Title: The Tale of the Tape
1The Tale of the Tape
- Measuring Pond Surface Area and Volume for
Stocking and Chemical ApplicationsBilly
Higginbotham - Professor and Extension Wildlife and Fisheries
Specialist - Texas Cooperative Extension
2How Big is Your Pond?
- Its a 2,000 yard pond.
- My ponds pretty small.
- Its about an acre, I guess.
- My ponds real big.
3Why Measure?
- Surface area
- Fish stocking
- Carrying capacity
- A few chemical applications
- Volume - most chemical applications
4What Do I Measure?
- Surface area in acres
- Volume in acre-feet
5So What is an Acre?
- 1 surface acre 43,560 square feetEquivalent
to a square 209 x 209 a circle 235
across
6How Do I Measure Surface Area?
- Pace it off
- Tape measure
- Range finders
- Aerial photos
- Geographic Information Systems (GIS)
7Determining Surface Area
- Three basic pond shapes
- Square or rectangular
- Triangular
- Circular
- (or a combination of 2 of the 3)
8Area of a Square or Rectangle
Length
Width
9An Acre-foot of Water is
- 1 surface acre 1 foot deep
- 43,560 cubic feet
- 326,000 gallons
10Determining Pond Volume
- Pond Volume surface area (acres) x
- average depth (feet)
11How Do I Measure Depth?
- Guess!
- Depth finder
- Calibrated rope and anchor
- Calibrated pole
12Measuring Pond Depth
- Take at least 2 perpendicular transects
- Begin at one bank with zero and end with zero
- The more transects and depth soundings taken, the
better your depth estimate becomes - Average depth is always LESS than you suspected
BM (Before Measuring)!
13Measuring Depth
x
x
x
x
x
x x x x x x x x x x
x x x x x x x x x x x x x x x x x
x
x
x
x
x
x
x
14Determining Average Depth
- Average depth sum of soundings
- (feet) ? number of soundings
- Transect 1 - 0,2,3,6,6,8,7,5,3,1,0
- Transect 2 - 0,1,1,1,3,4,8,6,6,4,1,0
- 76 feet ? 23 3.3 feet
15Determining Average Depth
- If you do not include zeros
- Transect 1 - 2,3,6,6,8,7,5,3,1
- Transect 2 - 1,1,3,4,8,6,6,4,1
- 76 feet ? 19 4.0 feet
16Determining Surface Area in Acres
- Square or Rectangular Pond
- Length (ft.) x Width (ft.) ? 43,560Acres
17Determining Surface Area in Acres
- Square or Rectangular Pond
- Length (ft.) x Width (ft.) ? 43,560Acres
- Example Pond is 200 x 350 70,000 square
feet - 70,000 ? 43,560 1.6 surface acres
18Determining Volume in Acre-Feet
- Square or Rectangular Pond
- Example pond is 200 x 350 70,000 square
feet - 70,000 ? 43,560 1.6 acres
- Average depth 3.2 feet
- 1.6 acres x 3.2 feet 5.1 acre-feet of water
19Determining Surface Area in Acres
- Triangular Pond1/2 base (ft.) x height (ft.) ?
43,560 acres
20Area of a Triangle
Base
Height
21Determining Surface Area in Acres
- Triangular Pond1/2 base (ft.) x height (ft.) ?
