Title: Ideal Analysis Aircraft Gas Turbine Engine
1Ideal Analysis Aircraft Gas Turbine Engine
2Numbering of turbine engines
0 2 3 4
5
intake compressor burner
turbine afterburner (AB) nozzle (n)
(diffuser)
(e.g., turbofan)
3Thrust Equation
Take a step back
D
Apply the momentum equation to the steady flow
through c.v. (forces time rate of change of
momentum)
P0 V0 A0
P9 V9 A9
Finternal
9
0
2
by convention use gauge pressures (pressure
referenced to Po)
4Thrust Eqn.
- Subtract Drag Force acting on the external
surface to get net thrust (T Fint D) - The drag is obtained by integrating the pressure
over the external surface, i.e.,
5Lets outline some NOTATIONthat is used to
characterize gas turbines
6Total Temperature and Total Pressure
- The total temperature and pressure are the values
reached when a steadily flowing fluid is brought
to rest (stagnated) adiabatically reversibly
(i.e., isentropically) - Tt total temperature T static temperature V
flow velocity the 1st law of thermodynamics for
perfect gas gives - Introduce, get
- Stagnation (Total) Pressure
- From compressible flow
- (isentropic process)
from before
7Steady flow eqn (energy egn) in absence of
g-effects (No PE)
From previous lecture
Stagnation or total enthalpy ht hV2/2
1st law
For calorically perfect gas
Stagnation or total temperature Tt TV2/2cp
Divide by cp
Static Temperature
8Total/Static Temperature Ratio and Pressure Ratio
of the Freestream (Inlet)
1
2
define tl as ratio of the burner exit
enthalpy, ht,burner exit cpTt to the ambient
enthalpy hocp,oTo
3
9Ratios across component i
- Ratio of total temperatures across a component
ti - Ratio of total pressures across a component pi
-
- where i d diffuser (intake), c compressor,
b burner, t turbine, n nozzle, f fan
10Temperature and Pressure Component Relations
11Steps to Engine Cycle Analysis
- Objective Want to know how the engine
performance (specific thrust fuel consumption)
varies with changes in - flight conditions (Mach number),
- design limits (burner exit temp),
- component performance (turbine efficiency),
- design choices (compressor pressure ratio)
- Rewrite the thrust equation in terms of total
pressure and total temperature ratios, ambient
pressure Po temperature To speed of sound
ao flight Mach number Mo
12Steps to Engine Cycle Analysis
- Calculate as f(M, Ts, gas properties)
freestream
13Steps to Engine Cycle Analysis
from comp. flow
14Steps to Engine Cycle Analysis
- Apply 1st law of thermodynamics to the combustor
(adiabatic, no work done) - Evaluate the specific thrust
- Evaluate the thrust specific fuel consumption S
for the specific thrust and fuel-to-air ratio
(f) - Evaluate thermal and propulsion efficiencies.
15Assumptions
- Compression and expansion cycles are reversible
and adiabatic (isentropic) in compressor,
turbine, inlet (diffuser), nozzle. - Constant Pressure Combustion fuel flow rate
small relative to air flow rate - Air is perfect gas with constant specific heat
- Exhaust nozzle expands gas to ambient pressure
(Pe (?P9) Po)
16Ramjet (Ideal - Simplest)
1. Intake (Diffuser) Slows air from flight speed
V0 to V2 (P2 T2 increase)
3. Gas expansion to ambient pressure Temp.
decrease to T9
2. Conversion from chemical to thermal
energy (increases T4)
17T-s diagram of ideal ramjet
T
Tt4, Tt9
heat in
expansion
Tto, Tt2
T9
compression
heat rejected
To
0
s
18Apply the steps
1
with P9Po and
2
with g9 g0 g and R9 R0R (for ideal cycle,
no
composition change)
(will need T9/To later)
19Apply the steps
3
Nozzle outlet to inlet
Total/static freestream
Combustor outlet to inlet
Diffuser outlet to inlet
thus, or
Recall,
20Apply the steps
4
thus,
recall,
21Apply the steps
5
Application of first law of thermo to cv about
the burner
Combustor
2 4
heat of reaction
where cp2cp4 cp
(needed to evaluate f)
22Apply the steps
and Tto Tt2 Totr
thus
and Tt4/Tt2 tb
and use
rewrite
23Apply the steps
7
Evaluate specific thrust
1
1
from steps 2,3,4
24Apply the steps
8
Evaluate specific fuel consumption S
step 5
step 7
9
Efficiencies (left to you)
Thermal Propulsion Overall
25Summary
INPUTS Mo, To (K), g, cp (kJ/kg.K), hPR (KJ/kg),
Tt4 (K) OUTPUTS
(N/(kg/s)), f, S ((kg/s)/N), hT, hP, hO
26Example Performance vs M
- To217K
- g1.4
- cp1.004 kJ/(kgK)
- hPR42800kJ/kg
- Tt41600-2200K
27Specific Thrust vs Mo
28Specific Fuel Consumption vs Mo
29Fuel/air ratio (f) vs Mo
30Efficiencies vs Mo