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METO 621

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... the medium is optically thin, i.e. t(P2) 1 then the second term becomes B t(P2) ... The half-range intensities are defined by: ... – PowerPoint PPT presentation

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Title: METO 621


1
METO 621
  • Lesson 9

2
Solution for Zero Scattering
  • If there is no scattering, e.g. in the
    thermal infrared, then the equation becomes
  • This equation can be easily integrated using
    an integrating factor et

3
Solution for Zero Scattering
4
Solution for Zero Scattering
  • Consider a straight path between point P1 and
    P2 . The optical path from P1 to an intermediate
    point P is given by
  • Integrating along the path from P1 to P2

5
Solution for Zero Scattering
  • Dividing through by et(P2) we get
  • But what does this equation tell us about
    the physics of the problem?

6
Physical Description
7
Solution for Zero Scattering
  • Break up the path from P1 to P2 into small
    elements ds with optical depths d?
  • When sn is zero then en is equal to 1
  • Hence dtB is the blackbody emission from the
    element ds
  • The intensity at P1 is It(P1)
  • This intensity will be absorbed as it moves from
    P1 to P2 , and the intensity at P2 will be
    It(P1)exp-(t(P2)-t(P1)

8
Solution for Zero Scattering
  • Now consider each small element P with a Dt, with
    an optical depth t
  • Emission from each element is BDt
  • The amount of this radiation that reaches P2 is B
    Dt exp-t(P,P2) where t is the optical depth
    between P and P2
  • Hence the total amount of radiation reaching P2
    from all elements is

9
Isothermal Medium Arbitrary Geometry
If the medium is optically thin, i.e. t(P2) ltlt1
then the second term becomes B t(P2). If there
is no absorption or scattering then t0 and the
intensity in any direction is a constant, i.e.
It(P2)It(P1)
10
Isothermal Medium Arbitrary Geometry
  • If we consider the case when tgtgt1 then the total
    intensity is equal to B(T). In this case the
    medium acts like a blackbody in all frequencies,
    i.e. is in a state of thermodynamic equilibrium.
  • If ones looks toward the horizon then in a
    homogeneous atmosphere the atmosphere has a
    constant temperature. Hence the observed
    intensity is also blackbody

11
Zero Scattering in Slab Geometry
  • Most common geometry in the theory of radiative
    transfer is a plane-parallel medium or a slab
  • The vertical optical path (optical depth) is
    given the symbol t as distinct from the slant
    optical path ts
  • Using z as altitude t(z) ts cosq ts m
  • The optical depth is measured along the vertical
    downward direction, i.e. from the top of the
    medium

12
Half-range Intensities
13
Half-Range Quantities in Slab Geometry
  • The half-range intensities are defined by
  • Note that the negative direction is for the
    downward flux,

14
Half-Range Quantities in Slab Geometry
  • The radiative flux is also defined in terms of
    half-range quantities.

15
Half Range Quantities
  • In the limit of no scattering the radiative
    transfer equations for the half-range intensities
    become

16
Formal Solution in Slab Geometry
  • Choose the integrating factor e t/m,, for the
    first equation, then
  • This represents a downward beam so we
    integrate from the top of the atmosphere (t0)
    to the bottom (tt).

17
Slab geometry
18
Slab Geometry
  • For an interior point, t lt t , we integrate
    from 0 to t. The solution is easily found by
    replacing t with t
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