43,560 acres - Example pond is 200 along the dam x 500
to upper end - 1/2 (200 x 500) ? 43,560 1.1
surface acres
22Measuring Depth
x
x x x x x x x x x
x
x x x x x x
x x
x
23Determining Volume in Acre-Feet
- Triangular Pond
- Example pond averages 4.2 feet deep and is 200
along the dam x 500 to upper end - 1/2 (200 x 500) 50,000 ? 43,560
- 1.1 surface acres
- 1.1 surface acres x 4.2 feet
- 4.6 acre-feet of water
24Determining Surface Area in Acres
- Circular Pond ? x (radius)2 ? 43,560 acres
? is the ratio of the pond circumference to the
pond diameter and approximates 3.14The pond
radius is 1/2 of the pond diameter
25Determining Surface Area in Acres
- Circular Pond ? x (radius)2 ? 43,560 acres
- Example Pond is 150 across the middle
(diameter) - ? 3.14 and radius 75, so
- 3.14 x (75)2 ? 43,560 0.41 acres
26Area of a Circle
Radius
27Area of a Circle
Diameter
28Measuring Depth
x
x x
x x x x x x x x x x x x x x x
x
x x
x x
x
29Determining Volume in Acre-Feet
- Circular Pond
- Example pond averages 3.9 feet deep and is 150
across the middle (diameter) - 3.14 x (75)2 ? 43,560
- 17,662.5 ? 43,560 0.41 acres
- 0.41 acres x 3.9 feet 1.6 acre-feet of water
30Pond Math
- My pond is 0.5 surface acres and averages 4 feet
deep. How much powdered 5 Rotenone do I need to
apply at the recommended rate of 10 pounds per
acre-foot of water to kill my fish so I can
re-stock?
31Pond Math
- My pond is 0.5 surface acres and averages 4 feet
deep. How much powdered 5 Rotenone do I need to
apply at the recommended rate of 10 pounds per
acre-foot of water to kill my fish so I can
re-stock? - 0.5 surface acres x 4 feet deep 2 acre-feet
- 2 acre-feet of water x 10 lbs Rotenone per
acre-foot 20 lbs of Rotenone needed
32Pond Math
- Information from Texas Cooperative Extension
states that I can stock 1,000 catfish per surface
acre if I feed 5-7 days per week from April
through October. How many catfish should I order
for my triangle-shaped pond that is 125 feet
across at the dam and 200 feet long from the dam
to the upper end?
33Pond Math
- Information from Texas Cooperative Extension
states that I can stock 1,000 catfish per surface
acre if I feed 5-7 days per week from April
through October. How many catfish should I order
for my triangle-shaped pond that is 125 feet
across at the dam and 200 feet long from the dam
to the upper end? - 1/2 b x h 1/2 (125 x 200)
- 12,500 ? 43,560 0.29 surface acres
- 1,000 fingerlings per acre x 0.29 acres 290
fingerlings
34Pond Math
- I have a pond that is a rectangle on one side
connected by a culvert under my driveway to a
triangular shaped upper end. The rectangle side
is 100 feet by 150 feet and the average depth is
6.2 feet. The triangle is 100 feet along the
driveway and runs up into a neck 75 feet from the
driveway and average depth is only 3.0 feet. How
much copper sulfate do I need to apply at 2
pounds per acre-foot of water to kill the
filamentous algae covering the entire pond?
35Rectangular Side
- 100 x 150 15,000
- 15,000 ? 43,560 0.34 acres
- 0.34 x 6.2 2.1 acre-feet of water
- 2 lbs of copper sulfate per acre-foot x 2.1
acre-feet 4.2 lbs of copper sulfate
36Triangular Side
- 1/2 (100 x 75) 3750
- 3750 ? 43,560 0.09 acres
- 0.09 acres x 3 feet 0.27 acre-feet of water
- 2 lbs of copper sulfate per acre-foot x 0.27
acre-feet 0.54 lbs of copper sulfate
37Spot Treatments
- When fish are important pond resources
- When vegetation covers more than 50 of thepond
- When treatment is required in the summer months
- To spot-treat, applyherbicide to no morethan
20 of the totalpond surface at weeklyintervals
38Spot Treatment
- I have bushy pondweed growing from the pond
edge to about 20 feet out around 250 feet of
shoreline. The water where the weeds are growing
averages - 2 feet in depth. How much
- Aquathol Super K do I
- need to buy to treat
- the affected area if the
- application rate is 3ppm
- (13.2 pounds per acre-foot
- of water)?
39Spot Treatment
- 250 x 20 5,000 square feet of area to be
treated - 5,000 ? 43,560 0.11 surface acres
- 0.11 acres x 2 feet average depth 0.22
acre-feet - 0.22 acre-feet x 13.2 pounds of Aquathol Super K
per acre-foot - 2.9 pounds of Aquathol Super K
40Restricted Use Pesticides for Aquatic Applications
41(No Transcript)
42The End