ELEG 840 - PowerPoint PPT Presentation

1 / 27
About This Presentation
Title:

ELEG 840

Description:

NONE. NONE. 3. NONE. Change . NONE. 2. NONE. NONE. Change . 1. z=constant. y=constant. x=constant. Draw a two cell interface: ... – PowerPoint PPT presentation

Number of Views:47
Avg rating:3.0/5.0
Slides: 28
Provided by: dennisw
Category:
Tags: eleg | none

less

Transcript and Presenter's Notes

Title: ELEG 840


1
ELEG 840
  • Lecture 8
  • Professor Dennis W. Prather

2
  • Last Time
  • Structure of a 2D FDTD program
  • Stability in higher dimensions
  • Derived the 3D FDTD formulation
  • Today
  • Equivalent medium parameters
  • Ideal conducting sources
  • Determination of steady state fields
  • Transient sources

3
  • Equivalent Medium Parameters
  • The discretization of Maxwells equations becomes
    invalid at the boundary, or interface, between
    two media.
  • In this case, we use special boundary conditions
    to deal with this problem.
  • One simple method is to simply let all of the
    cell be homogenous cubes ?ignore the interface.
  • A better method is to introduce an equivalent
    medium parameter at the surface of scattering
    object.
  • Once the medium is discretized, the boundaries,
    or surfaces align perfectly with the boundaries
    of the FDTD cells.

2
y
1
x
4
  • The E field components at each node are
    tangential to the surface of the cells.
  • The H-Field components are normal to the surface
  • ?Along x constant surface
  • ?TE, 2D
  • The arrangement of cells and surface is
    consistent with the boundary conditions that the
    E-field and normal B-field are continuous across
    the boundary.

5
  • To see this consider

6
Consider them across an x constant surface
Ey
z
Hz
Ez
Ez
y
Ex
Hx
Ex
Hy
x
Ey
Hy
Ey
Hz
2D Space
Ez
Ez
Hx
Ey
7
  • At one side of the surface, and at
    the other side , so we need to decide
    what value of we should use.
  • Therefore we make a table of modification to
    at different constant surfaces

8
Draw a two cell interface
z
y
x
x constant surface
9
The corresponding form of (5) (1) medium
1 (2) medium 2 If we add these two equations,
we get
10
  • At the x constant surface, the tangential
    Hz-field is continuous
  • Also, the normal Bx-field is continuous

11
Combining, we get
12
Substituting in we get This form must be
representative of Maxwells Equations
13
Similar to two inductors in series. ?We can
follow a similar procedure to determine the
equivalent permitivity and conductivity
14
This then requires that
Series capacitor
So the resulting expression is
This is the same as eqn. 5, but
15
  • Ideal Conducting Surfaces
  • In a highly conducting media, there are two
    common methods for dealing with this kind of
    boundary.
  • The first way us to assume the surface to a PEC
  • In this case, the tangential electric field
    components are set equal to ZERO!
  • The second approach we use the medium parameters
    for a real conductor.
  • For example, if the medium has mhos/m ?
    copper
  • ? aluminum
  • If the frequency is then the corresponding skin
    depth

16
  • If the FDTD cell was
  • Then the skin depth is only a small fraction of
    the edge of one cell!
  • Determination of Steady State Fields
  • One of the more significant advantages of the
    FDTD is its ability to perform both steady state
    and transient field analysis.
  • A steady state condition can be achieved using
    the FDTD method by either Fourier transforming
    the output response of the EM and the extracting
    the frequency of interest.
  • ? Pulse based incident field
  • ? Store 1N,
  • As incident source use was a sinwave and let a
    steady condition build up.

Frequency domain representations of E-field at
(i, j, k)
17
  • A key factor in achieving a steady state
    condition is to time-step long enough to ensure
    that all of the transient fields have decayed
    away.
  • Typically, this requires 2-5 transient periods,
    T5, which are defined as the number of time-steps
    required for one cycle of the incident field to
    transverse the maximum extent of the scattering
    object.

T5
2-5 periods of this to reach s.s
x
18
  • In this case, the incident field is a sinusoidal
    wave, having a frequency of the desired response.
  • Note that the source may also be different from a
    plane wave.
  • In this approach the value of the E and the H
    field components are zero at t 0, throughout
    the entire computational domain.
  • Once introduced, the source as time marched
    according to the Yee algorithm.
  • The question then arises how do we extract the
    S.S. field in both amplitude and phases at each
    node?
  • Generally speaking, there are three ways to do
    this
  • 1. Peak value method
  • 2. Quarter wave method
  • 3. Least squares method

19
t
  • Peak Value Method
  • In a steady state field, the derivative of the
    field at its maximum value is 0, in other words,
    the sign of the derivative on either side is
    different.
  • Therefore, if we look at the field values at 3
    consecutive time steps, fn-1, fn, fn1, we can
    determine if we are at a maximum or not.



-

20
  • More succinctly as
  • When at peak value that is the magnitude of the
    frequency response at that point.
  • We can also determine the phase at any point in
    computational region from the sinusoidal behavior
    of the steady state field.
  • Consider the the scattered field at any point in
    space can be written as
  • refers to the phase of the scattered field
    relative to the origin of the computational
    region.
  • If we let the time when the field is at a
    positive peak be n?t, then we have

21
t
t
T
2T
has a value between
22
  • Complex Quarter Wave Transform
  • An alternate method for determining the amplitude
    and phase of the steady state field is to sample
    the field at a particular node for a given
    instant in time.
  • By doing this, we can define the electric field
    as
  • If we now sample the same node at a given number
    of time steps, later, ?n, we have
  • If we chose (which
    corresponds to a quarter wave delay) then we have
  • We can combine E1 anf E2 to form a complex field
    value.

Embers Formula
23
  • So we divide both sides by (we know this value
    tn?t)
  • We can uniquely determine both
  • Least Squares Fit Method
  • In contrast to the two previous methods, this
    method offers unlimited precision or accuracy.
  • This method stores the field values at selected
    nodes for a given number of steady state cycles.

I
peak
24
  • Note that the data only has to be stored during
    the remaining steady state cycles.
  • Once the field values have been stored, once can
    extract the magnitude and phase according to the
    following algorithm
  • We first note the filed at any node can be
    written as a sinusoidal field with a magnitude c,
    and phase
  • Using trigonometric identities, we can rearrange
    this as
  • where
  • Using the FDTD method, we can store the values of
  • for the last few cycles of time marching.

25
  • Now using a least squares approach, we can find
    the values of A and B that minimize the error
    between
  • To minimize this we perform
  • 1)
  • 2)
  • Where
  • As a result

26
  • And
  • Using this to form a system of equations, we have

27

Then simply invert the 2 x 2 matrix and solve for
A B ? C Ø
Write a Comment
User Comments (0)
About PowerShow.com