Title: CHEM 1405
1CHEM 1405
2Assignments and Reminders
- Reading Assignment
- Chapter 12 by Thursday April 20th
- Homework Problems due Thursday Apr 20th
- Chapter 10 even numbered Problems 2-8 and
1830, 36, 38, 42-50 - Class website
http//iws.ccccd.edu/jstankus/
Please use only one side of the page when
submitting Homework
3Chemistry Help Resources
- My office hours
- Tuesdays after class in Lecture room
- Thursdays 1-2 in Math Lab
- Free Tutoring through college
- Students must submit a tutor request form in
order to receive detailed information about the
available tutoring services. The form is
available on Collin's website and in the
following offices - CPC room A108 (ask for Sonia Castillo)
- PRC room F109 (ask for Shontel Penny or Mary
Eldridge) - SCC rooms G200 and G141
- There are group tutoring services available for
the following courses (SUBJECT TO CHANGE!) - CHEM 1405, 1411, 1412, 2423,
-
- Also available will be online tutoring in the
following courses (SUBJECT TO CHANGE!) - CHEM 1412 below
4Objectives
- What is meant by the ionization constant for a
weak acid or weak base? - How can we calculate the concentration of
hydrogen ion from an ionization constant and a
given concentration of a weak acid or weak base? - What is a buffer? How does a buffer work?
- How does the body maintain the pH of blood and
other fluids? - How can we use the Henderson-Hasselbalch equation
to calculate the pH of a buffer?
5Equilibrium Calculations
- The ionization of a weak acid or base is a
reversible reaction - Typically reaches equilibrium when only a small
percentage of molecules have ionized.
We will now treat these equilibria in a more
quantitative fashion
6Equilibrium Constant Expressions
Coefficients
a A(g) b B(g) c C(g) d D(g)
Products
Reactants
Equilibrium Constant
Remember C is molar concentration of C
7Equilibrium Constant Example
8Equilibrium Constant Example
9Ionization of Weak Acids
At equilibrium
Ka
This is the Acid Ionization constant, Ka
10Acid Ionization Constant Example
- Calculate the H in a 0.10 M solution of acetic
acid
1.8 x 10-5
From table 10.1
From the balanced equation We know that H
CH3COO- x Therefore CH3COOH 0.10
M - x
11Acid Ionization Constant Example (cont)
1.8 x 10-5
Substituting into the equilibrium constant
expression
Since only a very small amount of acetic acid is
ionized 0.10-x 0.10
x2 1.8 x 10-6
Solving for x
H
x 1.3 x 10-3
Need to check assumptions
12Acid Ionization Constant Example (cont)
Checking assumptions
We assumed that 0.10 x 0.10 with
that assumption we calculated x to be
0.0013 0.10 0.0013 0.10 to two significant
figures Our assumption is good
13Ionization of Weak Bases
At equilibrium
Since only a small amount of water reacts its
concentration is assumed constant
This is the base Ionization constant, Kb
14Base Ionization Constant Example
- Calculate the OH- in a 0.010 M solution of
aniline
4.2 x 10-10
From table 10.2
From the balanced equation We know that OH-
C6H5NH3 x Therefore C6H5NH3
0.010 M x 0.010 M
15Base Ionization Constant Example
Substituting into the base ionization expression
4.2 x 10-10
x2 4.2 x 10-12
x 2.0 x 10-6 M OH-
16Salts in Water
- Recall that an acid reacting with a base forming
a salt is called a neutralization reaction - Not all salt solutions are neutral
- The equilibria will determine if the solution is
acidic, basic or neutral
17Salts in Water Acidic, Basic or Neutral
Prediction rules
- The salt of a strong acid and a strong base forms
a neutral solution. - The salt of a strong acid and a weak base forms
an acidic solution. - The salt of a weak acid and a strong base forms a
basic solution. - The salt of a weak acid and a weak base may form
an acidic, basic, or (by chance) neutral solution.
18Acids and Bases added to pure Water
19Buffers Control of pH
- A buffer solution is one in which the pH remains
nearly constant even if acid or base is added.
20Buffer solutions
- A buffer solution is a solution containing a weak
acid and its salt, or a weak base and its salt. - Small quantities of added acid are neutralized by
one buffer component and small quantities of
added base by the other. - As a result, the solution pH is maintained nearly
constant.
21How Buffers work
- Application of Le Chateliers Principle
22Common Buffer Solutions
23Common Ion Effect
Adding Acetate Ions Shifts equilibrium to left
- The common ion effect refers to the ability of
ions from a strong electrolyte to repress the
ionization of a weak acid or weak base or the
solubility of a slightly soluble substance
24Common Ion Effect Example
- What is the H in a solution that is 0.10 M
acetic acid and 0.10 M sodium acetate?
Let x H Sodium acetate is totally
ionized CH3COO- 0.10 x CH3COOH
0.10 - x
Assume x ltlt 0.10
x H 1.8 x 10-5
25pH of Buffer Solutions
Manipulating the equilibrium expression
Where pKa -log(Ka)
This is the Henderson-Hasselbalch equation
26Henderson-Hasselbalch Equation Example
- What is the pH of a solution that is 0.20 M H2S
and 0.20 M HS-?
The Ka 1 x 10-7 for H2S
27Henderson-Hasselbalch Equation Example
- What is the pH of a solution that is 0.10 M HCN
and 0.50 M NaCN?
The Ka 6.2 x 10-10 for HCN
28Buffer Capacity
- There are limits to how much acid or base a
buffer can handle - Generally related to the concentration of the
buffer components - Rule of thumb
- Effective pH range of a buffer is about
- pH pKa1
29Buffers in Blood
- Blood Plasma normally varies from 7.35 to 7.45 in
pH - Blood pH gt 7.8 or lt 6.8 will do irreversible
damage to the brain - Blood pH lt 7.35 is acidosis
- Blood pH gt 7.45 is alkalosis
- Body has at least three buffer systems to
maintain the proper pH
30Buffers in Blood
Bicarbonate/carbonic Acid system
Dihydrogen Phosphate/Monohydrogen Phosphate system
Protein system
31Lactic Acid in Muscles
- Muscle contractions produce lactic acid
- This can lower blood pH
- Blood Buffers
- Work hard enough can overload buffers