Physics 221 Chapter 6 - PowerPoint PPT Presentation

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Physics 221 Chapter 6

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A red car goes counterclockwise around a track at a constant speed (see figure) A. The car is accelerating and Q shows the direction of the force on it ... – PowerPoint PPT presentation

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Title: Physics 221 Chapter 6


1
Physics 221Chapter 6
2
Problem 1 . . . Round and round
  • A red car goes counterclockwise around a track at
    a constant speed (see figure)
  • A. The car is accelerating and Q shows the
    direction of the force on it
  • B. The car is accelerating and P shows the
    direction of the force on it
  • C. The car is not accelerating
  • D. The car is accelerating but there is no force
    acting on it.

3
Solution 1 . . . Round and round
  • A red car goes counterclockwise around a track at
    a constant speed (see figure)
  • A. The car is accelerating and Q shows the
    direction of the force on it.
  • Centripetal Force changes the direction
  • Centripetal Force does not change speed
  • Centripetal Force points toward the center

4
Problem 2 . . . Equation for C.F.
  • The correct equation for centripetal force is
  • A. F mv
  • B. F mvr
  • C. F mv / r
  • D. F mv2 / r

5
Solution 2 . . . Equation for C.F.
  • The correct equation for centripetal force is
  • F mv2 / r

6
Problem 3 . . . Stoned and strung
  • Dennis the menace ties a 250 g rock to a 160 cm.
    string and whirls it above his head. The string
    will break if the tension exceeds 90 N. What
    minimum speed will endanger the windshield on his
    neighbors car?

7
Solution 3 . . . Dennis the Menace
  • Centripetal Force is F mv2 / r
  • 90 (0.25)(v2 / 1.6 )
  • v 24 m/s

8
Problem 4 . . . Slippery when wet!
  • A car exits on a ramp (unbanked) of radius 20 m.
    The coefficient of friction is 0.6. The maximum
    speed before slipping starts is most nearly
  • A. 10 m/s
  • B. 20 m/s
  • C. 40 m/s
  • D. 120 m/s

9
Solution 4 . . . Slippery when wet!
  • Force of Friction Centripetal force
  • (0.6)(m)(g) (m)(v2) / r
  • v 11 m/s

10
Problem 5 . . . Spaced out!
  • Residents in a colony in outer space live in a
    cylindrical spaceship that has a diameter of 90 m
    and its speed at the rim is 15 m/s. The
    simulated g felt by the occupants is most
    nearly
  • A. 0.5 g
  • B. 1.0 g
  • C. 2.0 g
  • D. 5 g

11
Solution 5 . . . Spaced out!
  • (m)(v2) / r m g
  • g v2 / r
  • g (15)(15)/45
  • g 5 m/s2
  • g 0.5 g
  • Correct answer is A.

12
Satellites
  • Many LEO (Low Earth Orbit) satellites are fairly
    close to the Earth. There is substantial g out
    there. Yet people feel weightless! This has
    to do with free-fall like when you are in an
    elevator and it accelerates down.
  • Problem 8 How much would a 120 lb woman feel
    she weighs in an elevator decelerating at 2 m/s2 ?

13
Satellites
  • Solution8 F ma
  • mg - T ma
  • T mg - ma
  • T 12 x 10 - 12 x 2
  • T 120 - 24
  • T 96 lbs.
  • Note Satellites are in free-fall so the
    occupants feel weightless!

a
14
Air Drag
  • Free-fall acceleration is g 9.8 m/s2. However,
    if air resistance is taken into account then the
    acceleration keeps decreasing as the objects
    speed keeps increasing. This is because the
    resistive force of air drag increases as the
    speed increases. When the resistive force
    becomes equal to the force of gravity (weight)
    the object attains a constant speed. This final
    constant speed is called Terminal Velocity.

15
What does drag depend on?
  • Air Resistance (drag) is generally proportional
    to the square of the speed
  • R Cv2
  • R ½ D ? A v2
  • R resistive force
  • D Drag coefficient (0.5 to 2)
  • ? density of air
  • A cross-sectional area
  • Generally in a liquid, the resistance is
    proportional to the speed
  • R - bv

16
  • Thats all Folks!
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