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Quantum Mechanics 102

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... from two points, such as waves passing through two slits, will interfere ... Only electrons with energies equal to the energy state in the well will get through ... – PowerPoint PPT presentation

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Title: Quantum Mechanics 102


1
Quantum Mechanics 102
  • Tunneling and its Applications

2
Interference of Waves and the Double Slit
Experiment
  • Waves spreading out from two points, such as
    waves passing through two slits, will interfere

l
Wave crest Wave trough
Spot of constructive interference Spot of
destructive interference
d
3
Interpretation
  • The probability of finding a particle in a
    particular region within a particular time
    interval is found by integrating the square of
    the wave function
  • P (x,t) ? Y(x,t)2 dx ? c(x)2 dx
  • c(x)2 dx is called the probability density
    the area under a curve of probability density
    yields the probability the particle is in that
    region
  • When a measurement is made, we say the wave
    function collapses to a point, and a particle
    is detected at some particular location

4
Particle in a box
  • c(x) B sin (npx/a)

n3
c(x)
c(x)2
n2
  • Only certain wavelengths l 2a/n are allowed
  • Only certain momenta p h/l hn/2a are allowed
  • Only certain energies E p2/2m h2n2/8ma2 are
    allowed - energy is QUANTIZED
  • Allowed energies depend on well width

5
What about the real world?
  • Solution has non-trivial form, but only certain
    states (integer n) are solutions
  • Each state has one allowed energy, so energy is
    again quantized
  • Energy depends on well width a
  • Can pick energies for electron by adjusting a

c(x)2
n2
n1
x
6
Putting Several Wells Together
  • How does the number of energy bands compare with
    the number of energy levels in a single well?
  • As atom spacing decreases, what happens to energy
    bands?
  • What happens when impurities are added?

7
Quantum wells
  • An electron is trapped since no empty energy
    states exist on either side of the well

8
Escaping quantum wells
  • Classically, an electron could gain thermal
    energy and escape
  • For a deep well, this is not very probable

9
Escaping quantum wells
  • Thanks to quantum mechanics, an electron has a
    non-zero probability of appearing outside of the
    well
  • This happens more often than thermal escape

10
What if free electron encounters barrier?
  • Do Todays Activity

11
What Have You Seen?
  • What happens when electron energy is less than
    barrier height?
  • What happens when electron energy is greater than
    barrier height?
  • What affects tunneling probability?
  • T ? e2kL
  • k 8p2m(Epot E)½/h

12
A classical diode
  • According to classical physics, to get to the
    holes on the other side of the junction, the
    conduction electrons must first gain enough
    energy to get to the conduction band on the
    p-side
  • This does not happen often once the energy
  • barrier gets large
  • Applying a bias increases
  • the current by decreasing
  • the barrier

13
A tunnel diode
  • According to quantum physics, electrons could
    tunnel through to holes on the other side of the
    junction with comparable energy to the electron
  • This happens fairly often
  • Applying a bias moves the
  • electrons out of the p-side
  • so more can tunnel in

14
Negative resistance
  • As the bias is increased, however, the energy of
    the empty states in the p-side decreases
  • A tunneling electron would then end up in the
    band gap - no allowed energy
  • So as the potential difference is increased, the
    current actually decreases negative R

15
No more negative resistance
  • As bias continues to increase, it becomes easier
    for conduction electrons on the n-side to
    surmount the energy barrier with thermal energy
  • So resistance becomes positive again

16
The tunneling transistor
  • Only electrons with energies equal to the energy
    state in the well will get through

17
The tunneling transistor
  • As the potential difference increases, the energy
    levels on the positive side are lowered toward
    the electrons energy
  • Once the energy state in the well equals the
    electrons energy, the electron can go through,
    and the current increases.

18
The tunneling transistor
  • The current through the transistor increases as
    each successive energy level reaches the
    electrons energy, then decreases as the energy
    level sinks below the electrons energy

19
Randomness
  • Consider photons going through beam splitters
  • NO way to predict whether photon will be
    reflected or transmitted!

(Color of line is NOT related to actual color of
laser all beams have same wavelength!)
20
Randomness Revisited
  • If particle/probabilistic theory correct, half
    the intensity always arrives in top detector,
    half in bottom
  • BUT, can move mirror so no light in bottom!

(Color of line is NOT related to actual color of
laser all beams have same wavelength!)
21
Interference effects
  • Laser light taking different paths interferes,
    causing zero intensity at bottom detector
  • EVEN IF INTENSITY SO LOW THAT ONE PHOTON TRAVELS
    THROUGH AT A TIME
  • What happens if I detect path with bomb?

No interference, even if bomb does not detonate!
22
Interpretation
  • Wave theory does not explain why bomb detonates
    half the time
  • Particle probability theory does not explain why
    changing position of mirrors affects detection
  • Neither explains why presence of bomb destroys
    interference
  • Quantum theory explains both!
  • Amplitudes, not probabilities add - interference
  • Measurement yields probability, not amplitude -
    bomb detonates half the time
  • Once path determined, wavefunction reflects only
    that possibility - presence of bomb destroys
    interference

23
Quantum Theory meets Bomb
  • Four possible paths RR and TT hit upper
    detector, TR and RT hit lower detector
    (Rreflected, Ttransmitted)
  • Classically, 4 equally-likely paths, so prob of
    each is 1/4, so prob at each detector is 1/4
    1/4 1/2
  • Quantum mechanically, square of amplitudes must
    each be 1/4 (prob for particular path), but
    amplitudes can be imaginary or complex!
  • e.g.,

24
Adding amplitudes
  • Lower detector
  • Upper detector

25
What wave function would give 50 at each
detector?
  • Must have a b c d 1/4
  • Need a b2 cd2 1/2
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