 0, throughout
the entire computational domain. - Once introduced, the source as time marched
according to the Yee algorithm. - The question then arises how do we extract the
S.S. field in both amplitude and phases at each
node? - Generally speaking, there are three ways to do
this - 1. Peak value method
- 2. Quarter wave method
- 3. Least squares method
19t
- Peak Value Method
- In a steady state field, the derivative of the
field at its maximum value is 0, in other words,
the sign of the derivative on either side is
different. - Therefore, if we look at the field values at 3
consecutive time steps, fn-1, fn, fn1, we can
determine if we are at a maximum or not.
-
20- More succinctly as
- When at peak value that is the magnitude of the
frequency response at that point. - We can also determine the phase at any point in
computational region from the sinusoidal behavior
of the steady state field. - Consider the the scattered field at any point in
space can be written as - refers to the phase of the scattered field
relative to the origin of the computational
region. - If we let the time when the field is at a
positive peak be n?t, then we have
21t
t
T
2T
has a value between
22- Complex Quarter Wave Transform
- An alternate method for determining the amplitude
and phase of the steady state field is to sample
the field at a particular node for a given
instant in time. - By doing this, we can define the electric field
as - If we now sample the same node at a given number
of time steps, later, ?n, we have - If we chose (which
corresponds to a quarter wave delay) then we have - We can combine E1 anf E2 to form a complex field
value.
Embers Formula
23- So we divide both sides by (we know this value
tn?t) - We can uniquely determine both
- Least Squares Fit Method
- In contrast to the two previous methods, this
method offers unlimited precision or accuracy. - This method stores the field values at selected
nodes for a given number of steady state cycles.
I
peak
24- Note that the data only has to be stored during
the remaining steady state cycles. - Once the field values have been stored, once can
extract the magnitude and phase according to the
following algorithm - We first note the filed at any node can be
written as a sinusoidal field with a magnitude c,
and phase - Using trigonometric identities, we can rearrange
this as - where
- Using the FDTD method, we can store the values of
- for the last few cycles of time marching.
25- Now using a least squares approach, we can find
the values of A and B that minimize the error
between - To minimize this we perform
- 1)
- 2)
- Where
- As a result
26- And
- Using this to form a system of equations, we have
27Then simply invert the 2 x 2 matrix and solve for
A B ? C Ø